49 Balancing Chemical Equations Worksheets [with Answers] - Free Printable
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Show Answer Key & Explanations
Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
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Show Answer Key & Explanations
Step-by-step solution for: 49 Balancing Chemical Equations Worksheets [with Answers]
Here is the fully balanced version of each chemical equation from your "Balancing Equations Worksheet", along with a clear explanation for each.
---
> Goal: Ensure the number of atoms of each element is equal on both sides (reactants and products). We adjust coefficients (numbers in front), never subscripts.
---
#### 1)
Na₃PO₄ + KOH → NaOH + K₃PO₄
✔ Balanced:
1 Na₃PO₄ + 3 KOH → 3 NaOH + 1 K₃PO₄
🔹 *Explanation*:
- Left: Na=3, P=1, O=4+3=7, K=3, H=3
- Right: Na=3, O=3+4=7, H=3, K=3, P=1
✔️ All atoms balanced.
---
#### 2)
MgF₂ + Li₂CO₃ → MgCO₃ + LiF
✔ Balanced:
1 MgF₂ + 1 Li₂CO₃ → 1 MgCO₃ + 2 LiF
🔹 *Explanation*:
- Fluorine: 2 on left → need 2 LiF on right.
- Lithium: 2 on left → 2 on right (in 2 LiF).
✔️ All elements match.
---
#### 3)
P₄ + O₂ → P₂O₃
✔ Balanced:
1 P₄ + 3 O₂ → 2 P₂O₃
🔹 *Explanation*:
- Phosphorus: 4 on left → need 2 P₂O₃ (which gives 4 P).
- Oxygen: 6 on right (2×3) → need 3 O₂ (3×2=6).
✔️ Balanced.
---
#### 4)
RbNO₃ + BeF₂ → Be(NO₃)₂ + RbF
✔ Balanced:
2 RbNO₃ + 1 BeF₂ → 1 Be(NO₃)₂ + 2 RbF
🔹 *Explanation*:
- Nitrate (NO₃⁻): Be(NO₃)₂ needs 2 NO₃ → so 2 RbNO₃.
- Rb: 2 on left → 2 RbF on right.
- F: 2 on left → 2 on right (in 2 RbF).
✔️ Balanced.
---
#### 5)
AgNO₃ + Cu → Cu(NO₃)₂ + Ag
✔ Balanced:
2 AgNO₃ + 1 Cu → 1 Cu(NO₃)₂ + 2 Ag
🔹 *Explanation*:
- Cu(NO₃)₂ has 2 NO₃ → need 2 AgNO₃.
- Ag: 2 on left → 2 Ag on right.
✔️ Single displacement reaction.
---
#### 6)
CF₄ + Br₂ → CBr₄ + F₂
✔ Balanced:
1 CF₄ + 2 Br₂ → 1 CBr₄ + 2 F₂
🔹 *Explanation*:
- Fluorine: 4 on left → need 2 F₂ (4 F) on right.
- Bromine: 4 on right → need 2 Br₂ (4 Br) on left.
✔️ Halogen exchange.
---
#### 7)
HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
✔ Balanced:
2 HCN + 1 CuSO₄ → 1 H₂SO₄ + 1 Cu(CN)₂
🔹 *Explanation*:
- CN⁻: Cu(CN)₂ needs 2 CN → so 2 HCN.
- H: 2 on left → 2 on right (in H₂SO₄).
✔️ Double displacement.
---
#### 8)
GaF₃ + Cs → CsF + Ga
✔ Balanced:
1 GaF₃ + 3 Cs → 3 CsF + 1 Ga
🔹 *Explanation*:
- F: 3 on left → need 3 CsF on right.
- Cs: 3 on right → 3 Cs on left.
✔️ Single displacement (active metal displaces less active).
---
#### 9)
BaS + PtF₂ → BaF₂ + PtS
✔ Balanced:
1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS
🔹 *Explanation*:
Already balanced!
- Ba:1, S:1, Pt:1, F:2 on both sides.
✔️ Simple double displacement.
---
#### 10)
N₂ + H₂ → NH₃
✔ Balanced:
1 N₂ + 3 H₂ → 2 NH₃
🔹 *Explanation*:
Classic Haber process.
- N: 2 on left → 2 on right (in 2 NH₃).
- H: 6 on right → 3 H₂ (6 H) on left.
✔️ Balanced.
---
#### 11)
NaF + Br₂ → NaBr + F₂
✔ Balanced:
2 NaF + 1 Br₂ → 2 NaBr + 1 F₂
🔹 *Explanation*:
- F: 2 on left → 1 F₂ on right.
- Na: 2 on left → 2 NaBr on right.
- Br: 2 on left → 2 on right.
