Volume of 3D Shapes Worksheet | Fun and Engaging 8th Grade PDF ... - Free Printable
Educational worksheet: Volume of 3D Shapes Worksheet | Fun and Engaging 8th Grade PDF .... Download and print for classroom or home learning activities.
JPG
1811×2560
250.9 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #381790
⭐
Show Answer Key & Explanations
Step-by-step solution for: Volume of 3D Shapes Worksheet | Fun and Engaging 8th Grade PDF ...
▼
Show Answer Key & Explanations
Step-by-step solution for: Volume of 3D Shapes Worksheet | Fun and Engaging 8th Grade PDF ...
Let's solve each problem step by step to find the volume of the given 3D shapes (cuboids or combinations of cuboids). The volume of a cuboid is calculated using:
$$
\text{Volume} = \text{length} \times \text{width} \times \text{height}
$$
We'll break complex shapes into simpler cuboids, calculate their volumes separately, and then add or subtract as needed.
---
This shape consists of two cuboids:
- Bottom part:
Length = 4 cm, Width = 2 cm, Height = 2 cm
Volume = $ 4 \times 2 \times 2 = 16 \, \text{cm}^3 $
- Top part:
Length = 2 cm, Width = 2 cm, Height = 2 cm
Volume = $ 2 \times 2 \times 2 = 8 \, \text{cm}^3 $
> Total Volume = $ 16 + 8 = \boxed{24} \, \text{cm}^3 $
---
This shape has two parts:
- Left part:
Length = 5 cm, Width = 2 cm, Height = 6 cm
Volume = $ 5 \times 2 \times 6 = 60 \, \text{cm}^3 $
- Right part (top):
Length = 4 cm, Width = 2 cm, Height = 6 cm
But wait — it's only on top, so height is 4 cm? Let’s clarify.
Actually, looking at the figure:
- The base is 6 cm long and 2 cm high.
- The left block is 5 cm wide, 6 cm long, 2 cm high.
- The right block is 4 cm wide, 6 cm long, but only 4 cm high?
Wait — no. The total depth is 6 cm. The front face shows:
- Left section: 5 cm tall → height = 5 cm?
But the label says "5 cm" on the side.
Wait — let's interpret carefully.
Looking again:
- The bottom base is 6 cm (length), 6 cm (depth), and 2 cm (height) — but wait, the depth is 2 cm (from side view).
- Actually, the depth is 2 cm (as labeled on the right side).
So:
- The entire shape has depth = 2 cm (into page), length = 6 cm (front-back), height varies.
But the figure shows:
- A large rectangular block:
- Length = 6 cm, Depth = 2 cm, Height = 5 cm → Volume = $ 6 \times 2 \times 5 = 60 \, \text{cm}^3 $
- Then a smaller block on top of the right side:
- It extends 4 cm in height above the base? Wait, the height of the small block is 4 cm, but the base is already 5 cm?
Wait — this seems inconsistent.
Let’s re-analyze:
The total height is 5 cm (left side), and the right side has a step down of 4 cm.
So:
- The left block:
- Length = 6 cm, Depth = 2 cm, Height = 5 cm → $ 6 \times 2 \times 5 = 60 \, \text{cm}^3 $
- The right block:
- It's lower, height = 4 cm? But it's not attached properly.
Wait — actually, the shape has a notch.
Better approach: Think of it as a big cuboid minus a smaller one.
- Big cuboid:
- Length = 6 cm, Width = 6 cm, Height = 5 cm? No — depth is 2 cm.
Wait — dimensions:
From labels:
- Front depth = 2 cm (right side)
- Length (along base) = 6 cm
- Height on left = 5 cm
- Height on right = 4 cm? But there’s a 4 cm label on the top.
Actually, look at the top view: The top surface is missing a piece.
Wait — better: This shape is made of two parts.
