Area and Perimeter Worksheet 4 - Practice calculating perimeters and solving for unknown lengths in geometric figures.
A worksheet titled "Area and Perimeter" from Learners' Planet, featuring three math problems involving calculating unknown lengths and perimeters of geometric shapes, including a composite figure and two triangles.
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Step-by-step solution for: 301 Moved Permanently
Let's solve each problem step by step from the worksheet.
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We are given a composite shape made of rectangles, with some side lengths labeled:
- The total horizontal length at the bottom is 11 cm.
- The top horizontal segment is split into two parts: 7 cm and a, and there’s another segment b on the left side.
- The vertical sides are:
- Left side: 6 cm
- Right side: 8 cm
Let’s analyze the figure carefully.
This shape appears to be a rectangle with a smaller rectangle removed or extended on top. But since it's a closed shape, we can use the fact that opposite sides are equal in a rectangle.
#### Step-by-step analysis:
The total height on the right side is 8 cm, and on the left side it's 6 cm, so the difference must come from the "step" in the middle.
Looking at the top edge:
- Total top length = 7 cm + a
- But the bottom length is 11 cm → So, the horizontal projection of the left side (with length b) must make up the rest.
Wait — let's think differently.
Actually, look at the horizontal segments:
- Bottom: 11 cm
- Top: 7 cm + a
But for the shape to close properly, the total horizontal length must match.
However, the left side has a vertical segment of 6 cm, and the right side has 8 cm.
So, the difference in vertical height is due to the "step" in the shape.
Now consider the horizontal projections:
- The top part is 7 cm long and is aligned with the upper portion.
- The bottom part is 11 cm long.
- The vertical drop on the left side is 6 cm, and on the right side is 8 cm.
But the key is that the total horizontal width must be consistent.
Let’s reconstruct:
From the diagram:
- The base is 11 cm.
- The top is split: one part is 7 cm, and the other is 'a'.
- On the left, there is a vertical segment of 6 cm, then a horizontal segment of 'b', then upward to meet the top.
But actually, the left side has:
- A vertical segment of 6 cm (bottom),
- Then a horizontal segment of b going right,
- Then a vertical segment of (8 - 6) = 2 cm upward,
- Then a horizontal segment of 7 cm to the right,
- Then down 8 cm to complete the shape.
Wait — better approach:
Let’s look at horizontal alignment.
The total width at the bottom is 11 cm.
On the top, we have:
- A segment of 7 cm on the right,
- And a segment of 'a' on the left (next to 'b').
But also, the left side has a vertical segment of 6 cm, and the right side has 8 cm.
So the horizontal extension on the left must account for the difference in height.
But here's the trick:
Look at the horizontal lines:
- The bottom is 11 cm.
- The top is divided into two parts: 7 cm and 'a'.
But the vertical line between them is not straight — it steps up.
Let’s suppose the shape is like this:
```
_________
| |
| | 8 cm
|______ |
| | 6 cm
| |
|_______|
```
Wait — better:
It's an L-shaped figure? No — it looks more like a rectangular shape with a rectangular notch on the top-left?
No — actually, it seems like a rectangle with a smaller rectangle added on top.
Wait — looking again:
- The right side is 8 cm tall.
- The left side is 6 cm tall.
- So, the top must go up 2 cm higher on the right than on the left.
So the top edge starts at 6 cm height and goes up to 8 cm at the right.
But the top horizontal segment is only 7 cm long, and there's a segment 'a' and 'b' on the left.
Let’s try to use horizontal balance.
Total bottom width = 11 cm.
The top has:
- 7 cm on the right,
- And 'a' on the left (which is connected to 'b').
But the horizontal segment 'b' is likely the overhang on the left.
Wait — perhaps the figure is like this:
Imagine a large rectangle of width 11 cm and height 8 cm.
Then, on the left side, a smaller rectangle of height 6 cm is cut out or attached?
But the left side shows 6 cm, and the right side shows 8 cm.
So the shape is taller on the right.
Thus, the top must be stepped: from the left side (6 cm), it goes up to 8 cm on the right.
So the top edge is broken into two parts:
- One part of 7 cm at the right end (at height 8 cm),
- And the rest is at height 6 cm.
But wait — the top edge is drawn as:
- A horizontal segment of 7 cm,
- Then a vertical segment down?
No — the diagram shows:
From the top-left, it goes:
- Rightward for 'b',
- Then up for 'a',
- Then right for 7 cm,
- Then down 8 cm,
- Then left for 11 cm,
- Then up 6 cm.
