Math worksheet featuring six word problems that require adding and subtracting fractions, designed for educational practice.
Worksheet titled "Adding and Subtracting Fractions Word Problems" with six word problems involving fractions, including time, weight, money, distance, and fuel usage.
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Step-by-step solution for: Adding and Subtracting Fractions Worksheets with Answer Key
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Step-by-step solution for: Adding and Subtracting Fractions Worksheets with Answer Key
Here is the step-by-step solution to each of the six word problems involving adding and subtracting fractions.
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Problem 1: Robert spent 16½ hours on jogging and 12½ hours on swimming. What is the total time he spent on the two activities?
We need to add the two mixed numbers:
`16½ + 12½`
Step 1: Add the whole numbers:
`16 + 12 = 28`
Step 2: Add the fractions:
`½ + ½ = 1`
Step 3: Add the results:
`28 + 1 = 29`
✔ Answer: 29 hours
---
Problem 2: Mandy bought 22⅗ kg of tomatoes and 19⅔ kg potatoes. Find the total weight of vegetables she bought.
We need to add: `22⅗ + 19⅔`
Step 1: Add the whole numbers:
`22 + 19 = 41`
Step 2: Add the fractions: `⅗ + ⅔`
Find a common denominator. LCM of 5 and 3 is 15.
Convert:
- `⅗ = (3×3)/(5×3) = 9/15`
- `⅔ = (2×5)/(3×5) = 10/15`
Add: `9/15 + 10/15 = 19/15`
Step 3: Convert improper fraction to mixed number:
`19/15 = 1 4/15`
Step 4: Add to whole number part:
`41 + 1 4/15 = 42 4/15`
✔ Answer: 42⁴⁄₁₅ kg
---
Problem 3: Julia spent 11¹⁄₆ of her pocket money on movie tickets and ¾ on chocolates. How much money did she spend altogether?
We need to add: `11¹⁄₆ + ¾`
Step 1: Add the whole number and fractions separately.
Whole number: `11`
Fractions: `¹⁄₆ + ¾`
Find common denominator. LCM of 6 and 4 is 12.
Convert:
- `¹⁄₆ = 2/12`
- `¾ = 9/12`
Add: `2/12 + 9/12 = 11/12`
Step 2: Combine with whole number:
`11 + 11/12 = 11¹¹⁄₁₂`
✔ Answer: 11¹¹⁄₁₂ of her pocket money
*(Note: This means she spent more than her entire pocket money — perhaps it’s a trick question or implies she used savings too. But mathematically, this is correct.)*
---
Problem 4: In a high jump contest, Sandy jumped 3⁶⁄₇ m and Mike jumped 4²⁄₉ m. Who jumped higher and by how much?
We need to compare `3⁶⁄₇` and `4²⁄₉`, then find the difference.
Since 4 > 3, Mike jumped higher.
Now calculate: `4²⁄₉ - 3⁶⁄₇`
Step 1: Convert to improper fractions.
- `4²⁄₉ = (4×9 + 2)/9 = 38/9`
- `3⁶⁄₇ = (3×7 + 6)/7 = 27/7`
Step 2: Subtract: `38/9 - 27/7`
Find common denominator. LCM of 9 and 7 is 63.
Convert:
- `38/9 = (38×7)/(9×7) = 266/63`
- `27/7 = (27×9)/(7×9) = 243/63`
Subtract: `266/63 - 243/63 = 23/63`
✔ Answer: Mike jumped higher by ²³⁄₆₃ meters
---
Problem 5: Frank had 15⁸⁄₉ liters of fuel in his car. After he reached home by car, he had only 4⁵⁄₆ liters left. How much fuel was used?
We need to subtract: `15⁸⁄₉ - 4⁵⁄₆`
Step 1: Convert to improper fractions.
- `15⁸⁄₉ = (15×9 + 8)/9 = 143/9`
- `4⁵⁄₆ = (4×6 + 5)/6 = 29/6`
Step 2: Subtract: `143/9 - 29/6`
LCM of 9 and 6 is 18.
Convert:
- `143/9 = (143×2)/(9×2) = 286/18`
- `29/6 = (29×3)/(6×3) = 87/18`
Subtract: `286/18 - 87/18 = 199/18`
Step 3: Convert to mixed number:
`199 ÷ 18 = 11 remainder 1 → 11¹⁄₁₈`
✔ Answer: 11¹⁄₁₈ liters of fuel were used
---
Problem 6: Billy traveled 18¹⁄₃ km by car and then took a boat. Then he cycled 13¹⁄₆ km. If he had covered 35¾ km in total, then how many km did he travel by boat?
Total distance = Car + Boat + Cycle
So:
Boat = Total - Car - Cycle
→ `35¾ - 18¹⁄₃ - 13¹⁄₆`
Step 1: Convert all to improper fractions.
- `35¾ = (35×4 + 3)/4 = 143/4`
- `18¹⁄₃ = (18×3 + 1)/3 = 55/3`
- `13¹⁄₆ = (13×6 + 1)/6 = 79/6`
Step 2: Find a common denominator for subtraction. LCM of 4, 3, and 6 is 12.
Convert:
- `143/4 = (143×3)/(4×3) = 429/12`
- `55/3 = (55×4)/(3×4) = 220/12`
- `79/6 = (79×2)/(6×2) = 158/12`
Step 3: Subtract:
`429/12 - 220/12 - 158/12 = (429 - 220 - 158)/12 = 51/12`
Step 4: Simplify:
`51/12 = 17/4 = 4¼`
✔ Answer: Billy traveled 4¼ km by boat
---
1. 29 hours
2. 42⁴⁄₁₅ kg
3. 11¹¹⁄₁₂ of her pocket money
4. Mike jumped higher by ²³⁄₆₃ meters
5. 11¹⁄₁₈ liters
6. 4¼ km by boat
Let me know if you’d like visual diagrams or further explanation for any problem!