Let’s split:
- Lower block:
- Covers entire base: length = 6 cm, depth = 2 cm, height = 4 cm → Volume = $ 6 \times 2 \times 4 = 48 \, \text{cm}^3 $
- Upper block:
- On the left side, adds extra height:
- Length = 6 cm, depth = 2 cm, height = 1 cm (since 5 cm total height, 4 cm base → extra 1 cm)
→ Volume = $ 6 \times 2 \times 1 = 12 \, \text{cm}^3 $
Wait — but the label says "5 cm" on the left side, and "4 cm" on the top.
So yes:
- Base: 6 cm × 2 cm × 4 cm = 48 cm³
- Top layer: 6 cm × 2 cm × 1 cm = 12 cm³
→ Total = $ 48 + 12 = \boxed{60} \, \text{cm}^3 $
Alternatively, think of it as:
- Whole block: 6×2×5 = 60 cm³
- But the right part is only 4 cm high? No — the whole height is 5 cm on the left, but the right side is shorter?
Wait — the diagram shows a step, like an L-shape.
Wait — the top has a 4 cm label, and the side has a 5 cm label.
Let me draw mentally:
- The shape has:
- A base of 6 cm (length), 2 cm (depth), 4 cm (height) → Volume = 48 cm³
- A top extension on the left: 6 cm (length), 2 cm (depth), 1 cm (height) → 12 cm³
→ Total = 60 cm³
Yes.
✔ Answer: $ \boxed{60} \, \text{cm}^3 $
---
This is a stepped shape with three levels.
Break into three cuboids:
- Bottom layer:
- Length = 5 cm, Width = 3 cm, Height = 2 cm
→ Volume = $ 5 \times 3 \times 2 = 30 \, \text{cm}^3 $
- Middle layer:
- Length = 3 cm, Width = 3 cm, Height = 2 cm
→ Volume = $ 3 \times 3 \times 2 = 18 \, \text{cm}^3 $
- Top layer:
- Length = 3 cm, Width = 3 cm, Height = 2 cm
→ Volume = $ 3 \times 3 \times 2 = 18 \, \text{cm}^3 $
Wait — but the middle and top are stacked?
Actually, from the diagram:
- Bottom: full width = 5 cm, depth = 3 cm, height = 2 cm → 30 cm³
- Middle: sits on top of bottom, centered? But width = 3 cm, so it's inset.
- So: 3 cm (length), 3 cm (depth), 2 cm (height) → 18 cm³
- Top: same size as middle? Yes, 3×3×2 = 18 cm³
But wait — the top layer is on top of the middle, so total height is 6 cm?
But the labels show:
- Height of bottom = 2 cm
- Middle = 2 cm
- Top = 2 cm → total 6 cm
So all good.
Total volume = $ 30 + 18 + 18 = \boxed{66} \, \text{cm}^3 $
✔ Answer: $ \boxed{66} \, \text{cm}^3 $
---
This is a zig-zag shape.
Split into three cuboids:
- Left block:
- Length = 3 cm, Depth = 4 cm, Height = 2 cm → $ 3 \times 4 \times 2 = 24 \, \text{cm}^3 $
- Middle block:
- Length = 4 cm, Depth = 4 cm, Height = 2 cm → $ 4 \times 4 \times 2 = 32 \, \text{cm}^3 $? Wait — depth is 4 cm, but the block is only 4 cm long?
Wait — labels:
- Depth = 4 cm (on right side)
- Height = 2 cm (bottom)
- Top block: 1 cm high, 2 cm long, 4 cm deep
Let’s analyze:
- The bottom layer:
- Full length = 3 cm + 4 cm = 7 cm? No — looks like a step.
Actually, from the side:
- The base is 4 cm deep (into page)
- The shape has:
- A left step: 3 cm wide, 2 cm high
- A middle step: 4 cm wide, 4 cm high? No — height is only 2 cm for base.
