Comparing Fractions Word Problems: Level 1 | Interactive Worksheet ... - Free Printable

Problem: Comparing Fractions Word Problems (Level 1)

We are tasked with solving each word problem by comparing fractions. Let's go through each problem step by step.

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#### Problem 1:
Bella and Jude are reading the same book about penguins. Bella has read \( \frac{3}{4} \) of the book. Jude has read \( \frac{2}{3} \) of the book. Who has read more?

Solution:
To compare \( \frac{3}{4} \) and \( \frac{2}{3} \), we need a common denominator. The least common denominator (LCD) of 4 and 3 is 12.

- Convert \( \frac{3}{4} \) to a fraction with a denominator of 12:
\[
\frac{3}{4} = \frac{3 \times 3}{4 \times 3} = \frac{9}{12}
\]

- Convert \( \frac{2}{3} \) to a fraction with a denominator of 12:
\[
\frac{2}{3} = \frac{2 \times 4}{3 \times 4} = \frac{8}{12}
\]

Now compare \( \frac{9}{12} \) and \( \frac{8}{12} \):
\[
\frac{9}{12} > \frac{8}{12}
\]

Thus, Bella has read more of the book.

Answer: Bella

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#### Problem 2:
Ben and Jake shared a pepperoni pizza. Ben ate \( \frac{5}{8} \) of the pizza. Jake ate \( \frac{3}{5} \) of the pizza. Who ate less?

Solution:
To compare \( \frac{5}{8} \) and \( \frac{3}{5} \), we need a common denominator. The least common denominator (LCD) of 8 and 5 is 40.

- Convert \( \frac{5}{8} \) to a fraction with a denominator of 40:
\[
\frac{5}{8} = \frac{5 \times 5}{8 \times 5} = \frac{25}{40}
\]

- Convert \( \frac{3}{5} \) to a fraction with a denominator of 40:
\[
\frac{3}{5} = \frac{3 \times 8}{5 \times 8} = \frac{24}{40}
\]

Now compare \( \frac{25}{40} \) and \( \frac{24}{40} \):
\[
\frac{25}{40} > \frac{24}{40}
\]

Thus, Jake ate less of the pizza.

Answer: Jake

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#### Problem 3:
Hanna and Emily are running a race. Hanna has finished \( \frac{7}{10} \) of the race. Emily has finished \( \frac{3}{5} \) of the race. Who has finished more of the race?

Solution:
To compare \( \frac{7}{10} \) and \( \frac{3}{5} \), we need a common denominator. The least common denominator (LCD) of 10 and 5 is 10.

- \( \frac{7}{10} \) is already in terms of 10.
- Convert \( \frac{3}{5} \) to a fraction with a denominator of 10:
\[
\frac{3}{5} = \frac{3 \times 2}{5 \times 2} = \frac{6}{10}
\]

Now compare \( \frac{7}{10} \) and \( \frac{6}{10} \):
\[
\frac{7}{10} > \frac{6}{10}
\]

Thus, Hanna has finished more of the race.

Answer: Hanna

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#### Problem 4:
Chase and Ashley are painting pictures in art class. Chase has completed \( \frac{2}{3} \) of his painting. Ashley has completed \( \frac{3}{5} \) of her painting. Who has completed more of their painting?

Solution:
To compare \( \frac{2}{3} \) and \( \frac{3}{5} \), we need a common denominator. The least common denominator (LCD) of 3 and 5 is 15.

- Convert \( \frac{2}{3} \) to a fraction with a denominator of 15:
\[
\frac{2}{3} = \frac{2 \times 5}{3 \times 5} = \frac{10}{15}
\]

- Convert \( \frac{3}{5} \) to a fraction with a denominator of 15:
\[
\frac{3}{5} = \frac{3 \times 3}{5 \times 3} = \frac{9}{15}
\]

Now compare \( \frac{10}{15} \) and \( \frac{9}{15} \):
\[
\frac{10}{15} > \frac{9}{15}
\]

Thus, Chase has completed more of his painting.

Answer: Chase

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#### Problem 5:
Olivia and Claire planted flowers in their garden. Olivia planted \( \frac{3}{4} \) of the flowers, and Claire planted \( \frac{1}{2} \) of the flowers. Who planted fewer flowers?

Solution:
To compare \( \frac{3}{4} \) and \( \frac{1}{2} \), we need a common denominator. The least common denominator (LCD) of 4 and 2 is 4.

- \( \frac{3}{4} \) is already in terms of 4.
- Convert \( \frac{1}{2} \) to a fraction with a denominator of 4:
\[
\frac{1}{2} = \frac{1 \times 2}{2 \times 2} = \frac{2}{4}
\]

Now compare \( \frac{3}{4} \) and \( \frac{2}{4} \):
\[
\frac{3}{4} > \frac{2}{4}
\]

Thus, Claire planted fewer flowers.

Answer: Claire

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#### Problem 6:
Pablo and Kyle each bought a bag of popcorn at the movies. Pablo ate \( \frac{5}{6} \) of his popcorn. Kyle ate \( \frac{2}{3} \) of his popcorn. Who ate less popcorn?

Solution:
To compare \( \frac{5}{6} \) and \( \frac{2}{3} \), we need a common denominator. The least common denominator (LCD) of 6 and 3 is 6.

- \( \frac{5}{6} \) is already in terms of 6.
- Convert \( \frac{2}{3} \) to a fraction with a denominator of 6:
\[
\frac{2}{3} = \frac{2 \times 2}{3 \times 2} = \frac{4}{6}
\]

Now compare \( \frac{5}{6} \) and \( \frac{4}{6} \):
\[
\frac{5}{6} > \frac{4}{6}
\]

Thus, Kyle ate less popcorn.

Answer: Kyle

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Final Answers:

1. Bella
2. Jake
3. Hanna
4. Chase
5. Claire
6. Kyle

Boxed Final Answer:
\[
\boxed{\text{Bella, Jake, Hanna, Chase, Claire, Kyle}}
\]