5th Grade Fractions Worksheets | Comparison of Fractions | Addition - Free Printable
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Step-by-step solution for: 5th Grade Fractions Worksheets | Comparison of Fractions | Addition
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Show Answer Key & Explanations
Step-by-step solution for: 5th Grade Fractions Worksheets | Comparison of Fractions | Addition
Let's solve each problem step by step.
---
Both fractions have the same denominator, so we can simply add the numerators:
\[
\frac{7}{10} + \frac{3}{10} = \frac{7 + 3}{10} = \frac{10}{10} = 1
\]
Answer:
\[
\boxed{1}
\]
---
Both fractions have the same denominator, so we can subtract the numerators:
\[
\frac{14}{25} - \frac{9}{25} = \frac{14 - 9}{25} = \frac{5}{25}
\]
Simplify the fraction by dividing both numerator and denominator by their greatest common divisor (GCD), which is 5:
\[
\frac{5}{25} = \frac{1}{5}
\]
Answer:
\[
\boxed{\frac{1}{5}}
\]
---
First, find a common denominator for the fractions. The denominators are 7, 28, and 4. The least common multiple (LCM) of 7, 28, and 4 is 28.
Convert each fraction to have a denominator of 28:
- For $\frac{5}{7}$: Multiply numerator and denominator by 4:
\[
\frac{5}{7} = \frac{5 \times 4}{7 \times 4} = \frac{20}{28}
\]
- For $\frac{13}{28}$: It already has a denominator of 28.
\[
\frac{13}{28} = \frac{13}{28}
\]
- For $\frac{3}{4}$: Multiply numerator and denominator by 7:
\[
\frac{3}{4} = \frac{3 \times 7}{4 \times 7} = \frac{21}{28}
\]
Now add the fractions:
\[
\frac{20}{28} + \frac{13}{28} + \frac{21}{28} = \frac{20 + 13 + 21}{28} = \frac{54}{28}
\]
Simplify the fraction by dividing both numerator and denominator by their GCD, which is 2:
\[
\frac{54}{28} = \frac{27}{14}
\]
Answer:
\[
\boxed{\frac{27}{14}}
\]
---
First, simplify $\frac{3}{12}$:
\[
\frac{3}{12} = \frac{1}{4}
\]
Now, rewrite 7 as a fraction with a denominator of 4:
\[
7 = \frac{7 \times 4}{1 \times 4} = \frac{28}{4}
\]
Subtract the fractions:
\[
\frac{28}{4} - \frac{1}{4} = \frac{28 - 1}{4} = \frac{27}{4}
\]
Answer:
\[
\boxed{\frac{27}{4}}
\]
---
First, find a common denominator for the fractions. The denominators are 15, 30, and 5. The LCM of 15, 30, and 5 is 30.
Convert each fraction to have a denominator of 30:
- For $\frac{8}{15}$: Multiply numerator and denominator by 2:
\[
\frac{8}{15} = \frac{8 \times 2}{15 \times 2} = \frac{16}{30}
\]
- For $\frac{19}{30}$: It already has a denominator of 30.
\[
\frac{19}{30} = \frac{19}{30}
\]
- For $\frac{4}{5}$: Multiply numerator and denominator by 6:
\[
\frac{4}{5} = \frac{4 \times 6}{5 \times 6} = \frac{24}{30}
\]
Now perform the addition and subtraction:
\[
\frac{16}{30} + \frac{19}{30} - \frac{24}{30} = \frac{16 + 19 - 24}{30} = \frac{11}{30}
\]
Answer:
\[
\boxed{\frac{11}{30}}
\]
---
To divide fractions, multiply the first fraction by the reciprocal of the second fraction:
\[
\frac{16}{44} \div \frac{8}{11} = \frac{16}{44} \times \frac{11}{8}
\]
Simplify the multiplication:
\[
\frac{16 \times 11}{44 \times 8} = \frac{176}{352}
\]
Simplify the fraction by dividing both numerator and denominator by their GCD, which is 176:
\[
\frac{176}{352} = \frac{1}{2}
\]
Answer:
\[
\boxed{\frac{1}{2}}
\]
---
Multiply the numerators and the denominators:
\[
\frac{6}{31} \times \frac{62}{18} = \frac{6 \times 62}{31 \times 18} = \frac{372}{558}
\]
Simplify the fraction by dividing both numerator and denominator by their GCD, which is 6:
\[
\frac{372}{558} = \frac{62}{93}
\]
Answer:
\[
\boxed{\frac{62}{93}}
\]
---
To divide fractions, multiply the first fraction by the reciprocal of the second fraction:
\[
\frac{24}{50} \div \frac{8}{25} = \frac{24}{50} \times \frac{25}{8}
\]
Simplify the multiplication:
\[
\frac{24 \times 25}{50 \times 8} = \frac{600}{400}
\]
Simplify the fraction by dividing both numerator and denominator by their GCD, which is 200:
\[
\frac{600}{400} = \frac{3}{2}
\]
Answer:
\[
\boxed{\frac{3}{2}}
\]
---
\[
\boxed{1, \frac{1}{5}, \frac{27}{14}, \frac{27}{4}, \frac{11}{30}, \frac{1}{2}, \frac{62}{93}, \frac{3}{2}}
\]
---
(i) $\frac{7}{10} + \frac{3}{10}$
Both fractions have the same denominator, so we can simply add the numerators:
\[
\frac{7}{10} + \frac{3}{10} = \frac{7 + 3}{10} = \frac{10}{10} = 1
\]
Answer:
\[
\boxed{1}
\]
---
(ii) $\frac{14}{25} - \frac{9}{25}$
Both fractions have the same denominator, so we can subtract the numerators:
\[
\frac{14}{25} - \frac{9}{25} = \frac{14 - 9}{25} = \frac{5}{25}
\]
Simplify the fraction by dividing both numerator and denominator by their greatest common divisor (GCD), which is 5:
\[
\frac{5}{25} = \frac{1}{5}
\]
Answer:
\[
\boxed{\frac{1}{5}}
\]
---
(iii) $\frac{5}{7} + \frac{13}{28} + \frac{3}{4}$
First, find a common denominator for the fractions. The denominators are 7, 28, and 4. The least common multiple (LCM) of 7, 28, and 4 is 28.
