Second Grade Worksheets for Language-Learning Fun - Free Printable

Let’s solve this step by step.

We are given a box of letters:

**a b c d e e f f g
h h i i l m n r
r r s t t t w y**

Total letters: Let’s count — 3 rows × 9 = 27 letters? Wait, let’s list them carefully:

Row 1: a, b, c, d, e, e, f, f, g → 9
Row 2: h, h, i, i, l, m, n, r → wait, that’s only 8? No — looking again at the image layout (even though we can’t describe it), the user provided the text version in the problem. Actually, from the original puzzle description, the letter box is:

> a b c d e e f f g
> h h i i l m n r
> r r s t t t w y

Wait — second row has 8? That doesn’t match. Let me recount based on standard puzzles like this.

Actually, let’s just go word by word and cross off letters as we use them. We’ll keep track.

We have 12 words to complete. Each blank needs one or more letters filled in using the letter bank. After filling all blanks, 5 letters will be left over. Then we unscramble those 5 to form a word that tells us if our answers are correct.

Also, note: “Cross out each letter as you use it.” So we must use exactly the letters in the box — no extras, no repeats beyond what’s available.

Let’s start solving each word.

---

Word 1: g _ r l

Possible word: girl → uses g, i, r, l

Check letter bank:
g ✔
i ✔ (we have two i’s)
r ✔ (multiple r’s)
l ✔

So: girl → uses g, i, r, l

Leftover letters so far: remove one g, one i, one r, one l

Original bank:
a, b, c, d, e, e, f, f, g,
h, h, i, i, l, m, n, r,
r, r, s, t, t, t, w, y

After removing g, i, r, l:

Remaining:
a, b, c, d, e, e, f, f,
h, h, i, m, n, r, r,
s, t, t, t, w, y

(removed one g, one i, one r, one l)

---

Word 2: b o _

Likely: boy → b, o, y

But wait — do we have an ‘o’? Look at original letter bank: there is NO ‘o’ listed!

Original letters: a,b,c,d,e,e,f,f,g,h,h,i,i,l,m,n,r,r,r,s,t,t,t,w,y

No ‘o’! So “boy” is impossible.

What else? “bo_” — maybe “bob”? But we need to check.

Wait — perhaps “b o _” is “bow”? Still needs ‘o’.

Hold on — maybe I misread. Is there an ‘o’? Let me double-check the original letter set provided in the problem:

From user input:

> a b c d e e f f g
> h h i i l m n r
> r r s t t t w y

Still no ‘o’. Hmm.

Alternative: Maybe “b o _” is “bot”? Like robot? But still needs ‘o’.

Wait — perhaps it’s “boo”? As in ghost? But again, needs ‘o’.

This is a problem. Unless... did I miss something?

Wait — look back at the original puzzle instruction: “Each word below names a person.”

So “b o _” must name a person.

Possibilities: boy, bob, ben, bud, etc.

But without ‘o’, how?

Unless… maybe the second letter is not ‘o’? Wait, the puzzle says:

“2. b o _”

It clearly shows “b o _”, meaning first letter b, second letter o, third blank.

But no ‘o’ in letter bank. Contradiction?

Wait — let me re-express the entire letter bank as a single string to count frequencies.

Letters given:

a, b, c, d, e, e, f, f, g,
h, h, i, i, l, m, n, r,
r, r, s, t, t, t, w, y

List with counts:

a:1
b:1
c:1
d:1
e:2
f:2
g:1
h:2
i:2
l:1
m:1
n:1
r:3
s:1
t:3
w:1
y:1

Total: 1+1+1+1+2+2+1+2+2+1+1+1+3+1+3+1+1 = let's add:

Singles: a,b,c,d,g,l,m,n,s,w,y → 11
Doubles: e,f,h,i → 4×2=8
Triples: r,t → 2×3=6
Total: 11+8+6 = 25 letters.

Earlier I thought 27, but actually 25.

Now, for word 2: “b o _” — requires ‘o’, which is NOT in the list. So either:

- The puzzle has a typo? Unlikely.
- Or I misread the word.

Wait — looking back at the user’s transcription:

> 2. b o _

But in the actual image (which we can't see), maybe it’s “b _ _” or something else? But the user wrote “b o _”.

Alternatively, perhaps it’s “b u _”? But user said “b o _”.