Wait — labels:
- Height of base = 2 cm
- Height of top block = 1 cm
- Depth = 4 cm
- Widths: 3 cm, 4 cm, 2 cm
Better to split:
1. Bottom block:
- Length = 3 cm, Depth = 4 cm, Height = 2 cm → $ 3 \times 4 \times 2 = 24 \, \text{cm}^3 $
2. Middle block:
- Length = 4 cm, Depth = 4 cm, Height = 2 cm → $ 4 \times 4 \times 2 = 32 \, \text{cm}^3 $
3. Top block:
- Length = 2 cm, Depth = 4 cm, Height = 1 cm → $ 2 \times 4 \times 1 = 8 \, \text{cm}^3 $
Wait — but are these aligned?
From the diagram:
- The bottom is 3 cm wide (left), then 4 cm wide (middle), total 7 cm? But the label says "3 cm" and "4 cm" — so maybe:
- Left: 3 cm wide, 2 cm high
- Middle: 4 cm wide, 2 cm high
- Top: 2 cm wide, 1 cm high, sitting on the middle?
But the top block is only 2 cm long and 1 cm high, placed on the right side.
Wait — actually, the top block is 2 cm long, 1 cm high, 4 cm deep — so it sits on top of the right end.
But the middle block is 4 cm wide, so the top block can sit on it.
But the bottom block is only 3 cm wide, so the rest is supported by the middle?
No — the structure is:
- Bottom layer:
- A base of 3 cm (left) + 4 cm (right) = 7 cm long? But the diagram shows a gap.
Wait — perhaps it's:
- Left block: 3 cm × 4 cm × 2 cm → 24 cm³
- Right block: 4 cm × 4 cm × 2 cm → 32 cm³
- Top block: 2 cm × 4 cm × 1 cm → 8 cm³
But do they overlap? No — the left and right are adjacent.
But the top block is on top of the right block.
So total volume = $ 24 + 32 + 8 = \boxed{64} \, \text{cm}^3 $
But wait — is the right block really 4 cm wide? The label says "4 cm" on the bottom, but the total length is 3 cm + 4 cm = 7 cm?
Yes — so total length = 7 cm.
So:
- Left: 3×4×2 = 24
- Right: 4×4×2 = 32
- Top: 2×4×1 = 8
- Total = 24 + 32 + 8 = 64 cm³
✔ Answer: $ \boxed{64} \, \text{cm}^3 $
---
This is an L-shaped prism.
Split into two cuboids:
- Vertical arm:
- Length = 5 cm, Depth = 2 cm, Height = 5 cm → $ 5 \times 2 \times 5 = 50 \, \text{cm}^3 $
- Horizontal arm:
- Length = 7 cm, Depth = 1 cm, Height = 3 cm → $ 7 \times 1 \times 3 = 21 \, \text{cm}^3 $
Wait — but they share a common part? Look at the diagram:
- The vertical arm is 5 cm high, 5 cm long, 2 cm deep
- The horizontal arm is 7 cm long, 1 cm deep, 3 cm high
- They meet at a corner — but the overlap is a 5 cm × 1 cm × 3 cm block?
Wait — no — the horizontal arm is 3 cm high, and the vertical arm is 5 cm high, so the horizontal arm rests on the bottom of the vertical arm.
But the depth of the horizontal arm is 1 cm, while the vertical arm is 2 cm deep — so they don’t fully overlap.
Let’s read labels:
- Vertical arm:
- Length = 5 cm, Depth = 2 cm, Height = 5 cm → Volume = $ 5 \times 2 \times 5 = 50 \, \text{cm}^3 $
- Horizontal arm:
- Length = 7 cm, Depth = 1 cm, Height = 3 cm → $ 7 \times 1 \times 3 = 21 \, \text{cm}^3 $
But they intersect at a region: 5 cm (length) × 1 cm (depth) × 3 cm (height)
Wait — the horizontal arm is 7 cm long, but only overlaps 5 cm with the vertical arm?
Actually, the horizontal arm starts at the bottom of the vertical arm and extends 7 cm.
But the vertical arm is 5 cm long and 2 cm deep.
The horizontal arm is 1 cm deep, so it sits beside the vertical arm.
But the diagram shows a shared edge.
Wait — the horizontal arm is 7 cm long, 1 cm deep, 3 cm high — but it connects to the vertical arm.
