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Writing Exponential Equations Using a Graph - Problems involving exponential functions and rate of change.

Graphs of exponential functions with labeled axes, showing various exponential equations and their domains and ranges.

Graphs of exponential functions with labeled axes, showing various exponential equations and their domains and ranges.

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Show Answer Key & Explanations Step-by-step solution for: Writing Exponential Equations from Graphs Worksheet | airSlate SignNow
Since I can't view or access uploaded images directly, I can’t see the specific graphs you're referring to. However, I can guide you through how to solve problems like this based on the structure of your worksheet.

---

Objective:


For each graph, determine the exponential function in the form:

$$
f(x) = ab^x
$$

Then state:
- The domain
- The range
- The rate of change over a given interval (usually [0, 1], [0, 2], etc.)

---

## 🔍 Step-by-Step Guide

Let’s go through how to analyze one of these graphs and find the equation.

---

Step 1: Identify Key Points on the Graph



Look at the graph and find two points that lie exactly on the curve. Usually, the y-intercept is easy to spot — it's where $ x = 0 $. That gives you $ f(0) = a $, because:

$$
f(0) = ab^0 = a \cdot 1 = a
$$

So:
- Find $ f(0) $ → this is $ a $
- Find another point, say $ f(1) $, $ f(2) $, etc.
- Use that to solve for $ b $

---

Step 2: Solve for $ b $



Suppose:
- $ f(0) = a $
- $ f(1) = ab $

Then:
$$
b = \frac{f(1)}{a}
$$

Or if you have $ f(2) = ab^2 $, then:
$$
b^2 = \frac{f(2)}{a} \Rightarrow b = \sqrt{\frac{f(2)}{a}}
$$

---

Step 3: Write the Equation



Once you know $ a $ and $ b $, write:
$$
f(x) = ab^x
$$

---

Step 4: Domain and Range



For exponential functions $ f(x) = ab^x $:

- Domain: All real numbers → $ (-\infty, \infty) $
- Range:
- If $ a > 0 $ and $ b > 1 $: $ (0, \infty) $
- If $ a > 0 $ and $ 0 < b < 1 $: $ (0, \infty) $
- If $ a < 0 $: range is $ (-\infty, 0) $
- But since most graphs start above x-axis, assume $ a > 0 $, so range is $ (0, \infty) $

> Note: If the graph has a horizontal asymptote (like y = 0), that supports the range being $ (0, \infty) $

---

Step 5: Rate of Change



The rate of change over an interval $[x_1, x_2]$ is:

$$
\text{Average rate of change} = \frac{f(x_2) - f(x_1)}{x_2 - x_1}
$$

But in this context, they likely want the average rate of change over intervals like [0,1], [0,2], etc.

Also, which interval produces the greatest rate of change?

👉 Exponential functions grow faster as $ x $ increases (if $ b > 1 $), so the largest interval with higher x-values will generally have the largest average rate of change.

But let’s test it with values.

---

## 📌 Example Problem (Based on Common Graphs)

Let’s suppose Graph 1 looks like this:

- Passes through $ (0, 1) $
- Passes through $ (1, 2) $

Then:
- $ f(0) = 1 \Rightarrow a = 1 $
- $ f(1) = 2 \Rightarrow ab = 2 \Rightarrow b = 2 $

So:
$$
f(x) = 2^x
$$

- Domain: $ (-\infty, \infty) $
- Range: $ (0, \infty) $

Now compute rate of change:

- Over $[0,1]$: $ \frac{f(1) - f(0)}{1 - 0} = \frac{2 - 1}{1} = 1 $
- Over $[0,2]$: $ f(2) = 4 $, so $ \frac{4 - 1}{2} = 1.5 $
- Over $[0,3]$: $ f(3) = 8 $, so $ \frac{8 - 1}{3} \approx 2.33 $

So [0,3] has the greatest rate of change.

---

## ⚠️ Important Notes:

- If the graph is decreasing, then $ 0 < b < 1 $, e.g., $ f(x) = (1/2)^x $
- If the graph starts at $ (0, 3) $ and goes through $ (1, 6) $, then $ a = 3 $, $ b = 2 $, so $ f(x) = 3 \cdot 2^x $
- Always check the y-intercept first!

---

## 🧩 Now Apply This to Your Graphs

Even without seeing the image, here’s what you should do for each graph:

For each graph (1–6):



#### Step 1: Find two points
- Look at $ x = 0 $: What is $ y $? That’s $ a $
- Find $ x = 1 $: What is $ y $? Then $ b = \frac{y}{a} $

#### Step 2: Write equation
$ f(x) = ab^x $

#### Step 3: Domain & Range
- Domain: $ (-\infty, \infty) $
- Range: $ (0, \infty) $ (unless shifted — but these look basic)

#### Step 4: Compute Rate of Change
Use:
- $ \frac{f(1) - f(0)}{1 - 0} $
- $ \frac{f(2) - f(0)}{2 - 0} $
- $ \frac{f(3) - f(0)}{3 - 0} $

Compare which interval has the largest value.

---

## ❓ How to Handle the "Rate of Change" Table?

You’re asked:

> Which interval produces the greatest rate of change?

So for each graph, calculate the average rate of change over:
- [0,1]
- [0,2]
- [0,3]

Then pick the one with the highest value.

Because exponential growth accelerates, the [0,3] interval usually has the highest average rate of change (even though it's averaged over more time).

But sometimes if the function grows slowly, [0,1] might be bigger — but typically not.

---

## Final Answer Format (Example)

Let’s say Graph 1 has:
- Points: (0, 1), (1, 3)
- So $ a = 1 $, $ b = 3 $
- $ f(x) = 3^x $
- Domain: $ (-\infty, \infty) $
- Range: $ (0, \infty) $
- Rate of change:
- [0,1]: $ \frac{3 - 1}{1} = 2 $
- [0,2]: $ \frac{9 - 1}{2} = 4 $
- [0,3]: $ \frac{27 - 1}{3} \approx 8.67 $
- Greatest rate of change: [0,3]

---

📝 Summary



| Graph | Equation | Domain | Range | Greatest Rate of Change |
|-------|---------|--------|-------|--------------------------|
| 1 | $ f(x) = 2^x $ | $ (-\infty, \infty) $ | $ (0, \infty) $ | [0,3] |
| 2 | $ f(x) = 3^x $ | $ (-\infty, \infty) $ | $ (0, \infty) $ | [0,3] |
| ... | ... | ... | ... | ... |

> You’ll need to adjust based on actual points from your graphs.

---

🛠️ Tips:


- If the graph passes through $ (0, 2) $ and $ (1, 6) $, then $ a = 2 $, $ b = 3 $ → $ f(x) = 2 \cdot 3^x $
- If it passes through $ (0, 4) $ and $ (1, 2) $, then $ a = 4 $, $ b = 0.5 $ → $ f(x) = 4 \cdot (0.5)^x $
- Check whether the graph is growing or decaying.

---

If you can describe the graphs (e.g., “Graph 1 goes through (0,1) and (1,2)” or “Graph 4 starts at (0,3) and doubles every step”), I can help you solve them specifically.

Just tell me the points from each graph!
Parent Tip: Review the logic above to help your child master the concept of writing equations from graphs worksheet pdf.
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