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Area and Perimeter Worksheets - Free Printable

Area and Perimeter Worksheets

Educational worksheet: Area and Perimeter Worksheets. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Area and Perimeter Worksheets
Let’s solve each problem one by one. We’ll find both the area and perimeter for each composite shape.

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Problem 1:



Shape is like a “U” made of rectangles.

We can split it into 3 parts:
- Left rectangle: width = ? , height = 43 cm
- Bottom rectangle: width = 26 cm, height = ?
- Right rectangle: same as left? Let’s figure out missing sides.

Actually, better way: think of it as a big rectangle with a piece cut out from the top middle.

Big outer rectangle would be:
Width = 44 cm (given at bottom)
Height = 43 cm (left side)

But there’s a gap in the top middle: width = 26 cm, depth = 30 cm (so the top part is missing a rectangle of 26 cm × 30 cm).

Wait — actually, looking again: the vertical sides are 43 cm tall. The inner horizontal part is 26 cm long, and the drop-down from top to that inner part is 30 cm. So the top arms must be 43 - 30 = 13 cm tall.

So we can break it into:
- Two side rectangles: each 13 cm high × ? wide
- One bottom rectangle: 26 cm wide × 30 cm high? Wait no.

Better approach: use the full outline.

Total width = 44 cm
Inner gap width = 26 cm → so each side arm width = (44 - 26)/2 = 9 cm

Each side arm: 9 cm wide × 43 cm tall → area = 9×43 = 387 cm² each → total for two = 774 cm²

Bottom connecting part: 26 cm wide × (43 - 30) = 26 × 13 = 338 cm²? Wait no — that doesn’t make sense because the 30 cm is the depth of the U, meaning the bottom part is only 30 cm up from bottom? Actually, let's reorient.

Actually, the shape has:
- Total height = 43 cm
- The "cutout" goes down 30 cm from the top → so the bottom slab is 43 - 30 = 13 cm thick.
- The bottom slab spans full 44 cm? No — wait, the inner horizontal line is labeled 26 cm — that’s the width of the opening at the top of the U.

Actually, standard way: this is a rectangle 44 cm wide × 43 cm tall, minus a rectangle 26 cm wide × 30 cm tall cut out from the top center.

Yes! That makes sense.

So:

Area = Big rectangle - Cutout rectangle
= (44 × 43) - (26 × 30)
= 1892 - 780 = 1112 cm²

Perimeter: trace all outer edges.

Start at bottom left corner:
→ right 44 cm
→ up 43 cm
→ left 9 cm (since 44 - 26 = 18, divided by 2 = 9 on each side)
→ down 30 cm
→ left 26 cm
→ down 13 cm (because 43 - 30 = 13)
→ left 9 cm
→ down? Wait no — we’re going around.

Actually, better to list all segments:

Top: two horizontal pieces: each 9 cm (left and right arms) → total top horizontal = 9 + 9 = 18 cm? But they’re not connected — perimeter includes the inner edges too!

Important: Perimeter includes ALL outer boundaries — including the inside of the U.

So path:

Start at bottom-left corner:
1. Right along bottom: 44 cm
2. Up right side: 43 cm
3. Left along top-right arm: 9 cm
4. Down inner right side: 30 cm
5. Left along bottom of cutout: 26 cm
6. Up inner left side: 30 cm
7. Left along top-left arm: 9 cm
8. Down left side: 43 cm ← but wait, we already went up 43 on right, now down 43 on left? That would double count.

No — let’s draw mentally:

The shape has:
- Outer frame: bottom 44, left 43, right 43, top has two segments: left 9, right 9 (total top outer = 18)
- Plus inner U: down 30, across 26, up 30

So perimeter =
bottom: 44
right side: 43
top right arm: 9
inner right drop: 30
inner bottom: 26
inner left rise: 30
top left arm: 9
left side: 43

Add them:
44 + 43 + 9 + 30 + 26 + 30 + 9 + 43 = let’s compute:

44 + 43 = 87
87 + 9 = 96
96 + 30 = 126
126 + 26 = 152
152 + 30 = 182
182 + 9 = 191
191 + 43 = 234 cm

Area = 1112 cm², Perimeter = 234 cm

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Problem 2:



L-shaped figure.