But the vertical arm is 5 cm long, 2 cm deep, 5 cm high.
They intersect in a 5 cm × 1 cm × 3 cm block?
But that would be double-counting.
But actually, the horizontal arm is attached to the side of the vertical arm.
So no overlap — just touching.
So total volume = $ 50 + 21 = \boxed{71} \, \text{cm}^3 $
But wait — the horizontal arm is only 3 cm high, and the vertical arm is 5 cm high — so they don't interfere.
Yes — the horizontal arm is in front of the vertical arm, but only 1 cm deep, while vertical is 2 cm deep.
So no overlap.
✔ Answer: $ \boxed{71} \, \text{cm}^3 $
---
This is a large cuboid with a hole.
- Outer cuboid:
- Length = 8 cm, Width = 4 cm, Height = 6 cm
→ Volume = $ 8 \times 4 \times 6 = 192 \, \text{cm}^3 $
- Hole inside:
- The hole is a rectangular prism, dimensions:
- From diagram:
- The inner rectangle is 4 cm wide, 2 cm high, and depth = 4 cm?
- But the hole is shown as a square cutout.
Wait — the hole is not a full-through? It's a rectangular cavity.
From the diagram:
- The hole has:
- Length = 4 cm (top), Width = 2 cm (side), Height = 4 cm? No — the depth is 4 cm?
Wait — the hole is visible on the front face:
- It's 4 cm wide, 2 cm high, and since it's a cavity, its depth is equal to the width of the object? No — the object is 4 cm thick (into page).
Wait — the object is 8 cm (length), 4 cm (height), 6 cm (depth)? No — the depth is 4 cm? Wait:
Labels:
- Top: 8 cm
- Side: 6 cm
- Depth: 4 cm
So outer box: $ 8 \times 6 \times 4 = 192 \, \text{cm}^3 $
Now the hole:
- On the front face: a rectangle of 4 cm (width) × 2 cm (height)
- Since it's a cavity going through, its depth is the thickness of the object — which is 4 cm (into page)
So hole volume = $ 4 \times 2 \times 4 = 32 \, \text{cm}^3 $
Wait — but the hole is not going all the way through? The diagram shows a cavity that is not fully open.
Wait — the hole is shown as a square with a diagonal line — suggesting it's a rectangular prism cut out.
But the depth of the cavity is 4 cm (same as the thickness of the wall)?
Wait — the object has depth = 4 cm (into page), so the hole goes through the entire depth.
So yes:
- Hole: length = 4 cm, width = 2 cm, depth = 4 cm → Volume = $ 4 \times 2 \times 4 = 32 \, \text{cm}^3 $
But wait — the label says "4 cm" and "2 cm" — so it's 4 cm wide, 2 cm high.
And the depth is the same as the object’s depth: 4 cm.
So hole volume = $ 4 \times 2 \times 4 = 32 \, \text{cm}^3 $
Therefore, total volume = $ 192 - 32 = \boxed{160} \, \text{cm}^3 $
But wait — is the hole fully enclosed? Or does it go through?
The diagram shows a cavity on the front face — but not necessarily through.
Wait — the inner rectangle is drawn with dashed lines — suggesting it's a cutout.
But the depth of the hole is not labeled.
However, the object’s depth is 4 cm, and the hole is drawn as a rectangle on the front — so likely it's a through-hole.
But the dimensions:
- The hole is 4 cm wide, 2 cm high — and since the object is 4 cm thick, the hole goes through.
So volume removed = $ 4 \times 2 \times 4 = 32 \, \text{cm}^3 $
So final volume = $ 8 \times 6 \times 4 = 192 $, minus $ 32 = \boxed{160} \, \text{cm}^3 $
But wait — the height of the object is 6 cm, and the hole is only 2 cm high — so yes.
