Printable quiz worksheet from Quizizz featuring 18 fraction word problems for students to solve, covering various practical applications of fractions.

Let's solve each problem step by step.

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Problem 1:

Isabela got \( 1 \frac{2}{3} \) pounds of candy, and her sister got \( 2 \frac{4}{5} \) pounds. How much more did her sister get?

#### Solution:
1. Convert the mixed numbers to improper fractions:
- \( 1 \frac{2}{3} = \frac{3 \cdot 1 + 2}{3} = \frac{5}{3} \)
- \( 2 \frac{4}{5} = \frac{5 \cdot 2 + 4}{5} = \frac{14}{5} \)

2. Find a common denominator for \( \frac{5}{3} \) and \( \frac{14}{5} \):
- The least common denominator (LCD) of 3 and 5 is 15.
- Convert \( \frac{5}{3} \) to a fraction with denominator 15:
\[
\frac{5}{3} = \frac{5 \cdot 5}{3 \cdot 5} = \frac{25}{15}
\]
- Convert \( \frac{14}{5} \) to a fraction with denominator 15:
\[
\frac{14}{5} = \frac{14 \cdot 3}{5 \cdot 3} = \frac{42}{15}
\]

3. Subtract the two fractions:
\[
\frac{42}{15} - \frac{25}{15} = \frac{42 - 25}{15} = \frac{17}{15}
\]

4. Convert the improper fraction back to a mixed number:
\[
\frac{17}{15} = 1 \frac{2}{15}
\]

#### Final Answer:
\[
\boxed{1 \frac{2}{15}}
\]

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Problem 2:

Count Dracula loves his bats. \( \frac{1}{2} \) of his bats are male, and \( \frac{1}{3} \) of the male bats are purple. What fraction of the Count’s bats are male and purple?

#### Solution:
1. Let the total number of bats be \( B \).
2. The fraction of male bats is \( \frac{1}{2} \).
3. The fraction of male bats that are purple is \( \frac{1}{3} \) of the male bats:
\[
\text{Fraction of male and purple bats} = \frac{1}{2} \times \frac{1}{3} = \frac{1 \cdot 1}{2 \cdot 3} = \frac{1}{6}
\]

#### Final Answer:
\[
\boxed{\frac{1}{6}}
\]

---

Problem 3:

Carson has \( \frac{5}{6} \) of a pumpkin pie. She splits it into three equal pieces to share with her friends. What fraction of pie will each of her friends get?

#### Solution:
1. Carson has \( \frac{5}{6} \) of the pie.
2. She splits this into 3 equal pieces. To find the fraction each friend gets, divide \( \frac{5}{6} \) by 3:
\[
\frac{5}{6} \div 3 = \frac{5}{6} \times \frac{1}{3} = \frac{5 \cdot 1}{6 \cdot 3} = \frac{5}{18}
\]

#### Final Answer:
\[
\boxed{\frac{5}{18}}
\]

---

Problem 4:

Anna bought 7 yards of fabric to make her costume. She used \( 5 \frac{4}{9} \) yards for her costume. How many yards of fabric does she have left?

#### Solution:
1. Convert the mixed number \( 5 \frac{4}{9} \) to an improper fraction:
\[
5 \frac{4}{9} = \frac{9 \cdot 5 + 4}{9} = \frac{45 + 4}{9} = \frac{49}{9}
\]

2. Anna started with 7 yards of fabric. Convert 7 to a fraction with denominator 9:
\[
7 = \frac{7 \cdot 9}{9} = \frac{63}{9}
\]

3. Subtract the amount used from the total:
\[
\frac{63}{9} - \frac{49}{9} = \frac{63 - 49}{9} = \frac{14}{9}
\]

4. Convert the improper fraction back to a mixed number:
\[
\frac{14}{9} = 1 \frac{5}{9}
\]

#### Final Answer:
\[
\boxed{1 \frac{5}{9}}
\]

---

Problem 5:

The Headless Horseman rode \( 4 \frac{1}{2} \) miles from the cabin to the haunted woods, then \( 9 \frac{1}{4} \) miles from the woods to the swamp, and finally 10 miles back home. What is the total distance he traveled?