Wait — no.
Let me interpret the diagram clearly:
The figure is a polygon with the following sides:
1. Start at bottom-left corner.
2. Go right 11 cm → bottom.
3. Go up 8 cm → right side.
4. Go left 7 cm → top-right.
5. Go down 'a' → vertical segment.
6. Go left 'b' → horizontal segment.
7. Go up 6 cm → back to start.
Wait — but the left side is labeled 6 cm.
So the path should be:
- Start at bottom-left.
- Up 6 cm → left side.
- Then right 'b' → horizontal.
- Then up 'a' → vertical.
- Then right 7 cm → top.
- Then down 8 cm → right side.
- Then left 11 cm → bottom.
Wait — but the bottom is 11 cm, so if you go from right to left 11 cm, that matches.
But now, check horizontal consistency.
From the bottom-left, you go up 6 cm, then right 'b', then up 'a', then right 7 cm, then down 8 cm, then left 11 cm.
So the total horizontal movement:
- Right: 'b' + 7 cm
- Left: 11 cm
For the shape to close, the net horizontal displacement must be zero.
But we’re going right (b + 7), then left 11 cm.
So:
$$
b + 7 = 11 \Rightarrow b = 4
$$
Similarly, vertically:
- Up: 6 cm + a
- Down: 8 cm
So:
$$
6 + a = 8 \Rightarrow a = 2
$$
Now, we are asked: $ b - a = ? $
$$
b - a = 4 - 2 = 2
$$
✔ Answer: (b) 2
---
Triangle with sides:
- 3 cm, 3 cm, and 4 cm
This is an isosceles triangle.
Perimeter = sum of all sides:
$$
3 + 3 + 4 = 10 \text{ cm}
$$
✔ Answer: (a) 10
---
Triangle with sides:
- 3 cm, 4 cm, 5 cm
This is a right triangle (since $ 3^2 + 4^2 = 9 + 16 = 25 = 5^2 $)
Perimeter = $ 3 + 4 + 5 = 12 $ cm
✔ Answer: (b) 12
---
1. $ b - a = 2 $ → (b) 2
2. Perimeter = 10 units → (a) 10
3. Perimeter = 12 units → (b) 12
---
Let me know if you'd like a visual explanation or diagram!
---
(1) Find $ b - a $?
We are given a composite shape made of rectangles, with some side lengths labeled:
- The total horizontal length at the bottom is 11 cm.
- The top horizontal segment is split into two parts: 7 cm and a, and there’s another segment b on the left side.
- The vertical sides are:
- Left side: 6 cm
- Right side: 8 cm
Let’s analyze the figure carefully.
This shape appears to be a rectangle with a smaller rectangle removed or extended on top. But since it's a closed shape, we can use the fact that opposite sides are equal in a rectangle.
#### Step-by-step analysis:
The total height on the right side is 8 cm, and on the left side it's 6 cm, so the difference must come from the "step" in the middle.
Looking at the top edge:
- Total top length = 7 cm + a
- But the bottom length is 11 cm → So, the horizontal projection of the left side (with length b) must make up the rest.
Wait — let's think differently.
Actually, look at the horizontal segments:
- Bottom: 11 cm
- Top: 7 cm + a
But for the shape to close properly, the total horizontal length must match.
However, the left side has a vertical segment of 6 cm, and the right side has 8 cm.
So, the difference in vertical height is due to the "step" in the shape.
Now consider the horizontal projections:
- The top part is 7 cm long and is aligned with the upper portion.
- The bottom part is 11 cm long.
- The vertical drop on the left side is 6 cm, and on the right side is 8 cm.
But the key is that the total horizontal width must be consistent.
Let’s reconstruct:
From the diagram:
- The base is 11 cm.
- The top is split: one part is 7 cm, and the other is 'a'.
- On the left, there is a vertical segment of 6 cm, then a horizontal segment of 'b', then upward to meet the top.
But actually, the left side has:
- A vertical segment of 6 cm (bottom),
- Then a horizontal segment of b going right,
- Then a vertical segment of (8 - 6) = 2 cm upward,
- Then a horizontal segment of 7 cm to the right,
- Then down 8 cm to complete the shape.
Wait — better approach:
Let’s look at horizontal alignment.
The total width at the bottom is 11 cm.
On the top, we have:
- A segment of 7 cm on the right,
- And a segment of 'a' on the left (next to 'b').