Given:
Top width = 101 cm
Right height = 98 cm
Left part: bottom segment 30 cm, then up 39 cm? Wait labels:

It says:
- Top: 101 cm
- Right side: 98 cm
- Bottom left: 30 cm (horizontal), then up 39 cm (vertical) — so the L has a notch.

Actually, it’s a rectangle with a smaller rectangle cut out from bottom left.

Full rectangle would be 101 cm wide × 98 cm tall.

Cutout: width = 30 cm, height = 39 cm? But wait — if you go up 39 cm from bottom on the left, and the total height is 98, then the remaining height on the right is 98 - 39 = 59 cm? Not matching.

Looking at diagram description:

The shape has:
- Top edge: 101 cm
- Right edge: 98 cm
- Then from bottom right, going left: some length, then up 39 cm, then left 30 cm to meet left side.

Actually, standard L-shape: imagine a big rectangle 101x98, and we remove a rectangle from bottom left of size 30 cm (width) by (98 - 39) = 59 cm? No.

Wait — the vertical segment labeled 39 cm is on the left side, starting from bottom. So from bottom left, you go right 30 cm, then up 39 cm, then right to meet the main body.

That means the cutout is 30 cm wide and (98 - 39) = 59 cm tall? But that doesn't fit.

Alternative: the shape consists of two rectangles:

Rectangle A (top): width 101 cm, height = 98 - 39 = 59 cm?
Rectangle B (bottom right): width = 101 - 30 = 71 cm, height = 39 cm

Check: total height on right is 59 + 39 = 98 cm — good.
Total width on top is 101 cm — good.
On bottom, only 71 cm is present (since 30 cm is missing on left).

So area = area of top rect + area of bottom rect
= (101 × 59) + (71 × 39)

Calculate:

101 × 59 = 101 × 60 - 101 = 6060 - 101 = 5959
71 × 39 = 70×39 + 1×39 = 2730 + 39 = 2769
Total area = 5959 + 2769 = 8728 cm²

Perimeter: trace outer edge.

Start at top-left:
→ right 101 cm
→ down 98 cm
→ left 71 cm (since bottom right part is 71 cm wide)
→ up 39 cm
→ left 30 cm
→ up 59 cm (to close to start) — wait, from where?

After going left 30 cm, you're at bottom-left corner? Then up 39 cm gets you to the inner corner, then you need to go up another 59 cm to reach top? But that would be internal.

Actually, perimeter path:

Start at top-left corner:
1. Right 101 cm (top)
2. Down 98 cm (right side)
3. Left 71 cm (bottom of right part)
4. Up 39 cm (inner vertical)
5. Left 30 cm (bottom of left part)
6. Up 59 cm (left side) — since 98 - 39 = 59, yes
Back to start.

So segments: 101, 98, 71, 39, 30, 59

Sum:
101 + 98 = 199
199 + 71 = 270
270 + 39 = 309
309 + 30 = 339
339 + 59 = 398 cm

Area = 8728 cm², Perimeter = 398 cm

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Problem 3:



T-shaped or inverted T? Looks like a rectangle on top of a smaller rectangle.

Top part: 52 cm wide × 65 cm tall? Wait no — label says 52 cm on top, 65 cm on left side — but then below that, a stem: 28 cm wide? And 21 cm tall? Labels:

From diagram:
- Top rectangle: width 52 cm, height ? — actually, the 65 cm is the total height of the top part? No.

Looking: the left side has 65 cm, which is the height of the upper block. Then below it, a narrower block: width 28 cm? But it says 28 cm and 21 cm — probably the stem is 28 cm wide and 21 cm tall? But 28 cm is less than 52, so centered?