Another idea: Maybe “b o _” is meant to be “bro”? Like brother? But that would be “b r o” — still needs ‘o’.

Wait — unless the second letter is not fixed? No, the puzzle format is: some letters given, blanks to fill.

Perhaps it’s “bee”? But that’s not a person.

Or “ben”? B-e-n — that’s a person’s name.

But the puzzle says “b o _”, not “b _ _”.

Unless... maybe the ‘o’ is a mistake in transcription? Or perhaps in the original, it’s “b _ _” and the user typed “b o _” by error?

But we have to work with what’s given.

Wait — let’s skip and come back. Maybe other words will help.

---

Word 3: c h i _ _ r e _

That’s 8 letters: positions 1:c, 2:h, 3:i, 4:_, 5:_, 6:r, 7:e, 8:_

Likely word: children? C-h-i-l-d-r-e-n → yes!

Uses: c, h, i, l, d, r, e, n

Check availability:

c:1 → ok
h:2 → use one
i:2 → use one
l:1 → ok
d:1 → ok
r:3 → use one
e:2 → use one
n:1 → ok

All available.

So “children” → uses c,h,i,l,d,r,e,n

Update remaining letters after previous removals.

Previously after word 1 (girl): removed g,i,r,l

Then now remove c,h,i,d,r,e,n

Current remaining before word 3:

After word 1:
a, b, c, d, e, e, f, f,
h, h, i, m, n, r, r,
s, t, t, t, w, y

Remove for "children": c, h, i, d, r, e, n

So remove:

c: gone
h: was 2, now 1 left
i: was 1 (after girl took one), now 0
d: gone
r: was 2 (after girl took one, originally 3), now 1 left
e: was 2, now 1 left
n: gone

Also, we had m, s, t,t,t, w, y, a, b, f,f, h (one left), r (one left), e (one left)

List current remaining:

a, b, e, f, f, h, m, r, s, t, t, t, w, y

Count: 14 letters left? Let's list:

From earlier post-word1: 21 letters? Original 25 minus 4 used in girl = 21.

Then children uses 8 letters → 21 - 8 = 13 left.

List:

a, b, e, f, f, h, m, r, s, t, t, t, w, y → that’s 14? Inconsistency.

Better to maintain a running tally.

Start fresh with frequency count:

Initial counts:

a:1
b:1
c:1
d:1
e:2
f:2
g:1
h:2
i:2
l:1
m:1
n:1
r:3
s:1
t:3
w:1
y:1

Total: 25

Word 1: girl → g,i,r,l

Subtract:

g:0
i:1 (was 2)
r:2 (was 3)
l:0

Remaining:

a:1
b:1
c:1
d:1
e:2
f:2
h:2
i:1
m:1
n:1
r:2
s:1
t:3
w:1
y:1

Word 3: children → c,h,i,l,d,r,e,n

But l is already 0! Problem.

In word 1, we used 'l' for "girl", so l is gone. But "children" needs 'l'.

Contradiction.

Therefore, "girl" might not be correct? Or "children" not correct?

But both seem obvious.

Alternative for word 1: g_r_l — could it be "garl"? Not a word. "gerl"? No. "gorl"? No. Only "girl" makes sense.

For word 3: chi__re_ — could it be "chickaree"? Too long. "chimerae"? Rare. "children" is most likely.

But conflict on 'l'.

Unless... perhaps word 1 is not "girl"? What other person starts with g and ends with rl? None really.

Perhaps the puzzle allows reusing letters? No, it says "cross out each letter as you use it", implying no reuse.

Another idea: Maybe "g_r_l" is "general"? But that's 7 letters, and it's written as 4 characters: g _ r l — so 4-letter word.

Must be "girl".

Similarly, "children" is 8 letters, matches c h i _ _ r e _ — positions 4 and 5 are blanks, then r,e, and last blank — so yes, 8 letters.

But 'l' is needed for both.

Unless... in "girl", is 'l' used? Yes. In "children", 'l' is the 4th letter.

So conflict.

Perhaps I have the order wrong. Maybe solve word 3 first.

Let's try word 3 first.

Assume "children" — requires c,h,i,l,d,r,e,n

Available initially: all present.

Use them.

Then word 1: g_r_l — needs g,i,r,l — but l is used, i is used (children used one i, there were two, so one left), r used (children used one r, three total, so two left), g available.

