Blueprint help, makes no sense. : r/Welding - Free Printable

The task involves determining the locations of holes on a manufactured part based on the given dimensions and fractions. Let's solve this step by step.

Step 1: Understand the Problem

The worksheet provides a diagram with various hole locations marked, along with fractional measurements. The goal is to calculate the cumulative distances from the starting point (left edge) to each hole location.

Step 2: Analyze the Diagram

- The diagram shows a series of holes labeled with numbers (1 through 10).
- Each hole has a specified distance from the previous hole or from the starting point.
- The distances are given as mixed numbers or improper fractions.

Step 3: Solve for Each Hole Location

#### Hole 1
- Distance from the start: \( 1 \frac{7}{64} \)
- Convert to an improper fraction:
\[
1 \frac{7}{64} = \frac{64}{64} + \frac{7}{64} = \frac{71}{64}
\]
- Location of Hole 1: \( \frac{71}{64} \)

#### Hole 2
- Distance from Hole 1: \( 1 \frac{3}{2} \)
- Convert to an improper fraction:
\[
1 \frac{3}{2} = \frac{2}{2} + \frac{3}{2} = \frac{5}{2}
\]
- Add to the location of Hole 1:
\[
\text{Location of Hole 2} = \frac{71}{64} + \frac{5}{2}
\]
- Convert \( \frac{5}{2} \) to a fraction with a denominator of 64:
\[
\frac{5}{2} = \frac{5 \times 32}{2 \times 32} = \frac{160}{64}
\]
- Add the fractions:
\[
\frac{71}{64} + \frac{160}{64} = \frac{231}{64}
\]
- Location of Hole 2: \( \frac{231}{64} \)

#### Hole 3
- Distance from Hole 2: \( \frac{31}{32} \)
- Convert \( \frac{31}{32} \) to a fraction with a denominator of 64:
\[
\frac{31}{32} = \frac{31 \times 2}{32 \times 2} = \frac{62}{64}
\]
- Add to the location of Hole 2:
\[
\text{Location of Hole 3} = \frac{231}{64} + \frac{62}{64} = \frac{293}{64}
\]
- Location of Hole 3: \( \frac{293}{64} \)

#### Hole 4
- Distance from Hole 3: \( 1 \frac{43}{64} \)
- Convert to an improper fraction:
\[
1 \frac{43}{64} = \frac{64}{64} + \frac{43}{64} = \frac{107}{64}
\]
- Add to the location of Hole 3:
\[
\text{Location of Hole 4} = \frac{293}{64} + \frac{107}{64} = \frac{400}{64}
\]
- Simplify \( \frac{400}{64} \):
\[
\frac{400}{64} = \frac{25}{4}
\]
- Location of Hole 4: \( \frac{25}{4} \)

#### Hole 5
- Distance from the start: \( 5 \frac{37}{64} \)
- Convert to an improper fraction:
\[
5 \frac{37}{64} = \frac{5 \times 64}{64} + \frac{37}{64} = \frac{320}{64} + \frac{37}{64} = \frac{357}{64}
\]
- Location of Hole 5: \( \frac{357}{64} \)

#### Hole 6
- Distance from Hole 5: \( 2 \frac{3}{4} \)
- Convert to an improper fraction:
\[
2 \frac{3}{4} = \frac{8}{4} + \frac{3}{4} = \frac{11}{4}
\]
- Convert \( \frac{11}{4} \) to a fraction with a denominator of 64:
\[
\frac{11}{4} = \frac{11 \times 16}{4 \times 16} = \frac{176}{64}
\]
- Add to the location of Hole 5:
\[
\text{Location of Hole 6} = \frac{357}{64} + \frac{176}{64} = \frac{533}{64}
\]
- Location of Hole 6: \( \frac{533}{64} \)

#### Hole 7
- Distance from Hole 6: \( 5 \frac{7}{8} \)
- Convert to an improper fraction:
\[
5 \frac{7}{8} = \frac{5 \times 8}{8} + \frac{7}{8} = \frac{40}{8} + \frac{7}{8} = \frac{47}{8}
\]
- Convert \( \frac{47}{8} \) to a fraction with a denominator of 64:
\[
\frac{47}{8} = \frac{47 \times 8}{8 \times 8} = \frac{376}{64}
\]
- Add to the location of Hole 6:
\[
\text{Location of Hole 7} = \frac{533}{64} + \frac{376}{64} = \frac{909}{64}
\]
- Location of Hole 7: \( \frac{909}{64} \)

#### Hole 8
- Distance from Hole 7: \( 2 \frac{41}{64} \)
- Convert to an improper fraction:
\[
2 \frac{41}{64} = \frac{128}{64} + \frac{41}{64} = \frac{169}{64}
\]
- Add to the location of Hole 7:
\[
\text{Location of Hole 8} = \frac{909}{64} + \frac{169}{64} = \frac{1078}{64}
\]
- Simplify \( \frac{1078}{64} \):
\[
\frac{1078}{64} = \frac{539}{32}
\]
- Location of Hole 8: \( \frac{539}{32} \)

#### Hole 9
- Distance from Hole 8: \( \frac{5}{16} \)
- Convert \( \frac{5}{16} \) to a fraction with a denominator of 64:
\[
\frac{5}{16} = \frac{5 \times 4}{16 \times 4} = \frac{20}{64}
\]
- Add to the location of Hole 8:
\[
\text{Location of Hole 9} = \frac{1078}{64} + \frac{20}{64} = \frac{1098}{64}
\]
- Simplify \( \frac{1098}{64} \):
\[
\frac{1098}{64} = \frac{549}{32}
\]
- Location of Hole 9: \( \frac{549}{32} \)

#### Hole 10
- Distance from Hole 9: \( 1 \frac{3}{5} \)
- Convert to an improper fraction:
\[
1 \frac{3}{5} = \frac{5}{5} + \frac{3}{5} = \frac{8}{5}
\]
- Convert \( \frac{8}{5} \) to a fraction with a denominator of 160 (LCM of 32 and 5):
\[
\frac{8}{5} = \frac{8 \times 32}{5 \times 32} = \frac{256}{160}
\]
- Convert \( \frac{549}{32} \) to a fraction with a denominator of 160:
\[
\frac{549}{32} = \frac{549 \times 5}{32 \times 5} = \frac{2745}{160}
\]
- Add the fractions:
\[
\text{Location of Hole 10} = \frac{2745}{160} + \frac{256}{160} = \frac{2901}{160}
\]
- Location of Hole 10: \( \frac{2901}{160} \)

Final Answer

\[
\boxed{
\begin{array}{ll}
(1) & \frac{71}{64} \\
(2) & \frac{231}{64} \\
(3) & \frac{293}{64} \\
(4) & \frac{25}{4} \\
(5) & \frac{357}{64} \\
(6) & \frac{533}{64} \\
(7) & \frac{909}{64} \\
(8) & \frac{539}{32} \\
(9) & \frac{549}{32} \\
(10) & \frac{2901}{160} \\
\end{array}
}
\]