Actually, likely: the shape is composed of:
- Upper rectangle: 52 cm wide × 65 cm high
- Lower rectangle (stem): 28 cm wide × 21 cm high, attached below the center of the upper one.

But then total height = 65 + 21 = 86 cm

Area = (52 × 65) + (28 × 21)

Calculate:

52 × 65: 50×65 = 3250, 2×65=130 → 3380
28 × 21: 28×20=560, 28×1=28 → 588
Total area = 3380 + 588 = 3968 cm²

Perimeter: trace outer boundary.

Start at top-left:
→ right 52 cm
→ down 65 cm
→ left (52 - 28)/2 = 12 cm (overhang on right)
→ down 21 cm
→ left 28 cm
→ up 21 cm
→ left 12 cm (overhang on left)
→ up 65 cm back to start? No — after going up 21 cm on left side of stem, you're at the bottom of the upper rectangle, then you go left 12 cm to the left edge, then up 65 cm.

Segments:

1. Top: 52
2. Right side down: 65
3. Right overhang inward: 12 (since (52-28)/2 = 12)
4. Stem right side down: 21
5. Bottom of stem: 28
6. Stem left side up: 21
7. Left overhang outward: 12
8. Left side up: 65

Sum: 52 + 65 + 12 + 21 + 28 + 21 + 12 + 65

Compute step by step:

52 + 65 = 117
117 + 12 = 129
129 + 21 = 150
150 + 28 = 178
178 + 21 = 199
199 + 12 = 211
211 + 65 = 276 cm

Area = 3968 cm², Perimeter = 276 cm

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Problem 4:



Similar to problem 3, but different dimensions.

Top part: 27 cm wide, 18 cm high? Label says 27 cm on top, 18 cm on left side of top part. Then stem: 27 cm high? And 16 cm wide.

Wait — labels:
- Top: 27 cm (width)
- Left side of top: 18 cm (height)
- Stem: 27 cm (height)? And 16 cm (width)

Probably: upper rectangle 27 cm × 18 cm, lower rectangle (stem) 16 cm × 27 cm, attached below center.

Total height = 18 + 27 = 45 cm

Area = (27 × 18) + (16 × 27)

Note: factor out 27: 27 × (18 + 16) = 27 × 34

27 × 34 = 27×30 + 27×4 = 810 + 108 = 918 cm²

Perimeter: similar to before.

Overhang on each side: (27 - 16)/2 = 11/2 = 5.5 cm

Path:

Start top-left:
→ right 27
→ down 18
→ left 5.5 (overhang)
→ down 27 (stem)
→ left 16
→ up 27
→ left 5.5
→ up 18

Segments: 27, 18, 5.5, 27, 16, 27, 5.5, 18

Sum:
27+18=45
45+5.5=50.5
50.5+27=77.5
77.5+16=93.5
93.5+27=120.5
120.5+5.5=126
126+18= 144 cm

Area = 918 cm², Perimeter = 144 cm

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Problem 5:



Units are yards (yd). Shape is L-shaped.

Labels:
- Left side: 35 yd (vertical)
- Bottom: 18 yd (horizontal)
- Then up 5 yd, then right 25 yd? Wait.

Diagram description:
It’s an L-shape standing vertically.

From bottom-left:
→ right 18 yd
→ up 5 yd
→ right ? to meet the main body
→ up 25 yd? Total height on right is 35 yd? Since left is 35, and we went up 5, then up 25 more? 5+25=30, not 35.

Wait — labels say:
- Vertical left: 35 yd
- Horizontal bottom: 18 yd
- Then a small step: up 5 yd, then right to connect, and the right side is 25 yd? But 25 + 5 = 30 ≠ 35.

Perhaps the 25 yd is the height of the right part, and the total height is 35, so the bottom part height is 35 - 25 = 10 yd? But it says up 5 yd.

I think I misread. Looking back:

User wrote: "5) [shape] 35 yd, 25 yd, 5 yd, 18 yd"

Probably: the shape has:
- Full height on left: 35 yd
- On the right, from bottom, up 25 yd, then left to meet, but there's a notch.

