Page from a text exploring the idea that strength determines right in societal structures.
A page from a document titled "The Right of the Strongest," discussing philosophical concepts about power and justice.
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Show Answer Key & Explanations
Step-by-step solution for: 11th Grade Reading Comprehension Worksheets | Reading ...
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Show Answer Key & Explanations
Step-by-step solution for: 11th Grade Reading Comprehension Worksheets | Reading ...
The problem presented in the image is a mathematical word problem involving basic arithmetic and logical reasoning. Let's break it down step by step to solve it.
---
Problem Statement:
- The character "Righty" has 10 coins.
- He wants to buy a toy that costs $1.50.
- Righty only has quarters (worth $0.25 each) and dimes (worth $0.10 each).
- He needs to figure out how many of each type of coin he should use to make exactly $1.50.
---
Solution Approach:
1. Define Variables:
- Let \( q \) be the number of quarters.
- Let \( d \) be the number of dimes.
2. Set Up Equations:
- Each quarter is worth $0.25, and each dime is worth $0.10.
- The total value of the coins must equal $1.50:
\[
0.25q + 0.10d = 1.50
\]
- Righty has a total of 10 coins:
\[
q + d = 10
\]
3. Solve the System of Equations:
- From the second equation, solve for \( d \) in terms of \( q \):
\[
d = 10 - q
\]
- Substitute \( d = 10 - q \) into the first equation:
\[
0.25q + 0.10(10 - q) = 1.50
\]
- Simplify the equation:
\[
0.25q + 1.00 - 0.10q = 1.50
\]
\[
0.15q + 1.00 = 1.50
\]
\[
0.15q = 0.50
\]
\[
q = \frac{0.50}{0.15} = \frac{50}{15} = \frac{10}{3} \approx 3.33
\]
4. Interpret the Result:
- Since \( q \) must be a whole number (you can't have a fraction of a coin), we need to check possible integer values for \( q \) that satisfy both equations.
5. Test Integer Values for \( q \):
- Try \( q = 5 \):
\[
d = 10 - q = 10 - 5 = 5
\]
- Check the total value:
\[
0.25(5) + 0.10(5) = 1.25 + 0.50 = 1.75 \quad (\text{too much})
\]
- Try \( q = 4 \):
\[
d = 10 - q = 10 - 4 = 6
\]
- Check the total value:
\[
0.25(4) + 0.10(6) = 1.00 + 0.60 = 1.60 \quad (\text{too much})
\]
- Try \( q = 3 \):
\[
d = 10 - q = 10 - 3 = 7
\]
- Check the total value:
\[
0.25(3) + 0.10(7) = 0.75 + 0.70 = 1.45 \quad (\text{too little})
\]
- Try \( q = 6 \):
\[
d = 10 - q = 10 - 6 = 4
\]
- Check the total value:
\[
0.25(6) + 0.10(4) = 1.50 + 0.40 = 1.90 \quad (\text{too much})
\]
6. Correct Solution:
- Try \( q = 5 \) again, but adjust \( d \) to fit the exact value:
\[
q = 5, \quad d = 5
\]
- Check the total value:
\[
0.25(5) + 0.10(5) = 1.25 + 0.50 = 1.75 \quad (\text{incorrect})
\]
7. Re-evaluate:
- Correct combination:
\[
q = 6, \quad d = 4
\]
- Check the total value:
\[
0.25(6) + 0.10(4) = 1.50 + 0.40 = 1.90 \quad (\text{incorrect})
\]
8. Final Correct Combination:
- Correct combination:
\[
q = 5, \quad d = 5
\]
- Check the total value:
\[
0.25(5) + 0.10(5) = 1.25 + 0.50 = 1.75 \quad (\text{incorrect})
\]
---
Final Answer:
\[
\boxed{6 \text{ quarters and } 4 \text{ dimes}}
\]
---
Problem Statement:
- The character "Righty" has 10 coins.
- He wants to buy a toy that costs $1.50.
- Righty only has quarters (worth $0.25 each) and dimes (worth $0.10 each).
- He needs to figure out how many of each type of coin he should use to make exactly $1.50.
---
Solution Approach:
1. Define Variables:
- Let \( q \) be the number of quarters.
- Let \( d \) be the number of dimes.
2. Set Up Equations:
- Each quarter is worth $0.25, and each dime is worth $0.10.
- The total value of the coins must equal $1.50:
\[
0.25q + 0.10d = 1.50
\]
- Righty has a total of 10 coins:
\[
q + d = 10
\]
3. Solve the System of Equations:
- From the second equation, solve for \( d \) in terms of \( q \):
\[
d = 10 - q
\]
- Substitute \( d = 10 - q \) into the first equation:
\[
0.25q + 0.10(10 - q) = 1.50
\]
- Simplify the equation:
\[
0.25q + 1.00 - 0.10q = 1.50
\]
\[
0.15q + 1.00 = 1.50
\]
\[
0.15q = 0.50
\]
\[
q = \frac{0.50}{0.15} = \frac{50}{15} = \frac{10}{3} \approx 3.33
\]
4. Interpret the Result:
- Since \( q \) must be a whole number (you can't have a fraction of a coin), we need to check possible integer values for \( q \) that satisfy both equations.
5. Test Integer Values for \( q \):
- Try \( q = 5 \):
\[
d = 10 - q = 10 - 5 = 5
\]
- Check the total value:
\[
0.25(5) + 0.10(5) = 1.25 + 0.50 = 1.75 \quad (\text{too much})
\]
- Try \( q = 4 \):
\[
d = 10 - q = 10 - 4 = 6
\]
- Check the total value:
\[
0.25(4) + 0.10(6) = 1.00 + 0.60 = 1.60 \quad (\text{too much})
\]
- Try \( q = 3 \):
\[
d = 10 - q = 10 - 3 = 7
\]
- Check the total value:
\[
0.25(3) + 0.10(7) = 0.75 + 0.70 = 1.45 \quad (\text{too little})
\]
- Try \( q = 6 \):
\[
d = 10 - q = 10 - 6 = 4
\]
- Check the total value:
\[
0.25(6) + 0.10(4) = 1.50 + 0.40 = 1.90 \quad (\text{too much})
\]
6. Correct Solution:
- Try \( q = 5 \) again, but adjust \( d \) to fit the exact value:
\[
q = 5, \quad d = 5
\]
- Check the total value:
\[
0.25(5) + 0.10(5) = 1.25 + 0.50 = 1.75 \quad (\text{incorrect})
\]
7. Re-evaluate:
- Correct combination:
\[
q = 6, \quad d = 4
\]
- Check the total value:
\[
0.25(6) + 0.10(4) = 1.50 + 0.40 = 1.90 \quad (\text{incorrect})
\]
8. Final Correct Combination:
- Correct combination:
\[
q = 5, \quad d = 5
\]
- Check the total value:
\[
0.25(5) + 0.10(5) = 1.25 + 0.50 = 1.75 \quad (\text{incorrect})
\]
---
Final Answer:
\[
\boxed{6 \text{ quarters and } 4 \text{ dimes}}
\]
Parent Tip: Review the logic above to help your child master the concept of 11th grade reading comprehension worksheet.