✔ Answer: $ \boxed{160} \, \text{cm}^3 $
---
1) $ \boxed{24} \, \text{cm}^3 $
2) $ \boxed{60} \, \text{cm}^3 $
3) $ \boxed{66} \, \text{cm}^3 $
4) $ \boxed{64} \, \text{cm}^3 $
5) $ \boxed{71} \, \text{cm}^3 $
6) $ \boxed{160} \, \text{cm}^3 $
Let me know if you'd like the surface area too!
$$
\text{Volume} = \text{length} \times \text{width} \times \text{height}
$$
We'll break complex shapes into simpler cuboids, calculate their volumes separately, and then add or subtract as needed.
---
1)
This shape consists of two cuboids:
- Bottom part:
Length = 4 cm, Width = 2 cm, Height = 2 cm
Volume = $ 4 \times 2 \times 2 = 16 \, \text{cm}^3 $
- Top part:
Length = 2 cm, Width = 2 cm, Height = 2 cm
Volume = $ 2 \times 2 \times 2 = 8 \, \text{cm}^3 $
> Total Volume = $ 16 + 8 = \boxed{24} \, \text{cm}^3 $
---
2)
This shape has two parts:
- Left part:
Length = 5 cm, Width = 2 cm, Height = 6 cm
Volume = $ 5 \times 2 \times 6 = 60 \, \text{cm}^3 $
- Right part (top):
Length = 4 cm, Width = 2 cm, Height = 6 cm
But wait — it's only on top, so height is 4 cm? Let’s clarify.
Actually, looking at the figure:
- The base is 6 cm long and 2 cm high.
- The left block is 5 cm wide, 6 cm long, 2 cm high.
- The right block is 4 cm wide, 6 cm long, but only 4 cm high?
Wait — no. The total depth is 6 cm. The front face shows:
- Left section: 5 cm tall → height = 5 cm?
But the label says "5 cm" on the side.
Wait — let's interpret carefully.
Looking again:
- The bottom base is 6 cm (length), 6 cm (depth), and 2 cm (height) — but wait, the depth is 2 cm (from side view).
- Actually, the depth is 2 cm (as labeled on the right side).
So:
- The entire shape has depth = 2 cm (into page), length = 6 cm (front-back), height varies.
But the figure shows:
- A large rectangular block:
- Length = 6 cm, Depth = 2 cm, Height = 5 cm → Volume = $ 6 \times 2 \times 5 = 60 \, \text{cm}^3 $
- Then a smaller block on top of the right side:
- It extends 4 cm in height above the base? Wait, the height of the small block is 4 cm, but the base is already 5 cm?
Wait — this seems inconsistent.
Let’s re-analyze:
The total height is 5 cm (left side), and the right side has a step down of 4 cm.
So:
- The left block:
- Length = 6 cm, Depth = 2 cm, Height = 5 cm → $ 6 \times 2 \times 5 = 60 \, \text{cm}^3 $
- The right block:
- It's lower, height = 4 cm? But it's not attached properly.
Wait — actually, the shape has a notch.
Better approach: Think of it as a big cuboid minus a smaller one.
- Big cuboid:
- Length = 6 cm, Width = 6 cm, Height = 5 cm? No — depth is 2 cm.
Wait — dimensions:
From labels:
- Front depth = 2 cm (right side)
- Length (along base) = 6 cm
- Height on left = 5 cm
- Height on right = 4 cm? But there’s a 4 cm label on the top.
Actually, look at the top view: The top surface is missing a piece.
Wait — better: This shape is made of two parts.
Let’s split:
- Lower block:
- Covers entire base: length = 6 cm, depth = 2 cm, height = 4 cm → Volume = $ 6 \times 2 \times 4 = 48 \, \text{cm}^3 $
- Upper block:
- On the left side, adds extra height:
- Length = 6 cm, depth = 2 cm, height = 1 cm (since 5 cm total height, 4 cm base → extra 1 cm)
→ Volume = $ 6 \times 2 \times 1 = 12 \, \text{cm}^3 $
Wait — but the label says "5 cm" on the left side, and "4 cm" on the top.
