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Grade 5 Geometry Worksheet: Find the perimeter and area of each rectangle.

A Grade 5 geometry worksheet titled "Rectangles - area and perimeter" with eight problems asking to find the perimeter and area of rectangles, featuring dimensions in feet, yards, and inches.

A Grade 5 geometry worksheet titled "Rectangles - area and perimeter" with eight problems asking to find the perimeter and area of rectangles, featuring dimensions in feet, yards, and inches.

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Show Answer Key & Explanations Step-by-step solution for: Area & perimeter of rectangles - Grade 5 geometry worksheets | Worsheets library...
Let’s solve each rectangle one by one. For every rectangle, we need to find:

- Perimeter = 2 × (length + width)
- Area = length × width

We’ll go step by step for all 8 problems.

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Problem 1:
Length = 54 ft, Width = 13 ft
Perimeter = 2 × (54 + 13) = 2 × 67 = 134 ft
Area = 54 × 13 → Let’s calculate:
50×13 = 650, 4×13=52 → 650+52 = 702 sq ft

Check: 54×10=540, 54×3=162 → 540+162=702 ✔️

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Problem 2:
Length = 38 yd, Width = 12 yd
Perimeter = 2 × (38 + 12) = 2 × 50 = 100 yd
Area = 38 × 12 → 38×10=380, 38×2=76 → 380+76 = 456 sq yd

Check: 40×12=480 minus 2×12=24 → 480-24=456 ✔️

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Problem 3:
Length = 24 yd, Width = 10 yd
Perimeter = 2 × (24 + 10) = 2 × 34 = 68 yd
Area = 24 × 10 = 240 sq yd

Easy check: 24×10 is just add a zero → 240 ✔️

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Problem 4:
This is a square? No — it says 14 ft and 12 ft. So not a square.
Length = 14 ft, Width = 12 ft
Perimeter = 2 × (14 + 12) = 2 × 26 = 52 ft
Area = 14 × 12 → 10×12=120, 4×12=48 → 120+48 = 168 sq ft

Check: 14×10=140, 14×2=28 → 140+28=168 ✔️

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Problem 5:
Length = 21 yd, Width = 14 yd
Perimeter = 2 × (21 + 14) = 2 × 35 = 70 yd
Area = 21 × 14 → Break it down:
20×14=280, 1×14=14 → 280+14 = 294 sq yd

Check: 21×10=210, 21×4=84 → 210+84=294 ✔️

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Problem 6:
Length = 39 in, Width = 14 in
Perimeter = 2 × (39 + 14) = 2 × 53 = 106 in
Area = 39 × 14 → Let’s do:
40×14=560, minus 1×14=14 → 560 - 14 = 546 sq in

Check: 39×10=390, 39×4=156 → 390+156=546 ✔️

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Problem 7:
Length = 47 yd, Width = 22 yd
Perimeter = 2 × (47 + 22) = 2 × 69 = 138 yd
Area = 47 × 22 → Break into:
47×20 = 940, 47×2 = 94 → 940 + 94 = 1034 sq yd

Check: 50×22=1100, minus 3×22=66 → 1100-66=1034 ✔️

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Problem 8:
Length = 25 yd, Width = 6 yd
Perimeter = 2 × (25 + 6) = 2 × 31 = 62 yd
Area = 25 × 6 = 150 sq yd

Easy: 25×6 is half of 50×6=300 → so 150 ✔️

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Final Answer:

1. Perimeter: 134 ft, Area: 702 sq ft
2. Perimeter: 100 yd, Area: 456 sq yd
3. Perimeter: 68 yd, Area: 240 sq yd
4. Perimeter: 52 ft, Area: 168 sq ft
5. Perimeter: 70 yd, Area: 294 sq yd
6. Perimeter: 106 in, Area: 546 sq in
7. Perimeter: 138 yd, Area: 1034 sq yd
8. Perimeter: 62 yd, Area: 150 sq yd
Parent Tip: Review the logic above to help your child master the concept of 5th grade math worksheet area and perimeter.
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