Writing Equations of Lines Worksheets with Answer Key - Free Printable
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Step-by-step solution for: Writing Equations of Lines Worksheets with Answer Key
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Step-by-step solution for: Writing Equations of Lines Worksheets with Answer Key
Let’s solve each problem step by step.
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Problem 1:
Given:
- Line 1: 3y = 3x + 15
- Line 2: 2x - 2y = 2
We need to find the slope of each line. If slopes are equal → parallel.
If slopes multiply to -1 → perpendicular. Otherwise → none.
→ Convert both to slope-intercept form (y = mx + b)
Line 1:
3y = 3x + 15
Divide both sides by 3:
y = x + 5 → slope m₁ = 1
Line 2:
2x - 2y = 2
Subtract 2x from both sides:
-2y = -2x + 2
Divide by -2:
y = x - 1 → slope m₂ = 1
Slopes are equal → parallel
---
Problem 2:
Given:
- Line 1: y = -4x + 1 → slope m₁ = -4
- Line 2: 4y = x + 3
Convert Line 2 to slope-intercept:
4y = x + 3
Divide by 4:
y = (1/4)x + 3/4 → slope m₂ = 1/4
Check if perpendicular: m₁ × m₂ = (-4) × (1/4) = -1 → YES!
So, perpendicular
---
Problem 3:
Given:
- Line 1: y = (5/6)x - 6 → slope m₁ = 5/6
- Line 2: x + 5y = 4
Convert Line 2:
x + 5y = 4
Subtract x:
5y = -x + 4
Divide by 5:
y = (-1/5)x + 4/5 → slope m₂ = -1/5
Check product: (5/6) × (-1/5) = -5/30 = -1/6 ≠ -1 → not perpendicular
Not equal → not parallel → none
---
Problem 4:
Given:
- Line 1: -6x + y = 1
- Line 2: -6x + 3y = -9
Convert both to slope-intercept.
Line 1:
-6x + y = 1 → y = 6x + 1 → slope m₁ = 6
Line 2:
-6x + 3y = -9
Add 6x:
3y = 6x - 9
Divide by 3:
y = 2x - 3 → slope m₂ = 2
Slopes: 6 and 2 → not equal, product = 12 ≠ -1 → none
Wait — let me double-check Line 2:
Original: -6x + 3y = -9
Add 6x: 3y = 6x - 9 → divide by 3 → y = 2x - 3 → yes, slope is 2.
But wait — maybe I made a mistake? Let me check again.
Actually, let’s re-express Line 1 correctly:
Line 1: -6x + y = 1 → y = 6x + 1 → slope 6 ✔️
Line 2: -6x + 3y = -9 → 3y = 6x - 9 → y = 2x - 3 → slope 2 ✔️
Yes, different slopes, not negative reciprocals → none
BUT — hold on! Maybe I misread the second equation?
Looking back at original image: Problem 4 says:
“-6x + y = 1”
“-6x + 3y = -9”
Wait — perhaps we can simplify Line 2 differently?
Let me try dividing entire Line 2 by 3 first:
(-6x)/3 + (3y)/3 = -9/3 → -2x + y = -3 → then y = 2x - 3 → same as before.
Still slope 2.
But what if we compare with Line 1: y = 6x + 1
Nope — still not matching.
Wait — maybe I should check if they’re actually the same line? No, different slopes.
Alternatively — perhaps there's a typo in my reading? Let me look again.
Actually — let me recalculate Line 2 carefully:
Equation: -6x + 3y = -9
Add 6x to both sides: 3y = 6x - 9
Divide by 3: y = 2x - 3 → slope = 2
Line 1: y = 6x + 1 → slope = 6
Product: 6 * 2 = 12 ≠ -1 → not perpendicular
Not equal → not parallel → none
But wait — let me check if maybe the second equation was meant to be something else? Or did I misread?
Looking back at user input: “-6x + 3y = -9” — that’s correct.
Hmm — but let me think — maybe I made an error in Line 1?
Line 1: -6x + y = 1 → add 6x → y = 6x + 1 → correct.
Okay, so answer is none
Wait — no! Wait a minute — let me check if these lines are actually parallel or not by comparing coefficients.
Another way: For two lines A1x + B1y = C1 and A2x + B2y = C2,
They are parallel if A1/A2 = B1/B2 ≠ C1/C2
Perpendicular if A1*A2 + B1*B2 = 0
Let’s use that for Problem 4.
Line 1: -6x + y = 1 → A1=-6, B1=1, C1=1
Line 2: -6x + 3y = -9 → A2=-6, B2=3, C2=-9
Check parallel: A1/A2 = (-6)/(-6) = 1; B1/B2 = 1/3 → 1 ≠ 1/3 → not parallel
Check perpendicular: A1*A2 + B1*B2 = (-6)*(-6) + (1)*(3) = 36 + 3 = 39 ≠ 0 → not perpendicular
So definitely none
Okay, confirmed.
