Let’s solve each problem step by step. We’ll write the chemical formulas, balance the charges to make neutral compounds, then balance the whole equation so atoms are equal on both sides.
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Problem 1: zinc metal reacts lead(II) nitrate to yield zinc nitrate and lead metal.
Step 1: Write correct formulas.
- Zinc metal = Zn (elemental form)
- Lead(II) nitrate → Pb²⁺ and NO₃⁻ → Pb(NO₃)₂ (because you need two nitrates to balance +2 charge)
- Zinc nitrate → Zn²⁺ and NO⁻ → Zn(NO₃)₂
- Lead metal = Pb (elemental form)
Unbalanced equation:
Zn + Pb(NO₃)₂ → Zn(NO₃)₂ + Pb
Step 2: Check if it’s already balanced.
Left side:
Zn: 1
Pb: 1
N: 2 (from Pb(NO₃)₂)
O: 6 (3×2 from two NO₃ groups)
Right side:
Zn: 1
Pb: 1
N: 2 (from Zn(NO₃)₂)
O: 6
✔ Already balanced!
Final answer for #1:
Zn + Pb(NO₃)₂ → Zn(NO₃)₂ + Pb
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Problem 2: aluminum bromide and chlorine gas yields aluminum chloride and liquid bromine
Step 1: Write correct formulas.
- Aluminum bromide → Al³⁺ and Br⁻ → AlBr₃
- Chlorine gas → Cl₂ (diatomic element)
- Aluminum chloride → Al³⁺ and Cl⁻ → AlCl₃
- Liquid bromine → Br₂ (diatomic element in liquid state)
Unbalanced equation:
AlBr₃ + Cl₂ → AlCl₃ + Br₂
Step 2: Balance atoms.
Look at Br: left has 3, right has 2 → LCM is 6 → put 2 in front of AlBr₃ and 3 in front of Br₂
Now:
2AlBr₃ + Cl₂ → AlCl₃ + 3Br₂
Check Al: left has 2, right has 1 → put 2 in front of AlCl₃
Now:
2AlBr₃ + Cl₂ → 2AlCl₃ + 3Br₂
Check Cl: right has 6 (2×3), left has 2 → put 3 in front of Cl₂
Now:
2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂
Check all:
Left:
Al: 2
Br: 6
Cl: 6
Right:
Al: 2
Cl: 6
Br: 6
✔ Balanced!
Final answer for #2:
2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂
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Problem 3: sodium phosphate and calcium chloride yields calcium phosphate and sodium chloride
Step 1: Write correct formulas.
- Sodium phosphate → Na⁺ and PO₄³⁻ → Na₃PO₄ (need 3 Na⁺ to balance -3)
- Calcium chloride → Ca²⁺ and Cl⁻ → CaCl₂
- Calcium phosphate → Ca²⁺ and PO₄³⁻ → Ca(PO₄)₂ (LCM of 2 and 3 is 6 → 3 Ca²⁺ and 2 PO₄³⁻)
- Sodium chloride → Na⁺ and Cl → NaCl
Unbalanced equation:
Na₃PO₄ + CaCl₂ → Ca₃(PO₄)₂ + NaCl
Step 2: Balance atoms.
Start with PO₄: left has 1, right has 2 → put 2 in front of Na₃PO₄
Now:
2Na₃PO₄ + CaCl₂ → Ca₃(PO)₂ + NaCl
Now Na: left has 6 (2×3), right has 1 → put 6 in front of NaCl
Now:
2Na₃PO₄ + CaCl₂ → Ca₃(PO₄)₂ + 6NaCl
Now Cl: right has 6, left has 2 → put 3 in front of CaCl₂
Now:
2Na₃PO₄ + 3CaCl₂ → Ca₃(PO₄)₂ + 6NaCl
Check Ca: left has 3, right has 3 → good
Check everything:
Left:
Na: 6
P: 2
O: 8 (4×2)
Ca: 3
Cl: 6
Right:
Ca: 3
P: 2
O: 8
Na: 6
Cl: 6
✔ Balanced!
Final answer for #3:
2Na₃PO₄ + 3CaCl₂ → Ca₃(PO₄)₂ + 6NaCl
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Final Answer:
1) Zn + Pb(NO₃)₂ → Zn(NO₃)₂ + Pb
2) 2AlBr₃ + 3Cl₂ → 2AlCl₃ + 3Br₂
3) 2Na₃PO₄ + 3CaCl₂ → Ca₃(PO₄)₂ + 6NaCl
Parent Tip: Review the logic above to help your child master the concept of writing word equations chemistry worksheet.