Division worksheet for Grade 5 students to practice long division with 15 equations.

$Grade 5 division worksheet with 15 division problems for students to solve, featuring long division equations with numbers up to four digits.$

Grade 5 division worksheet with 15 division problems for students to solve, featuring long division equations with numbers up to four digits.

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The task involves solving division problems. Below, I will solve each problem step by step and explain the process.

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Problem 1: $ 11 \div 489 $

Solution:
1. Divide 489 by 11.
2. Perform long division:
- 11 goes into 48 (the first two digits of 489) 4 times (since $ 11 \times 4 = 44 $).
- Subtract $ 44 $ from 48 to get a remainder of 4.
- Bring down the next digit (9), making it 49.
- 11 goes into 49 4 times (since $ 11 \times 4 = 44 $).
- Subtract $ 44 $ from 49 to get a remainder of 5.
3. The quotient is 44 with a remainder of 5.

Answer: $ 44 \text{ R } 5 $

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Problem 2: $ 6 \div 813 $

Solution:
1. Divide 813 by 6.
2. Perform long division:
- 6 goes into 8 (the first digit of 813) 1 time (since $ 6 \times 1 = 6 $).
- Subtract $ 6 $ from 8 to get a remainder of 2.
- Bring down the next digit (1), making it 21.
- 6 goes into 21 3 times (since $ 6 \times 3 = 18 $).
- Subtract $ 18 $ from 21 to get a remainder of 3.
- Bring down the next digit (3), making it 33.
- 6 goes into 33 5 times (since $ 6 \times 5 = 30 $).
- Subtract $ 30 $ from 33 to get a remainder of 3.
3. The quotient is 135 with a remainder of 3.

Answer: $ 135 \text{ R } 3 $

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Problem 3: $ 12 \div 492 $

Solution:
1. Divide 492 by 12.
2. Perform long division:
- 12 goes into 49 (the first two digits of 492) 4 times (since $ 12 \times 4 = 48 $).
- Subtract $ 48 $ from 49 to get a remainder of 1.
- Bring down the next digit (2), making it 12.
- 12 goes into 12 1 time (since $ 12 \times 1 = 12 $).
- Subtract $ 12 $ from 12 to get a remainder of 0.
3. The quotient is 41 with no remainder.

Answer: $ 41 $

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Problem 4: $ 9 \div 689 $

Solution:
1. Divide 689 by 9.
2. Perform long division:
- 9 goes into 68 (the first two digits of 689) 7 times (since $ 9 \times 7 = 63 $).
- Subtract $ 63 $ from 68 to get a remainder of 5.
- Bring down the next digit (9), making it 59.
- 9 goes into 59 6 times (since $ 9 \times 6 = 54 $).
- Subtract $ 54 $ from 59 to get a remainder of 5.
3. The quotient is 76 with a remainder of 5.

Answer: $ 76 \text{ R } 5 $

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Problem 5: $ 5 \div 4813 $

Solution:
1. Divide 4813 by 5.
2. Perform long division:
- 5 goes into 48 (the first two digits of 4813) 9 times (since $ 5 \times 9 = 45 $).
- Subtract $ 45 $ from 48 to get a remainder of 3.
- Bring down the next digit (1), making it 31.
- 5 goes into 31 6 times (since $ 5 \times 6 = 30 $).
- Subtract $ 30 $ from 31 to get a remainder of 1.
- Bring down the next digit (3), making it 13.
- 5 goes into 13 2 times (since $ 5 \times 2 = 10 $).
- Subtract $ 10 $ from 13 to get a remainder of 3.
3. The quotient is 962 with a remainder of 3.