Standard interpretation: it's a rectangle 18 yd wide × 35 yd tall, with a rectangle cut out from top right of size ?

Alternatively, compose of two rectangles:

Rectangle A (left): width = ? , height = 35 yd
Rectangle B (bottom right): width = 18 - ? , height = 5 yd?

Notice: from bottom, you go right 18 yd, then up 5 yd, then right? No — likely, after going up 5 yd, you go left to connect to the main column.

Assume the main column is on the left, width W, height 35 yd. Then attached to its bottom right, a rectangle extending right: width X, height 5 yd, and total bottom width is 18 yd, so W + X = 18.

Also, the right side of the bottom extension is 25 yd? That doesn't match.

Another way: the vertical dimension on the right is 25 yd, meaning from bottom to the top of the lower part is 25 yd? But left is 35, so difference is 10 yd.

Perhaps the 25 yd is the height of the right arm, and the 5 yd is the thickness of the bottom.

Let me define:

The shape can be seen as:
- A large rectangle: 18 yd wide × 35 yd tall
- Minus a rectangle cut out from top right: width = 18 - W, height = 35 - 25 = 10 yd? But we have 5 yd mentioned.

Labels given: 35 yd (left height), 25 yd (right height?), 5 yd (step up), 18 yd (bottom width)

Probably: from bottom-left, go right 18 yd, up 5 yd, then left (18 - something) to meet the left column, then up to 35 yd.

And the right side from bottom to the step is 5 yd, then from there up to top is 25 yd? 5 + 25 = 30, but left is 35 — inconsistency.

Unless the 25 yd is not a height but a width? User said "25 yd" next to the right vertical side.

Re-examining user input: "5) [shape] 35 yd, 25 yd, 5 yd, 18 yd"

In many such problems, for an L-shape like this, it's often:

- The vertical leg: height 35 yd, width say A
- The horizontal leg: length 18 yd, height 5 yd, but overlapping.

Common configuration: the shape has overall width 18 yd, overall height 35 yd, and the "notch" is such that the right part has height 25 yd, so the bottom part has height 35 - 25 = 10 yd, but it says 5 yd.

Perhaps the 5 yd is the width of the vertical leg.

Let's assume:

The shape is made of:
- Left rectangle: width 5 yd, height 35 yd
- Bottom rectangle: width 18 - 5 = 13 yd, height 5 yd? But then the right side would be only 5 yd high, not 25.

I think there's a mistake in my assumption.

Another idea: the 25 yd is the length of the top horizontal part.

Let's look for symmetry or standard problems.

Perhaps: the shape is like a backwards L.

From top-left:
→ right 25 yd (top)
→ down 35 yd (right side)
→ left 18 yd (bottom)
→ up 5 yd
→ left (25 - 18) = 7 yd
→ up 30 yd? Not matching.

Let's calculate based on common sense.

Suppose the shape has:
- Total width = 18 yd
- Total height = 35 yd
- The cutout is at top right: width = 18 - A, height = 35 - B

But we have numbers 25 and 5.

Notice that 35 - 25 = 10, and 18 - 5 = 13, not helpful.

Perhaps the 5 yd is the height of the bottom part, and 25 yd is the width of the top part.

Let me try this composition:

Rectangle 1 (bottom): 18 yd wide × 5 yd high
Rectangle 2 (left top): width = 18 - C, height = 30 yd? But 5 + 30 = 35.

If the right part of the top is missing, and the remaining top part has width 25 yd? But 25 > 18, impossible.

I think I found it: in some diagrams, for problem 5, it's an L-shape where the vertical part is 35 yd tall and 5 yd wide, and the horizontal part is 18 yd long and 5 yd high, but they overlap in a 5x5 square.

So area = area of vertical rect + area of horizontal rect - overlap

Vertical: 5 yd × 35 yd = 175 yd²
Horizontal: 18 yd × 5 yd = 90 yd²
Overlap: 5 yd × 5 yd = 25 yd² (since they share the corner)

So area = 175 + 90 - 25 = 240 yd²

Perimeter: when you join them, you lose two sides of the overlap.

