Students can practice their statistics skills by calculating the mean, median, mode, and range for these ten sets of numbers.

Here are the step-by-step solutions for each problem on the worksheet.

How to solve these:
1. Mean (Average): Add all the numbers together, then divide by how many numbers there are.
2. Median (Middle): Put the numbers in order from smallest to largest. The middle number is the median. If there are two middle numbers, add them and divide by 2.
3. Mode (Most Frequent): The number that appears the most times.
4. Range: Subtract the smallest number from the largest number.

---

Problem 1

Numbers: 7, 6, 9, 8, 6, 7, 7, 7, 6
* Ordered: 6, 6, 6, 7, 7, 7, 7, 8, 9
* Mean: Sum = 63. Count = 9. $63 \div 9 = 7$
* Median: The 5th number is 7.
* Mode: 7 appears four times. Mode is 7.
* Range: $9 - 6 = 3$

Problem 2

Numbers: 8, 3, 6, 9, 7, 9
* Ordered: 3, 6, 7, 8, 9, 9
* Mean: Sum = 42. Count = 6. $42 \div 6 = 7$
* Median: Middle two are 7 and 8. $(7+8) \div 2 = 7.5$
* Mode: 9 appears twice. Mode is 9.
* Range: $9 - 3 = 6$

Problem 3

Numbers: 8, 9, 9, 8, 2, 3, 2, 3, 1
* Ordered: 1, 2, 2, 3, 3, 8, 8, 9, 9
* Mean: Sum = 45. Count = 9. $45 \div 9 = 5$
* Median: The 5th number is 3.
* Mode: 2, 3, 8, and 9 all appear twice. This data set has multiple modes: 2, 3, 8, 9.
* Range: $9 - 1 = 8$

Problem 4

Numbers: 2, 4, 8, 3, 6, 7
* Ordered: 2, 3, 4, 6, 7, 8
* Mean: Sum = 30. Count = 6. $30 \div 6 = 5$
* Median: Middle two are 4 and 6. $(4+6) \div 2 = 5$
* Mode: No number repeats. There is No Mode.
* Range: $8 - 2 = 6$

Problem 5

Numbers: 6, 3, 9, 5, 7, 2, 5, 5, 3
* Ordered: 2, 3, 3, 5, 5, 5, 6, 7, 9
* Mean: Sum = 45. Count = 9. $45 \div 9 = 5$
* Median: The 5th number is 5.
* Mode: 5 appears three times. Mode is 5.
* Range: $9 - 2 = 7$

Problem 6

Numbers: 8, 9, 5, 8, 3, 7, 3, 9, 2
* Ordered: 2, 3, 3, 5, 7, 8, 8, 9, 9
* Mean: Sum = 54. Count = 9. $54 \div 9 = 6$
* Median: The 5th number is 7.
* Mode: 3, 8, and 9 all appear twice. Modes are 3, 8, 9.
* Range: $9 - 2 = 7$

Problem 7

Numbers: 9, 3, 8, 5, 2, 9
* Ordered: 2, 3, 5, 8, 9, 9
* Mean: Sum = 36. Count = 6. $36 \div 6 = 6$
* Median: Middle two are 5 and 8. $(5+8) \div 2 = 6.5$
* Mode: 9 appears twice. Mode is 9.
* Range: $9 - 2 = 7$

Problem 8

Numbers: 8, 2, 3, 4, 4, 3
* Ordered: 2, 3, 3, 4, 4, 8
* Mean: Sum = 24. Count = 6. $24 \div 6 = 4$
* Median: Middle two are 3 and 4. $(3+4) \div 2 = 3.5$
* Mode: 3 and 4 both appear twice. Modes are 3, 4.
* Range: $8 - 2 = 6$

Problem 9

Numbers: 8, 6, 2, 5, 7, 8
* Ordered: 2, 5, 6, 7, 8, 8
* Mean: Sum = 36. Count = 6. $36 \div 6 = 6$
* Median: Middle two are 6 and 7. $(6+7) \div 2 = 6.5$
* Mode: 8 appears twice. Mode is 8.
* Range: $8 - 2 = 6$

Problem 10

Numbers: 5, 3, 9, 7, 2, 4
* Ordered: 2, 3, 4, 5, 7, 9
* Mean: Sum = 30. Count = 6. $30 \div 6 = 5$
* Median: Middle two are 4 and 5. $(4+5) \div 2 = 4.5$
* Mode: No number repeats. There is No Mode.
* Range: $9 - 2 = 7$

──────────────────────────────────────

Final Answer:

1) Mean: 7, Median: 7, Mode: 7, Range: 3
2) Mean: 7, Median: 7.5, Mode: 9, Range: 6
3) Mean: 5, Median: 3, Mode: 2, 3, 8, 9, Range: 8
4) Mean: 5, Median: 5, Mode: None, Range: 6
5) Mean: 5, Median: 5, Mode: 5, Range: 7
6) Mean: 6, Median: 7, Mode: 3, 8, 9, Range: 7
7) Mean: 6, Median: 6.5, Mode: 9, Range: 7
8) Mean: 4, Median: 3.5, Mode: 3, 4, Range: 6
9) Mean: 6, Median: 6.5, Mode: 8, Range: 6
10) Mean: 5, Median: 4.5, Mode: None, Range: 7