Answer: $ 962 \text{ R } 3 $

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Problem 6: $ 10 \div 4238 $

Solution:
1. Divide 4238 by 10.
2. Perform long division:
- 10 goes into 42 (the first two digits of 4238) 4 times (since $ 10 \times 4 = 40 $).
- Subtract $ 40 $ from 42 to get a remainder of 2.
- Bring down the next digit (3), making it 23.
- 10 goes into 23 2 times (since $ 10 \times 2 = 20 $).
- Subtract $ 20 $ from 23 to get a remainder of 3.
- Bring down the next digit (8), making it 38.
- 10 goes into 38 3 times (since $ 10 \times 3 = 30 $).
- Subtract $ 30 $ from 38 to get a remainder of 8.
3. The quotient is 423 with a remainder of 8.

Answer: $ 423 \text{ R } 8 $

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Problem 7: $ 12 \div 3036 $

Solution:
1. Divide 3036 by 12.
2. Perform long division:
- 12 goes into 30 (the first two digits of 3036) 2 times (since $ 12 \times 2 = 24 $).
- Subtract $ 24 $ from 30 to get a remainder of 6.
- Bring down the next digit (3), making it 63.
- 12 goes into 63 5 times (since $ 12 \times 5 = 60 $).
- Subtract $ 60 $ from 63 to get a remainder of 3.
- Bring down the next digit (6), making it 36.
- 12 goes into 36 3 times (since $ 12 \times 3 = 36 $).
- Subtract $ 36 $ from 36 to get a remainder of 0.
3. The quotient is 253 with no remainder.

Answer: $ 253 $

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Problem 8: $ 12 \div 9270 $

Solution:
1. Divide 9270 by 12.
2. Perform long division:
- 12 goes into 92 (the first two digits of 9270) 7 times (since $ 12 \times 7 = 84 $).
- Subtract $ 84 $ from 92 to get a remainder of 8.
- Bring down the next digit (7), making it 87.
- 12 goes into 87 7 times (since $ 12 \times 7 = 84 $).
- Subtract $ 84 $ from 87 to get a remainder of 3.
- Bring down the next digit (0), making it 30.
- 12 goes into 30 2 times (since $ 12 \times 2 = 24 $).
- Subtract $ 24 $ from 30 to get a remainder of 6.
3. The quotient is 772 with a remainder of 6.

Answer: $ 772 \text{ R } 6 $

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Problem 9: $ 11 \div 1529 $

Solution:
1. Divide 1529 by 11.
2. Perform long division:
- 11 goes into 15 (the first two digits of 1529) 1 time (since $ 11 \times 1 = 11 $).
- Subtract $ 11 $ from 15 to get a remainder of 4.
- Bring down the next digit (2), making it 42.
- 11 goes into 42 3 times (since $ 11 \times 3 = 33 $).
- Subtract $ 33 $ from 42 to get a remainder of 9.
- Bring down the next digit (9), making it 99.
- 11 goes into 99 9 times (since $ 11 \times 9 = 99 $).
- Subtract $ 99 $ from 99 to get a remainder of 0.
3. The quotient is 139 with no remainder.

Answer: $ 139 $

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Problem 10: $ 8 \div 618 $

Solution:
1. Divide 618 by 8.
2. Perform long division:
- 8 goes into 61 (the first two digits of 618) 7 times (since $ 8 \times 7 = 56 $).
- Subtract $ 56 $ from 61 to get a remainder of 5.
- Bring down the next digit (8), making it 58.
- 8 goes into 58 7 times (since $ 8 \times 7 = 56 $).
- Subtract $ 56 $ from 58 to get a remainder of 2.
3. The quotient is 77 with a remainder of 2.

Answer: $ 77 \text{ R } 2 $

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Problem 11: $ 8 \div 745 $

Solution:
1. Divide 745 by 8.
2. Perform long division:
- 8 goes into 74 (the first two digits of 745) 9 times (since $ 8 \times 9 = 72 $).
- Subtract $ 72 $ from 74 to get a remainder of 2.
- Bring down the next digit (5), making it 25.
- 8 goes into 25 3 times (since $ 8 \times 3 = 24 $).
- Subtract $ 24 $ from 25 to get a remainder of 1.
3. The quotient is 93 with a remainder of 1.