So yes:
- Base: 6 cm × 2 cm × 4 cm = 48 cm³
- Top layer: 6 cm × 2 cm × 1 cm = 12 cm³
→ Total = $ 48 + 12 = \boxed{60} \, \text{cm}^3 $
Alternatively, think of it as:
- Whole block: 6×2×5 = 60 cm³
- But the right part is only 4 cm high? No — the whole height is 5 cm on the left, but the right side is shorter?
Wait — the diagram shows a step, like an L-shape.
Wait — the top has a 4 cm label, and the side has a 5 cm label.
Let me draw mentally:
- The shape has:
- A base of 6 cm (length), 2 cm (depth), 4 cm (height) → Volume = 48 cm³
- A top extension on the left: 6 cm (length), 2 cm (depth), 1 cm (height) → 12 cm³
→ Total = 60 cm³
Yes.
✔ Answer: $ \boxed{60} \, \text{cm}^3 $
---
3)
This is a stepped shape with three levels.
Break into three cuboids:
- Bottom layer:
- Length = 5 cm, Width = 3 cm, Height = 2 cm
→ Volume = $ 5 \times 3 \times 2 = 30 \, \text{cm}^3 $
- Middle layer:
- Length = 3 cm, Width = 3 cm, Height = 2 cm
→ Volume = $ 3 \times 3 \times 2 = 18 \, \text{cm}^3 $
- Top layer:
- Length = 3 cm, Width = 3 cm, Height = 2 cm
→ Volume = $ 3 \times 3 \times 2 = 18 \, \text{cm}^3 $
Wait — but the middle and top are stacked?
Actually, from the diagram:
- Bottom: full width = 5 cm, depth = 3 cm, height = 2 cm → 30 cm³
- Middle: sits on top of bottom, centered? But width = 3 cm, so it's inset.
- So: 3 cm (length), 3 cm (depth), 2 cm (height) → 18 cm³
- Top: same size as middle? Yes, 3×3×2 = 18 cm³
But wait — the top layer is on top of the middle, so total height is 6 cm?
But the labels show:
- Height of bottom = 2 cm
- Middle = 2 cm
- Top = 2 cm → total 6 cm
So all good.
Total volume = $ 30 + 18 + 18 = \boxed{66} \, \text{cm}^3 $
✔ Answer: $ \boxed{66} \, \text{cm}^3 $
---
4)
This is a zig-zag shape.
Split into three cuboids:
- Left block:
- Length = 3 cm, Depth = 4 cm, Height = 2 cm → $ 3 \times 4 \times 2 = 24 \, \text{cm}^3 $
- Middle block:
- Length = 4 cm, Depth = 4 cm, Height = 2 cm → $ 4 \times 4 \times 2 = 32 \, \text{cm}^3 $? Wait — depth is 4 cm, but the block is only 4 cm long?
Wait — labels:
- Depth = 4 cm (on right side)
- Height = 2 cm (bottom)
- Top block: 1 cm high, 2 cm long, 4 cm deep
Let’s analyze:
- The bottom layer:
- Full length = 3 cm + 4 cm = 7 cm? No — looks like a step.
Actually, from the side:
- The base is 4 cm deep (into page)
- The shape has:
- A left step: 3 cm wide, 2 cm high
- A middle step: 4 cm wide, 4 cm high? No — height is only 2 cm for base.
Wait — labels:
- Height of base = 2 cm
- Height of top block = 1 cm
- Depth = 4 cm
- Widths: 3 cm, 4 cm, 2 cm
Better to split:
1. Bottom block:
- Length = 3 cm, Depth = 4 cm, Height = 2 cm → $ 3 \times 4 \times 2 = 24 \, \text{cm}^3 $
2. Middle block:
- Length = 4 cm, Depth = 4 cm, Height = 2 cm → $ 4 \times 4 \times 2 = 32 \, \text{cm}^3 $
3. Top block:
- Length = 2 cm, Depth = 4 cm, Height = 1 cm → $ 2 \times 4 \times 1 = 8 \, \text{cm}^3 $
Wait — but are these aligned?
