Grade 7 Word Problems Set 1 Worksheet - Free Printable

Let's solve each problem step by step:

---

Problem 1:

Kara was interested in going to the mall to buy some new clothes. Once she got there, she purchased two shirts that cost $13.42 total. If she started out with $40.00, what percentage of her money did she spend?

#### Solution:
1. Total amount spent: Kara spent $13.42.
2. Initial amount: Kara started with $40.00.
3. Percentage calculation formula:
\[
\text{Percentage spent} = \left( \frac{\text{Amount spent}}{\text{Initial amount}} \right) \times 100
\]
4. Substitute the values:
\[
\text{Percentage spent} = \left( \frac{13.42}{40.00} \right) \times 100
\]
5. Perform the division:
\[
\frac{13.42}{40.00} = 0.3355
\]
6. Multiply by 100 to get the percentage:
\[
0.3355 \times 100 = 33.55\%
\]

#### Final Answer:
\[
\boxed{33.55\%}
\]

---

Problem 2:

There are 90 people voting in a school election. There were two parties. 35% of the students voted for the red party. How many students voted for the blue party? Express your answer as a numeral, not as a percentage.

#### Solution:
1. Total voters: 90 people.
2. Percentage voting for the red party: 35%.
3. Number of votes for the red party:
\[
\text{Votes for red party} = 35\% \times 90 = 0.35 \times 90 = 31.5
\]
Since the number of voters must be a whole number, we assume it is rounded to 32 (as typically fractional votes are not possible in this context).
4. Number of votes for the blue party:
\[
\text{Votes for blue party} = \text{Total voters} - \text{Votes for red party} = 90 - 32 = 58
\]

#### Final Answer:
\[
\boxed{58}
\]

---

Problem 3:

Two of these numbers are the same value, which ones are they? 40%, .44, 1/4, .04, 4/10?

#### Solution:
1. Convert all numbers to decimal form for easy comparison:
- \( 40\% = 0.40 \)
- \( 0.44 = 0.44 \)
- \( \frac{1}{4} = 0.25 \)
- \( 0.04 = 0.04 \)
- \( \frac{4}{10} = 0.40 \)
2. Compare the decimal values:
- \( 40\% = 0.40 \)
- \( \frac{4}{10} = 0.40 \)

The two numbers that are the same are \( 40\% \) and \( \frac{4}{10} \).

#### Final Answer:
\[
\boxed{40\%, \frac{4}{10}}
\]

---

Problem 4:

Kara wanted to earn a 90% for her overall history grade. During the course, she has to take 5 tests. So far, she has only taken 4 tests. Her exam scores for the tests are as follows; 85, 83, 99, 95. If Kara wants to ensure she will receive a 90%, what is the minimum score on the 5th test that she can receive?

#### Solution:
1. Total number of tests: 5.
2. Desired average: 90%.
3. Formula for average:
\[
\text{Average} = \frac{\text{Sum of all scores}}{\text{Number of tests}}
\]
4. Let \( x \) be the score on the 5th test. The sum of all scores is:
\[
85 + 83 + 99 + 95 + x
\]
5. Set up the equation for the desired average:
\[
\frac{85 + 83 + 99 + 95 + x}{5} = 90
\]
6. Simplify the numerator:
\[
85 + 83 + 99 + 95 = 362
\]
So the equation becomes:
\[
\frac{362 + x}{5} = 90
\]
7. Multiply both sides by 5 to eliminate the denominator:
\[
362 + x = 450
\]
8. Solve for \( x \):
\[
x = 450 - 362 = 88
\]

#### Final Answer:
\[
\boxed{88}
\]

---

Problem 5:

Ellen was interested in selling her father’s tools for their garage sale. Her father said she could sell 43% of the total tools. If Ellen ended up selling 12 tools, how many tools did Ellen’s father begin with?

#### Solution:
1. Let \( T \) be the total number of tools.
2. Percentage sold: 43%.
3. Number of tools sold: 12.
4. Relationship between percentage and total tools:
\[
43\% \times T = 12
\]
5. Convert 43% to a decimal:
\[
0.43 \times T = 12
\]
6. Solve for \( T \):
\[
T = \frac{12}{0.43}
\]
7. Perform the division:
\[
T \approx 27.91
\]
Since the number of tools must be a whole number, we round to the nearest whole number:
\[
T = 28
\]

#### Final Answer:
\[
\boxed{28}
\]

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Final Answers:

1. \(\boxed{33.55\%}\)
2. \(\boxed{58}\)
3. \(\boxed{40\%, \frac{4}{10}}\)
4. \(\boxed{88}\)
5. \(\boxed{28}\)