So for "girl": g, i (second one), r (second or third), l — but l is used up by children.

Same problem.

Unless "children" doesn't require 'l'? No, it does.

Perhaps the word is "chirpere"? Not a word.

Another possibility: "chipper" + e? No.

Or "chiffre"? French, not English person.

Perhaps "chief" + re? No.

Let's look at other words.

Word 4: m y s _ l _

Likely: "myself" — m,y,s,e,l,f

Uses m,y,s,e,l,f

Check if possible.

Word 5: _ r o _ h e _

Likely: "brother" — b,r,o,t,h,e,r — but needs 'o', which we don't have.

Again 'o' problem.

Word 6: m o _ _ e r — again 'o'.

Many words have 'o', but no 'o' in letter bank.

This suggests that perhaps the 'o' in the puzzle is a red herring, or I misread.

Let's list all the words again:

1. g _ r l
2. b o _
3. c h i _ _ r e _
4. m y s _ l _
5. _ r o _ h e _
6. m o _ _ e r
7. _ e n
8. _ _ o t h _ r
9. s i _ t e _
10. _ o m a n
11. f _ r m e _
12. t e a _ _ e r

Many have 'o': 2,5,6,8,10

But no 'o' in letter bank. This is impossible unless the letter bank has 'o' and I missed it.

Let's double-check the user's input of the letter box:

> a b c d e e f f g
> h h i i l m n r
> r r s t t t w y

No 'o'. But perhaps in the actual image, there is an 'o'? The user might have transcribed incorrectly.

Maybe "b o _" is "b u _" and 'u' is there? No 'u' either.

Another idea: Perhaps "b o _" is "bee" but that's not a person, and it's "b o _", not "b e e".

Or "bob" — b,o,b — needs 'o'.

I think there's a mistake in the transcription.

Perhaps the second row is "h h i i l m n o" or something.

Let's assume that 'o' is available, because otherwise the puzzle is unsolvable.

Maybe in the letter bank, the 'n' in second row is 'o'? User wrote "n", but perhaps it's 'o'.

Let's look at the user's text: "h h i i l m n r" — probably 'n'.

But let's count the letters in the box as per common puzzles.

Perhaps I can search for similar puzzles online, but since I can't, let's try to proceed with the assumption that 'o' is available, or find words that don't require 'o'.

For example, word 7: _ e n — could be "men", "pen", "ten", "yen", "den", etc. "Men" is a person.

Uses m,e,n

Word 9: s i _ t e _ — "sister" — s,i,s,t,e,r — but has two s's? Letter bank has only one s.

"sister" requires two s's? S-i-s-t-e-r — yes, two s's.

Letter bank has only one s.

So not "sister".

"site" + e? "situation"? Too long.

"single"? Not matching.

"smite"? Not a person.

"spite"? Not a person.

"stole"? Not.

Perhaps "sixteen"? Not a person.

Another idea: "sightseer"? Too long.

Let's try word 12: t e a _ _ e r — "teacher" — t,e,a,c,h,e,r — uses t,e,a,c,h,e,r

Has two e's, which we have.

C,h available.

So "teacher" is possible.

Uses t,e,a,c,h,e,r

Similarly, word 10: _ o m a n — "woman" — w,o,m,a,n — needs 'o'.

"man" is part, but with _ o m a n, likely "woman".

Word 8: _ _ o t h _ r — "mother" — m,o,t,h,e,r — needs 'o'.

"father" — f,a,t,h,e,r — no 'o', but the pattern is _ _ o t h _ r, so third letter is 'o', so not "father".

"brother" — b,r,o,t,h,e,r — has 'o'.

So many require 'o'.

Perhaps the letter bank has 'o', and the user omitted it.

Maybe in the second row, "n" is "o".

Let's assume that the letter bank includes 'o'. Perhaps the user made a typo.

Commonly in such puzzles, 'o' is included.

Perhaps "b o _" is "b oy" but still.

Another approach: let's list all possible words for each blank, using only the given letters, and see what fits.

Given letters: a,b,c,d,e,e,f,f,g,h,h,i,i,l,m,n,r,r,r,s,t,t,t,w,y

No o, no u, no p, etc.

So for word 2: b o _ — if no 'o', perhaps it's "b ar" but "bar" is not a person.

"bed"? Not.

"beg"? Not a person.

"bel"? No.

Perhaps "b en" — but it's "b o _", not "b _ _".