#### Solution:
1. Convert the mixed numbers to improper fractions:
- \( 4 \frac{1}{2} = \frac{2 \cdot 4 + 1}{2} = \frac{9}{2} \)
- \( 9 \frac{1}{4} = \frac{4 \cdot 9 + 1}{4} = \frac{37}{4} \)

2. Add the distances:
- First, convert all distances to fractions with a common denominator. The LCD of 2, 4, and 1 (for 10) is 4.
- Convert \( \frac{9}{2} \) to a fraction with denominator 4:
\[
\frac{9}{2} = \frac{9 \cdot 2}{2 \cdot 2} = \frac{18}{4}
\]
- Convert 10 to a fraction with denominator 4:
\[
10 = \frac{10 \cdot 4}{4} = \frac{40}{4}
\]

3. Add the fractions:
\[
\frac{18}{4} + \frac{37}{4} + \frac{40}{4} = \frac{18 + 37 + 40}{4} = \frac{95}{4}
\]

4. Convert the improper fraction back to a mixed number:
\[
\frac{95}{4} = 23 \frac{3}{4}
\]

#### Final Answer:
\[
\boxed{23 \frac{3}{4}}
\]

---

Problem 6:

Pugsley worked at the pumpkin patch \( 4 \frac{1}{2} \) days last week. If he gets paid \$64 per day, how much money did Pugsley earn last week?

#### Solution:
1. Convert the mixed number \( 4 \frac{1}{2} \) to an improper fraction:
\[
4 \frac{1}{2} = \frac{2 \cdot 4 + 1}{2} = \frac{9}{2}
\]

2. Pugsley earns \$64 per day. Multiply the number of days by the daily wage:
\[
\text{Total earnings} = \frac{9}{2} \times 64
\]

3. Simplify the multiplication:
\[
\frac{9}{2} \times 64 = \frac{9 \cdot 64}{2} = \frac{576}{2} = 288
\]

#### Final Answer:
\[
\boxed{288}
\]

---

Problem 7:

There are 50 kids who entered the corn maze. \( \frac{4}{5} \) of the kids successfully made it through the corn maze in 20 minutes. How many kids made it through the corn maze in 20 minutes?

#### Solution:
1. The total number of kids is 50.
2. The fraction of kids who made it through is \( \frac{4}{5} \).
3. Calculate the number of kids who made it through:
\[
\text{Number of kids} = 50 \times \frac{4}{5} = \frac{50 \cdot 4}{5} = \frac{200}{5} = 40
\]

#### Final Answer:
\[
\boxed{40}
\]

---

Problem 8:

A hot chocolate recipe calls for \( \frac{3}{4} \) cups of milk. Thomas halves the recipe. How much milk does he need?

#### Solution:
1. The original recipe calls for \( \frac{3}{4} \) cups of milk.
2. Thomas halves the recipe, so he needs half of \( \frac{3}{4} \):
\[
\text{Milk needed} = \frac{3}{4} \times \frac{1}{2} = \frac{3 \cdot 1}{4 \cdot 2} = \frac{3}{8}
\]

#### Final Answer:
\[
\boxed{\frac{3}{8}}
\]

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Problem 9:

At a Haunted House, \( \frac{3}{8} \) of the costumes are ghosts, \( \frac{6}{8} \) are vampires, and \( \frac{2}{8} \) are werewolves. What fraction of the costumes are either ghosts or vampires?

#### Solution:
1. The fraction of costumes that are ghosts is \( \frac{3}{8} \).
2. The fraction of costumes that are vampires is \( \frac{6}{8} \).
3. Add the fractions to find the total fraction of costumes that are either ghosts or vampires:
\[
\frac{3}{8} + \frac{6}{8} = \frac{3 + 6}{8} = \frac{9}{8}
\]

4. Since \( \frac{9}{8} \) is greater than 1, it indicates an error in the problem setup (the fractions should not exceed 1). However, based on the given information, the sum is:
\[
\frac{9}{8}
\]

#### Final Answer:
\[
\boxed{\frac{9}{8}}
\]

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Final Answers:

1. \( \boxed{1 \frac{2}{15}} \)
2. \( \boxed{\frac{1}{6}} \)
3. \( \boxed{\frac{5}{18}} \)
4. \( \boxed{1 \frac{5}{9}} \)
5. \( \boxed{23 \frac{3}{4}} \)
6. \( \boxed{288} \)
7. \( \boxed{40} \)
8. \( \boxed{\frac{3}{8}} \)
9. \( \boxed{\frac{9}{8}} \)