From the diagram:
- The bottom is 3 cm wide (left), then 4 cm wide (middle), total 7 cm? But the label says "3 cm" and "4 cm" — so maybe:
- Left: 3 cm wide, 2 cm high
- Middle: 4 cm wide, 2 cm high
- Top: 2 cm wide, 1 cm high, sitting on the middle?
But the top block is only 2 cm long and 1 cm high, placed on the right side.
Wait — actually, the top block is 2 cm long, 1 cm high, 4 cm deep — so it sits on top of the right end.
But the middle block is 4 cm wide, so the top block can sit on it.
But the bottom block is only 3 cm wide, so the rest is supported by the middle?
No — the structure is:
- Bottom layer:
- A base of 3 cm (left) + 4 cm (right) = 7 cm long? But the diagram shows a gap.
Wait — perhaps it's:
- Left block: 3 cm × 4 cm × 2 cm → 24 cm³
- Right block: 4 cm × 4 cm × 2 cm → 32 cm³
- Top block: 2 cm × 4 cm × 1 cm → 8 cm³
But do they overlap? No — the left and right are adjacent.
But the top block is on top of the right block.
So total volume = $ 24 + 32 + 8 = \boxed{64} \, \text{cm}^3 $
But wait — is the right block really 4 cm wide? The label says "4 cm" on the bottom, but the total length is 3 cm + 4 cm = 7 cm?
Yes — so total length = 7 cm.
So:
- Left: 3×4×2 = 24
- Right: 4×4×2 = 32
- Top: 2×4×1 = 8
- Total = 24 + 32 + 8 = 64 cm³
✔ Answer: $ \boxed{64} \, \text{cm}^3 $
---
5)
This is an L-shaped prism.
Split into two cuboids:
- Vertical arm:
- Length = 5 cm, Depth = 2 cm, Height = 5 cm → $ 5 \times 2 \times 5 = 50 \, \text{cm}^3 $
- Horizontal arm:
- Length = 7 cm, Depth = 1 cm, Height = 3 cm → $ 7 \times 1 \times 3 = 21 \, \text{cm}^3 $
Wait — but they share a common part? Look at the diagram:
- The vertical arm is 5 cm high, 5 cm long, 2 cm deep
- The horizontal arm is 7 cm long, 1 cm deep, 3 cm high
- They meet at a corner — but the overlap is a 5 cm × 1 cm × 3 cm block?
Wait — no — the horizontal arm is 3 cm high, and the vertical arm is 5 cm high, so the horizontal arm rests on the bottom of the vertical arm.
But the depth of the horizontal arm is 1 cm, while the vertical arm is 2 cm deep — so they don’t fully overlap.
Let’s read labels:
- Vertical arm:
- Length = 5 cm, Depth = 2 cm, Height = 5 cm → Volume = $ 5 \times 2 \times 5 = 50 \, \text{cm}^3 $
- Horizontal arm:
- Length = 7 cm, Depth = 1 cm, Height = 3 cm → $ 7 \times 1 \times 3 = 21 \, \text{cm}^3 $
But they intersect at a region: 5 cm (length) × 1 cm (depth) × 3 cm (height)
Wait — the horizontal arm is 7 cm long, but only overlaps 5 cm with the vertical arm?
Actually, the horizontal arm starts at the bottom of the vertical arm and extends 7 cm.
But the vertical arm is 5 cm long and 2 cm deep.
The horizontal arm is 1 cm deep, so it sits beside the vertical arm.
But the diagram shows a shared edge.
Wait — the horizontal arm is 7 cm long, 1 cm deep, 3 cm high — but it connects to the vertical arm.
But the vertical arm is 5 cm long, 2 cm deep, 5 cm high.
They intersect in a 5 cm × 1 cm × 3 cm block?
But that would be double-counting.
But actually, the horizontal arm is attached to the side of the vertical arm.
So no overlap — just touching.
So total volume = $ 50 + 21 = \boxed{71} \, \text{cm}^3 $
But wait — the horizontal arm is only 3 cm high, and the vertical arm is 5 cm high — so they don't interfere.