Convert each fraction to have a denominator of 28:
- For $\frac{5}{7}$: Multiply numerator and denominator by 4:
\[
\frac{5}{7} = \frac{5 \times 4}{7 \times 4} = \frac{20}{28}
\]
- For $\frac{13}{28}$: It already has a denominator of 28.
\[
\frac{13}{28} = \frac{13}{28}
\]
- For $\frac{3}{4}$: Multiply numerator and denominator by 7:
\[
\frac{3}{4} = \frac{3 \times 7}{4 \times 7} = \frac{21}{28}
\]
Now add the fractions:
\[
\frac{20}{28} + \frac{13}{28} + \frac{21}{28} = \frac{20 + 13 + 21}{28} = \frac{54}{28}
\]
Simplify the fraction by dividing both numerator and denominator by their GCD, which is 2:
\[
\frac{54}{28} = \frac{27}{14}
\]
Answer:
\[
\boxed{\frac{27}{14}}
\]
---
(iv) $7 - \frac{3}{12}$
First, simplify $\frac{3}{12}$:
\[
\frac{3}{12} = \frac{1}{4}
\]
Now, rewrite 7 as a fraction with a denominator of 4:
\[
7 = \frac{7 \times 4}{1 \times 4} = \frac{28}{4}
\]
Subtract the fractions:
\[
\frac{28}{4} - \frac{1}{4} = \frac{28 - 1}{4} = \frac{27}{4}
\]
Answer:
\[
\boxed{\frac{27}{4}}
\]
---
(v) $\frac{8}{15} + \frac{19}{30} - \frac{4}{5}$
First, find a common denominator for the fractions. The denominators are 15, 30, and 5. The LCM of 15, 30, and 5 is 30.
Convert each fraction to have a denominator of 30:
- For $\frac{8}{15}$: Multiply numerator and denominator by 2:
\[
\frac{8}{15} = \frac{8 \times 2}{15 \times 2} = \frac{16}{30}
\]
- For $\frac{19}{30}$: It already has a denominator of 30.
\[
\frac{19}{30} = \frac{19}{30}
\]
- For $\frac{4}{5}$: Multiply numerator and denominator by 6:
\[
\frac{4}{5} = \frac{4 \times 6}{5 \times 6} = \frac{24}{30}
\]
Now perform the addition and subtraction:
\[
\frac{16}{30} + \frac{19}{30} - \frac{24}{30} = \frac{16 + 19 - 24}{30} = \frac{11}{30}
\]
Answer:
\[
\boxed{\frac{11}{30}}
\]
---
(vi) $\frac{16}{44} \div \frac{8}{11}$
To divide fractions, multiply the first fraction by the reciprocal of the second fraction:
\[
\frac{16}{44} \div \frac{8}{11} = \frac{16}{44} \times \frac{11}{8}
\]
Simplify the multiplication:
\[
\frac{16 \times 11}{44 \times 8} = \frac{176}{352}
\]
Simplify the fraction by dividing both numerator and denominator by their GCD, which is 176:
\[
\frac{176}{352} = \frac{1}{2}
\]
Answer:
\[
\boxed{\frac{1}{2}}
\]
---
(vii) $\frac{6}{31} \times \frac{62}{18}$
Multiply the numerators and the denominators:
\[
\frac{6}{31} \times \frac{62}{18} = \frac{6 \times 62}{31 \times 18} = \frac{372}{558}
\]
Simplify the fraction by dividing both numerator and denominator by their GCD, which is 6:
\[
\frac{372}{558} = \frac{62}{93}
\]
Answer:
\[
\boxed{\frac{62}{93}}
\]
---
(viii) $\frac{24}{50} \div \frac{8}{25}$
To divide fractions, multiply the first fraction by the reciprocal of the second fraction:
\[
\frac{24}{50} \div \frac{8}{25} = \frac{24}{50} \times \frac{25}{8}
\]
Simplify the multiplication:
\[
\frac{24 \times 25}{50 \times 8} = \frac{600}{400}
\]
Simplify the fraction by dividing both numerator and denominator by their GCD, which is 200:
\[
\frac{600}{400} = \frac{3}{2}
\]
Answer:
\[
\boxed{\frac{3}{2}}
\]
---
Final Answers:
\[
\boxed{1, \frac{1}{5}, \frac{27}{14}, \frac{27}{4}, \frac{11}{30}, \frac{1}{2}, \frac{62}{93}, \frac{3}{2}}
\]
Parent Tip: Review the logic above to help your child master the concept of worksheet on fractions for grade 5.