Let’s solve each problem step by step.
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Problem 1:
You have a mineral with:
- Volume = 15 cm³
- Mass = 45 g
Density = Mass ÷ Volume
So, D = 45g ÷ 15cm³ =
3 g/cm³
✔ Its density is:
3 g/cm³
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Problem 2:
Different mineral:
- Volume = 15 cm³ (same as before)
- Mass = 75 g
D = 75g ÷ 15cm³ =
5 g/cm³
✔ Its density is:
5 g/cm³
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Problem 3:
Compare the two densities:
- First mineral: 3 g/cm³
- Second mineral: 5 g/cm³
The second one has higher density.
✔ The
second mineral is more dense than the
first one.
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Problem 4:
Cube of sugar:
- Mass = 12.8 grams
- Side length = 2 cm
Volume of a cube = side × side × side
→ Volume = 2 cm × 2 cm × 2 cm =
8 cm³
Now, Density = Mass ÷ Volume
→ D = 12.8g ÷ 8cm³ =
1.6 g/cm³
✔ mass =
12.8 g
✔ volume =
2 × 2 × 2 = 8 cm³
✔ Its density is:
1.6 g/cm³
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Final Answer:
1. Density = 3 g/cm³
2. Density = 5 g/cm³
3. The second mineral is more dense than the first one.
4. mass = 12.8 g, volume = 8 cm³, density = 1.6 g/cm³
Parent Tip: Review the logic above to help your child master the concept of 6th grade density worksheet.