Yes — the horizontal arm is in front of the vertical arm, but only 1 cm deep, while vertical is 2 cm deep.
So no overlap.
✔ Answer: $ \boxed{71} \, \text{cm}^3 $
---
6)
This is a large cuboid with a hole.
- Outer cuboid:
- Length = 8 cm, Width = 4 cm, Height = 6 cm
→ Volume = $ 8 \times 4 \times 6 = 192 \, \text{cm}^3 $
- Hole inside:
- The hole is a rectangular prism, dimensions:
- From diagram:
- The inner rectangle is 4 cm wide, 2 cm high, and depth = 4 cm?
- But the hole is shown as a square cutout.
Wait — the hole is not a full-through? It's a rectangular cavity.
From the diagram:
- The hole has:
- Length = 4 cm (top), Width = 2 cm (side), Height = 4 cm? No — the depth is 4 cm?
Wait — the hole is visible on the front face:
- It's 4 cm wide, 2 cm high, and since it's a cavity, its depth is equal to the width of the object? No — the object is 4 cm thick (into page).
Wait — the object is 8 cm (length), 4 cm (height), 6 cm (depth)? No — the depth is 4 cm? Wait:
Labels:
- Top: 8 cm
- Side: 6 cm
- Depth: 4 cm
So outer box: $ 8 \times 6 \times 4 = 192 \, \text{cm}^3 $
Now the hole:
- On the front face: a rectangle of 4 cm (width) × 2 cm (height)
- Since it's a cavity going through, its depth is the thickness of the object — which is 4 cm (into page)
So hole volume = $ 4 \times 2 \times 4 = 32 \, \text{cm}^3 $
Wait — but the hole is not going all the way through? The diagram shows a cavity that is not fully open.
Wait — the hole is shown as a square with a diagonal line — suggesting it's a rectangular prism cut out.
But the depth of the cavity is 4 cm (same as the thickness of the wall)?
Wait — the object has depth = 4 cm (into page), so the hole goes through the entire depth.
So yes:
- Hole: length = 4 cm, width = 2 cm, depth = 4 cm → Volume = $ 4 \times 2 \times 4 = 32 \, \text{cm}^3 $
But wait — the label says "4 cm" and "2 cm" — so it's 4 cm wide, 2 cm high.
And the depth is the same as the object’s depth: 4 cm.
So hole volume = $ 4 \times 2 \times 4 = 32 \, \text{cm}^3 $
Therefore, total volume = $ 192 - 32 = \boxed{160} \, \text{cm}^3 $
But wait — is the hole fully enclosed? Or does it go through?
The diagram shows a cavity on the front face — but not necessarily through.
Wait — the inner rectangle is drawn with dashed lines — suggesting it's a cutout.
But the depth of the hole is not labeled.
However, the object’s depth is 4 cm, and the hole is drawn as a rectangle on the front — so likely it's a through-hole.
But the dimensions:
- The hole is 4 cm wide, 2 cm high — and since the object is 4 cm thick, the hole goes through.
So volume removed = $ 4 \times 2 \times 4 = 32 \, \text{cm}^3 $
So final volume = $ 8 \times 6 \times 4 = 192 $, minus $ 32 = \boxed{160} \, \text{cm}^3 $
But wait — the height of the object is 6 cm, and the hole is only 2 cm high — so yes.
✔ Answer: $ \boxed{160} \, \text{cm}^3 $
---
✔ Final Answers:
1) $ \boxed{24} \, \text{cm}^3 $
2) $ \boxed{60} \, \text{cm}^3 $
3) $ \boxed{66} \, \text{cm}^3 $
4) $ \boxed{64} \, \text{cm}^3 $
5) $ \boxed{71} \, \text{cm}^3 $
6) $ \boxed{160} \, \text{cm}^3 $
Let me know if you'd like the surface area too!
Parent Tip: Review the logic above to help your child master the concept of volume of shapes worksheet.