To solve the problem, we need to calculate the area of each shape by dividing them into rectangles and then summing up the areas of these rectangles. Let's go through each shape step by step.
---
Shape 1:
The shape can be divided into two rectangles:
1. A rectangle with dimensions \(8 \, \text{cm} \times 3 \, \text{cm}\).
2. A rectangle with dimensions \(5 \, \text{cm} \times 7 \, \text{cm}\).
#### Step 1: Calculate the area of the first rectangle
\[
\text{Area}_1 = 8 \, \text{cm} \times 3 \, \text{cm} = 24 \, \text{cm}^2
\]
#### Step 2: Calculate the area of the second rectangle
\[
\text{Area}_2 = 5 \, \text{cm} \times 7 \, \text{cm} = 35 \, \text{cm}^2
\]
#### Step 3: Sum the areas
\[
\text{Total Area} = \text{Area}_1 + \text{Area}_2 = 24 \, \text{cm}^2 + 35 \, \text{cm}^2 = 59 \, \text{cm}^2
\]
Answer for Shape 1:
\[
\boxed{59}
\]
---
Shape 2:
The shape can be divided into two rectangles:
1. A rectangle with dimensions \(10 \, \text{cm} \times 5 \, \text{cm}\).
2. A rectangle with dimensions \(6 \, \text{cm} \times 2 \, \text{cm}\) (since \(7 \, \text{cm} - 5 \, \text{cm} = 2 \, \text{cm}\)).
#### Step 1: Calculate the area of the first rectangle
\[
\text{Area}_1 = 10 \, \text{cm} \times 5 \, \text{cm} = 50 \, \text{cm}^2
\]
#### Step 2: Calculate the area of the second rectangle
\[
\text{Area}_2 = 6 \, \text{cm} \times 2 \, \text{cm} = 12 \, \text{cm}^2
\]
#### Step 3: Sum the areas
\[
\text{Total Area} = \text{Area}_1 + \text{Area}_2 = 50 \, \text{cm}^2 + 12 \, \text{cm}^2 = 62 \, \text{cm}^2
\]
Answer for Shape 2:
\[
\boxed{62}
\]
---
Shape 3:
The shape can be divided into two rectangles:
1. A rectangle with dimensions \(30 \, \text{mm} \times 5 \, \text{mm}\).
2. A rectangle with dimensions \(20 \, \text{mm} \times 7 \, \text{mm}\).
#### Step 1: Calculate the area of the first rectangle
\[
\text{Area}_1 = 30 \, \text{mm} \times 5 \, \text{mm} = 150 \, \text{mm}^2
\]
#### Step 2: Calculate the area of the second rectangle
\[
\text{Area}_2 = 20 \, \text{mm} \times 7 \, \text{mm} = 140 \, \text{mm}^2
\]
#### Step 3: Sum the areas
\[
\text{Total Area} = \text{Area}_1 + \text{Area}_2 = 150 \, \text{mm}^2 + 140 \, \text{mm}^2 = 290 \, \text{mm}^2
\]
Answer for Shape 3:
\[
\boxed{290}
\]
---
Shape 4:
The shape can be divided into two rectangles:
1. A rectangle with dimensions \(7 \, \text{m} \times 4 \, \text{m}\).
2. A rectangle with dimensions \(5 \, \text{m} \times 1 \, \text{m}\) (since \(7 \, \text{m} - 2 \, \text{m} = 5 \, \text{m}\)).
#### Step 1: Calculate the area of the first rectangle
\[
\text{Area}_1 = 7 \, \text{m} \times 4 \, \text{m} = 28 \, \text{m}^2
\]
#### Step 2: Calculate the area of the second rectangle
\[
\text{Area}_2 = 5 \, \text{m} \times 1 \, \text{m} = 5 \, \text{m}^2
\]
#### Step 3: Sum the areas
\[
\text{Total Area} = \text{Area}_1 + \text{Area}_2 = 28 \, \text{m}^2 + 5 \, \text{m}^2 = 33 \, \text{m}^2
\]
Answer for Shape 4:
\[
\boxed{33}
\]
---
Final Answers:
1. \(\boxed{59}\)
2. \(\boxed{62}\)
3. \(\boxed{290}\)
4. \(\boxed{33}\)
Parent Tip: Review the logic above to help your child master the concept of 4th grade area and perimeter worksheets.
