Water Displacement Method online exercise for - Free Printable

To solve the problem using the water displacement method, we need to follow these steps for each object:

1. Identify the initial volume (\( V_i \)) of water in the graduated cylinder before the object is added.
2. Identify the final volume (\( V_f \)) of water in the graduated cylinder after the object is submerged.
3. Calculate the volume of the object using the formula:
\[
V_{\text{object}} = V_f - V_i
\]
4. Convert the volume from mL to cm³ (since 1 mL = 1 cm³).

Let's solve each part step by step.

---

First Object (Ring)

#### Step 1: Initial Volume (\( V_i \))
From the image, the initial volume of water is 60 mL.

#### Step 2: Final Volume (\( V_f \))
After adding the ring, the final volume of water is 65 mL.

#### Step 3: Calculate the Volume of the Object
\[
V_{\text{object}} = V_f - V_i = 65 \, \text{mL} - 60 \, \text{mL} = 5 \, \text{mL}
\]

#### Step 4: Convert to cm³
Since \( 1 \, \text{mL} = 1 \, \text{cm}^3 \):
\[
V_{\text{object}} = 5 \, \text{cm}^3
\]

#### Final Answer for the Ring:
\[
\boxed{5 \, \text{cm}^3}
\]

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Second Object (Cylinder)

#### Step 1: Initial Volume (\( V_i \))
From the image, the initial volume of water is 20 mL.

#### Step 2: Final Volume (\( V_f \))
After adding the cylinder, the final volume of water is 30 mL.

#### Step 3: Calculate the Volume of the Object
\[
V_{\text{object}} = V_f - V_i = 30 \, \text{mL} - 20 \, \text{mL} = 10 \, \text{mL}
\]

#### Step 4: Convert to cm³
Since \( 1 \, \text{mL} = 1 \, \text{cm}^3 \):
\[
V_{\text{object}} = 10 \, \text{cm}^3
\]

#### Final Answer for the Cylinder:
\[
\boxed{10 \, \text{cm}^3}
\]

---

Third Object (Sphere)

#### Step 1: Initial Volume (\( V_i \))
From the image, the initial volume of water is 100 mL.

#### Step 2: Final Volume (\( V_f \))
After adding the sphere, the final volume of water is 150 mL.

#### Step 3: Calculate the Volume of the Object
\[
V_{\text{object}} = V_f - V_i = 150 \, \text{mL} - 100 \, \text{mL} = 50 \, \text{mL}
\]

#### Step 4: Convert to cm³
Since \( 1 \, \text{mL} = 1 \, \text{cm}^3 \):
\[
V_{\text{object}} = 50 \, \text{cm}^3
\]

#### Final Answer for the Sphere:
\[
\boxed{50 \, \text{cm}^3}
\]

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Summary of Answers

1. Ring: \( \boxed{5 \, \text{cm}^3} \)
2. Cylinder: \( \boxed{10 \, \text{cm}^3} \)
3. Sphere: \( \boxed{50 \, \text{cm}^3} \)

These are the volumes of the irregular objects calculated using the water displacement method.