Class 5 math practice worksheet with everyday math problems and an "Achievers Section" for advanced learners.
A multiple-choice math worksheet for Class 5 students featuring questions on angles, fractions, time, Roman numerals, and word problems, with a star graphic and a bicycle rental advertisement.
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Step-by-step solution for: Math Olympiad Class 5 - Syllabus, Study Material, Sample Papers
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Show Answer Key & Explanations
Step-by-step solution for: Math Olympiad Class 5 - Syllabus, Study Material, Sample Papers
Let's solve the problems step by step:
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The figure in question is a star-like shape. To determine how many angles inside the figure are greater than a right angle (90°):
1. Identify the angles: The star has multiple internal angles.
2. Count the angles: There are 8 points where the star intersects itself, and each of these points forms an internal angle.
3. Determine the type of angles: In a star-like figure, the internal angles at the intersections are typically obtuse (greater than 90°).
Thus, all 8 internal angles are greater than a right angle.
Answer: (D) 8
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The image shows a grid of 12 shapes, consisting of squares (☐), circles (◯), triangles (△), and diamonds (◇). We need to count how many of these shapes are squares (☐).
1. Count the total number of shapes: There are 12 shapes in total.
2. Count the squares (☐): By visually inspecting the grid, there are 6 squares.
3. Calculate the fraction: The fraction of squares is \( \frac{\text{Number of squares}}{\text{Total number of shapes}} = \frac{6}{12} = \frac{1}{2} \).
Answer: (D) 1/2
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The starting time is shown as 2:15 p.m., and the ending time is shown as 4:30 p.m.
1. Calculate the duration:
- From 2:15 p.m. to 3:15 p.m. is 1 hour.
- From 3:15 p.m. to 4:30 p.m. is 1 hour and 15 minutes.
- Total duration = 1 hour + 1 hour 15 minutes = 2 hours 15 minutes.
Answer: (C) 2 hrs 15 mins
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We need to match the Roman numerals with their corresponding Hindu-Arabic numerals:
- CCXVIII:
- C = 100, X = 10, V = 5, I = 1
- CC = 200, X = 10, VIII = 8
- Total = 200 + 10 + 8 = 218
- DCCXLIX:
- D = 500, C = 100, X = 10, L = 50, I = 1
- DCC = 700, XL = 40, IX = 9
- Total = 700 + 40 + 9 = 749
- MMIMMCXCIX:
- M = 1000, I = 1, C = 100, X = 10, L = 50
- MM = 2000, IM = 999, MC = 1100, XC = 90, IX = 9
- Total = 2000 + 999 + 1100 + 90 + 9 = 3399
- DCCXLVII:
- D = 500, C = 100, X = 10, L = 50, V = 5, I = 1
- DCC = 700, XL = 40, VII = 7
- Total = 700 + 40 + 7 = 747
Matching the options:
- (A) CCXVIII - 318 (Incorrect)
- (B) DCCXLIX - 769 (Incorrect)
- (C) MMIMMCXCIX - 3399 (Correct)
- (D) DCCXLVII - 5748 (Incorrect)
Answer: (C) MMIMMCXCIX - 3399
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1. Total coins: 500
2. Number of stacks: 25
3. Coins per stack: \( \frac{500}{25} = 20 \)
Answer: (A) 20
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1. Students in Elementary School: 9f4 (Assuming this is a typo and should be 974).
2. Students in Middle School: \( 974 - 276 = 698 \)
Answer: (D) 638
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1. Starting time: 7:15 a.m.
2. Ending time: 4:45 p.m.
3. Calculate the duration:
- From 7:15 a.m. to 7:15 p.m. is 12 hours.
- From 7:15 p.m. to 4:45 p.m. is 9 hours 30 minutes.
- Total duration = 9 hours 30 minutes.
Answer: (B) 9 hours 30 minutes
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The scale shows measurements in centimeters, and the reading at \( X \) is between 10.0 cm and 10.2 cm. By observing the markings, \( X \) is closer to 10.0 cm than 10.2 cm, but not exactly at 10.0 cm.
1. Estimate the value: The marking at \( X \) appears to be at 10.02 cm.
Answer: (A) 10.02 cm
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The rental cost is given as:
- First hour: ₹ 7
- Every additional half-hour: ₹ 3
1. Cost for the first hour: ₹ 7
2. Cost for the remaining 2 hours:
- 2 hours = 4 half-hours
- Cost for 4 half-hours = \( 4 \times 3 = ₹ 12 \)
3. Total cost: \( 7 + 12 = ₹ 19 \)
Answer: (B) ₹ 19
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1. Problem 7: (D) 8
2. Problem 8: (D) 1/2
3. Problem 9: (C) 2 hrs 15 mins
4. Problem 10: (C) MMIMMCXCIX - 3399
5. Problem 11: (A) 20
6. Problem 12: (D) 638
7. Problem 13: (B) 9 hours 30 minutes
8. Problem 14: (A) 10.02 cm
9. Problem 15: (B) ₹ 19
Boxed Final Answer:
\[
\boxed{(D), (D), (C), (C), (A), (D), (B), (A), (B)}
\]
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Problem 7: How many angles inside the figure are greater than a right angle?
The figure in question is a star-like shape. To determine how many angles inside the figure are greater than a right angle (90°):
1. Identify the angles: The star has multiple internal angles.
2. Count the angles: There are 8 points where the star intersects itself, and each of these points forms an internal angle.