---
Now Problems 5–8: Write slope-intercept form of line through given point, parallel to given line.
Remember: Parallel lines have same slope.
Use point-slope form: y - y1 = m(x - x1), then convert to y = mx + b
---
Problem 5:
Through (-4, -5), parallel to y = -2x - 5
Slope m = -2 (same as given line)
Point: (x1, y1) = (-4, -5)
Point-slope: y - (-5) = -2(x - (-4))
→ y + 5 = -2(x + 4)
Distribute: y + 5 = -2x - 8
Subtract 5: y = -2x - 13
Final: y = -2x - 13
---
Problem 6:
Through (1, 3), parallel to y = x + 5
Slope m = 1
Point: (1, 3)
y - 3 = 1(x - 1)
→ y - 3 = x - 1
Add 3: y = x + 2
Final: y = x + 2
---
Problem 7:
Through (5, -5), parallel to y = -(3/2)x - 5
Slope m = -3/2
Point: (5, -5)
y - (-5) = (-3/2)(x - 5)
→ y + 5 = (-3/2)(x - 5)
Distribute right side:
y + 5 = (-3/2)x + (15/2) [because (-3/2)*(-5) = +15/2]
Subtract 5:
y = (-3/2)x + 15/2 - 5
Convert 5 to 10/2:
y = (-3/2)x + 15/2 - 10/2 = (-3/2)x + 5/2
Final: y = -\frac{3}{2}x + \frac{5}{2}
---
Problem 8:
Through (-2, 2), parallel to y = (2/3)x - 2
Slope m = 2/3
Point: (-2, 2)
y - 2 = (2/3)(x - (-2))
→ y - 2 = (2/3)(x + 2)
Distribute:
y - 2 = (2/3)x + 4/3
Add 2:
y = (2/3)x + 4/3 + 2
Convert 2 to 6/3:
y = (2/3)x + 4/3 + 6/3 = (2/3)x + 10/3
Final: y = \frac{2}{3}x + \frac{10}{3}
---
Now compiling all answers:
1. parallel
2. perpendicular
3. none
4. none
5. y = -2x - 13
6. y = x + 2
7. y = -\frac{3}{2}x + \frac{5}{2}
8. y = \frac{2}{3}x + \frac{10}{3}
Double-checked calculations — all seem correct.
Final Answer:
1. parallel
2. perpendicular
3. none
4. none
5. y = -2x - 13
6. y = x + 2
7. y = -\frac{3}{2}x + \frac{5}{2}
8. y = \frac{2}{3}x + \frac{10}{3}
---
Problem 1:
Given:
- Line 1: 3y = 3x + 15
- Line 2: 2x - 2y = 2
We need to find the slope of each line. If slopes are equal → parallel.
If slopes multiply to -1 → perpendicular. Otherwise → none.
→ Convert both to slope-intercept form (y = mx + b)
Line 1:
3y = 3x + 15
Divide both sides by 3:
y = x + 5 → slope m₁ = 1
Line 2:
2x - 2y = 2
Subtract 2x from both sides:
-2y = -2x + 2
Divide by -2:
y = x - 1 → slope m₂ = 1
Slopes are equal → parallel
---
Problem 2:
Given:
- Line 1: y = -4x + 1 → slope m₁ = -4
- Line 2: 4y = x + 3
Convert Line 2 to slope-intercept:
4y = x + 3
Divide by 4:
y = (1/4)x + 3/4 → slope m₂ = 1/4
Check if perpendicular: m₁ × m₂ = (-4) × (1/4) = -1 → YES!
So, perpendicular
---
Problem 3:
Given:
- Line 1: y = (5/6)x - 6 → slope m₁ = 5/6
- Line 2: x + 5y = 4
Convert Line 2:
x + 5y = 4
Subtract x:
5y = -x + 4
Divide by 5:
y = (-1/5)x + 4/5 → slope m₂ = -1/5
Check product: (5/6) × (-1/5) = -5/30 = -1/6 ≠ -1 → not perpendicular
Not equal → not parallel → none
---
Problem 4:
Given:
- Line 1: -6x + y = 1
- Line 2: -6x + 3y = -9
Convert both to slope-intercept.
Line 1:
-6x + y = 1 → y = 6x + 1 → slope m₁ = 6
Line 2:
-6x + 3y = -9
Add 6x:
3y = 6x - 9
Divide by 3:
y = 2x - 3 → slope m₂ = 2
Slopes: 6 and 2 → not equal, product = 12 ≠ -1 → none
Wait — let me double-check Line 2:
Original: -6x + 3y = -9
Add 6x: 3y = 6x - 9 → divide by 3 → y = 2x - 3 → yes, slope is 2.
But wait — maybe I made a mistake? Let me check again.
Actually, let’s re-express Line 1 correctly:
Line 1: -6x + y = 1 → y = 6x + 1 → slope 6 ✔️
Line 2: -6x + 3y = -9 → 3y = 6x - 9 → y = 2x - 3 → slope 2 ✔️
Yes, different slopes, not negative reciprocals → none
BUT — hold on! Maybe I misread the second equation?
