Math worksheet on percent word problems using decimal expressions, featuring 10 questions with answer spaces.
A worksheet titled "Percent Word Problems as Decimal Expressions" with ten math problems involving percentages and decimal expressions, including calculations for phone prices, gas prices, sales discounts, and computer pricing, with answer spaces on the right side.
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Step-by-step solution for: Algebra Worksheets | Free - CommonCoreSheets
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Show Answer Key & Explanations
Step-by-step solution for: Algebra Worksheets | Free - CommonCoreSheets
Problem: Solve the given percent word problems and determine the correct expressions for each scenario.
#### 1. A cell phone company dropped the prices on their phones by 9%. Which expression shows the new price of the phone (p)?
- Options:
- A. \( p - 0.09p \)
- B. \( p \times 1.09 \)
- C. \( p \times 0.09 \)
- D. \( p - 0.09 \)
Solution:
If the price of the phone is reduced by 9%, the new price is calculated as:
\[ \text{New Price} = \text{Original Price} - (\text{Original Price} \times 0.09) \]
\[ \text{New Price} = p - 0.09p \]
Correct Answer: A. \( p - 0.09p \)
---
#### 2. Over the summer gas prices dropped 3%. Which expression shows the new price of a gallon of gas (the old price is represented by \( g \))?
- Options:
- A. \( g \times 0.03 \)
- B. \( g - 0.03 \)
- C. \( g \times 0.97 \)
- D. \( g - 0.03g \)
Solution:
If gas prices drop by 3%, the new price is:
\[ \text{New Price} = \text{Original Price} - (\text{Original Price} \times 0.03) \]
\[ \text{New Price} = g - 0.03g \]
Alternatively, this can be expressed as:
\[ \text{New Price} = g \times (1 - 0.03) = g \times 0.97 \]
Correct Answer: C. \( g \times 0.97 \)
---
#### 3. While clearing out some old inventory a store offered 10 percent off of any item (i). Which expression can be used to calculate the new cost of an item?
- Options:
- A. \( i - 1.1 \)
- B. \( i - 0.1i \)
- C. \( i \times 0.1 \)
- D. \( i - 0.1 \)
Solution:
If the store offers a 10% discount, the new cost of the item is:
\[ \text{New Cost} = \text{Original Cost} - (\text{Original Cost} \times 0.1) \]
\[ \text{New Cost} = i - 0.1i \]
Correct Answer: B. \( i - 0.1i \)
---
#### 4. Joe was earning $11 an hour before his raise. After his 5% raise he is making $11.55 an hour. Which expression shows how his new hourly rate was calculated?
- Options:
- A. \( 11 \times 1.05 \)
- B. \( 11 \times 0.05 \)
- C. \( 11 + 0.05 \)
- D. \( 11 + 0.05 \)
Solution:
If Joe received a 5% raise, his new hourly rate is:
\[ \text{New Hourly Rate} = \text{Original Hourly Rate} + (\text{Original Hourly Rate} \times 0.05) \]
\[ \text{New Hourly Rate} = 11 + (11 \times 0.05) \]
This can also be expressed as:
\[ \text{New Hourly Rate} = 11 \times (1 + 0.05) = 11 \times 1.05 \]
Correct Answer: A. \( 11 \times 1.05 \)
---
#### 5. A mall kiosk needed to buy 33 new cell phone cases at \( z \) dollars a piece. Because they were buying so many they got 5% off the price. Which expression shows how much they saved?
- Options:
- A. \( 33z \times 0.05 \)
- B. \( 0.05 \times 33z \)
- C. \( 33z \times 0.05 \)
- D. \( 33z + 0.05 \)
Solution:
The total cost without the discount is \( 33z \). With a 5% discount, the amount saved is:
\[ \text{Amount Saved} = \text{Total Cost} \times 0.05 \]
\[ \text{Amount Saved} = 33z \times 0.05 \]
Correct Answer: A. \( 33z \times 0.05 \)
---
#### 6. Roger drew a square with each side being exactly 12 centimeters long. If he wanted to make the square 6% larger, which expression can he use to find the new side lengths?
