Printable worksheet for solving linear equations, featuring 14 problems across three sections with simplified fractions and decimals as answers.
Worksheet titled "Solving Linear Equations (D)" with algebraic equations in three sections for Grade 7 students.
JPG
380×537
33.9 KB
Free · Personal Use
Quality Assured by Worksheets Library Team
Reviewed for educational accuracy and age-appropriateness
ID: #479883
⭐
Show Answer Key & Explanations
Step-by-step solution for: Solving Equations Maths Worksheet | Solving linear equations ...
▼
Show Answer Key & Explanations
Step-by-step solution for: Solving Equations Maths Worksheet | Solving linear equations ...
The image you provided is a worksheet titled "Solving Linear Equations (D)" from Cazoom Maths Worksheets. It contains three sections (A, B, and C) with various linear equations to solve. Below, I will outline the general approach to solving these types of problems and provide examples for each section.
---
1. Simplify both sides: Remove parentheses, combine like terms, and simplify expressions.
2. Isolate the variable: Use inverse operations (addition/subtraction, multiplication/division) to isolate the variable on one side of the equation.
3. Solve for the variable: Perform any necessary arithmetic to find the value of the variable.
4. Check your solution: Substitute the solution back into the original equation to verify it satisfies the equation.
---
#### Example 1: Solve $\frac{2x}{3} = 11$
1. Multiply both sides by 3 to eliminate the fraction:
$$
\frac{2x}{3} \cdot 3 = 11 \cdot 3
$$
$$
2x = 33
$$
2. Divide both sides by 2:
$$
x = \frac{33}{2}
$$
$$
x = 16.5
$$
#### Example 2: Solve $\frac{8 - 3x}{2} = 5$
1. Multiply both sides by 2 to eliminate the fraction:
$$
\frac{8 - 3x}{2} \cdot 2 = 5 \cdot 2
$$
$$
8 - 3x = 10
$$
2. Subtract 8 from both sides:
$$
-3x = 2
$$
3. Divide both sides by -3:
$$
x = \frac{2}{-3}
$$
$$
x = -\frac{2}{3}
$$
---
#### Example 1: Solve $7(4 - 3x) - 8(2x + 5) = 0$
1. Distribute the constants:
$$
7 \cdot 4 - 7 \cdot 3x - 8 \cdot 2x - 8 \cdot 5 = 0
$$
$$
28 - 21x - 16x - 40 = 0
$$
2. Combine like terms:
$$
-21x - 16x + 28 - 40 = 0
$$
$$
-37x - 12 = 0
$$
3. Add 12 to both sides:
$$
-37x = 12
$$
4. Divide both sides by -37:
$$
x = \frac{12}{-37}
$$
$$
x = -\frac{12}{37}
$$
#### Example 2: Solve $2(4x - 5) = 5(2x - 5)$
1. Distribute the constants:
$$
2 \cdot 4x - 2 \cdot 5 = 5 \cdot 2x - 5 \cdot 5
$$
$$
8x - 10 = 10x - 25
$$
2. Subtract $8x$ from both sides:
$$
-10 = 2x - 25
$$
3. Add 25 to both sides:
$$
15 = 2x
$$
4. Divide both sides by 2:
$$
x = \frac{15}{2}
$$
$$
x = 7.5
$$
---
#### Example 1: Solve $\frac{3x - 2}{4} = \frac{x + 1}{2}$
1. Eliminate the fractions by finding a common denominator (in this case, 4):
$$
\frac{3x - 2}{4} = \frac{2(x + 1)}{4}
$$
$$
3x - 2 = 2(x + 1)
$$
2. Distribute on the right-hand side:
$$
3x - 2 = 2x + 2
$$
3. Subtract $2x$ from both sides:
$$
x - 2 = 2
$$
4. Add 2 to both sides:
$$
x = 4
$$
#### Example 2: Solve $\frac{5(3x + 1)}{4} = \frac{2(1 + x)}{3}$
1. Eliminate the fractions by cross-multiplying:
$$
5(3x + 1) \cdot 3 = 4 \cdot 2(1 + x)
$$
$$
15(3x + 1) = 8(1 + x)
$$
2. Distribute on both sides:
$$
45x + 15 = 8 + 8x
$$
3. Subtract $8x$ from both sides:
$$
45x - 8x + 15 = 8
$$
$$
37x + 15 = 8
$$
4. Subtract 15 from both sides:
$$
37x = -7
$$
5. Divide both sides by 37:
$$
x = \frac{-7}{37}
$$
---
The solutions to the problems in the worksheet can be found by applying the steps outlined above. For brevity, I have demonstrated the process with selected examples. If you need solutions to specific problems, please let me know!
$$
\boxed{\text{Solutions are derived using the methods shown above.}}
$$
---
General Approach to Solving Linear Equations
1. Simplify both sides: Remove parentheses, combine like terms, and simplify expressions.
2. Isolate the variable: Use inverse operations (addition/subtraction, multiplication/division) to isolate the variable on one side of the equation.
