Work and Power Part 1 worksheet - Free Printable

Let's solve each problem step by step using the formulas provided in the worksheet.

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Problem 1: Joseph sweeping leaves

Given:
- Force (F) = 2.0 N
- Distance (d) = 3 meters
- Time (t) = 12 seconds

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#### Part A: Calculate mechanical work performed on the leaves

Use the formula for linear work:
> W = F · d

Substitute the values:
> W = 2.0 N × 3 m = 6.0 Joules

✔ Answer: 6.0 J

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#### Part B: Calculate the power used to push the leaves

Use the formula for power:
> P = W / t

We just found W = 6.0 J, and t = 12 s.

> P = 6.0 J / 12 s = 0.5 Watts

✔ Answer: 0.5 W

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Problem 2: Tractor pulling a hay wagon

Given:
- Force (F) = 500 N
- Distance (d) = 2000 meters
- Time (t) = 5 minutes → must convert to seconds!

> 5 minutes × 60 seconds/minute = 300 seconds

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#### Part A: Calculate the work performed on the hay wagon

Use the formula:
> W = F · d

> W = 500 N × 2000 m = 1,000,000 Joules

(You can also write this as 1 × 10⁶ J or 1 MJ, but since the question asks for Joules, we’ll keep it as 1,000,000 J)

✔ Answer: 1,000,000 J

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#### Part B: Calculate the power used to pull the hay wagon

Use the formula:
> P = W / t

> P = 1,000,000 J / 300 s ≈ 3333.33 Watts

(Rounded to two decimal places, or you can leave it as a fraction: 1000000/300 = 10000/3 ≈ 3333.33)

✔ Answer: 3333.33 W

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## ✔ Final Answers:

Problem 1:

- Work = 6.0 J
- Power = 0.5 W

Problem 2:

- Work = 1,000,000 J
- Power = 3333.33 W

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💡 Key Concepts Reminder:
- Work is force times distance (when force is parallel to displacement).
- Power is how fast work is done — work divided by time.
- Always check units — especially converting minutes to seconds for power calculations!

Let me know if you’d like to see these explained with diagrams or real-world analogies!