Adding Fractions Worksheet - Practice adding fractions with visual aids.

Let’s solve each problem step by step. Remember: when adding fractions with the same denominator (bottom number), you just add the numerators (top numbers) and keep the denominator the same.

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Problem 1:
$\frac{1}{5} + \frac{1}{5}$
Add top numbers: $1 + 1 = 2$
Keep bottom number: 5
Answer: $\frac{2}{5}$

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Problem 2:
$\frac{3}{7} + \frac{2}{7}$
Add top numbers: $3 + 2 = 5$
Keep bottom number: 7
Answer: $\frac{5}{7}$

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Problem 3:
$\frac{3}{5} + \frac{1}{5}$
Add top numbers: $3 + 1 = 4$
Keep bottom number: 5
Answer: $\frac{4}{5}$

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Problem 4:
$\frac{5}{10} + \frac{4}{10}$
Add top numbers: $5 + 4 = 9$
Keep bottom number: 10
Answer: $\frac{9}{10}$

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Problem 5:
$\frac{2}{6} + \frac{3}{6}$
Add top numbers: $2 + 3 = 5$
Keep bottom number: 6
Answer: $\frac{5}{6}$

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Problem 6:
$\frac{4}{8} + \frac{3}{8}$
Add top numbers: $4 + 3 = 7$
Keep bottom number: 8
Answer: $\frac{7}{8}$

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Problem 7:
$\frac{8}{15} + \frac{5}{15}$
Add top numbers: $8 + 5 = 13$
Keep bottom number: 15
Answer: $\frac{13}{15}$

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Problem 8:
$\frac{7}{12} + \frac{3}{12}$
Add top numbers: $7 + 3 = 10$
Keep bottom number: 12
Answer: $\frac{10}{12}$ → This can be simplified! Both 10 and 12 are divisible by 2.
$\frac{10 ÷ 2}{12 ÷ 2} = \frac{5}{6}$
So final answer is $\frac{5}{6}$

Wait — let me double-check Problem 8. The worksheet doesn’t say to simplify, but in math we usually do. However, looking at the other problems, none of them were simplified (like $\frac{9}{10}$ or $\frac{7}{8}$). So maybe we should leave it as $\frac{10}{12}$? But actually, $\frac{10}{12}$ reduces to $\frac{5}{6}$, which is simpler and correct. Since the instruction says “add the fractions”, and doesn’t specify whether to simplify, I’ll go with the simplified form because that’s standard practice.

But wait — let’s check if any other answers could be simplified:

- Problem 4: $\frac{9}{10}$ → already simplest
- Problem 5: $\frac{5}{6}$ → simplest
- Problem 6: $\frac{7}{8}$ → simplest
- Problem 7: $\frac{13}{15}$ → simplest
- Problem 8: $\frac{10}{12} = \frac{5}{6}$ → yes, simplifies

Actually, looking back at the worksheet, all denominators match, so no need for common denominators. And since the student is learning basic addition, maybe they’re not expected to simplify yet? But the problem says “solve accurately” — and accurate means simplified if possible.

I think safest is to give simplified answers where possible. So for #8, $\frac{5}{6}$ is better.

But let me confirm: in many elementary worksheets, they accept unsimplified unless told otherwise. Hmm.

Looking at the diagram for #8: circle divided into 12 parts. Adding 7 + 3 = 10 shaded parts out of 12 → $\frac{10}{12}$. If the worksheet expects matching the diagram, then $\frac{10}{12}$ might be what they want. But mathematically, $\frac{5}{6}$ is equivalent and simpler.

Since the instruction says “solve accurately”, and accuracy includes simplifying, I will simplify #8.

Final decision: Simplify only if it reduces evenly and obviously. For #8, 10/12 reduces to 5/6 — that’s clear.

Okay, let’s list all answers again carefully:

1. $\frac{2}{5}$
2. $\frac{5}{7}$
3. $\frac{4}{5}$
4. $\frac{9}{10}$
5. $\frac{5}{6}$
6. $\frac{7}{8}$
7. $\frac{13}{15}$
8. $\frac{5}{6}$ ← simplified from $\frac{10}{12}$

Wait — hold on! In problem 5, we have $\frac{2}{6} + \frac{3}{6} = \frac{5}{6}$ — that’s already simplified. Good.

In problem 8, $\frac{7}{12} + \frac{3}{12} = \frac{10}{12} = \frac{5}{6}$ — yes.

But now I notice: problem 5 and problem 8 both end up as $\frac{5}{6}$. That’s fine — different problems can have same answer.

Let me verify each calculation one more time:

1. 1+1=2 → 2/5 ✔️
2. 3+2=5 → 5/7 ✔️
3. 3+1=4 → 4/5 ✔️
4. 5+4=9 → 9/10 ✔️
5. 2+3=5 → 5/6 ✔️
6. 4+3=7 → 7/8 ✔️
7. 8+5=13 → 13/15 ✔️
8. 7+3=10 → 10/12 = 5/6 ✔️

All correct.

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Final Answer:
1. $\frac{2}{5}$
2. $\frac{5}{7}$
3. $\frac{4}{5}$
4. $\frac{9}{10}$
5. $\frac{5}{6}$
6. $\frac{7}{8}$
7. $\frac{13}{15}$
8. $\frac{5}{6}$