Original perimeters:
Vertical rect: 2*(5+35) = 80 yd
Horizontal rect: 2*(18+5) = 46 yd
Total without joining: 80 + 46 = 126 yd
When joined, you remove two sides of 5 yd each (the overlapping edges), so subtract 2*5 = 10 yd
Perimeter = 126 - 10 = 116 yd

But let's verify with tracing.

Start at top-left of vertical part:
→ right 5 yd (top of vertical)
→ down 35 yd (right side of vertical)
→ right 13 yd (since horizontal extends 18 - 5 = 13 yd to the right)
→ up 5 yd (right end of horizontal)
→ left 18 yd (bottom of horizontal)
→ up 30 yd? No, from bottom-left, after going left 18 yd, you're at bottom-left corner, then up 35 yd, but we already did down 35.

Better path:

Start at top-left corner of the entire shape (top of vertical part):
1. Right 5 yd (along top of vertical leg)
2. Down 35 yd (down right side of vertical leg) — now at bottom-right of vertical leg
3. Right 13 yd (along bottom of horizontal leg, since total bottom is 18, minus 5 already covered)
4. Up 5 yd (up right end of horizontal leg)
5. Left 18 yd (along top of horizontal leg) — but this would go over the vertical leg.

Mistake.

Correct path for L-shape with vertical leg 5x35 and horizontal leg 18x5 attached at bottom-left:

The horizontal leg is attached to the bottom of the vertical leg, extending to the right.

So the shape has:
- From top-left: down 35 yd (left side)
- Right 5 yd (bottom of vertical leg)
- Right 13 yd (extension of horizontal leg, total bottom 18 yd)
- Up 5 yd (right side of horizontal leg)
- Left 18 yd (top of horizontal leg) — but this top of horizontal leg is at height 5 yd, while the vertical leg goes up to 35 yd, so from here, you need to go up 30 yd to reach the top, but that's internal.

Actually, after going left 18 yd on the top of the horizontal leg, you're at the left end, which is also the bottom of the vertical leg, so then you go up 35 yd, but you already went down 35 yd at the beginning.

This is confusing.

Standard way for such L-shape:

The outer perimeter consists of:
- Left side: 35 yd
- Bottom: 18 yd
- Right side of horizontal part: 5 yd
- Top of horizontal part: 18 yd? No.

Let's define coordinates.

Set bottom-left corner as (0,0).

Then:
- Vertical leg: from (0,0) to (0,35) to (5,35) to (5,0) — but that's a rectangle.

For L-shape with vertical leg on left and horizontal leg on bottom:

- Points: (0,0), (18,0), (18,5), (5,5), (5,35), (0,35), back to (0,0)

Yes! That makes sense.

So vertices:
A(0,0), B(18,0), C(18,5), D(5,5), E(5,35), F(0,35), back to A(0,0)

Now, perimeter is sum of distances between consecutive points.

AB: 18 - 0 = 18 yd (bottom)
BC: 5 - 0 = 5 yd (up)
CD: 5 - 18 = -13, abs 13 yd (left)
DE: 35 - 5 = 30 yd (up)
EF: 0 - 5 = -5, abs 5 yd (left)
FA: 0 - 35 = -35, abs 35 yd (down) — but from F(0,35) to A(0,0) is down 35 yd.

Segments: AB=18, BC=5, CD=13, DE=30, EF=5, FA=35

Sum: 18+5=23; 23+13=36; 36+30=66; 66+5=71; 71+35= 106 yd

Area: can be calculated as area of rectangle 18x5 plus rectangle 5x30 (since from y=5 to y=35, width 5)

Rectangle 1 (bottom): 18 * 5 = 90 yd²
Rectangle 2 (left top): 5 * 30 = 150 yd² (height 35-5=30)
Total area = 90 + 150 = 240 yd²

Yes, matches earlier calculation.

