The image appears to be a worksheet containing a series of multiplication problems. Each row consists of five numbers, where the first four are given and the fifth is marked with an "x" (e.g., \( x322 \)), indicating that it needs to be calculated as the product of the first two numbers.
Task:
For each row, calculate the product of the first two numbers and fill in the missing value marked with an "x".
Solution:
#### Row 1:
- Numbers: \( 823, 743, 124, 298, 112, 893 \)
- Missing value: \( x322 \)
- Calculation: \( 823 \times 743 = 610,589 \)
- Result: \( x322 = 610,589 \)
#### Row 2:
- Numbers: \( 312, 723, 743, 212, 877, 187 \)
- Missing value: \( x122 \)
- Calculation: \( 312 \times 723 = 225,776 \)
- Result: \( x122 = 225,776 \)
#### Row 3:
- Numbers: \( 543, 975, 138, 278, 107, 124 \)
- Missing value: \( x905 \)
- Calculation: \( 543 \times 975 = 529,875 \)
- Result: \( x905 = 529,875 \)
#### Row 4:
- Numbers: \( 532, 998, 923, 209, 112, 118 \)
- Missing value: \( x678 \)
- Calculation: \( 532 \times 998 = 531,436 \)
- Result: \( x678 = 531,436 \)
#### Row 5:
- Numbers: \( 980, 567, 989, 245, 237, 419 \)
- Missing value: \( x937 \)
- Calculation: \( 980 \times 567 = 555,060 \)
- Result: \( x937 = 555,060 \)
#### Row 6:
- Numbers: \( 326, 265, 154, 235, 137, 378 \)
- Missing value: \( x487 \)
- Calculation: \( 326 \times 265 = 86,390 \)
- Result: \( x487 = 86,390 \)
Final Answer:
\[
\boxed{
\begin{array}{c}
x322 = 610,589 \\
x122 = 225,776 \\
x905 = 529,875 \\
x678 = 531,436 \\
x937 = 555,060 \\
x487 = 86,390
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of 3 digit multiplication worksheet grade 5.