49 Balancing Chemical Equations Worksheets [with Answers] - Free Printable

Let's solve each of these chemical equations by balancing them. The goal is to ensure the number of atoms of each element is the same on both sides of the equation.

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1) Li₃PO₄ + NaOH → LiOH + Na₃PO₄

- Left: 3 Li, 1 P, 4 O, 1 Na, 1 O, 1 H
- Right: 1 Li, 1 O, 1 H, 3 Na, 1 P, 4 O

We need:
- 3 Li on right → 3 LiOH
- 3 Na on left → 3 NaOH

So:
→ Li₃PO₄ + 3NaOH → 3LiOH + Na₃PO₄

✔ Balanced.

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2) MgF₂ + Li₂CO₃ → MgCO₃ + LiF

- Left: 1 Mg, 2 F, 2 Li, 1 C, 3 O
- Right: 1 Mg, 1 C, 3 O, 1 Li, 1 F

Need:
- 2 LiF on right → 2 LiF
- Then 2 Li on left → need 1 Li₂CO₃ (already have)

So:
→ MgF₂ + Li₂CO₃ → MgCO₃ + 2LiF

✔ Balanced.

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3) P₄ + O₂ → P₂O₃

- Left: 4 P, 2 O
- Right: 2 P, 3 O

Need:
- P₄ → 2P₂O₃ → 4 P and 6 O
- So need 3 O₂ → 6 O

→ P₄ + 3O₂ → 2P₂O₃

✔ Balanced.

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4) RbNO₃ + MgF₂ → Mg(NO₃)₂ + RbF

- Left: 1 Rb, 1 N, 3 O, 1 Mg, 2 F
- Right: 1 Mg, 2 N, 6 O, 1 Rb, 1 F

Need:
- 2 NO₃ on right → need 2 RbNO₃
- Then 2 Rb → 2 RbF
- 2 F → need 1 MgF₂

So:
→ 2RbNO₃ + MgF₂ → Mg(NO₃)₂ + 2RbF

✔ Balanced.

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5) AgNO₃ + Cu → Cu(NO₃)₂ + Ag

- Left: 1 Ag, 1 N, 3 O, 1 Cu
- Right: 1 Cu, 2 N, 6 O, 1 Ag

Need:
- 2 AgNO₃ → 2 Ag, 2 N, 6 O
- Then Cu(NO₃)₂ → needs 2 NO₃ → so 2 AgNO₃
- 2 Ag on right → 2 Ag
- 1 Cu on left → 1 Cu

→ 2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag

✔ Balanced.

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6) CF₄ + Br₂ → CBr₄ + F₂

- Left: 1 C, 4 F, 2 Br
- Right: 1 C, 4 Br, 2 F

Swap roles:
- Need 4 Br → 2 Br₂
- Need 4 F → 2 F₂

But:
- CF₄ → CBr₄: replace 4 F with 4 Br → need 2 Br₂
- Then produce 2 F₂ from 4 F

So:
→ CF₄ + 2Br₂ → CBr₄ + 2F₂

✔ Balanced.

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7) HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂

- Left: 1 H, 1 C, 1 N, 1 Cu, 1 S, 4 O
- Right: 2 H, 1 S, 4 O, 1 Cu, 2 C, 2 N

Need:
- 2 HCN → 2 H, 2 C, 2 N
- Then Cu(CN)₂ → 2 CN → matches
- H₂SO₄ → 2 H, 1 S, 4 O

So:
→ 2HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂

✔ Balanced.

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8) GaF₃ + Cs → CsF + Ga

- Left: 1 Ga, 3 F, 1 Cs
- Right: 1 Cs, 1 F, 1 Ga

Need:
- 3 F → 3 CsF
- So 3 Cs on left

→ GaF₃ + 3Cs → 3CsF + Ga

✔ Balanced.

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9) SrS + PtF₂ → SrF₂ + PtS

- Left: 1 Sr, 1 S, 1 Pt, 2 F
- Right: 1 Sr, 2 F, 1 Pt, 1 S

All match already!

→ SrS + PtF₂ → SrF₂ + PtS

✔ Balanced.

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10) N₂ + H₂ → NH₃

- Left: 2 N, 2 H
- Right: 1 N, 3 H

Need:
- 2 N → 2 NH₃ → 2 N, 6 H
- So need 3 H₂ → 6 H

→ N₂ + 3H₂ → 2NH₃

✔ Balanced.

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11) LiF + Br₂ → LiBr + F₂

- Left: 1 Li, 1 F, 2 Br
- Right: 1 Li, 1 Br, 2 F

Need:
- 2 LiF → 2 Li, 2 F
- 2 LiBr → 2 Li, 2 Br
- Br₂ → 2 Br
- F₂ → 2 F

So:
→ 2LiF + Br₂ → 2LiBr + F₂

✔ Balanced.

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12) Pb(OH)₂ + HCl → H₂O + PbCl₂

- Left: 1 Pb, 2 O, 2 H, 1 H, 1 Cl → total: 1 Pb, 2 O, 3 H, 1 Cl
- Right: 2 H, 1 O, 1 Pb, 2 Cl

Need:
- PbCl₂ → 2 Cl → need 2 HCl
- Then 2 HCl → 2 H, 2 Cl
- Now left: Pb(OH)₂ + 2HCl → 1 Pb, 2 O, 2 H + 2 H = 4 H, 2 Cl
- Right: H₂O → 2 H, 1 O; PbCl₂ → 1 Pb, 2 Cl

Wait — only 1 H₂O? But we have 4 H?

We need 2 H₂O → 4 H, 2 O

So:
→ Pb(OH)₂ + 2HCl → 2H₂O + PbCl₂

✔ Balanced.