I think there's a transcription error.

Perhaps the 'o' in "b o _" is actually a 'u', and "b u _" could be "bud" or "bus", but "bud" is a nickname, "bus" not a person.

"bun"? Not.

Let's look at word 5: _ r o _ h e _ — if no 'o', perhaps "breath" but not ending with e_, and not a person.

"bravehe"? No.

Perhaps "prince" but not matching.

I recall that in some versions of this puzzle, the letter bank has 'o', and the words are standard.

Perhaps for this sake, I'll assume that 'o' is available, and proceed, as otherwise it's impossible.

Maybe the 'n' in the second row is 'o'. Let's assume that.

So suppose the letter bank is:

a b c d e e f f g
h h i i l m o r // changed n to o
r r s t t t w y

Then we have 'o'.

Let's try that.

So initial counts with 'o' instead of 'n':

a:1
b:1
c:1
d:1
e:2
f:2
g:1
h:2
i:2
l:1
m:1
o:1 // instead of n
r:3
s:1
t:3
w:1
y:1

And no 'n'? But then "children" needs 'n'.

Problem.

If we have 'o' and 'n', then extra letter.

Perhaps the bank has 26 letters.

Let's calculate the number of blanks to fill.

List the words with number of blanks:

1. g _ r l — 1 blank
2. b o _ — 1 blank
3. c h i _ _ r e _ — 3 blanks (positions 4,5,8)
4. m y s _ l _ — 2 blanks (4,6)
5. _ r o _ h e _ — 3 blanks (1,4,7)
6. m o _ _ e r — 2 blanks (3,4)
7. _ e n — 1 blank (1)
8. _ _ o t h _ r — 3 blanks (1,2,6)
9. s i _ t e _ — 2 blanks (3,6)
10. _ o m a n — 1 blank (1)
11. f _ r m e _ — 2 blanks (2,6)
12. t e a _ _ e r — 2 blanks (4,5)

Sum of blanks: 1+1+3+2+3+2+1+3+2+1+2+2 = let's add:

1+1=2; +3=5; +2=7; +3=10; +2=12; +1=13; +3=16; +2=18; +1=19; +2=21; +2=23 blanks.

The letter bank has 25 letters, and we will have 5 left over, so we use 20 letters for the blanks? No.

The words have some letters given, and we fill the blanks with letters from the bank.

The total letters used in the completed words will be the sum of the lengths of the words.

Let's calculate the length of each word:

1. g_r_l — 4 letters
2. b o _ — 3 letters
3. c h i _ _ r e _ — 8 letters
4. m y s _ l _ — 6 letters
5. _ r o _ h e _ — 7 letters
6. m o _ _ e r — 6 letters
7. _ e n — 3 letters
8. _ _ o t h _ r — 7 letters
9. s i _ t e _ — 6 letters
10. _ o m a n — 5 letters
11. f _ r m e _ — 6 letters
12. t e a _ _ e r — 7 letters

Sum of lengths: 4+3+8+6+7+6+3+7+6+5+6+7 = let's calculate:

4+3=7; +8=15; +6=21; +7=28; +6=34; +3=37; +7=44; +6=50; +5=55; +6=61; +7=68 letters in total for all words.

The given letters in the words (not blanks) are:

For each word, the non-blank letters are given, and we fill the blanks.

So the number of letters we need to supply from the bank is the number of blanks, which is 23, as calculated earlier.

The letter bank has 25 letters, and we use 23 for the blanks, leaving 2, but the puzzle says 5 left over. Contradiction.

The puzzle says: "You will have five letters leftover."

So we use 20 letters from the bank for the blanks? But we have 23 blanks.

Unless some of the "given" letters in the words are also from the bank, but the instruction is: "Use the letters in the box to finish spelling the words. Cross out each letter as you use it."

So the letters in the box are used to fill the blanks, and the given letters in the words are already there, not from the box.

So for example, in "g _ r l", the 'g','r','l' are given, so we only need to provide the '_' , which is one letter from the box.

Similarly for others.

So the number of letters to take from the box is equal to the number of blanks, which is 23.

But the box has 25 letters, and we should have 5 left over, so 25 - 23 = 2 left, not 5.

Inconsistency.

Unless the given letters in the words are also from the box, but that doesn't make sense because they are already printed.

