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Exponent Rules worksheet with 10 problems to simplify expressions.

Worksheet titled "Exponent Rules (A)" with 10 math problems involving simplifying expressions using exponent rules.

Worksheet titled "Exponent Rules (A)" with 10 math problems involving simplifying expressions using exponent rules.

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Show Answer Key & Explanations Step-by-step solution for: Mixed Exponent Rules (With Negatives) (A)
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Let’s go through each problem one by one, using exponent rules. We’ll simplify step by step and check our work.

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Problem 1:
$\frac{7^6}{7^4}$

Rule: When dividing powers with the same base, subtract exponents: $a^m / a^n = a^{m-n}$

So: $7^{6-4} = 7^2 = 49$

✔ Check: $7^6 = 117649$, $7^4 = 2401$, $117649 ÷ 2401 = 49$ → Correct.

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Problem 2:
$\frac{4^1}{4^0}$

Any number to the power of 0 is 1 → $4^0 = 1$

So: $\frac{4}{1} = 4$

✔ Check: Direct calculation → Correct.

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Problem 3:
$2^6 \cdot 2^{-9}$

Rule: Multiply powers with same base → add exponents: $a^m \cdot a^n = a^{m+n}$

So: $2^{6 + (-9)} = 2^{-3} = \frac{1}{2^3} = \frac{1}{8}$

✔ Check: $2^6 = 64$, $2^{-9} = 1/512$, $64 × (1/512) = 64/512 = 1/8$ → Correct.

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Problem 4:
$((-4)^9)^9$

Rule: Power of a power → multiply exponents: $(a^m)^n = a^{m·n}$

So: $(-4)^{9×9} = (-4)^{81}$

Since 81 is odd, negative base stays negative → answer is $-4^{81}$? Wait — actually, we write it as $(-4)^{81}$, which is a huge negative number, but we leave it in exponential form unless asked to compute.

But note: sometimes people confuse this with $-(4^{81})$. But here, since the base is -4 and raised to an odd power, it's negative. However, for simplification purposes, we just write $(-4)^{81}$.

Actually, let’s double-check: The rule applies directly: $((-4)^9)^9 = (-4)^{81}$

✔ No further simplification needed — that’s the simplified form.

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Problem 5:
$\frac{3^2}{3^3}$

Same base → subtract exponents: $3^{2-3} = 3^{-1} = \frac{1}{3}$

✔ Check: $9 / 27 = 1/3$ → Correct.

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Problem 6:
$(-4)^7 \cdot (-8)^7$

Different bases! But both have exponent 7 → use rule: $a^n \cdot b^n = (a·b)^n$

So: $[(-4) · (-8)]^7 = (32)^7$

Because negative times negative is positive.

✔ Check: Each term is negative, multiplied together → positive. And 4×8=32 → Correct.

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Problem 7:
$\frac{(-2)^{-8}}{(-2)^{-1}}$

Same base → subtract exponents: $(-2)^{-8 - (-1)} = (-2)^{-7}$

Which equals $\frac{1}{(-2)^7} = \frac{1}{-128} = -\frac{1}{128}$

Wait — let’s be careful:

Exponent subtraction: $-8 - (-1) = -8 + 1 = -7$

So: $(-2)^{-7} = \frac{1}{(-2)^7} = \frac{1}{-128} = -\frac{1}{128}$

✔ Check: Numerator: $(-2)^{-8} = 1/256$, Denominator: $(-2)^{-1} = -1/2$, so division: $(1/256) ÷ (-1/2) = (1/256) × (-2) = -2/256 = -1/128$ → Correct.

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Problem 8:
$(-8)^2 \cdot (-8)^{-5}$

Same base → add exponents: $(-8)^{2 + (-5)} = (-8)^{-3} = \frac{1}{(-8)^3} = \frac{1}{-512} = -\frac{1}{512}$

✔ Check: $(-8)^2 = 64$, $(-8)^{-5} = 1/(-32768)$, so 64 × (1/-32768) = -64/32768 = -1/512 → Correct.

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Problem 9:
$(-5)^{-4} \cdot 3^{-4}$

Different bases, same exponent → combine: $[(-5) · 3]^{-4} = (-15)^{-4}$

Now, $(-15)^{-4} = \frac{1}{(-15)^4} = \frac{1}{50625}$ because even power makes it positive.

Alternatively, you can write as $\left(\frac{1}{-15}\right)^4 = \left(\frac{1}{15}\right)^4 = \frac{1}{50625}$

✔ Check: $(-5)^{-4} = 1/625$, $3^{-4} = 1/81$, product = 1/(625×81) = 1/50625 → Correct.

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Problem 10:
$(6^{-9})^1$

Power of 1 doesn’t change anything → $6^{-9} = \frac{1}{6^9}$

We can leave it like that or compute denominator if needed, but usually left as fraction.

$6^9 = 10077696$, so $\frac{1}{10077696}$, but better to keep as $6^{-9}$ or $\frac{1}{6^9}$

The problem says “simplify”, so either is acceptable, but typically we write without negative exponents.

So final answer: $\frac{1}{6^9}$

✔ Check: Raising to power 1 does nothing → Correct.

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Final Answers Summary:

1. 49
2. 4
3. 1/8
4. $(-4)^{81}$
5. 1/3
6. $32^7$
7. -1/128
8. -1/512
9. 1/50625
10. 1/6⁹

But wait — Problem 4: Should we write it as $-4^{81}$? No! Because $(-4)^{81}$ means the entire -4 is raised to 81st power. Since 81 is odd, result is negative, but writing $-4^{81}$ would mean -(4^81), which is different. So we must keep parentheses: $(-4)^{81}$

Similarly, Problem 6: $32^7$ is correct.

Problem 9: $(-15)^{-4} = \frac{1}{(-15)^4} = \frac{1}{50625}$ — yes.

All verified.

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Final Answer:
1. 49
2. 4
3. $\frac{1}{8}$
4. $(-4)^{81}$
5. $\frac{1}{3}$
6. $32^7$
7. $-\frac{1}{128}$
8. $-\frac{1}{512}$
9. $\frac{1}{50625}$
10. $\frac{1}{6^9}$
Parent Tip: Review the logic above to help your child master the concept of zero and negative exponents worksheet pdf.
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