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Practice worksheet for adding and subtracting radical expressions with simplification problems.

Worksheet titled "Adding & Subtracting Radical Expressions" with algebraic problems involving square roots and simplification exercises.

Worksheet titled "Adding & Subtracting Radical Expressions" with algebraic problems involving square roots and simplification exercises.

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Show Answer Key & Explanations Step-by-step solution for: Algebra 2 Homework Worksheets / Review Worksheets by The Engineer
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To solve the problems involving adding, subtracting, and multiplying radical expressions, we need to follow specific rules. Let's go through each type of problem step by step.

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1. Adding or Subtracting Radical Expressions



#### Rule:
- You can only add or subtract radical expressions if they have the same radicand (the number under the square root). If the radicands are different, you cannot combine them.

#### Examples:

1. Simplify: \( 4\sqrt{5} + 3\sqrt{5} \)
- Both terms have the same radicand (\(\sqrt{5}\)).
- Combine the coefficients: \( 4 + 3 = 7 \).
- Result: \( 7\sqrt{5} \).

2. Simplify: \( 6\sqrt{3} + 2\sqrt{3} \)
- Both terms have the same radicand (\(\sqrt{3}\)).
- Combine the coefficients: \( 6 + 2 = 8 \).
- Result: \( 8\sqrt{3} \).

3. Simplify: \( 16\sqrt{2} + 9\sqrt{2} \)
- Both terms have the same radicand (\(\sqrt{2}\)).
- Combine the coefficients: \( 16 + 9 = 25 \).
- Result: \( 25\sqrt{2} \).

4. Simplify: \( 7\sqrt{3} + 2\sqrt{3} \)
- Both terms have the same radicand (\(\sqrt{3}\)).
- Combine the coefficients: \( 7 + 2 = 9 \).
- Result: \( 9\sqrt{3} \).

5. Simplify: \( 4\sqrt{7} + \sqrt{7} \)
- Both terms have the same radicand (\(\sqrt{7}\)).
- Combine the coefficients: \( 4 + 1 = 5 \).
- Result: \( 5\sqrt{7} \).

6. Simplify: \( 3\sqrt{11} + 4\sqrt{11} \)
- Both terms have the same radicand (\(\sqrt{11}\)).
- Combine the coefficients: \( 3 + 4 = 7 \).
- Result: \( 7\sqrt{11} \).

7. Simplify: \( 5\sqrt{13} + 3\sqrt{13} \)
- Both terms have the same radicand (\(\sqrt{13}\)).
- Combine the coefficients: \( 5 + 3 = 8 \).
- Result: \( 8\sqrt{13} \).

8. Simplify: \( 6\sqrt{4} + 4\sqrt{4} \)
- Both terms have the same radicand (\(\sqrt{4}\)).
- Simplify \(\sqrt{4}\): \(\sqrt{4} = 2\).
- Combine the coefficients: \( 6 + 4 = 10 \).
- Result: \( 10 \cdot 2 = 20 \).

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2. Multiplying Radical Expressions



#### Rule:
- When multiplying radical expressions, you can multiply the coefficients together and the radicands together.
- Use the property: \( \sqrt{a} \cdot \sqrt{b} = \sqrt{a \cdot b} \).

#### Examples:

1. Simplify: \( (3\sqrt{2})(2\sqrt{3}) \)
- Multiply the coefficients: \( 3 \cdot 2 = 6 \).
- Multiply the radicands: \( \sqrt{2} \cdot \sqrt{3} = \sqrt{6} \).
- Result: \( 6\sqrt{6} \).

2. Simplify: \( (2\sqrt{5})(3\sqrt{2}) \)
- Multiply the coefficients: \( 2 \cdot 3 = 6 \).
- Multiply the radicands: \( \sqrt{5} \cdot \sqrt{2} = \sqrt{10} \).
- Result: \( 6\sqrt{10} \).