Answer: $ 93 \text{ R } 1 $

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Problem 12: $ 8 \div 4730 $

Solution:
1. Divide 4730 by 8.
2. Perform long division:
- 8 goes into 47 (the first two digits of 4730) 5 times (since $ 8 \times 5 = 40 $).
- Subtract $ 40 $ from 47 to get a remainder of 7.
- Bring down the next digit (3), making it 73.
- 8 goes into 73 9 times (since $ 8 \times 9 = 72 $).
- Subtract $ 72 $ from 73 to get a remainder of 1.
- Bring down the next digit (0), making it 10.
- 8 goes into 10 1 time (since $ 8 \times 1 = 8 $).
- Subtract $ 8 $ from 10 to get a remainder of 2.
3. The quotient is 591 with a remainder of 2.

Answer: $ 591 \text{ R } 2 $

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Problem 13: $ 8 \div 1980 $

Solution:
1. Divide 1980 by 8.
2. Perform long division:
- 8 goes into 19 (the first two digits of 1980) 2 times (since $ 8 \times 2 = 16 $).
- Subtract $ 16 $ from 19 to get a remainder of 3.
- Bring down the next digit (8), making it 38.
- 8 goes into 38 4 times (since $ 8 \times 4 = 32 $).
- Subtract $ 32 $ from 38 to get a remainder of 6.
- Bring down the next digit (0), making it 60.
- 8 goes into 60 7 times (since $ 8 \times 7 = 56 $).
- Subtract $ 56 $ from 60 to get a remainder of 4.
3. The quotient is 247 with a remainder of 4.

Answer: $ 247 \text{ R } 4 $

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Problem 14: $ 8 \div 505 $

Solution:
1. Divide 505 by 8.
2. Perform long division:
- 8 goes into 50 (the first two digits of 505) 6 times (since $ 8 \times 6 = 48 $).
- Subtract $ 48 $ from 50 to get a remainder of 2.
- Bring down the next digit (5), making it 25.
- 8 goes into 25 3 times (since $ 8 \times 3 = 24 $).
- Subtract $ 24 $ from 25 to get a remainder of 1.
3. The quotient is 63 with a remainder of 1.

Answer: $ 63 \text{ R } 1 $

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Problem 15: $ 20 \div 5870 $

Solution:
1. Divide 5870 by 20.
2. Perform long division:
- 20 goes into 58 (the first two digits of 5870) 2 times (since $ 20 \times 2 = 40 $).
- Subtract $ 40 $ from 58 to get a remainder of 18.
- Bring down the next digit (7), making it 187.
- 20 goes into 187 9 times (since $ 20 \times 9 = 180 $).
- Subtract $ 180 $ from 187 to get a remainder of 7.
- Bring down the next digit (0), making it 70.
- 20 goes into 70 3 times (since $ 20 \times 3 = 60 $).
- Subtract $ 60 $ from 70 to get a remainder of 10.
3. The quotient is 293 with a remainder of 10.

Answer: $ 293 \text{ R } 10 $

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Final Answers:

\[
\boxed{
\begin{array}{ll}
1. & 44 \text{ R } 5 \\
2. & 135 \text{ R } 3 \\
3. & 41 \\
4. & 76 \text{ R } 5 \\
5. & 962 \text{ R } 3 \\
6. & 423 \text{ R } 8 \\
7. & 253 \\
8. & 772 \text{ R } 6 \\
9. & 139 \\
10. & 77 \text{ R } 2 \\
11. & 93 \text{ R } 1 \\
12. & 591 \text{ R } 2 \\
13. & 247 \text{ R } 4 \\
14. & 63 \text{ R } 1 \\
15. & 293 \text{ R } 10 \\
\end{array}
}
\]

Parent Tip: Review the logic above to help your child master the concept of 5 grade math division.

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