Multiplication Problems 4.2A worksheet with word problems and illustrations.

Problem Analysis and Solution

The worksheet contains 8 problems, most of which are multiplication problems. However, one problem is a "trick" problem that is not a multiplication problem. Let's solve each problem step by step and identify the trick problem.

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#### Problem 1:
A scale model of a Boeing 747 is 7m long. The real plane is 10 times longer. How long is the actual plane?

- Solution:
The length of the real plane is calculated by multiplying the length of the scale model by 10.
\[
\text{Length of real plane} = 7 \, \text{m} \times 10 = 70 \, \text{m}
\]

- Answer:
\[
\boxed{70 \, \text{m}}
\]

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#### Problem 2:
A box of eggs holds 6 eggs. If I had 20 full boxes, how many eggs would I have?

- Solution:
The total number of eggs is calculated by multiplying the number of eggs per box by the number of boxes.
\[
\text{Total eggs} = 6 \, \text{eggs/box} \times 20 \, \text{boxes} = 120 \, \text{eggs}
\]

- Answer:
\[
\boxed{120 \, \text{eggs}}
\]

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#### Problem 3:
A pack of 8 pens costs me \$10. I buy 12 packs. How many pens have I bought?

- Solution:
The total number of pens is calculated by multiplying the number of pens per pack by the number of packs.
\[
\text{Total pens} = 8 \, \text{pens/pack} \times 12 \, \text{packs} = 96 \, \text{pens}
\]

- Answer:
\[
\boxed{96 \, \text{pens}}
\]

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#### Problem 4:
A box of chocolates contains 30 chocolates. How many chocolates in 4 boxes?

- Solution:
The total number of chocolates is calculated by multiplying the number of chocolates per box by the number of boxes.
\[
\text{Total chocolates} = 30 \, \text{chocolates/box} \times 4 \, \text{boxes} = 120 \, \text{chocolates}
\]

- Answer:
\[
\boxed{120 \, \text{chocolates}}
\]

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#### Problem 5:
How many days in 20 weeks?

- Solution:
There are 7 days in a week. To find the total number of days in 20 weeks, multiply the number of weeks by the number of days per week.
\[
\text{Total days} = 20 \, \text{weeks} \times 7 \, \text{days/week} = 140 \, \text{days}
\]

- Answer:
\[
\boxed{140 \, \text{days}}
\]

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#### Problem 6:
A paperclip is made from 10cm of wire. How many paperclips could be made from 70cm of wire?

- Solution:
To find the number of paperclips, divide the total length of wire by the length of wire needed for one paperclip.
\[
\text{Number of paperclips} = \frac{70 \, \text{cm}}{10 \, \text{cm/paperclip}} = 7 \, \text{paperclips}
\]

- Answer:
\[
\boxed{7 \, \text{paperclips}}
\]

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#### Problem 7:
A ream contains 500 sheets of paper. How many sheets in 2 reams?

- Solution:
The total number of sheets is calculated by multiplying the number of sheets per ream by the number of reams.
\[
\text{Total sheets} = 500 \, \text{sheets/ream} \times 2 \, \text{reams} = 1000 \, \text{sheets}
\]

- Answer:
\[
\boxed{1000 \, \text{sheets}}
\]

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#### Problem 8:
How many seconds in 3 minutes?

- Solution:
There are 60 seconds in a minute. To find the total number of seconds in 3 minutes, multiply the number of minutes by the number of seconds per minute.
\[
\text{Total seconds} = 3 \, \text{minutes} \times 60 \, \text{seconds/minute} = 180 \, \text{seconds}
\]

- Answer:
\[
\boxed{180 \, \text{seconds}}
\]

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Identifying the Trick Problem:

The trick problem is Problem 6, which asks, "How many paperclips could be made from 70cm of wire?" This problem involves division, not multiplication. While the other problems require multiplication to solve, this one requires division.

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Final Answer:

\[
\boxed{6}
\] (The trick problem is Problem 6.)