IXL - Identify medians, altitudes, angle bisectors, and ... - Free Printable

Let’s think through this step by step.

We are given a diagram with points B, C, D on a straight vertical line (so they’re colinear), and point A off to the side. We have segments:

- BC = 82
- CD = 60
- So BD = BC + CD = 82 + 60 = 142

Point C is between B and D.

Segment AC connects point A to point C.

Now, we are asked: Which term describes segment AC?

Options:
- altitude
- angle bisector
- median
- none of these

Let’s recall what each term means in geometry:

🔹 Altitude – a perpendicular segment from a vertex to the opposite side (or its extension).
→ Is AC perpendicular to BD? The diagram doesn’t show any right angle symbol, and there’s no indication that AC ⊥ BD. So probably not an altitude.

🔹 Angle bisector – a ray or segment that splits an angle into two equal angles.
→ For AC to be an angle bisector, it would need to split ∠BAD (or some other angle at A) into two equal parts. But we don’t have any information about angles being equal — no markings, no measurements. So unlikely.

🔹 Median – a segment from a vertex to the midpoint of the opposite side.
→ In triangle ABD, if C were the midpoint of BD, then AC would be a median.

But let’s check:
BD = 142 → midpoint would be at 71 from either end.

C is located such that:
- From B to C: 82
- From C to D: 60

So C is NOT the midpoint — because 82 ≠ 60, and also 82 ≠ 71.

Therefore, AC is not a median.

Since AC is not an altitude, not an angle bisector, and not a median…

✔ The correct answer must be: none of these

Final Answer:
none of these