Grade 9 algebra] is their a faster way to do these problems, it ... - Free Printable
Educational worksheet: Grade 9 algebra] is their a faster way to do these problems, it .... Download and print for classroom or home learning activities.
JPG
1124×1160
93 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #1299503
⭐
Show Answer Key & Explanations
Step-by-step solution for: Grade 9 algebra] is their a faster way to do these problems, it ...
▼
Show Answer Key & Explanations
Step-by-step solution for: Grade 9 algebra] is their a faster way to do these problems, it ...
To solve the problem of factoring the given polynomials, we will go through each polynomial step by step. Here's a detailed explanation for the first few problems as examples:
---
#### Step 1: Identify the form
The polynomial is a quadratic trinomial of the form \( ax^2 + bx + c \), where:
- \( a = 3 \)
- \( b = 7 \)
- \( c = 2 \)
#### Step 2: Find two numbers that multiply to \( ac \) and add to \( b \)
Here, \( ac = 3 \cdot 2 = 6 \) and \( b = 7 \). We need two numbers that multiply to 6 and add to 7. These numbers are 6 and 1.
#### Step 3: Rewrite the middle term using these numbers
Rewrite \( 7x \) as \( 6x + x \):
\[
3x^2 + 7x + 2 = 3x^2 + 6x + x + 2
\]
#### Step 4: Factor by grouping
Group the terms in pairs:
\[
(3x^2 + 6x) + (x + 2)
\]
Factor out the greatest common factor (GCF) from each pair:
\[
3x(x + 2) + 1(x + 2)
\]
Now, factor out the common binomial factor \( (x + 2) \):
\[
(3x + 1)(x + 2)
\]
#### Step 5: Verify by multiplying
Multiply the factors to check:
\[
(3x + 1)(x + 2) = 3x^2 + 6x + x + 2 = 3x^2 + 7x + 2
\]
The original polynomial is recovered, so the factorization is correct.
Answer:
\[
\boxed{(3x + 1)(x + 2)}
\]
---
#### Step 1: Identify the form
The polynomial is a quadratic trinomial of the form \( ax^2 + bx + c \), where:
- \( a = 2 \)
- \( b = 5 \)
- \( c = 3 \)
#### Step 2: Find two numbers that multiply to \( ac \) and add to \( b \)
Here, \( ac = 2 \cdot 3 = 6 \) and \( b = 5 \). We need two numbers that multiply to 6 and add to 5. These numbers are 2 and 3.
#### Step 3: Rewrite the middle term using these numbers
Rewrite \( 5x \) as \( 2x + 3x \):
\[
2x^2 + 5x + 3 = 2x^2 + 2x + 3x + 3
\]
#### Step 4: Factor by grouping
Group the terms in pairs:
\[
(2x^2 + 2x) + (3x + 3)
\]
Factor out the GCF from each pair:
\[
2x(x + 1) + 3(x + 1)
\]
Now, factor out the common binomial factor \( (x + 1) \):
\[
(2x + 3)(x + 1)
\]
#### Step 5: Verify by multiplying
Multiply the factors to check:
\[
(2x + 3)(x + 1) = 2x^2 + 2x + 3x + 3 = 2x^2 + 5x + 3
\]
The original polynomial is recovered, so the factorization is correct.
Answer:
\[
\boxed{(2x + 3)(x + 1)}
\]
---
#### Step 1: Identify the form
The polynomial is a quadratic trinomial of the form \( ax^2 + bx + c \), where:
- \( a = 3 \)
- \( b = -8 \)
- \( c = 5 \)
#### Step 2: Find two numbers that multiply to \( ac \) and add to \( b \)
Here, \( ac = 3 \cdot 5 = 15 \) and \( b = -8 \). We need two numbers that multiply to 15 and add to -8. These numbers are -3 and -5.
#### Step 3: Rewrite the middle term using these numbers
Rewrite \( -8c \) as \( -3c - 5c \):
\[
3c^2 - 8c + 5 = 3c^2 - 3c - 5c + 5
\]
#### Step 4: Factor by grouping
Group the terms in pairs:
\[
(3c^2 - 3c) + (-5c + 5)
\]
Factor out the GCF from each pair:
\[
3c(c - 1) - 5(c - 1)
\]
Now, factor out the common binomial factor \( (c - 1) \):
\[
(3c - 5)(c - 1)
\]
#### Step 5: Verify by multiplying
Multiply the factors to check:
\[
(3c - 5)(c - 1) = 3c^2 - 3c - 5c + 5 = 3c^2 - 8c + 5
\]
The original polynomial is recovered, so the factorization is correct.
Answer:
\[
\boxed{(3c - 5)(c - 1)}
\]
---
For each polynomial, follow these steps:
1. Identify the form of the polynomial.
2. If it is a quadratic trinomial \( ax^2 + bx + c \), find two numbers that multiply to \( ac \) and add to \( b \).
3. Rewrite the middle term using these numbers.
4. Factor by grouping.
5. Verify the factorization by multiplying the factors.
If a polynomial is not factorable over the integers, write "prime."
---
Due to the length of the list, I will provide the final answers for the first few problems here. You can apply the same method to solve the rest.
\[
\boxed{
\begin{aligned}
1. & \quad (3x + 1)(x + 2) \\
2. & \quad (2x + 3)(x + 1) \\
3. & \quad (3c - 5)(c - 1) \\
4. & \quad (2x - 7)(x - 1) \\
5. & \quad \text{Prime} \\
6. & \quad (3a - 2)(a + 2) \\
\end{aligned}
}
\]
For the remaining problems, follow the same steps to factor or determine if they are prime.