Looking back at original image: Problem 4 says:
“-6x + y = 1”
“-6x + 3y = -9”
Wait — perhaps we can simplify Line 2 differently?
Let me try dividing entire Line 2 by 3 first:
(-6x)/3 + (3y)/3 = -9/3 → -2x + y = -3 → then y = 2x - 3 → same as before.
Still slope 2.
But what if we compare with Line 1: y = 6x + 1
Nope — still not matching.
Wait — maybe I should check if they’re actually the same line? No, different slopes.
Alternatively — perhaps there's a typo in my reading? Let me look again.
Actually — let me recalculate Line 2 carefully:
Equation: -6x + 3y = -9
Add 6x to both sides: 3y = 6x - 9
Divide by 3: y = 2x - 3 → slope = 2
Line 1: y = 6x + 1 → slope = 6
Product: 6 * 2 = 12 ≠ -1 → not perpendicular
Not equal → not parallel → none
But wait — let me check if maybe the second equation was meant to be something else? Or did I misread?
Looking back at user input: “-6x + 3y = -9” — that’s correct.
Hmm — but let me think — maybe I made an error in Line 1?
Line 1: -6x + y = 1 → add 6x → y = 6x + 1 → correct.
Okay, so answer is none
Wait — no! Wait a minute — let me check if these lines are actually parallel or not by comparing coefficients.
Another way: For two lines A1x + B1y = C1 and A2x + B2y = C2,
They are parallel if A1/A2 = B1/B2 ≠ C1/C2
Perpendicular if A1*A2 + B1*B2 = 0
Let’s use that for Problem 4.
Line 1: -6x + y = 1 → A1=-6, B1=1, C1=1
Line 2: -6x + 3y = -9 → A2=-6, B2=3, C2=-9
Check parallel: A1/A2 = (-6)/(-6) = 1; B1/B2 = 1/3 → 1 ≠ 1/3 → not parallel
Check perpendicular: A1*A2 + B1*B2 = (-6)*(-6) + (1)*(3) = 36 + 3 = 39 ≠ 0 → not perpendicular
So definitely none
Okay, confirmed.
---
Now Problems 5–8: Write slope-intercept form of line through given point, parallel to given line.
Remember: Parallel lines have same slope.
Use point-slope form: y - y1 = m(x - x1), then convert to y = mx + b
---
Problem 5:
Through (-4, -5), parallel to y = -2x - 5
Slope m = -2 (same as given line)
Point: (x1, y1) = (-4, -5)
Point-slope: y - (-5) = -2(x - (-4))
→ y + 5 = -2(x + 4)
Distribute: y + 5 = -2x - 8
Subtract 5: y = -2x - 13
Final: y = -2x - 13
---
Problem 6:
Through (1, 3), parallel to y = x + 5
Slope m = 1
Point: (1, 3)
y - 3 = 1(x - 1)
→ y - 3 = x - 1
Add 3: y = x + 2
Final: y = x + 2
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Problem 7:
Through (5, -5), parallel to y = -(3/2)x - 5
Slope m = -3/2
Point: (5, -5)
y - (-5) = (-3/2)(x - 5)
→ y + 5 = (-3/2)(x - 5)
Distribute right side:
y + 5 = (-3/2)x + (15/2) [because (-3/2)*(-5) = +15/2]
Subtract 5:
y = (-3/2)x + 15/2 - 5
Convert 5 to 10/2:
y = (-3/2)x + 15/2 - 10/2 = (-3/2)x + 5/2
Final: y = -\frac{3}{2}x + \frac{5}{2}
---
Problem 8:
Through (-2, 2), parallel to y = (2/3)x - 2
Slope m = 2/3
Point: (-2, 2)
y - 2 = (2/3)(x - (-2))
→ y - 2 = (2/3)(x + 2)
Distribute:
y - 2 = (2/3)x + 4/3
Add 2:
y = (2/3)x + 4/3 + 2
Convert 2 to 6/3:
y = (2/3)x + 4/3 + 6/3 = (2/3)x + 10/3
Final: y = \frac{2}{3}x + \frac{10}{3}
---
Now compiling all answers:
1. parallel
2. perpendicular
3. none
4. none
5. y = -2x - 13
6. y = x + 2
7. y = -\frac{3}{2}x + \frac{5}{2}
8. y = \frac{2}{3}x + \frac{10}{3}
Double-checked calculations — all seem correct.
Final Answer:
1. parallel
2. perpendicular
3. none
4. none
5. y = -2x - 13
6. y = x + 2
7. y = -\frac{3}{2}x + \frac{5}{2}
8. y = \frac{2}{3}x + \frac{10}{3}
Parent Tip: Review the logic above to help your child master the concept of writing equations of parallel and perpendicular lines worksheet answer key.