Surface area calculation worksheet for cylinders and cones with nine problems.
Worksheet titled "Surface Area of Cylinders and Cones" with nine problems, each showing a cylinder or cone with dimensions, asking to find the surface area and round to the nearest hundredth if necessary. Includes space for name, teacher, score, and date. Math-Aids.com logo in bottom right corner.
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Step-by-step solution for: Geometry Worksheets | Volume Worksheets
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Show Answer Key & Explanations
Step-by-step solution for: Geometry Worksheets | Volume Worksheets
To solve the problem of finding the surface area of each figure (cylinders and cones), we will use the appropriate formulas for each shape. Let's go through each part step by step.
1. Surface Area of a Cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
- \( r \) is the radius.
- \( h \) is the height.
2. Surface Area of a Cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
- \( r \) is the radius.
- \( l \) is the slant height.
---
#### 1) Cylinder (8 ft radius, 12 ft height)
- Radius (\( r \)) = 8 ft
- Height (\( h \)) = 12 ft
Using the formula for the surface area of a cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
\[
= 2\pi (8)^2 + 2\pi (8)(12)
\]
\[
= 2\pi (64) + 2\pi (96)
\]
\[
= 128\pi + 192\pi
\]
\[
= 320\pi
\]
\[
\approx 320 \times 3.1416 \approx 1005.31 \, \text{ft}^2
\]
#### 2) Cone (4 in radius, 6 in slant height)
- Radius (\( r \)) = 4 in
- Slant height (\( l \)) = 6 in
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (4)^2 + \pi (4)(6)
\]
\[
= \pi (16) + \pi (24)
\]
\[
= 16\pi + 24\pi
\]
\[
= 40\pi
\]
\[
\approx 40 \times 3.1416 \approx 125.66 \, \text{in}^2
\]
#### 3) Cylinder (6 yd radius, 8 yd height)
- Radius (\( r \)) = 6 yd
- Height (\( h \)) = 8 yd
Using the formula for the surface area of a cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
\[
= 2\pi (6)^2 + 2\pi (6)(8)
\]
\[
= 2\pi (36) + 2\pi (48)
\]
\[
= 72\pi + 96\pi
\]
\[
= 168\pi
\]
\[
\approx 168 \times 3.1416 \approx 527.79 \, \text{yd}^2
\]
#### 4) Cone (5 mm radius, 13 mm slant height)
- Radius (\( r \)) = 5 mm
- Slant height (\( l \)) = 13 mm
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (5)^2 + \pi (5)(13)
\]
\[
= \pi (25) + \pi (65)
\]
\[
= 25\pi + 65\pi
\]
\[
= 90\pi
\]
\[
\approx 90 \times 3.1416 \approx 282.74 \, \text{mm}^2
\]
#### 5) Cone (6 mm radius, 14 mm slant height)
- Radius (\( r \)) = 6 mm
- Slant height (\( l \)) = 14 mm
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (6)^2 + \pi (6)(14)
\]
\[
= \pi (36) + \pi (84)
\]
\[
= 36\pi + 84\pi
\]
\[
= 120\pi
\]
\[
\approx 120 \times 3.1416 \approx 376.99 \, \text{mm}^2
\]
#### 6) Cylinder (6 cm radius, 8 cm height)
- Radius (\( r \)) = 6 cm
- Height (\( h \)) = 8 cm
Using the formula for the surface area of a cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
\[
= 2\pi (6)^2 + 2\pi (6)(8)
\]
\[
= 2\pi (36) + 2\pi (48)
\]
\[
= 72\pi + 96\pi
\]
\[
= 168\pi
\]
\[
\approx 168 \times 3.1416 \approx 527.79 \, \text{cm}^2
\]
#### 7) Cylinder (7 yd radius, 10 yd height)
- Radius (\( r \)) = 7 yd
- Height (\( h \)) = 10 yd
Using the formula for the surface area of a cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
\[
= 2\pi (7)^2 + 2\pi (7)(10)
\]
\[
= 2\pi (49) + 2\pi (70)
\]
\[
= 98\pi + 140\pi
\]
\[
= 238\pi
\]
\[
\approx 238 \times 3.1416 \approx 748.69 \, \text{yd}^2
\]
#### 8) Cone (7 ft radius, 10 ft slant height)
- Radius (\( r \)) = 7 ft
- Slant height (\( l \)) = 10 ft
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (7)^2 + \pi (7)(10)
\]
\[
= \pi (49) + \pi (70)
\]
\[
= 49\pi + 70\pi
\]
\[
= 119\pi
\]
\[
\approx 119 \times 3.1416 \approx 373.93 \, \text{ft}^2
\]
#### 9) Cone (4 cm radius, 6 cm slant height)
- Radius (\( r \)) = 4 cm
- Slant height (\( l \)) = 6 cm
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (4)^2 + \pi (4)(6)
\]
\[
= \pi (16) + \pi (24)
\]
\[
= 16\pi + 24\pi
\]
\[
= 40\pi
\]
\[
\approx 40 \times 3.1416 \approx 125.66 \, \text{cm}^2
\]
---
1. \( \boxed{1005.31} \, \text{ft}^2 \)
2. \( \boxed{125.66} \, \text{in}^2 \)
3. \( \boxed{527.79} \, \text{yd}^2 \)
4. \( \boxed{282.74} \, \text{mm}^2 \)
5. \( \boxed{376.99} \, \text{mm}^2 \)
6. \( \boxed{527.79} \, \text{cm}^2 \)
7. \( \boxed{748.69} \, \text{yd}^2 \)
8. \( \boxed{373.93} \, \text{ft}^2 \)
9. \( \boxed{125.66} \, \text{cm}^2 \)
These are the rounded surface areas to the nearest hundredth.