But also, the left side has a vertical segment of 6 cm, and the right side has 8 cm.
So the horizontal extension on the left must account for the difference in height.
But here's the trick:
Look at the horizontal lines:
- The bottom is 11 cm.
- The top is divided into two parts: 7 cm and 'a'.
But the vertical line between them is not straight — it steps up.
Let’s suppose the shape is like this:
```
_________
| |
| | 8 cm
|______ |
| | 6 cm
| |
|_______|
```
Wait — better:
It's an L-shaped figure? No — it looks more like a rectangular shape with a rectangular notch on the top-left?
No — actually, it seems like a rectangle with a smaller rectangle added on top.
Wait — looking again:
- The right side is 8 cm tall.
- The left side is 6 cm tall.
- So, the top must go up 2 cm higher on the right than on the left.
So the top edge starts at 6 cm height and goes up to 8 cm at the right.
But the top horizontal segment is only 7 cm long, and there's a segment 'a' and 'b' on the left.
Let’s try to use horizontal balance.
Total bottom width = 11 cm.
The top has:
- 7 cm on the right,
- And 'a' on the left (which is connected to 'b').
But the horizontal segment 'b' is likely the overhang on the left.
Wait — perhaps the figure is like this:
Imagine a large rectangle of width 11 cm and height 8 cm.
Then, on the left side, a smaller rectangle of height 6 cm is cut out or attached?
But the left side shows 6 cm, and the right side shows 8 cm.
So the shape is taller on the right.
Thus, the top must be stepped: from the left side (6 cm), it goes up to 8 cm on the right.
So the top edge is broken into two parts:
- One part of 7 cm at the right end (at height 8 cm),
- And the rest is at height 6 cm.
But wait — the top edge is drawn as:
- A horizontal segment of 7 cm,
- Then a vertical segment down?
No — the diagram shows:
From the top-left, it goes:
- Rightward for 'b',
- Then up for 'a',
- Then right for 7 cm,
- Then down 8 cm,
- Then left for 11 cm,
- Then up 6 cm.
Wait — no.
Let me interpret the diagram clearly:
The figure is a polygon with the following sides:
1. Start at bottom-left corner.
2. Go right 11 cm → bottom.
3. Go up 8 cm → right side.
4. Go left 7 cm → top-right.
5. Go down 'a' → vertical segment.
6. Go left 'b' → horizontal segment.
7. Go up 6 cm → back to start.
Wait — but the left side is labeled 6 cm.
So the path should be:
- Start at bottom-left.
- Up 6 cm → left side.
- Then right 'b' → horizontal.
- Then up 'a' → vertical.
- Then right 7 cm → top.
- Then down 8 cm → right side.
- Then left 11 cm → bottom.
Wait — but the bottom is 11 cm, so if you go from right to left 11 cm, that matches.
But now, check horizontal consistency.
From the bottom-left, you go up 6 cm, then right 'b', then up 'a', then right 7 cm, then down 8 cm, then left 11 cm.
So the total horizontal movement:
- Right: 'b' + 7 cm
- Left: 11 cm
For the shape to close, the net horizontal displacement must be zero.
But we’re going right (b + 7), then left 11 cm.
So:
$$
b + 7 = 11 \Rightarrow b = 4
$$
Similarly, vertically:
- Up: 6 cm + a
- Down: 8 cm
So:
$$
6 + a = 8 \Rightarrow a = 2
$$
Now, we are asked: $ b - a = ? $
$$
b - a = 4 - 2 = 2
$$
✔ Answer: (b) 2
---
(2) Perimeter of the triangle
Triangle with sides:
- 3 cm, 3 cm, and 4 cm
This is an isosceles triangle.
Perimeter = sum of all sides:
$$
3 + 3 + 4 = 10 \text{ cm}
$$
✔ Answer: (a) 10
---
(3) Perimeter of the triangle
Triangle with sides:
- 3 cm, 4 cm, 5 cm
This is a right triangle (since $ 3^2 + 4^2 = 9 + 16 = 25 = 5^2 $)
Perimeter = $ 3 + 4 + 5 = 12 $ cm
✔ Answer: (b) 12
---
✔ Final Answers:
1. $ b - a = 2 $ → (b) 2
2. Perimeter = 10 units → (a) 10
3. Perimeter = 12 units → (b) 12
---
Let me know if you'd like a visual explanation or diagram!
Parent Tip: Review the logic above to help your child master the concept of 5th grade math worksheet area and perimeter.