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13) GaBr₃ + Na₂CO₃ → NaBr + Ga₂(CO₃)₃ (tough)

Note: Ga₂(CO₃)₃ has 2 Ga and 3 CO₃ groups.

So:
- Right: 2 Ga, 3 C, 9 O, 3 NaBr → 3 Na, 3 Br
- Left: GaBr₃ → 1 Ga, 3 Br; Na₂CO₃ → 2 Na, 1 C, 3 O

We need:
- 2 Ga → 2 GaBr₃
- 3 CO₃ → 3 Na₂CO₃ → 6 Na, 3 C, 9 O
- Then NaBr → 6 NaBr (since 6 Na on left)
- But 2 GaBr₃ → 6 Br → 6 NaBr → 6 Br

So:
→ 2GaBr₃ + 3Na₂CO₃ → 6NaBr + Ga₂(CO₃)₃

✔ Balanced.

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14) CH₄ + O₂ → CO₂ + H₂O

Classic combustion.

- Left: 1 C, 4 H, 2 O
- Right: 1 C, 2 O, 2 H, 1 O → total 1 C, 2 H, 3 O

Need:
- 2 H₂O → 4 H, 2 O → now 1 C, 4 H, 4 O on right
- So need 2 O₂ → 4 O

→ CH₄ + 2O₂ → CO₂ + 2H₂O

✔ Balanced.

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15) Li₃PO₄ + CaCl₂ → LiCl + Ca₃(PO₄)₂ (also tough)

Right: Ca₃(PO₄)₂ → 3 Ca, 2 PO₄

So:
- Need 2 Li₃PO₄ → 2 PO₄, 6 Li
- Need 3 CaCl₂ → 3 Ca, 6 Cl
- Then LiCl → 6 LiCl

So:
→ 2Li₃PO₄ + 3CaCl₂ → 6LiCl + Ca₃(PO₄)₂

✔ Balanced.

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16) Na + Cl₂ → NaCl

- Left: 1 Na, 2 Cl
- Right: 1 Na, 1 Cl

Need:
- 2 Na → 2 Na
- 1 Cl₂ → 2 Cl → 2 NaCl

→ 2Na + Cl₂ → 2NaCl

✔ Balanced.

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17) Ga + HCl → H₂ + GaCl₃ (last tough one)

- Left: 1 Ga, 1 H, 1 Cl
- Right: 2 H, 1 Ga, 3 Cl

Need:
- GaCl₃ → 3 Cl → need 3 HCl
- Then 3 H → 3/2 H₂ → but better use whole numbers

So:
- 2 Ga → 2 GaCl₃ → 6 Cl → 6 HCl
- 6 H → 3 H₂

→ 2Ga + 6HCl → 3H₂ + 2GaCl₃

✔ Balanced.

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18) N₂ + F₂ → NF₃

- Left: 2 N, 2 F
- Right: 1 N, 3 F

Need:
- 2 N → 2 NF₃ → 2 N, 6 F
- So need 3 F₂ → 6 F

→ N₂ + 3F₂ → 2NF₃

✔ Balanced.

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19) SO₂ + Li₂Se → SSe₂ + Li₂O

- Left: 1 S, 2 O, 2 Li, 1 Se
- Right: 1 S, 2 Se, 2 Li, 1 O

Need:
- 2 Se on right → need 2 Li₂Se → 4 Li, 2 Se
- Then Li₂O → 2 Li, 1 O → need 2 Li₂O → 4 Li, 2 O
- SO₂ → 1 S, 2 O → good

So:
→ SO₂ + 2Li₂Se → SSe₂ + 2Li₂O

✔ Balanced.

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20) NH₃ + H₂SO₄ → (NH₄)₂SO₄

- Left: 1 N, 3 H, 2 H, 1 S, 4 O → total: 1 N, 5 H, 1 S, 4 O
- Right: 2 N, 8 H, 1 S, 4 O

Need:
- 2 NH₃ → 2 N, 6 H
- H₂SO₄ → 2 H, 1 S, 4 O
- Total: 2 N, 8 H, 1 S, 4 O → matches (NH₄)₂SO₄

→ 2NH₃ + H₂SO₄ → (NH₄)₂SO₄

✔ Balanced.

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## ✔ Final Answers:

1) Li₃PO₄ + 3NaOH → 3LiOH + Na₃PO₄
2) MgF₂ + Li₂CO₃ → MgCO₃ + 2LiF
3) P₄ + 3O₂ → 2P₂O₃
4) 2RbNO₃ + MgF₂ → Mg(NO₃)₂ + 2RbF
5) 2AgNO₃ + Cu → Cu(NO₃)₂ + 2Ag
6) CF₄ + 2Br₂ → CBr₄ + 2F₂
7) 2HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
8) GaF₃ + 3Cs → 3CsF + Ga
9) SrS + PtF₂ → SrF₂ + PtS
10) N₂ + 3H₂ → 2NH₃
11) 2LiF + Br₂ → 2LiBr + F₂
12) Pb(OH)₂ + 2HCl → 2H₂O + PbCl₂
13) 2GaBr₃ + 3Na₂CO₃ → 6NaBr + Ga₂(CO₃)₃
14) CH₄ + 2O₂ → CO₂ + 2H₂O
15) 2Li₃PO₄ + 3CaCl₂ → 6LiCl + Ca₃(PO₄)₂
16) 2Na + Cl₂ → 2NaCl
17) 2Ga + 6HCl → 3H₂ + 2GaCl₃
18) N₂ + 3F₂ → 2NF₃
19) SO₂ + 2Li₂Se → SSe₂ + 2Li₂O
20) 2NH₃ + H₂SO₄ → (NH₄)₂SO₄

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