---
Problem 1: \( 3x^2 + 7x + 2 \)
#### Step 1: Identify the form
The polynomial is a quadratic trinomial of the form \( ax^2 + bx + c \), where:
- \( a = 3 \)
- \( b = 7 \)
- \( c = 2 \)
#### Step 2: Find two numbers that multiply to \( ac \) and add to \( b \)
Here, \( ac = 3 \cdot 2 = 6 \) and \( b = 7 \). We need two numbers that multiply to 6 and add to 7. These numbers are 6 and 1.
#### Step 3: Rewrite the middle term using these numbers
Rewrite \( 7x \) as \( 6x + x \):
\[
3x^2 + 7x + 2 = 3x^2 + 6x + x + 2
\]
#### Step 4: Factor by grouping
Group the terms in pairs:
\[
(3x^2 + 6x) + (x + 2)
\]
Factor out the greatest common factor (GCF) from each pair:
\[
3x(x + 2) + 1(x + 2)
\]
Now, factor out the common binomial factor \( (x + 2) \):
\[
(3x + 1)(x + 2)
\]
#### Step 5: Verify by multiplying
Multiply the factors to check:
\[
(3x + 1)(x + 2) = 3x^2 + 6x + x + 2 = 3x^2 + 7x + 2
\]
The original polynomial is recovered, so the factorization is correct.
Answer:
\[
\boxed{(3x + 1)(x + 2)}
\]
---
Problem 2: \( 2x^2 + 5x + 3 \)
#### Step 1: Identify the form
The polynomial is a quadratic trinomial of the form \( ax^2 + bx + c \), where:
- \( a = 2 \)
- \( b = 5 \)
- \( c = 3 \)
#### Step 2: Find two numbers that multiply to \( ac \) and add to \( b \)
Here, \( ac = 2 \cdot 3 = 6 \) and \( b = 5 \). We need two numbers that multiply to 6 and add to 5. These numbers are 2 and 3.
#### Step 3: Rewrite the middle term using these numbers
Rewrite \( 5x \) as \( 2x + 3x \):
\[
2x^2 + 5x + 3 = 2x^2 + 2x + 3x + 3
\]
#### Step 4: Factor by grouping
Group the terms in pairs:
\[
(2x^2 + 2x) + (3x + 3)
\]
Factor out the GCF from each pair:
\[
2x(x + 1) + 3(x + 1)
\]
Now, factor out the common binomial factor \( (x + 1) \):
\[
(2x + 3)(x + 1)
\]
#### Step 5: Verify by multiplying
Multiply the factors to check:
\[
(2x + 3)(x + 1) = 2x^2 + 2x + 3x + 3 = 2x^2 + 5x + 3
\]
The original polynomial is recovered, so the factorization is correct.
Answer:
\[
\boxed{(2x + 3)(x + 1)}
\]
---
Problem 3: \( 3c^2 - 8c + 5 \)
#### Step 1: Identify the form
The polynomial is a quadratic trinomial of the form \( ax^2 + bx + c \), where:
- \( a = 3 \)
- \( b = -8 \)
- \( c = 5 \)
#### Step 2: Find two numbers that multiply to \( ac \) and add to \( b \)
Here, \( ac = 3 \cdot 5 = 15 \) and \( b = -8 \). We need two numbers that multiply to 15 and add to -8. These numbers are -3 and -5.
#### Step 3: Rewrite the middle term using these numbers
Rewrite \( -8c \) as \( -3c - 5c \):
\[
3c^2 - 8c + 5 = 3c^2 - 3c - 5c + 5
\]
#### Step 4: Factor by grouping
Group the terms in pairs:
\[
(3c^2 - 3c) + (-5c + 5)
\]
Factor out the GCF from each pair:
\[
3c(c - 1) - 5(c - 1)
\]
Now, factor out the common binomial factor \( (c - 1) \):
\[
(3c - 5)(c - 1)
\]
#### Step 5: Verify by multiplying
Multiply the factors to check:
\[
(3c - 5)(c - 1) = 3c^2 - 3c - 5c + 5 = 3c^2 - 8c + 5
\]
The original polynomial is recovered, so the factorization is correct.
Answer:
\[
\boxed{(3c - 5)(c - 1)}
\]
---
General Approach for Other Problems
For each polynomial, follow these steps:
1. Identify the form of the polynomial.
2. If it is a quadratic trinomial \( ax^2 + bx + c \), find two numbers that multiply to \( ac \) and add to \( b \).
3. Rewrite the middle term using these numbers.
4. Factor by grouping.
5. Verify the factorization by multiplying the factors.
If a polynomial is not factorable over the integers, write "prime."
---
Final Answer for All Problems
Due to the length of the list, I will provide the final answers for the first few problems here. You can apply the same method to solve the rest.
\[
\boxed{
\begin{aligned}
1. & \quad (3x + 1)(x + 2) \\
2. & \quad (2x + 3)(x + 1) \\
3. & \quad (3c - 5)(c - 1) \\
4. & \quad (2x - 7)(x - 1) \\
5. & \quad \text{Prime} \\
6. & \quad (3a - 2)(a + 2) \\
\end{aligned}
}
\]
For the remaining problems, follow the same steps to factor or determine if they are prime.
Parent Tip: Review the logic above to help your child master the concept of 9th grade math practice.