- Options:
- A. \( 12 \times 1.06 \)
- B. \( 12 \times 1.06 \)
- C. \( 12 \times 0.06 \)
- D. \( 12 + 0.06 \)
Solution:
To increase the side length by 6%, the new side length is:
\[ \text{New Side Length} = \text{Original Side Length} \times (1 + 0.06) \]
\[ \text{New Side Length} = 12 \times 1.06 \]
Correct Answer: A. \( 12 \times 1.06 \)
---
#### 7. The regular price of a computer was $893, but over the weekend it'll be on sale for 10 percent off. Which expression shows the difference in price from normal to sale?
- Options:
- A. \( n - 10 \)
- B. \( n \times 0.1 \)
- C. \( n - 1.1 \)
- D. \( n - 0.1 \)
Solution:
If the computer is on sale for 10% off, the discount amount is:
\[ \text{Discount Amount} = \text{Regular Price} \times 0.1 \]
\[ \text{Discount Amount} = n \times 0.1 \]
Correct Answer: B. \( n \times 0.1 \)
---
#### 8. A house was on sell for $23,474. If you wanted to offer 7% less than the asking price (\( p \)), which expression shows how much you should offer?
- Options:
- A. \( p - 0.07 \)
- B. \( p - 0.07p \)
- C. \( p - 1.07 \)
- D. \( p \times 0.07 \)
Solution:
If you want to offer 7% less than the asking price, your offer is:
\[ \text{Offer} = \text{Asking Price} - (\text{Asking Price} \times 0.07) \]
\[ \text{Offer} = p - 0.07p \]
Correct Answer: B. \( p - 0.07p \)
---
#### 9. A company was having a sale for 19% off the price of computer monitors. Which expression shows how much money you would save if you bought 25 monitors for \( z \) dollars a piece?
- Options:
- A. \( 25z \times 0.19 \)
- B. \( 25z \times 1.19 \)
- C. \( 0.19 \times 25z \)
- D. \( 25z + 0.19 \)
Solution:
The total cost without the discount is \( 25z \). With a 19% discount, the amount saved is:
\[ \text{Amount Saved} = \text{Total Cost} \times 0.19 \]
\[ \text{Amount Saved} = 25z \times 0.19 \]
Correct Answer: A. \( 25z \times 0.19 \)
---
#### 10. Last year the price of a college textbook (\( b \)) was $197. This year the price will be 13% higher. Which expression shows the difference in price from last year to this year?
- Options:
- A. \( b \times 0.13 \)
- B. \( b - 1.13 \)
- C. \( b - 0.13 \)
- D. \( b - 13 \)
Solution:
If the price increases by 13%, the increase in price is:
\[ \text{Price Increase} = \text{Last Year's Price} \times 0.13 \]
\[ \text{Price Increase} = b \times 0.13 \]
Correct Answer: A. \( b \times 0.13 \)
---
Final Answers:
1. A. \( p - 0.09p \)
2. C. \( g \times 0.97 \)
3. B. \( i - 0.1i \)
4. A. \( 11 \times 1.05 \)
5. A. \( 33z \times 0.05 \)
6. A. \( 12 \times 1.06 \)
7. B. \( n \times 0.1 \)
8. B. \( p - 0.07p \)
9. A. \( 25z \times 0.19 \)
10. A. \( b \times 0.13 \)
Boxed Final Answer:
\[
\boxed{
\begin{array}{ll}
1. & \text{A. } p - 0.09p \\
2. & \text{C. } g \times 0.97 \\
3. & \text{B. } i - 0.1i \\
4. & \text{A. } 11 \times 1.05 \\
5. & \text{A. } 33z \times 0.05 \\
6. & \text{A. } 12 \times 1.06 \\
7. & \text{B. } n \times 0.1 \\
8. & \text{B. } p - 0.07p \\
9. & \text{A. } 25z \times 0.19 \\
10. & \text{A. } b \times 0.13 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of writing algebraic equations from word problems worksheet.