And the 25 yd? In the user input, it says "25 yd" — perhaps it's a typo or I misread. In the diagram, maybe the 25 yd is the height from bottom to the top of the horizontal part or something, but in our calculation, we have 35 and 5, and 18, and we got consistent answer.

Perhaps the 25 yd is the length of the top of the vertical part, but in our case, it's 5 yd.

Another possibility: in some versions, the horizontal leg is 25 yd long, but here it's given as 18 yd.

Given the numbers, and that 35, 18, 5 are used, and 25 might be a distractor or for another part, but in the user's text, it's listed as "35 yd, 25 yd, 5 yd, 18 yd", so perhaps the 25 yd is the height of the right part.

In our coordinate system, from (5,0) to (5,5) is 5 yd, then to (5,35) is 30 yd, not 25.

Perhaps the shape is different.

Let's assume that the 25 yd is the height of the vertical leg on the right, but in an L-shape, usually one leg is taller.

Perhaps it's a different orientation.

Another common type: the shape has a base of 18 yd, height 35 yd on left, and on the right, from bottom, up 25 yd, then left to meet, and the step is 5 yd high.

So from bottom-left (0,0) to (18,0) to (18,25) to (X,25) to (X,35) to (0,35) back to (0,0)

Then the step up is from y=25 to y=35, so 10 yd, but it says 5 yd.

Unless the 5 yd is the width of the step.

Suppose from (18,0) up to (18,25), then left to (18-5,25) = (13,25), then up to (13,35), then left to (0,35), down to (0,0).

Then the "5 yd" is the horizontal step.

So vertices: A(0,0), B(18,0), C(18,25), D(13,25), E(13,35), F(0,35), back to A(0,0)

Now, segments:
AB: 18
BC: 25
CD: 5 (left)
DE: 10 (up, 35-25=10)
EF: 13 (left, 13-0=13)
FA: 35 (down)

Sum: 18+25=43; 43+5=48; 48+10=58; 58+13=71; 71+35= 106 yd same as before.

Area: can be split into:
- Rectangle 18x25 = 450
- Rectangle 13x10 = 130 (from x=0 to 13, y=25 to 35)
But wait, from x=0 to 13, y=0 to 35 is included, but we have from y=0 to 25 for x=0 to 18, and y=25 to 35 for x=0 to 13.

So area = area of bottom rectangle 18*25 = 450
Plus top rectangle 13*10 = 130
Total 580 yd²

But we have the 5 yd mentioned, which is used in CD=5.

In this case, the left side is 35 yd, bottom 18 yd, right side has 25 yd up, then 5 yd left, then 10 yd up, etc.

But the user has "5 yd" and "25 yd", so this fits.

However, in the first interpretation, we had area 240, here 580, big difference.

Which one is correct? Probably the second one, because 25 yd is given as a height.

In the user's message, for problem 5, it's "35 yd, 25 yd, 5 yd, 18 yd", and in many worksheets, for such a shape, it's common to have the right height as 25 yd, and the step as 5 yd wide.

Moreover, in the first interpretation, we didn't use the 25 yd, which is suspicious.

So let's go with this:

Vertices: (0,0), (18,0), (18,25), (13,25), (13,35), (0,35), (0,0)

Perimeter: as above, 18 + 25 + 5 + 10 + 13 + 35 = let's calculate again:

18 (AB)
+25 (BC) = 43
+5 (CD) = 48
+10 (DE) = 58
+13 (EF) = 71
+35 (FA) = 106 yd

Area:
- Rectangle from x=0 to 18, y=0 to 25: 18*25 = 450
- Rectangle from x=0 to 13, y=25 to 35: 13*10 = 130
Total area = 450 + 130 = 580 yd²

But is the top rectangle from x=0 to 13? Yes, because from (0,25) to (13,25) to (13,35) to (0,35).

Yes.

So area = 580 yd², perimeter = 106 yd

But earlier with the other interpretation, we had 240, which is half, so likely this is correct.

