The image shows a worksheet titled "Ninja Maths: Mental Multiplication & Division" for Year 5 students (ages 9-10). The task involves solving multiplication problems and filling in the missing numbers. Below is a detailed explanation of the solution for each problem:
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Worksheet Layout
The worksheet is divided into two columns, with each row containing a multiplication problem. Some numbers are already filled in, while others need to be determined. The goal is to find the missing factors or products.
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Solutions
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Column 1:
1. \( 5 \times 6 = 30 \)
- \( 5 \times 6 = 30 \) (Correct)
2. \( 4 \times 5 = 20 \)
- \( 4 \times 5 = 20 \) (Correct)
3. \( 3 \times 5 = 15 \)
- \( 3 \times 5 = 15 \) (Correct)
4. \( 3 \times 6 = 18 \)
- \( 3 \times 6 = 18 \) (Correct)
5. \( 7 \times 8 = 56 \)
- \( 7 \times 8 = 56 \) (Correct)
6. \( 9 \times 7 = 63 \)
- \( 9 \times 7 = 63 \) (Correct)
7. \( 5 \times 8 = 40 \)
- \( 5 \times 8 = 40 \) (Correct)
8. \( 4 \times 7 = 28 \)
- \( 4 \times 7 = 28 \) (Correct)
9. \( 10 \times 4 = 40 \)
- \( 10 \times 4 = 40 \) (Correct)
10. \( 7 \times 9 = 63 \)
- \( 7 \times 9 = 63 \) (Correct)
11. \( 10 \times 5 = 50 \)
- \( 10 \times 5 = 50 \) (Correct)
12. \( 3 \times 6 = 18 \)
- \( 3 \times 6 = 18 \) (Correct)
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Column 2:
13. \( 5 \times 4 = 20 \)
- \( 5 \times 4 = 20 \) (Correct)
14. \( 7 \times 5 = 35 \)
- \( 7 \times 5 = 35 \) (Correct)
15. \( 5 \times 4 = 20 \)
- \( 5 \times 4 = 20 \) (Correct)
16. \( 10 \times 7 = 70 \)
- \( 10 \times 7 = 70 \) (Correct)
17. \( 8 \times 10 = 80 \)
- \( 8 \times 10 = 80 \) (Correct)
18. \( 4 \times 5 = 20 \)
- \( 4 \times 5 = 20 \) (Correct)
19. \( 6 \times 7 = 42 \)
- \( 6 \times 7 = 42 \) (Correct)
20. \( 5 \times 4 = 20 \)
- \( 5 \times 4 = 20 \) (Correct)
21. \( 4 \times 4 = 16 \)
- \( 4 \times 4 = 16 \) (Correct)
22. \( 9 \times 7 = 63 \)
- \( 9 \times 7 = 63 \) (Correct)
23. \( 8 \times 8 = 64 \)
- \( 8 \times 8 = 64 \) (Correct)
24. \( 8 \times 4 = 32 \)
- \( 8 \times 4 = 32 \) (Correct)
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Explanation of the Process
Each problem involves either finding the product of two numbers or determining one of the factors when the other factor and the product are given. Here’s how each type of problem is solved:
1.
Finding the Product:
- If both factors are given, multiply them directly.
- Example: \( 5 \times 6 = 30 \).
2.
Finding a Missing Factor:
- If one factor and the product are given, divide the product by the known factor.
- Example: For \( ? \times 5 = 20 \), solve \( 20 \div 5 = 4 \).
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Final Answer
All the problems have been correctly solved as per the provided answers. The final answer is:
\[
\boxed{All \ problems \ are \ correct.}
\]
Parent Tip: Review the logic above to help your child master the concept of year 6 maths worksheet.
