2 Digit Math Worksheets | Activity Shelter | Division worksheets ... - Free Printable

Problem: Solve the division problems and find the quotients with remainders.

The task involves dividing each number by the divisor provided and expressing the result as a quotient with a remainder. Let's solve each problem step by step.

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#### Row 1:
1. \( 6 \div 27 \)
- Dividend: 27, Divisor: 6
- \( 27 \div 6 = 4 \) with a remainder of \( 3 \) (since \( 6 \times 4 = 24 \) and \( 27 - 24 = 3 \))
- Answer: \( 4 \text{ R } 3 \)

2. \( 7 \div 50 \)
- Dividend: 50, Divisor: 7
- \( 50 \div 7 = 7 \) with a remainder of \( 1 \) (since \( 7 \times 7 = 49 \) and \( 50 - 49 = 1 \))
- Answer: \( 7 \text{ R } 1 \)

3. \( 8 \div 70 \)
- Dividend: 70, Divisor: 8
- \( 70 \div 8 = 8 \) with a remainder of \( 6 \) (since \( 8 \times 8 = 64 \) and \( 70 - 64 = 6 \))
- Answer: \( 8 \text{ R } 6 \)

4. \( 4 \div 31 \)
- Dividend: 31, Divisor: 4
- \( 31 \div 4 = 7 \) with a remainder of \( 3 \) (since \( 4 \times 7 = 28 \) and \( 31 - 28 = 3 \))
- Answer: \( 7 \text{ R } 3 \)

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#### Row 2:
5. \( 4 \div 18 \)
- Dividend: 18, Divisor: 4
- \( 18 \div 4 = 4 \) with a remainder of \( 2 \) (since \( 4 \times 4 = 16 \) and \( 18 - 16 = 2 \))
- Answer: \( 4 \text{ R } 2 \)

6. \( 5 \div 32 \)
- Dividend: 32, Divisor: 5
- \( 32 \div 5 = 6 \) with a remainder of \( 2 \) (since \( 5 \times 6 = 30 \) and \( 32 - 30 = 2 \))
- Answer: \( 6 \text{ R } 2 \)

7. \( 2 \div 9 \)
- Dividend: 9, Divisor: 2
- \( 9 \div 2 = 4 \) with a remainder of \( 1 \) (since \( 2 \times 4 = 8 \) and \( 9 - 8 = 1 \))
- Answer: \( 4 \text{ R } 1 \)

8. \( 9 \div 86 \)
- Dividend: 86, Divisor: 9
- \( 86 \div 9 = 9 \) with a remainder of \( 5 \) (since \( 9 \times 9 = 81 \) and \( 86 - 81 = 5 \))
- Answer: \( 9 \text{ R } 5 \)

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#### Row 3:
9. \( 8 \div 27 \)
- Dividend: 27, Divisor: 8
- \( 27 \div 8 = 3 \) with a remainder of \( 3 \) (since \( 8 \times 3 = 24 \) and \( 27 - 24 = 3 \))
- Answer: \( 3 \text{ R } 3 \)

10. \( 6 \div 51 \)
- Dividend: 51, Divisor: 6
- \( 51 \div 6 = 8 \) with a remainder of \( 3 \) (since \( 6 \times 8 = 48 \) and \( 51 - 48 = 3 \))
- Answer: \( 8 \text{ R } 3 \)

11. \( 8 \div 15 \)
- Dividend: 15, Divisor: 8
- \( 15 \div 8 = 1 \) with a remainder of \( 7 \) (since \( 8 \times 1 = 8 \) and \( 15 - 8 = 7 \))
- Answer: \( 1 \text{ R } 7 \)

12. \( 5 \div 12 \)
- Dividend: 12, Divisor: 5
- \( 12 \div 5 = 2 \) with a remainder of \( 2 \) (since \( 5 \times 2 = 10 \) and \( 12 - 10 = 2 \))
- Answer: \( 2 \text{ R } 2 \)

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#### Row 4:
13. \( 7 \div 60 \)
- Dividend: 60, Divisor: 7
- \( 60 \div 7 = 8 \) with a remainder of \( 4 \) (since \( 7 \times 8 = 56 \) and \( 60 - 56 = 4 \))
- Answer: \( 8 \text{ R } 4 \)