---
Problem 1: Robert spent 16½ hours on jogging and 12½ hours on swimming. What is the total time he spent on the two activities?
We need to add the two mixed numbers:
`16½ + 12½`
Step 1: Add the whole numbers:
`16 + 12 = 28`
Step 2: Add the fractions:
`½ + ½ = 1`
Step 3: Add the results:
`28 + 1 = 29`
✔ Answer: 29 hours
---
Problem 2: Mandy bought 22⅗ kg of tomatoes and 19⅔ kg potatoes. Find the total weight of vegetables she bought.
We need to add: `22⅗ + 19⅔`
Step 1: Add the whole numbers:
`22 + 19 = 41`
Step 2: Add the fractions: `⅗ + ⅔`
Find a common denominator. LCM of 5 and 3 is 15.
Convert:
- `⅗ = (3×3)/(5×3) = 9/15`
- `⅔ = (2×5)/(3×5) = 10/15`
Add: `9/15 + 10/15 = 19/15`
Step 3: Convert improper fraction to mixed number:
`19/15 = 1 4/15`
Step 4: Add to whole number part:
`41 + 1 4/15 = 42 4/15`
✔ Answer: 42⁴⁄₁₅ kg
---
Problem 3: Julia spent 11¹⁄₆ of her pocket money on movie tickets and ¾ on chocolates. How much money did she spend altogether?
We need to add: `11¹⁄₆ + ¾`
Step 1: Add the whole number and fractions separately.
Whole number: `11`
Fractions: `¹⁄₆ + ¾`
Find common denominator. LCM of 6 and 4 is 12.
Convert:
- `¹⁄₆ = 2/12`
- `¾ = 9/12`
Add: `2/12 + 9/12 = 11/12`
Step 2: Combine with whole number:
`11 + 11/12 = 11¹¹⁄₁₂`
✔ Answer: 11¹¹⁄₁₂ of her pocket money
*(Note: This means she spent more than her entire pocket money — perhaps it’s a trick question or implies she used savings too. But mathematically, this is correct.)*
---
Problem 4: In a high jump contest, Sandy jumped 3⁶⁄₇ m and Mike jumped 4²⁄₉ m. Who jumped higher and by how much?
We need to compare `3⁶⁄₇` and `4²⁄₉`, then find the difference.
Since 4 > 3, Mike jumped higher.
Now calculate: `4²⁄₉ - 3⁶⁄₇`
Step 1: Convert to improper fractions.
- `4²⁄₉ = (4×9 + 2)/9 = 38/9`
- `3⁶⁄₇ = (3×7 + 6)/7 = 27/7`
Step 2: Subtract: `38/9 - 27/7`
Find common denominator. LCM of 9 and 7 is 63.
Convert:
- `38/9 = (38×7)/(9×7) = 266/63`
- `27/7 = (27×9)/(7×9) = 243/63`
Subtract: `266/63 - 243/63 = 23/63`
✔ Answer: Mike jumped higher by ²³⁄₆₃ meters
---
Problem 5: Frank had 15⁸⁄₉ liters of fuel in his car. After he reached home by car, he had only 4⁵⁄₆ liters left. How much fuel was used?
We need to subtract: `15⁸⁄₉ - 4⁵⁄₆`
Step 1: Convert to improper fractions.
- `15⁸⁄₉ = (15×9 + 8)/9 = 143/9`
- `4⁵⁄₆ = (4×6 + 5)/6 = 29/6`
Step 2: Subtract: `143/9 - 29/6`
LCM of 9 and 6 is 18.
Convert:
- `143/9 = (143×2)/(9×2) = 286/18`
- `29/6 = (29×3)/(6×3) = 87/18`
Subtract: `286/18 - 87/18 = 199/18`
Step 3: Convert to mixed number:
`199 ÷ 18 = 11 remainder 1 → 11¹⁄₁₈`
✔ Answer: 11¹⁄₁₈ liters of fuel were used
---
Problem 6: Billy traveled 18¹⁄₃ km by car and then took a boat. Then he cycled 13¹⁄₆ km. If he had covered 35¾ km in total, then how many km did he travel by boat?
Total distance = Car + Boat + Cycle
So:
Boat = Total - Car - Cycle
→ `35¾ - 18¹⁄₃ - 13¹⁄₆`
Step 1: Convert all to improper fractions.
- `35¾ = (35×4 + 3)/4 = 143/4`
- `18¹⁄₃ = (18×3 + 1)/3 = 55/3`
- `13¹⁄₆ = (13×6 + 1)/6 = 79/6`
Step 2: Find a common denominator for subtraction. LCM of 4, 3, and 6 is 12.
Convert:
- `143/4 = (143×3)/(4×3) = 429/12`
- `55/3 = (55×4)/(3×4) = 220/12`
- `79/6 = (79×2)/(6×2) = 158/12`
Step 3: Subtract:
`429/12 - 220/12 - 158/12 = (429 - 220 - 158)/12 = 51/12`
Step 4: Simplify:
`51/12 = 17/4 = 4¼`
✔ Answer: Billy traveled 4¼ km by boat
---
✔ Final Answers Summary:
1. 29 hours
2. 42⁴⁄₁₅ kg
3. 11¹¹⁄₁₂ of her pocket money
4. Mike jumped higher by ²³⁄₆₃ meters
5. 11¹⁄₁₈ liters
6. 4¼ km by boat
Let me know if you’d like visual diagrams or further explanation for any problem!
Parent Tip: Review the logic above to help your child master the concept of adding fractions word problems worksheet.