Perhaps the "letters in the box" are to be used for the entire word, including the given letters, but that would mean we cross out letters for the given parts too, which is unusual.

Let's read the instruction: "Use the letters in the box to finish spelling the words. Cross out each letter as you use it."

"Finish spelling" implies that the given letters are already there, and we use the box letters for the blanks.

But then with 23 blanks and 25 letters, 2 left, but puzzle says 5 left.

So perhaps the given letters are also to be taken from the box.

In that case, for each word, all letters, given and filled, are from the box.

Then the total letters used is the sum of the lengths of the words, which is 68, but the box has only 25 letters, impossible.

That can't be.

Perhaps the "letters in the box" are additional letters to complete the words, and the given letters are not from the box, but then the math doesn't work.

Another interpretation: the box contains letters that are to be used to fill the blanks, and after filling all blanks, 5 letters remain unused in the box.

With 23 blanks, and 25 letters, 2 remain, not 5.

So perhaps I miscalculated the number of blanks.

Let's list each word and count the underscores.

1. g _ r l — 1 underscore
2. b o _ — 1 underscore
3. c h i _ _ r e _ — 3 underscores (after i, after i, after e) — positions 4,5,8
4. m y s _ l _ — 2 underscores (after s, after l) — positions 4,6
5. _ r o _ h e _ — 3 underscores (before r, after o, after e) — positions 1,4,7
6. m o _ _ e r — 2 underscores (after o, after o) — positions 3,4
7. _ e n — 1 underscore (before e) — position 1
8. _ _ o t h _ r — 3 underscores (before _, before o, after h) — positions 1,2,6
9. s i _ t e _ — 2 underscores (after i, after e) — positions 3,6
10. _ o m a n — 1 underscore (before o) — position 1
11. f _ r m e _ — 2 underscores (after f, after e) — positions 2,6
12. t e a _ _ e r — 2 underscores (after a, after a) — positions 4,5

Sum: 1+1+3+2+3+2+1+3+2+1+2+2 = let's group:

Words with 1 blank: 1,2,7,10 → 4 words ×1 = 4
With 2 blanks: 4,6,9,11,12 → 5 words ×2 = 10
With 3 blanks: 3,5,8 → 3 words ×3 = 9
Total: 4+10+9 = 23 blanks.

Yes.

Box has 25 letters, so 25-23=2 left, but puzzle says 5 left.

So perhaps the box has 28 letters or something.

Maybe I miscounted the box.

User's box:

First row: a b c d e e f f g — 9 letters
Second row: h h i i l m n r — 8 letters? That's 8, but should be 9 for symmetry.

Third row: r r s t t t w y — 8 letters.

9+8+8=25, as before.

Perhaps the second row is "h h i i l m n o r" or something.

Maybe "n" is "o", and there is another letter.

Another idea: perhaps the "five letters leftover" includes the letters not used, and we have to identify them, and their count is 5, so the box must have 23 +5 = 28 letters.

So likely, the box has 28 letters, and I have a transcription error.

Perhaps in the second row, it's "h h i i l m n o r" — 9 letters, and third row "r r s t t t w y z" or something.

To resolve this, I recall that in standard "People Puzzler" worksheets, the letter bank often has 28 letters, and 5 left over.

For example, a common version has the following words:

1. girl
2. boy
3. children
4. myself
5. brother
6. mother
7. men
8. father
9. sister
10. woman
11. farmer
12. teacher

And the letter bank has letters to spell these, with 5 left over.

Let's assume that's the case here.

So let's list the intended words:

1. girl
2. boy
3. children
4. myself
5. brother
6. mother
7. men
8. father
9. sister
10. woman
11. farmer
12. teacher

Now, let's verify the patterns:

1. g _ r l -> girl (fill 'i')
2. b o _ -> boy (fill 'y')
3. c h i _ _ r e _ -> children (fill 'l','d','n')
4. m y s _ l _ -> myself (fill 'e','f')
5. _ r o _ h e _ -> brother (fill 'b','t','r') — but "brother" is b-r-o-t-h-e-r, so positions: 1:b, 2:r, 3:o, 4:t, 5:h, 6:e, 7:r — so for "_ r o _ h e _", it would be fill 1,4,7 with b,t,r — yes.
6. m o _ _ e r -> mother (fill 't','h') — m-o-t-h-e-r, so positions 3,4: t,h
7. _ e n -> men (fill 'm')
8. _ _ o t h _ r -> father? f-a-t-h-e-r, but pattern is _ _ o t h _ r, which has 'o' as third letter, while "father" has 'a' as second, 't' as third, not 'o'. "Mother" has 'o' as second, not third. "Brother" has 'o' as third, but we already have brother for 5.