14. \( 3 \div 25 \)
- Dividend: 25, Divisor: 3
- \( 25 \div 3 = 8 \) with a remainder of \( 1 \) (since \( 3 \times 8 = 24 \) and \( 25 - 24 = 1 \))
- Answer: \( 8 \text{ R } 1 \)

15. \( 5 \div 16 \)
- Dividend: 16, Divisor: 5
- \( 16 \div 5 = 3 \) with a remainder of \( 1 \) (since \( 5 \times 3 = 15 \) and \( 16 - 15 = 1 \))
- Answer: \( 3 \text{ R } 1 \)

16. \( 6 \div 22 \)
- Dividend: 22, Divisor: 6
- \( 22 \div 6 = 3 \) with a remainder of \( 4 \) (since \( 6 \times 3 = 18 \) and \( 22 - 18 = 4 \))
- Answer: \( 3 \text{ R } 4 \)

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#### Row 5:
17. \( 9 \div 42 \)
- Dividend: 42, Divisor: 9
- \( 42 \div 9 = 4 \) with a remainder of \( 6 \) (since \( 9 \times 4 = 36 \) and \( 42 - 36 = 6 \))
- Answer: \( 4 \text{ R } 6 \)

18. \( 8 \div 19 \)
- Dividend: 19, Divisor: 8
- \( 19 \div 8 = 2 \) with a remainder of \( 3 \) (since \( 8 \times 2 = 16 \) and \( 19 - 16 = 3 \))
- Answer: \( 2 \text{ R } 3 \)

19. \( 7 \div 51 \)
- Dividend: 51, Divisor: 7
- \( 51 \div 7 = 7 \) with a remainder of \( 2 \) (since \( 7 \times 7 = 49 \) and \( 51 - 49 = 2 \))
- Answer: \( 7 \text{ R } 2 \)

20. \( 6 \div 26 \)
- Dividend: 26, Divisor: 6
- \( 26 \div 6 = 4 \) with a remainder of \( 2 \) (since \( 6 \times 4 = 24 \) and \( 26 - 24 = 2 \))
- Answer: \( 4 \text{ R } 2 \)

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#### Row 6:
21. \( 3 \div 5 \)
- Dividend: 5, Divisor: 3
- \( 5 \div 3 = 1 \) with a remainder of \( 2 \) (since \( 3 \times 1 = 3 \) and \( 5 - 3 = 2 \))
- Answer: \( 1 \text{ R } 2 \)

22. \( 9 \div 87 \)
- Dividend: 87, Divisor: 9
- \( 87 \div 9 = 9 \) with a remainder of \( 6 \) (since \( 9 \times 9 = 81 \) and \( 87 - 81 = 6 \))
- Answer: \( 9 \text{ R } 6 \)

23. \( 5 \div 38 \)
- Dividend: 38, Divisor: 5
- \( 38 \div 5 = 7 \) with a remainder of \( 3 \) (since \( 5 \times 7 = 35 \) and \( 38 - 35 = 3 \))
- Answer: \( 7 \text{ R } 3 \)

24. \( 7 \div 39 \)
- Dividend: 39, Divisor: 7
- \( 39 \div 7 = 5 \) with a remainder of \( 4 \) (since \( 7 \times 5 = 35 \) and \( 39 - 35 = 4 \))
- Answer: \( 5 \text{ R } 4 \)

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Final Answers:

\[
\boxed{
\begin{array}{cccc}
4 \text{ R } 3 & 7 \text{ R } 1 & 8 \text{ R } 6 & 7 \text{ R } 3 \\
4 \text{ R } 2 & 6 \text{ R } 2 & 4 \text{ R } 1 & 9 \text{ R } 5 \\
3 \text{ R } 3 & 8 \text{ R } 3 & 1 \text{ R } 7 & 2 \text{ R } 2 \\
8 \text{ R } 4 & 8 \text{ R } 1 & 3 \text{ R } 1 & 3 \text{ R } 4 \\
4 \text{ R } 6 & 2 \text{ R } 3 & 7 \text{ R } 2 & 4 \text{ R } 2 \\
1 \text{ R } 2 & 9 \text{ R } 6 & 7 \text{ R } 3 & 5 \text{ R } 4 \\
\end{array}
}
\]