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KS3. Algebra. 6. Solving Equations - Balancing - Maths with David - Free Printable

KS3. Algebra. 6. Solving Equations - Balancing - Maths with David

Educational worksheet: KS3. Algebra. 6. Solving Equations - Balancing - Maths with David. Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: KS3. Algebra. 6. Solving Equations - Balancing - Maths with David
(a) $4x + 1 = 2x + 7$
Subtract $2x$ from both sides: $2x + 1 = 7$
Subtract 1 from both sides: $2x = 6$
Divide by 2: $x = 3$

(b) $5x + 4 = 3x + 16$
Subtract $3x$ from both sides: $2x + 4 = 16$
Subtract 4 from both sides: $2x = 12$
Divide by 2: $x = 6$

(c) $2x + 8 = x + 12$
Subtract $x$ from both sides: $x + 8 = 12$
Subtract 8 from both sides: $x = 4$

(d) $7x + 1 = 2x + 46$
Subtract $2x$ from both sides: $5x + 1 = 46$
Subtract 1 from both sides: $5x = 45$
Divide by 5: $x = 9$

(e) $6x - 3 = 2x + 13$
Subtract $2x$ from both sides: $4x - 3 = 13$
Add 3 to both sides: $4x = 16$
Divide by 4: $x = 4$

(f) $9x - 10 = 7x + 24$
Subtract $7x$ from both sides: $2x - 10 = 24$
Add 10 to both sides: $2x = 34$
Divide by 2: $x = 17$

(g) $2x + 21 = 4x + 5$
Subtract $2x$ from both sides: $21 = 2x + 5$
Subtract 5 from both sides: $16 = 2x$
Divide by 2: $x = 8$

(h) $x + 2 = 5x - 2$
Subtract $x$ from both sides: $2 = 4x - 2$
Add 2 to both sides: $4 = 4x$
Divide by 4: $x = 1$

(i) $6x - 9 = 4x - 1$
Subtract $4x$ from both sides: $2x - 9 = -1$
Add 9 to both sides: $2x = 8$
Divide by 2: $x = 4$

(j) $5x + 2 = 16 - 2x$
Add $2x$ to both sides: $7x + 2 = 16$
Subtract 2 from both sides: $7x = 14$
Divide by 7: $x = 2$

(k) $3x - 1 = 23 - x$
Add $x$ to both sides: $4x - 1 = 23$
Add 1 to both sides: $4x = 24$
Divide by 4: $x = 6$

(l) $6x + 8 = 38 - 4x$
Add $4x$ to both sides: $10x + 8 = 38$
Subtract 8 from both sides: $10x = 30$
Divide by 10: $x = 3$

(m) $80 - x = 8x - 1$
Add $x$ to both sides: $80 = 9x - 1$
Add 1 to both sides: $81 = 9x$
Divide by 9: $x = 9$

(n) $2x + 7 = 17 - 8x$
Add $8x$ to both sides: $10x + 7 = 17$
Subtract 7 from both sides: $10x = 10$
Divide by 10: $x = 1$

(o) $15 - x = 27 - 3x$
Add $3x$ to both sides: $15 + 2x = 27$
Subtract 15 from both sides: $2x = 12$
Divide by 2: $x = 6$

(p) $12x - 20 = 15x - 38$
Subtract $12x$ from both sides: $-20 = 3x - 38$
Add 38 to both sides: $18 = 3x$
Divide by 3: $x = 6$

(q) $35x + 10 = 20x + 175$
Subtract $20x$ from both sides: $15x + 10 = 175$
Subtract 10 from both sides: $15x = 165$
Divide by 15: $x = 11$

(r) $14x = 2x + 60$
Subtract $2x$ from both sides: $12x = 60$
Divide by 12: $x = 5$
Parent Tip: Review the logic above to help your child master the concept of algebra solver.
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