For 8. _ _ o t h _ r — if it's "another", but not a person. "Smoothier"? No.

Perhaps "together"? Not a person.

Another common word: "grandmother" too long.

Perhaps "doctor" — d-o-c-t-o-r, not matching.

Let's check "father": f-a-t-h-e-r — for pattern _ _ o t h _ r, it doesn't match because third letter is 't', not 'o'.

Unless the pattern is for "mother": m-o-t-h-e-r — for _ _ o t h _ r, if we put m in 1, nothing in 2, but it's _ _ o, so two blanks before 'o', so for "mother", it would be m o t h e r, so if the pattern is _ _ o t h _ r, then position 1 and 2 are blank, position 3 is 'o', so for "mother", position 1 is 'm', position 2 is 'o', but 'o' is already given as position 3, so not match.

Perhaps it's "brother" for 8, but we have it for 5.

I think for 8, it might be "father" but the pattern is different.

Perhaps in some versions, 8 is "author" but not a person.

Let's look at 9. s i _ t e _ -> sister (s-i-s-t-e-r, so fill 's','r') — but two s's, and letter bank may have only one s.

In our letter bank, only one s, so "sister" requires two s's, impossible.

"smiter"? Not a person.

"spitter"? No.

"sticker"? No.

Perhaps "sightseer" too long.

Another idea: "single" not matching.

Perhaps "site" + "er" but not.

Let's assume the words are as above, and proceed with the letter bank that includes 'o' and has enough letters.

Suppose the letter bank is:

a, b, c, d, e, e, f, f, g, h, h, i, i, l, m, n, o, r, r, r, s, t, t, t, w, y, and say two more, but we need 28 for 23 used +5 left.

Perhaps add 'p' and 'u' or something.

To save time, I'll use the standard solution for this puzzle.

Upon recalling, in many sources, for this exact puzzle, the words are:

1. girl
2. boy
3. children
4. myself
5. brother
6. mother
7. men
8. father
9. sister
10. woman
11. farmer
12. teacher

And the letter bank has: a, b, c, d, e, e, f, f, g, h, h, i, i, l, m, n, o, r, r, r, s, t, t, t, w, y, and perhaps 'p', 'u' or duplicate.

But in our case, with the given letters, let's try to force it.

Perhaps for 9. s i _ t e _ , it's "sitter" but not a person, or "soter" no.

Another possibility: "saint" + "er" not.

Let's calculate the letters required for the standard words.

List the words and their letters:

1. girl: g,i,r,l
2. boy: b,o,y
3. children: c,h,i,l,d,r,e,n
4. myself: m,y,s,e,l,f
5. brother: b,r,o,t,h,e,r
6. mother: m,o,t,h,e,r
7. men: m,e,n
8. father: f,a,t,h,e,r
9. sister: s,i,s,t,e,r — two s's
10. woman: w,o,m,a,n
11. farmer: f,a,r,m,e,r
12. teacher: t,e,a,c,h,e,r

Now, let's count the frequency of each letter required.

Make a tally:

a: in 8,10,11,12 → 4 times
b: in 2,5 → 2 times
c: in 3,12 → 2 times
d: in 3 → 1 time
e: in 3,4,5,6,7,8,9,11,12 → let's see: 3:1, 4:1, 5:1, 6:1, 7:1, 8:1, 9:1, 11:1, 12:2 (teacher has two e's) — so 3:1, 4:1, 5:1, 6:1, 7:1, 8:1, 9:1, 11:1, 12:2 — sum 1*8 +2 = 10? List:

- children: 1 e
- myself: 1 e
- brother: 1 e
- mother: 1 e
- men: 1 e
- father: 1 e
- sister: 1 e
- farmer: 1 e
- teacher: 2 e's
So 1+1+1+1+1+1+1+1+2 = 10 e's

But in our letter bank, only 2 e's, so impossible.

This indicates that the given letters in the words are not from the box; only the blanks are filled from the box.

So for the blanks, we need to provide letters, and the given letters are already there.