✔️ Halogen displacement (Br₂ displaces F⁻? Actually, this reaction is not spontaneous — but we balance as written).
---
#### 12)
Pb(OH)₂ + HCl → H₂O + PbCl₂
✔ Balanced:
1 Pb(OH)₂ + 2 HCl → 2 H₂O + 1 PbCl₂
🔹 *Explanation*:
- Cl: 2 on right → 2 HCl on left.
- H: 2 (from HCl) + 2 (from OH) = 4 H → 2 H₂O (4 H).
- O: 2 from OH → 2 in 2 H₂O.
✔️ Acid-base neutralization.
---
#### 13)
AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
✔ Balanced:
2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
🔹 *Explanation*:
- Al: 2 on right → 2 AlBr₃ on left.
- SO₄: 3 on right → 3 K₂SO₄ on left.
- K: 6 on left → 6 KBr on right.
- Br: 6 on left → 6 on right.
✔️ Double displacement.
---
#### 14)
CH₄ + O₂ → CO₂ + H₂O
✔ Balanced:
1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
🔹 *Explanation*:
Combustion of methane.
- C: 1=1
- H: 4 on left → 2 H₂O (4 H) on right.
- O: 4 on right (2 in CO₂ + 2 in 2 H₂O) → 2 O₂ (4 O) on left.
✔️ Classic combustion.
---
#### 15)
Na₃PO₄ + CaCl₂ → NaCl + Ca₃(PO₄)₂
✔ Balanced:
2 Na₃PO₄ + 3 CaCl₂ → 6 NaCl + 1 Ca₃(PO₄)₂
🔹 *Explanation*:
- PO₄: 2 on right → 2 Na₃PO₄ on left.
- Ca: 3 on right → 3 CaCl₂ on left.
- Na: 6 on left → 6 NaCl on right.
- Cl: 6 on left → 6 on right.
✔️ Precipitation reaction.
---
#### 16)
K + Cl₂ → KCl
✔ Balanced:
2 K + 1 Cl₂ → 2 KCl
🔹 *Explanation*:
- K: 2 on left → 2 KCl on right.
- Cl: 2 on left → 2 on right.
✔️ Synthesis reaction.
---
#### 17)
Al + HCl → H₂ + AlCl₃
✔ Balanced:
2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
🔹 *Explanation*:
- Al: 2 on left → 2 AlCl₃ on right.
- Cl: 6 on right → 6 HCl on left.
- H: 6 on left → 3 H₂ (6 H) on right.
✔️ Single displacement.
---
#### 18)
N₂ + F₂ → NF₃
✔ Balanced:
1 N₂ + 3 F₂ → 2 NF₃
🔹 *Explanation*:
- N: 2 on left → 2 NF₃ on right.
- F: 6 on right → 3 F₂ (6 F) on left.
✔️ Synthesis.
---
#### 19)
SO₂ + Li₂Se → SSe₂ + Li₂O
✔ Balanced:
1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
🔹 *Explanation*:
- Se: 2 on right → 2 Li₂Se on left.
- Li: 4 on left → 2 Li₂O on right.
- O: 2 on left → 2 on right (in 2 Li₂O).
- S: 1=1
✔️ Unusual reaction — but balanced as written.
---
#### 20)
NH₃ + H₂SO₄ → (NH₄)₂SO₄
✔ Balanced:
2 NH₃ + 1 H₂SO₄ → 1 (NH₄)₂SO₄
🔹 *Explanation*:
- NH₄⁺: 2 needed → 2 NH₃.
- H: 6 from 2 NH₃ + 2 from H₂SO₄ = 8 H → 8 H in (NH₄)₂SO₄ (each NH₄ has 4 H → 2×4=8).
✔️ Acid-base reaction forming ammonium sulfate.
---
## ✔ Final Answer Summary (Coefficients Only):
1) 1, 3, 3, 1
2) 1, 1, 1, 2
3) 1, 3, 2
4) 2, 1, 1, 2
5) 2, 1, 1, 2
6) 1, 2, 1, 2
7) 2, 1, 1, 1
8) 1, 3, 3, 1
9) 1, 1, 1, 1
10) 1, 3, 2
11) 2, 1, 2, 1
12) 1, 2, 2, 1
13) 2, 3, 6, 1
14) 1, 2, 1, 2
15) 2, 3, 6, 1
16) 2, 1, 2
17) 2, 6, 3, 2
18) 1, 3, 2
19) 1, 2, 1, 2
20) 2, 1, 1
---
Let me know if you want step-by-step balancing for any specific one — or if you’d like to check your own work! 🧪
---
🔢 Balancing Chemical Equations — Solutions & Explanations
> Goal: Ensure the number of atoms of each element is equal on both sides (reactants and products). We adjust coefficients (numbers in front), never subscripts.
