Math worksheet for practicing number forms and conversions.

Let’s go through each problem step by step. We’ll solve them one at a time, carefully checking our work.

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1) Write these numbers in words.

We read the number from left to right, grouping by thousands, hundreds, tens, and ones.

a) 4578
→ 4000 = four thousand
→ 500 = five hundred
→ 70 = seventy
→ 8 = eight
So: four thousand five hundred seventy-eight

b) 3019
→ 3000 = three thousand
→ 0 hundreds → skip
→ 10 = ten
→ 9 = nine → so “nineteen”
So: three thousand nineteen

c) 3000
→ Just three thousand → three thousand

d) 2987
→ 2000 = two thousand
→ 900 = nine hundred
→ 80 = eighty
→ 7 = seven
So: two thousand nine hundred eighty-seven

e) 8730
→ 8000 = eight thousand
→ 700 = seven hundred
→ 30 = thirty
→ 0 ones → stop
So: eight thousand seven hundred thirty

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2) Write these numbers in standard form.

This means turning worded numbers into digits.

a) Six thousand four hundred and one
→ 6000 + 400 + 1 = 6401

b) Eight thousand two hundred and twelve
→ 8000 + 200 + 12 = 8212

c) One thousand and one
→ 1000 + 1 = 1001

d) Three thousand three hundred and thirteen
→ 3000 + 300 + 13 = 3313

e) Seven thousand four hundred and thirty one
→ 7000 + 400 + 31 = 7431

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3) Write the number in its expanded form.

Expanded form breaks the number into place values (thousands, hundreds, tens, ones).

a) 8765
→ 8000 + 700 + 60 + 5

b) 9999
→ 9000 + 900 + 90 + 9

c) 2323
→ 2000 + 300 + 20 + 3

d) 1016
→ 1000 + 0 + 10 + 6 → but we don’t write zero places usually → 1000 + 10 + 6

Wait — actually, for expanded form, we should include all place values even if zero? Let’s check common practice.

In most elementary worksheets, they expect you to show only non-zero parts unless specified otherwise. But sometimes they want full breakdown.

Looking at question 4, it shows addition with zeros implied (like 8000 + 100 + 7), so probably we can omit zero terms.

But let’s be safe — since 1016 has no hundreds, we write:

→ 1000 + 10 + 6

Similarly:

e) 9087
→ 9000 + 0 + 80 + 7 → again, skip zero → 9000 + 80 + 7

Actually, let me double-check with standard definition.

Standard expanded form often includes every place value, even if zero. For example, 1016 = 1000 + 0×100 + 10 + 6.

But in many school worksheets, especially at this level, they accept omitting zero terms.

Looking at Question 4, part c is “8000 + 100 + 7”, which skips the tens place (zero). So yes — we can omit zero terms.

So:

a) 8765 = 8000 + 700 + 60 + 5
b) 9999 = 9000 + 900 + 90 + 9
c) 2323 = 2000 + 300 + 20 + 3
d) 1016 = 1000 + 10 + 6
e) 9087 = 9000 + 80 + 7

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4) Write the numbers.

Just add up the given parts.

a) 4000 + 300 + 20 + 1 =
→ 4000 + 300 = 4300
→ 4300 + 20 = 4320
→ 4320 + 1 = 4321

b) 6000 + 200 + 30 + 9 =
→ 6000 + 200 = 6200
→ 6200 + 30 = 6230
→ 6230 + 9 = 6239

c) 8000 + 100 + 7 =
→ 8000 + 100 = 8100
→ 8100 + 7 = 8107

d) 5000 + 400 + 70 + 4 =
→ 5000 + 400 = 5400
→ 5400 + 70 = 5470
→ 5470 + 4 = 5474

e) 3000 + 4 =
→ 3004

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Now, let’s compile all answers neatly.

Final Answer:

1)
a) four thousand five hundred seventy-eight
b) three thousand nineteen
c) three thousand
d) two thousand nine hundred eighty-seven
e) eight thousand seven hundred thirty

2)
a) 6401
b) 8212
c) 1001
d) 3313
e) 7431

3)
a) 8000 + 700 + 60 + 5
b) 9000 + 900 + 90 + 9
c) 2000 + 300 + 20 + 3
d) 1000 + 10 + 6
e) 9000 + 80 + 7

4)
a) 4321
b) 6239
c) 8107
d) 5474
e) 3004