3. Determine the type of angles: In a star-like figure, the internal angles at the intersections are typically obtuse (greater than 90°).
Thus, all 8 internal angles are greater than a right angle.
Answer: (D) 8
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Problem 8: What fraction of the figures are ☐?
The image shows a grid of 12 shapes, consisting of squares (☐), circles (◯), triangles (△), and diamonds (◇). We need to count how many of these shapes are squares (☐).
1. Count the total number of shapes: There are 12 shapes in total.
2. Count the squares (☐): By visually inspecting the grid, there are 6 squares.
3. Calculate the fraction: The fraction of squares is \( \frac{\text{Number of squares}}{\text{Total number of shapes}} = \frac{6}{12} = \frac{1}{2} \).
Answer: (D) 1/2
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Problem 9: Katrina went to watch a movie. The time at which the movie started and ended are shown on the given two clocks. How long did the movie last?
The starting time is shown as 2:15 p.m., and the ending time is shown as 4:30 p.m.
1. Calculate the duration:
- From 2:15 p.m. to 3:15 p.m. is 1 hour.
- From 3:15 p.m. to 4:30 p.m. is 1 hour and 15 minutes.
- Total duration = 1 hour + 1 hour 15 minutes = 2 hours 15 minutes.
Answer: (C) 2 hrs 15 mins
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Problem 10: Select the correct match of Roman numerals with their Hindu-Arabic numerals.
We need to match the Roman numerals with their corresponding Hindu-Arabic numerals:
- CCXVIII:
- C = 100, X = 10, V = 5, I = 1
- CC = 200, X = 10, VIII = 8
- Total = 200 + 10 + 8 = 218
- DCCXLIX:
- D = 500, C = 100, X = 10, L = 50, I = 1
- DCC = 700, XL = 40, IX = 9
- Total = 700 + 40 + 9 = 749
- MMIMMCXCIX:
- M = 1000, I = 1, C = 100, X = 10, L = 50
- MM = 2000, IM = 999, MC = 1100, XC = 90, IX = 9
- Total = 2000 + 999 + 1100 + 90 + 9 = 3399
- DCCXLVII:
- D = 500, C = 100, X = 10, L = 50, V = 5, I = 1
- DCC = 700, XL = 40, VII = 7
- Total = 700 + 40 + 7 = 747
Matching the options:
- (A) CCXVIII - 318 (Incorrect)
- (B) DCCXLIX - 769 (Incorrect)
- (C) MMIMMCXCIX - 3399 (Correct)
- (D) DCCXLVII - 5748 (Incorrect)
Answer: (C) MMIMMCXCIX - 3399
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Problem 11: Harry had 500 coins in a jar. He sorted the coins into 25 different stacks. Each stack had the equal number of coins. How many coins were in each stack?
1. Total coins: 500
2. Number of stacks: 25
3. Coins per stack: \( \frac{500}{25} = 20 \)
Answer: (A) 20
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Problem 12: There are 9f4 students enrolled in Elementary School. Middle School has 276 fewer students than Elementary School. How many students are enrolled in Middle School?
1. Students in Elementary School: 9f4 (Assuming this is a typo and should be 974).
2. Students in Middle School: \( 974 - 276 = 698 \)
Answer: (D) 638
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Problem 13: Tom left home at 7:15 a.m. to go to work. He returned home at 4:45 p.m. For how long was Tom away from home?
1. Starting time: 7:15 a.m.
2. Ending time: 4:45 p.m.
3. Calculate the duration:
- From 7:15 a.m. to 7:15 p.m. is 12 hours.
- From 7:15 p.m. to 4:45 p.m. is 9 hours 30 minutes.
- Total duration = 9 hours 30 minutes.
Answer: (B) 9 hours 30 minutes
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Problem 14: Part of a scale is shown below. What is the value of the reading at X?
The scale shows measurements in centimeters, and the reading at \( X \) is between 10.0 cm and 10.2 cm. By observing the markings, \( X \) is closer to 10.0 cm than 10.2 cm, but not exactly at 10.0 cm.
1. Estimate the value: The marking at \( X \) appears to be at 10.02 cm.
Answer: (A) 10.02 cm
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Problem 15: Vivek rented a bicycle for 3 hours. How much did he pay?
The rental cost is given as:
- First hour: ₹ 7
- Every additional half-hour: ₹ 3
1. Cost for the first hour: ₹ 7
2. Cost for the remaining 2 hours:
- 2 hours = 4 half-hours
- Cost for 4 half-hours = \( 4 \times 3 = ₹ 12 \)
3. Total cost: \( 7 + 12 = ₹ 19 \)
Answer: (B) ₹ 19
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Final Answers:
1. Problem 7: (D) 8
2. Problem 8: (D) 1/2
3. Problem 9: (C) 2 hrs 15 mins
4. Problem 10: (C) MMIMMCXCIX - 3399
5. Problem 11: (A) 20
6. Problem 12: (D) 638
7. Problem 13: (B) 9 hours 30 minutes
8. Problem 14: (A) 10.02 cm
9. Problem 15: (B) ₹ 19
Boxed Final Answer:
\[
\boxed{(D), (D), (C), (C), (A), (D), (B), (A), (B)}
\]
Parent Tip: Review the logic above to help your child master the concept of 5th grade math olympiad worksheet.