---
#### 1)
Na₃PO₄ + KOH → NaOH + K₃PO₄
✔ Balanced:
1 Na₃PO₄ + 3 KOH → 3 NaOH + 1 K₃PO₄
🔹 *Explanation*:
- Left: Na=3, P=1, O=4+3=7, K=3, H=3
- Right: Na=3, O=3+4=7, H=3, K=3, P=1
✔️ All atoms balanced.
---
#### 2)
MgF₂ + Li₂CO₃ → MgCO₃ + LiF
✔ Balanced:
1 MgF₂ + 1 Li₂CO₃ → 1 MgCO₃ + 2 LiF
🔹 *Explanation*:
- Fluorine: 2 on left → need 2 LiF on right.
- Lithium: 2 on left → 2 on right (in 2 LiF).
✔️ All elements match.
---
#### 3)
P₄ + O₂ → P₂O₃
✔ Balanced:
1 P₄ + 3 O₂ → 2 P₂O₃
🔹 *Explanation*:
- Phosphorus: 4 on left → need 2 P₂O₃ (which gives 4 P).
- Oxygen: 6 on right (2×3) → need 3 O₂ (3×2=6).
✔️ Balanced.
---
#### 4)
RbNO₃ + BeF₂ → Be(NO₃)₂ + RbF
✔ Balanced:
2 RbNO₃ + 1 BeF₂ → 1 Be(NO₃)₂ + 2 RbF
🔹 *Explanation*:
- Nitrate (NO₃⁻): Be(NO₃)₂ needs 2 NO₃ → so 2 RbNO₃.
- Rb: 2 on left → 2 RbF on right.
- F: 2 on left → 2 on right (in 2 RbF).
✔️ Balanced.
---
#### 5)
AgNO₃ + Cu → Cu(NO₃)₂ + Ag
✔ Balanced:
2 AgNO₃ + 1 Cu → 1 Cu(NO₃)₂ + 2 Ag
🔹 *Explanation*:
- Cu(NO₃)₂ has 2 NO₃ → need 2 AgNO₃.
- Ag: 2 on left → 2 Ag on right.
✔️ Single displacement reaction.
---
#### 6)
CF₄ + Br₂ → CBr₄ + F₂
✔ Balanced:
1 CF₄ + 2 Br₂ → 1 CBr₄ + 2 F₂
🔹 *Explanation*:
- Fluorine: 4 on left → need 2 F₂ (4 F) on right.
- Bromine: 4 on right → need 2 Br₂ (4 Br) on left.
✔️ Halogen exchange.
---
#### 7)
HCN + CuSO₄ → H₂SO₄ + Cu(CN)₂
✔ Balanced:
2 HCN + 1 CuSO₄ → 1 H₂SO₄ + 1 Cu(CN)₂
🔹 *Explanation*:
- CN⁻: Cu(CN)₂ needs 2 CN → so 2 HCN.
- H: 2 on left → 2 on right (in H₂SO₄).
✔️ Double displacement.
---
#### 8)
GaF₃ + Cs → CsF + Ga
✔ Balanced:
1 GaF₃ + 3 Cs → 3 CsF + 1 Ga
🔹 *Explanation*:
- F: 3 on left → need 3 CsF on right.
- Cs: 3 on right → 3 Cs on left.
✔️ Single displacement (active metal displaces less active).
---
#### 9)
BaS + PtF₂ → BaF₂ + PtS
✔ Balanced:
1 BaS + 1 PtF₂ → 1 BaF₂ + 1 PtS
🔹 *Explanation*:
Already balanced!
- Ba:1, S:1, Pt:1, F:2 on both sides.
✔️ Simple double displacement.
---
#### 10)
N₂ + H₂ → NH₃
✔ Balanced:
1 N₂ + 3 H₂ → 2 NH₃
🔹 *Explanation*:
Classic Haber process.
- N: 2 on left → 2 on right (in 2 NH₃).
- H: 6 on right → 3 H₂ (6 H) on left.
✔️ Balanced.
---
#### 11)
NaF + Br₂ → NaBr + F₂
✔ Balanced:
2 NaF + 1 Br₂ → 2 NaBr + 1 F₂
🔹 *Explanation*:
- F: 2 on left → 1 F₂ on right.
- Na: 2 on left → 2 NaBr on right.
- Br: 2 on left → 2 on right.
✔️ Halogen displacement (Br₂ displaces F⁻? Actually, this reaction is not spontaneous — but we balance as written).
---
#### 12)
Pb(OH)₂ + HCl → H₂O + PbCl₂
✔ Balanced:
1 Pb(OH)₂ + 2 HCl → 2 H₂O + 1 PbCl₂
🔹 *Explanation*:
- Cl: 2 on right → 2 HCl on left.
