Subtract and find me - Math Worksheets - MathsDiary.com - Free Printable

The task involves solving simple subtraction problems to determine the unknown number in each case. Let's solve each problem step by step.

Problem 1:

Statement: If you subtract me from 7, you get 3.
Solution:
Let the unknown number be \( x \).
\[ 7 - x = 3 \]
To find \( x \), we can rearrange the equation:
\[ x = 7 - 3 \]
\[ x = 4 \]
So, the answer is:
\[ \boxed{4} \]

Problem 2:

Statement: If you subtract me from 8, you get 4.
Solution:
Let the unknown number be \( x \).
\[ 8 - x = 4 \]
To find \( x \), we can rearrange the equation:
\[ x = 8 - 4 \]
\[ x = 4 \]
So, the answer is:
\[ \boxed{4} \]

Problem 3:

Statement: If you subtract me from 2, you get 1.
Solution:
Let the unknown number be \( x \).
\[ 2 - x = 1 \]
To find \( x \), we can rearrange the equation:
\[ x = 2 - 1 \]
\[ x = 1 \]
So, the answer is:
\[ \boxed{1} \]

Problem 4:

Statement: If you subtract me from 9, you get 8.
Solution:
Let the unknown number be \( x \).
\[ 9 - x = 8 \]
To find \( x \), we can rearrange the equation:
\[ x = 9 - 8 \]
\[ x = 1 \]
So, the answer is:
\[ \boxed{1} \]

Problem 5:

Statement: If you subtract me from 10, you get 7.
Solution:
Let the unknown number be \( x \).
\[ 10 - x = 7 \]
To find \( x \), we can rearrange the equation:
\[ x = 10 - 7 \]
\[ x = 3 \]
So, the answer is:
\[ \boxed{3} \]

Problem 6:

Statement: If you subtract me from 5, you get 3.
Solution:
Let the unknown number be \( x \).
\[ 5 - x = 3 \]
To find \( x \), we can rearrange the equation:
\[ x = 5 - 3 \]
\[ x = 2 \]
So, the answer is:
\[ \boxed{2} \]

Final Answers:

1. \( \boxed{4} \)
2. \( \boxed{4} \)
3. \( \boxed{1} \)
4. \( \boxed{1} \)
5. \( \boxed{3} \)
6. \( \boxed{2} \)

So, the complete set of answers is:
\[ \boxed{4, 4, 1, 1, 3, 2} \]