To confirm, the "5 yd" is the width of the step (CD=5), "25 yd" is the height of the right part (BC=25), "35 yd" is total height (FA=35), "18 yd" is bottom width (AB=18).

Perfect.

Area = 580 yd², Perimeter = 106 yd

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Problem 6:



Units inches (in). Shape is like a rectangle with a bite taken out from bottom right.

Labels:
- Top: 111 in
- Left: 42 in
- Bottom left: 18 in (vertical? or horizontal?)
- Bottom: 66 in (horizontal)

From diagram description:
It's a rectangle with a rectangular notch at bottom right.

Full rectangle: 111 in wide × 42 in tall.

Notch: from bottom right, left 66 in? But 66 < 111, so the notch width is 111 - 66 = 45 in? And height 18 in.

Labels: "18 in" is likely the height of the notch, "66 in" is the width of the bottom part after notch.

So, the shape has:
- Overall width 111 in, height 42 in.
- At bottom right, a rectangle cut out: width = 111 - 66 = 45 in, height = 18 in.

So area = big rectangle - cutout = (111 × 42) - (45 × 18)

Calculate:

111 × 42 = 100×42 = 4200, 11×42=462, total 4662
45 × 18 = 40×18=720, 5×18=90, total 810
Area = 4662 - 810 = 3852 in²

Perimeter: trace outer edge.

Start at top-left:
→ right 111 in
→ down 42 in
→ left 66 in (bottom of right part)
→ up 18 in (inner vertical)
→ left 45 in (bottom of cutout)
→ up 24 in (since 42 - 18 = 24, to reach top)
→ left? No, from there, you're at the left side of the cutout, then you need to go left to the left edge, but you're already at x=66, and left edge is x=0, so left 66 in? But that would be internal.

Vertices:
Assume bottom-left (0,0), top-right (111,42)

Cutout at bottom right: from (66,0) to (111,0) to (111,18) to (66,18) back to (66,0)? But then the shape is from (0,0) to (111,0) to (111,18) to (66,18) to (66,42) to (0,42) back to (0,0)

Yes.

So points: A(0,0), B(111,0), C(111,18), D(66,18), E(66,42), F(0,42), back to A(0,0)

Segments:
AB: 111 - 0 = 111 in (bottom)
BC: 18 - 0 = 18 in (up)
CD: 66 - 111 = -45, abs 45 in (left)
DE: 42 - 18 = 24 in (up)
EF: 0 - 66 = -66, abs 66 in (left)
FA: 0 - 42 = -42, abs 42 in (down)

Sum: 111 + 18 = 129; 129 + 45 = 174; 174 + 24 = 198; 198 + 66 = 264; 264 + 42 = 306 in

Area we have 3852 in²

Area = 3852 in², Perimeter = 306 in

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Now, compiling all answers:

1) Area = 1112 cm², Perimeter = 234 cm
2) Area = 8728 cm², Perimeter = 398 cm
3) Area = 3968 cm², Perimeter = 276 cm
4) Area = 918 cm², Perimeter = 144 cm
5) Area = 580 yd², Perimeter = 106 yd
6) Area = 3852 in², Perimeter = 306 in

Final Answer:
1) Area: 1112 cm², Perimeter: 234 cm
2) Area: 8728 cm², Perimeter: 398 cm
3) Area: 3968 cm², Perimeter: 276 cm
4) Area: 918 cm², Perimeter: 144 cm
5) Area: 580 yd², Perimeter: 106 yd
6) Area: 3852 in², Perimeter: 306 in
Parent Tip: Review the logic above to help your child master the concept of worksheet for area.
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Geometry Worksheets | Area Worksheets
Area Worksheets
Area Worksheets
Area of 2D Shapes Worksheets | K5 Learning
Area Worksheets
Area of 2D shapes Worksheet | Cazoom Maths Worksheets
Area of Rectangles | 3rd Grade PDF Measurement Worksheets
Area by Counting Squares (A) | 3rd Grade PDF Measurement Worksheets
Area Worksheets
Area and Perimeter | Christal | Live Worksheets