3. Simplify: \( (4\sqrt{3})(5\sqrt{7}) \)
- Multiply the coefficients: \( 4 \cdot 5 = 20 \).
- Multiply the radicands: \( \sqrt{3} \cdot \sqrt{7} = \sqrt{21} \).
- Result: \( 20\sqrt{21} \).

4. Simplify: \( (5\sqrt{3})^2 \)
- Square both the coefficient and the radicand:
\[
(5\sqrt{3})^2 = 5^2 \cdot (\sqrt{3})^2 = 25 \cdot 3 = 75.
\]
- Result: \( 75 \).

5. Simplify: \( (-\sqrt{5})(x + 2\sqrt{5}) \)
- Distribute \(-\sqrt{5}\):
\[
(-\sqrt{5})(x) + (-\sqrt{5})(2\sqrt{5}) = -x\sqrt{5} - 2(\sqrt{5} \cdot \sqrt{5}) = -x\sqrt{5} - 2 \cdot 5 = -x\sqrt{5} - 10.
\]
- Result: \( -x\sqrt{5} - 10 \).

6. Simplify: \( (2\sqrt{3})(x - \sqrt{3}) \)
- Distribute \(2\sqrt{3}\):
\[
(2\sqrt{3})(x) + (2\sqrt{3})(-\sqrt{3}) = 2x\sqrt{3} - 2(\sqrt{3} \cdot \sqrt{3}) = 2x\sqrt{3} - 2 \cdot 3 = 2x\sqrt{3} - 6.
\]
- Result: \( 2x\sqrt{3} - 6 \).

7. Simplify: \( (3\sqrt{2})(x + 3\sqrt{2}) \)
- Distribute \(3\sqrt{2}\):
\[
(3\sqrt{2})(x) + (3\sqrt{2})(3\sqrt{2}) = 3x\sqrt{2} + 3 \cdot 3 \cdot (\sqrt{2} \cdot \sqrt{2}) = 3x\sqrt{2} + 9 \cdot 2 = 3x\sqrt{2} + 18.
\]
- Result: \( 3x\sqrt{2} + 18 \).

8. Simplify: \( (2 - 3\sqrt{5})(2 + 3\sqrt{5}) \)
- Use the difference of squares formula: \( (a - b)(a + b) = a^2 - b^2 \).
\[
(2 - 3\sqrt{5})(2 + 3\sqrt{5}) = 2^2 - (3\sqrt{5})^2 = 4 - 9 \cdot 5 = 4 - 45 = -41.
\]
- Result: \( -41 \).

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Final Answers:



1. \( 7\sqrt{5} \)
2. \( 8\sqrt{3} \)
3. \( 25\sqrt{2} \)
4. \( 9\sqrt{3} \)
5. \( 5\sqrt{7} \)
6. \( 7\sqrt{11} \)
7. \( 8\sqrt{13} \)
8. \( 20 \)

9. \( 6\sqrt{6} \)
10. \( 6\sqrt{10} \)
11. \( 20\sqrt{21} \)
12. \( 75 \)
13. \( -x\sqrt{5} - 10 \)
14. \( 2x\sqrt{3} - 6 \)
15. \( 3x\sqrt{2} + 18 \)
16. \( -41 \)

Boxed Final Answer:
\[
\boxed{
\begin{array}{ll}
1. & 7\sqrt{5} \\
2. & 8\sqrt{3} \\
3. & 25\sqrt{2} \\
4. & 9\sqrt{3} \\
5. & 5\sqrt{7} \\
6. & 7\sqrt{11} \\
7. & 8\sqrt{13} \\
8. & 20 \\
9. & 6\sqrt{6} \\
10. & 6\sqrt{10} \\
11. & 20\sqrt{21} \\
12. & 75 \\
13. & -x\sqrt{5} - 10 \\
14. & 2x\sqrt{3} - 6 \\
15. & 3x\sqrt{2} + 18 \\
16. & -41 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of 10th grade algebra 2 worksheet.
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