For example, in "g _ r l", the 'g','r','l' are given, so we only provide the '_' , which is 'i' for "girl".

Similarly, for "b o _", 'b','o' are given, we provide '_' , which is 'y' for "boy".

For "c h i _ _ r e _", 'c','h','i','r','e' are given, we provide the three blanks: for "children", we need 'l','d','n' for positions 4,5,8.

And so on.

Then the letters we use from the box are only for the blanks, 23 letters, and the box has 25, so 2 left, but puzzle says 5 left, so perhaps the box has 28 letters, or I have a mistake in the number of blanks.

Perhaps for some words, the given letters are not all provided; but in the puzzle, they are shown.

Another idea: perhaps "cross out each letter as you use it" means that for the entire word, you use letters from the box, including the given ones, but that would require the box to have all letters for all words, which is 68, impossible.

I think the only way is to assume that the letter bank has 28 letters, and proceed with the standard solution.

Perhaps in the user's transcription, the letter bank is incomplete.

Looking back at the user's input: "a b c d e e f f g" — 9
"h h i i l m n r" — 8, but perhaps it's "h h i i l m n o r" — 9
"r r s t t t w y" — 8, perhaps "r r s t t t w y z" or "r r s t t t w y y" etc.

Assume that the second row is "h h i i l m n o r" (9 letters), and third row "r r s t t t w y y" (9 letters), so 9+9+9=27 letters.

Then with 23 blanks, 4 left, still not 5.

Or 28 letters.

Perhaps add 'p' or 'u'.

To move forward, I'll use the standard answer for this puzzle.

Upon searching my knowledge, for this "People Puzzler", the completed words are:

1. girl
2. boy
3. children
4. myself
5. brother
6. mother
7. men
8. father
9. sister
10. woman
11. farmer
12. teacher

And the leftover letters are: a, p, u, and two others, but usually, the 5 leftover letters spell "super" or "group" or something.

In many versions, the 5 leftover letters are 'a', 'p', 'u', 'c', 'k' or something, but let's calculate.

Perhaps for this specific letter bank, we can solve it.

Let's try to fill the words with the given letters, assuming 'o' is available.

Assume the letter bank has 'o', and perhaps an extra 'n' or something.

Suppose the letter bank is: a, b, c, d, e, e, f, f, g, h, h, i, i, l, m, n, o, r, r, r, s, t, t, t, w, y, and say 'p', 'u' — 28 letters.

Then for the blanks:

1. g _ r l -> fill 'i'
2. b o _ -> fill 'y'
3. c h i _ _ r e _ -> fill 'l','d','n' for children
4. m y s _ l _ -> fill 'e','f' for myself
5. _ r o _ h e _ -> fill 'b','t','r' for brother (positions 1,4,7)
6. m o _ _ e r -> fill 't','h' for mother
7. _ e n -> fill 'm' for men
8. _ _ o t h _ r -> for father, but "father" is f-a-t-h-e-r, so for _ _ o t h _ r, if we put f in 1, a in 2, but 'o' is given as position 3, so not match. For "mother", m-o-t-h-e-r, so if pattern is _ _ o t h _ r, then position 1: m, position 2: o, but 'o' is already at position 3, so conflict.

For 8. _ _ o t h _ r, if it's "another", not a person. "Smoothier" no.

Perhaps "together" not.

Another common word: "doctor" d-o-c-t-o-r, not matching.

Perhaps "author" a-u-t-h-o-r, not.

Let's look at 9. s i _ t e _ -> for "sister", s-i-s-t-e-r, so fill 's','r' for positions 3,6
10. _ o m a n -> fill 'w' for woman
11. f _ r m e _ -> fill 'a','r' for farmer (positions 2,6)
12. t e a _ _ e r -> fill 'c','h' for teacher (positions 4,5)

Now, list the letters needed for the blanks:

1. i
2. y
3. l, d, n
4. e, f
5. b, t, r
6. t, h
7. m
8. ? for _ _ o t h _ r — let's say for "father", but doesn't match. Perhaps "brother" is for 5, so for 8, maybe "mother" but same issue.

Perhaps 8 is "father" and the pattern is misremembered.

Assume that for 8. _ _ o t h _ r, it is "father" with 'o' being a mistake, or perhaps it's "f a t h e r" and the 'o' is 'a', but user wrote 'o'.

Perhaps in the puzzle, it's "