Problem Analysis:
The task involves finding the unknown factor in division and multiplication equations. Each equation is structured as follows:
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Division Equation: \( \text{Dividend} \div \text{Divisor} = \text{Quotient} \)
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Multiplication Equation: \( \text{Factor 1} \times \text{Factor 2} = \text{Product} \)
The goal is to determine the missing number in each equation, ensuring that both the division and multiplication statements are consistent.
Step-by-Step Solution:
#### 1. \( 50 \div \_ = 25 \) because, \( 25 \times \_ = 50 \)
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Division: \( 50 \div 2 = 25 \)
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Multiplication: \( 25 \times 2 = 50 \)
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Answer: \( 2 \)
#### 2. \( 34 \div \_ = 4 \) because, \( \_ \times 4 = 34 \)
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Division: \( 34 \div 8.5 = 4 \) (This is not an integer solution, so let's recheck the problem setup. Assuming it should be an integer, there might be a typo. Let's proceed with the next ones.)
#### 3. \( 42 \div \_ = 6 \) because, \( 42 \times \_ = 6 \)
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Division: \( 42 \div 7 = 6 \)
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Multiplication: \( 7 \times 6 = 42 \)
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Answer: \( 7 \)
#### 4. \( 81 \div \_ = 9 \) because, \( \_ \times 9 = 81 \)
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Division: \( 81 \div 9 = 9 \)
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Multiplication: \( 9 \times 9 = 81 \)
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Answer: \( 9 \)
#### 5. \( 54 \div \_ = 9 \) because, \( 8 \times \_ = 56 \)
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Division: \( 54 \div 6 = 9 \)
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Multiplication: \( 8 \times 7 = 56 \) (Note: The multiplication part is unrelated to the division part. The correct answer for the division is \( 6 \).)
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Answer: \( 6 \)
#### 6. \( 16 \div \_ = 4 \) because, \( \_ \times 4 = 16 \)
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Division: \( 16 \div 4 = 4 \)
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Multiplication: \( 4 \times 4 = 16 \)
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Answer: \( 4 \)
#### 7. \( 32 \div \_ = 8 \) because, \( 8 \times \_ = 32 \)
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Division: \( 32 \div 4 = 8 \)
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Multiplication: \( 8 \times 4 = 32 \)
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Answer: \( 4 \)
#### 8. \( 72 \div \_ = 8 \) because, \( \_ \times 8 = 72 \)
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Division: \( 72 \div 9 = 8 \)
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Multiplication: \( 9 \times 8 = 72 \)
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Answer: \( 9 \)
#### 9. \( 63 \div \_ = 7 \) because, \( 7 \times \_ = 63 \)
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Division: \( 63 \div 9 = 7 \)
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Multiplication: \( 7 \times 9 = 63 \)
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Answer: \( 9 \)
#### 10. \( 24 \div \_ = 4 \) because, \( \_ \times 4 = 24 \)
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Division: \( 24 \div 6 = 4 \)
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Multiplication: \( 6 \times 4 = 24 \)
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Answer: \( 6 \)
#### 11. \( 100 \div \_ = 4 \) because, \( 4 \times \_ = 100 \)
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Division: \( 100 \div 25 = 4 \)
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Multiplication: \( 4 \times 25 = 100 \)
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Answer: \( 25 \)
Final Answers:
\[
\boxed{2, 8.5, 7, 9, 6, 4, 4, 9, 9, 6, 25}
\]
However, note that the second equation (\( 34 \div \_ = 4 \)) does not yield an integer solution. If this is intentional, the answer would be \( 8.5 \). Otherwise, there might be a typo in the problem statement. All other answers are integers and consistent with the given format.
Parent Tip: Review the logic above to help your child master the concept of 3rd grade mathematics worksheet.