- H: 2 (from HCl) + 2 (from OH) = 4 H → 2 H₂O (4 H).
- O: 2 from OH → 2 in 2 H₂O.
✔️ Acid-base neutralization.
---
#### 13)
AlBr₃ + K₂SO₄ → KBr + Al₂(SO₄)₃
✔ Balanced:
2 AlBr₃ + 3 K₂SO₄ → 6 KBr + 1 Al₂(SO₄)₃
🔹 *Explanation*:
- Al: 2 on right → 2 AlBr₃ on left.
- SO₄: 3 on right → 3 K₂SO₄ on left.
- K: 6 on left → 6 KBr on right.
- Br: 6 on left → 6 on right.
✔️ Double displacement.
---
#### 14)
CH₄ + O₂ → CO₂ + H₂O
✔ Balanced:
1 CH₄ + 2 O₂ → 1 CO₂ + 2 H₂O
🔹 *Explanation*:
Combustion of methane.
- C: 1=1
- H: 4 on left → 2 H₂O (4 H) on right.
- O: 4 on right (2 in CO₂ + 2 in 2 H₂O) → 2 O₂ (4 O) on left.
✔️ Classic combustion.
---
#### 15)
Na₃PO₄ + CaCl₂ → NaCl + Ca₃(PO₄)₂
✔ Balanced:
2 Na₃PO₄ + 3 CaCl₂ → 6 NaCl + 1 Ca₃(PO₄)₂
🔹 *Explanation*:
- PO₄: 2 on right → 2 Na₃PO₄ on left.
- Ca: 3 on right → 3 CaCl₂ on left.
- Na: 6 on left → 6 NaCl on right.
- Cl: 6 on left → 6 on right.
✔️ Precipitation reaction.
---
#### 16)
K + Cl₂ → KCl
✔ Balanced:
2 K + 1 Cl₂ → 2 KCl
🔹 *Explanation*:
- K: 2 on left → 2 KCl on right.
- Cl: 2 on left → 2 on right.
✔️ Synthesis reaction.
---
#### 17)
Al + HCl → H₂ + AlCl₃
✔ Balanced:
2 Al + 6 HCl → 3 H₂ + 2 AlCl₃
🔹 *Explanation*:
- Al: 2 on left → 2 AlCl₃ on right.
- Cl: 6 on right → 6 HCl on left.
- H: 6 on left → 3 H₂ (6 H) on right.
✔️ Single displacement.
---
#### 18)
N₂ + F₂ → NF₃
✔ Balanced:
1 N₂ + 3 F₂ → 2 NF₃
🔹 *Explanation*:
- N: 2 on left → 2 NF₃ on right.
- F: 6 on right → 3 F₂ (6 F) on left.
✔️ Synthesis.
---
#### 19)
SO₂ + Li₂Se → SSe₂ + Li₂O
✔ Balanced:
1 SO₂ + 2 Li₂Se → 1 SSe₂ + 2 Li₂O
🔹 *Explanation*:
- Se: 2 on right → 2 Li₂Se on left.
- Li: 4 on left → 2 Li₂O on right.
- O: 2 on left → 2 on right (in 2 Li₂O).
- S: 1=1
✔️ Unusual reaction — but balanced as written.
---
#### 20)
NH₃ + H₂SO₄ → (NH₄)₂SO₄
✔ Balanced:
2 NH₃ + 1 H₂SO₄ → 1 (NH₄)₂SO₄
🔹 *Explanation*:
- NH₄⁺: 2 needed → 2 NH₃.
- H: 6 from 2 NH₃ + 2 from H₂SO₄ = 8 H → 8 H in (NH₄)₂SO₄ (each NH₄ has 4 H → 2×4=8).
✔️ Acid-base reaction forming ammonium sulfate.
---
## ✔ Final Answer Summary (Coefficients Only):
1) 1, 3, 3, 1
2) 1, 1, 1, 2
3) 1, 3, 2
4) 2, 1, 1, 2
5) 2, 1, 1, 2
6) 1, 2, 1, 2
7) 2, 1, 1, 1
8) 1, 3, 3, 1
9) 1, 1, 1, 1
10) 1, 3, 2
11) 2, 1, 2, 1
12) 1, 2, 2, 1
13) 2, 3, 6, 1
14) 1, 2, 1, 2
15) 2, 3, 6, 1
16) 2, 1, 2
17) 2, 6, 3, 2
18) 1, 3, 2
19) 1, 2, 1, 2
20) 2, 1, 1
---
Let me know if you want step-by-step balancing for any specific one — or if you’d like to check your own work! 🧪
Parent Tip: Review the logic above to help your child master the concept of writing and balancing chemical equations worksheet.