Let’s solve Problem 1 step by step.
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Problem 1:
> A large pizza at Palanzio’s Pizzeria costs $6.80 plus $0.90 for each topping.
> The cost of a large cheese pizza at Guido’s Pizza is $7.30 plus $0.65 for each topping.
> How many toppings need to be added to a large cheese pizza from Palanzio’s Pizzeria and Guido’s Pizza in order for the pizzas to cost the same, not including tax?
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Step 1: Define variables
Let
t = number of toppings on each pizza (we’re assuming both pizzas have the same number of toppings — that’s what “in order for the pizzas to cost the same” implies).
We want to find
t such that:
Cost at Palanzio’s = Cost at Guido’s
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Step 2: Write equations
Palanzio’s cost:
Base price + per topping × number of toppings →
P(t) = 6.80 + 0.90t
Guido’s cost:
Base price + per topping × number of toppings →
G(t) = 7.30 + 0.65t
Set them equal:
6.80 + 0.90t = 7.30 + 0.65t
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Step 3: Solve the equation
Subtract 0.65t from both sides:
→ 6.80 + 0.25t = 7.30
Subtract 6.80 from both sides:
→ 0.25t = 0.50
Divide both sides by 0.25:
→ t = 0.50 / 0.25 =
2
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Step 4: Check your answer
Plug t = 2 back into both original equations.
Palanzio’s: 6.80 + 0.90×2 = 6.80 + 1.80 =
$8.60
Guido’s: 7.30 + 0.65×2 = 7.30 + 1.30 =
$8.60
✔ They match! So 2 toppings make the prices equal.
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Final Answer:
2
Parent Tip: Review the logic above to help your child master the concept of word problems for systems of equations worksheet.