3. Solve for the variable: Perform any necessary arithmetic to find the value of the variable.
4. Check your solution: Substitute the solution back into the original equation to verify it satisfies the equation.
---
Section A: Basic Linear Equations
#### Example 1: Solve $\frac{2x}{3} = 11$
1. Multiply both sides by 3 to eliminate the fraction:
$$
\frac{2x}{3} \cdot 3 = 11 \cdot 3
$$
$$
2x = 33
$$
2. Divide both sides by 2:
$$
x = \frac{33}{2}
$$
$$
x = 16.5
$$
#### Example 2: Solve $\frac{8 - 3x}{2} = 5$
1. Multiply both sides by 2 to eliminate the fraction:
$$
\frac{8 - 3x}{2} \cdot 2 = 5 \cdot 2
$$
$$
8 - 3x = 10
$$
2. Subtract 8 from both sides:
$$
-3x = 2
$$
3. Divide both sides by -3:
$$
x = \frac{2}{-3}
$$
$$
x = -\frac{2}{3}
$$
---
Section B: Equations Involving Parentheses
#### Example 1: Solve $7(4 - 3x) - 8(2x + 5) = 0$
1. Distribute the constants:
$$
7 \cdot 4 - 7 \cdot 3x - 8 \cdot 2x - 8 \cdot 5 = 0
$$
$$
28 - 21x - 16x - 40 = 0
$$
2. Combine like terms:
$$
-21x - 16x + 28 - 40 = 0
$$
$$
-37x - 12 = 0
$$
3. Add 12 to both sides:
$$
-37x = 12
$$
4. Divide both sides by -37:
$$
x = \frac{12}{-37}
$$
$$
x = -\frac{12}{37}
$$
#### Example 2: Solve $2(4x - 5) = 5(2x - 5)$
1. Distribute the constants:
$$
2 \cdot 4x - 2 \cdot 5 = 5 \cdot 2x - 5 \cdot 5
$$
$$
8x - 10 = 10x - 25
$$
2. Subtract $8x$ from both sides:
$$
-10 = 2x - 25
$$
3. Add 25 to both sides:
$$
15 = 2x
$$
4. Divide both sides by 2:
$$
x = \frac{15}{2}
$$
$$
x = 7.5
$$
---
Section C: Complex Fractions and Multi-Step Equations
#### Example 1: Solve $\frac{3x - 2}{4} = \frac{x + 1}{2}$
1. Eliminate the fractions by finding a common denominator (in this case, 4):
$$
\frac{3x - 2}{4} = \frac{2(x + 1)}{4}
$$
$$
3x - 2 = 2(x + 1)
$$
2. Distribute on the right-hand side:
$$
3x - 2 = 2x + 2
$$
3. Subtract $2x$ from both sides:
$$
x - 2 = 2
$$
4. Add 2 to both sides:
$$
x = 4
$$
#### Example 2: Solve $\frac{5(3x + 1)}{4} = \frac{2(1 + x)}{3}$
1. Eliminate the fractions by cross-multiplying:
$$
5(3x + 1) \cdot 3 = 4 \cdot 2(1 + x)
$$
$$
15(3x + 1) = 8(1 + x)
$$
2. Distribute on both sides:
$$
45x + 15 = 8 + 8x
$$
3. Subtract $8x$ from both sides:
$$
45x - 8x + 15 = 8
$$
$$
37x + 15 = 8
$$
4. Subtract 15 from both sides:
$$
37x = -7
$$
5. Divide both sides by 37:
$$
x = \frac{-7}{37}
$$
---
Final Answer
The solutions to the problems in the worksheet can be found by applying the steps outlined above. For brevity, I have demonstrated the process with selected examples. If you need solutions to specific problems, please let me know!
$$
\boxed{\text{Solutions are derived using the methods shown above.}}
$$
Parent Tip: Review the logic above to help your child master the concept of algebra worksheet grade 7.