Formulas Needed:
1. Surface Area of a Cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
- \( r \) is the radius.
- \( h \) is the height.
2. Surface Area of a Cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
- \( r \) is the radius.
- \( l \) is the slant height.
---
Solutions:
#### 1) Cylinder (8 ft radius, 12 ft height)
- Radius (\( r \)) = 8 ft
- Height (\( h \)) = 12 ft
Using the formula for the surface area of a cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
\[
= 2\pi (8)^2 + 2\pi (8)(12)
\]
\[
= 2\pi (64) + 2\pi (96)
\]
\[
= 128\pi + 192\pi
\]
\[
= 320\pi
\]
\[
\approx 320 \times 3.1416 \approx 1005.31 \, \text{ft}^2
\]
#### 2) Cone (4 in radius, 6 in slant height)
- Radius (\( r \)) = 4 in
- Slant height (\( l \)) = 6 in
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (4)^2 + \pi (4)(6)
\]
\[
= \pi (16) + \pi (24)
\]
\[
= 16\pi + 24\pi
\]
\[
= 40\pi
\]
\[
\approx 40 \times 3.1416 \approx 125.66 \, \text{in}^2
\]
#### 3) Cylinder (6 yd radius, 8 yd height)
- Radius (\( r \)) = 6 yd
- Height (\( h \)) = 8 yd
Using the formula for the surface area of a cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
\[
= 2\pi (6)^2 + 2\pi (6)(8)
\]
\[
= 2\pi (36) + 2\pi (48)
\]
\[
= 72\pi + 96\pi
\]
\[
= 168\pi
\]
\[
\approx 168 \times 3.1416 \approx 527.79 \, \text{yd}^2
\]
#### 4) Cone (5 mm radius, 13 mm slant height)
- Radius (\( r \)) = 5 mm
- Slant height (\( l \)) = 13 mm
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (5)^2 + \pi (5)(13)
\]
\[
= \pi (25) + \pi (65)
\]
\[
= 25\pi + 65\pi
\]
\[
= 90\pi
\]
\[
\approx 90 \times 3.1416 \approx 282.74 \, \text{mm}^2
\]
#### 5) Cone (6 mm radius, 14 mm slant height)
- Radius (\( r \)) = 6 mm
- Slant height (\( l \)) = 14 mm
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (6)^2 + \pi (6)(14)
\]
\[
= \pi (36) + \pi (84)
\]
\[
= 36\pi + 84\pi
\]
\[
= 120\pi
\]
\[
\approx 120 \times 3.1416 \approx 376.99 \, \text{mm}^2
\]
#### 6) Cylinder (6 cm radius, 8 cm height)
- Radius (\( r \)) = 6 cm
- Height (\( h \)) = 8 cm
Using the formula for the surface area of a cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
\[
= 2\pi (6)^2 + 2\pi (6)(8)
\]
\[
= 2\pi (36) + 2\pi (48)
\]
\[
= 72\pi + 96\pi
\]
\[
= 168\pi
\]
\[
\approx 168 \times 3.1416 \approx 527.79 \, \text{cm}^2
\]
#### 7) Cylinder (7 yd radius, 10 yd height)
- Radius (\( r \)) = 7 yd
- Height (\( h \)) = 10 yd
Using the formula for the surface area of a cylinder:
\[
\text{Surface Area} = 2\pi r^2 + 2\pi rh
\]
\[
= 2\pi (7)^2 + 2\pi (7)(10)
\]
\[
= 2\pi (49) + 2\pi (70)
\]
\[
= 98\pi + 140\pi
\]
\[
= 238\pi
\]
\[
\approx 238 \times 3.1416 \approx 748.69 \, \text{yd}^2
\]
#### 8) Cone (7 ft radius, 10 ft slant height)
- Radius (\( r \)) = 7 ft
- Slant height (\( l \)) = 10 ft
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (7)^2 + \pi (7)(10)
\]
\[
= \pi (49) + \pi (70)
\]
\[
= 49\pi + 70\pi
\]
\[
= 119\pi
\]
\[
\approx 119 \times 3.1416 \approx 373.93 \, \text{ft}^2
\]
#### 9) Cone (4 cm radius, 6 cm slant height)
- Radius (\( r \)) = 4 cm
- Slant height (\( l \)) = 6 cm
Using the formula for the surface area of a cone:
\[
\text{Surface Area} = \pi r^2 + \pi r l
\]
\[
= \pi (4)^2 + \pi (4)(6)
\]
\[
= \pi (16) + \pi (24)
\]
\[
= 16\pi + 24\pi
\]
\[
= 40\pi
\]
\[
\approx 40 \times 3.1416 \approx 125.66 \, \text{cm}^2
\]
---
Final Answers:
1. \( \boxed{1005.31} \, \text{ft}^2 \)
2. \( \boxed{125.66} \, \text{in}^2 \)
3. \( \boxed{527.79} \, \text{yd}^2 \)
4. \( \boxed{282.74} \, \text{mm}^2 \)
5. \( \boxed{376.99} \, \text{mm}^2 \)
6. \( \boxed{527.79} \, \text{cm}^2 \)
7. \( \boxed{748.69} \, \text{yd}^2 \)
8. \( \boxed{373.93} \, \text{ft}^2 \)
9. \( \boxed{125.66} \, \text{cm}^2 \)
These are the rounded surface areas to the nearest hundredth.
Parent Tip: Review the logic above to help your child master the concept of 7th grade surface area worksheet.