301 Moved Permanently - Free Printable
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Step-by-step solution for: 301 Moved Permanently
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Show Answer Key & Explanations
Step-by-step solution for: 301 Moved Permanently
Problem: Evaluate each algebraic expression using the values given.
We will solve each problem step by step, substituting the given values into the expressions and simplifying them.
---
#### 1. \( q^2 + p \); use \( p = 5 \), and \( q = 2 \)
Substitute \( p = 5 \) and \( q = 2 \):
\[
q^2 + p = 2^2 + 5
\]
Calculate \( 2^2 \):
\[
2^2 = 4
\]
Add 5:
\[
4 + 5 = 9
\]
Answer: \( 9 \)
---
#### 2. \( (x + y) \div 5 \); use \( x = 1 \), and \( y = 4 \)
Substitute \( x = 1 \) and \( y = 4 \):
\[
(x + y) \div 5 = (1 + 4) \div 5
\]
Calculate \( 1 + 4 \):
\[
1 + 4 = 5
\]
Divide by 5:
\[
5 \div 5 = 1
\]
Answer: \( 1 \)
---
#### 3. \( (x + y) \div 4 \); use \( x = 3 \), and \( y = 5 \)
Substitute \( x = 3 \) and \( y = 5 \):
\[
(x + y) \div 4 = (3 + 5) \div 4
\]
Calculate \( 3 + 5 \):
\[
3 + 5 = 8
\]
Divide by 4:
\[
8 \div 4 = 2
\]
Answer: \( 2 \)
---
#### 4. \( j + 6h \); use \( h = 4 \), and \( j = 1 \)
Substitute \( h = 4 \) and \( j = 1 \):
\[
j + 6h = 1 + 6(4)
\]
Calculate \( 6 \times 4 \):
\[
6 \times 4 = 24
\]
Add 1:
\[
1 + 24 = 25
\]
Answer: \( 25 \)
---
#### 5. \( x(5 - y) \); use \( x = 6 \), and \( y = 1 \)
Substitute \( x = 6 \) and \( y = 1 \):
\[
x(5 - y) = 6(5 - 1)
\]
Calculate \( 5 - 1 \):
\[
5 - 1 = 4
\]
Multiply by 6:
\[
6 \times 4 = 24
\]
Answer: \( 24 \)
---
#### 6. \( a(a - b) \); use \( a = 3 \), and \( b = 1 \)
Substitute \( a = 3 \) and \( b = 1 \):
\[
a(a - b) = 3(3 - 1)
\]
Calculate \( 3 - 1 \):
\[
3 - 1 = 2
\]
Multiply by 3:
\[
3 \times 2 = 6
\]
Answer: \( 6 \)
---
#### 7. \( j + j - h \); use \( h = 3 \), and \( j = 3 \)
Substitute \( h = 3 \) and \( j = 3 \):
\[
j + j - h = 3 + 3 - 3
\]
Calculate \( 3 + 3 \):
\[
3 + 3 = 6
\]
Subtract 3:
\[
6 - 3 = 3
\]
Answer: \( 3 \)
---
#### 8. \( y(x + x) \); use \( x = 5 \), and \( y = 3 \)
Substitute \( x = 5 \) and \( y = 3 \):
\[
y(x + x) = 3(5 + 5)
\]
Calculate \( 5 + 5 \):
\[
5 + 5 = 10
\]
Multiply by 3:
\[
3 \times 10 = 30
\]
Answer: \( 30 \)
---
#### 9. \( m(n - m) \); use \( m = 2 \), and \( n = 6 \)
Substitute \( m = 2 \) and \( n = 6 \):
\[
m(n - m) = 2(6 - 2)
\]
Calculate \( 6 - 2 \):
\[
6 - 2 = 4
\]
Multiply by 2:
\[
2 \times 4 = 8
\]
Answer: \( 8 \)
---
#### 10. \( p(m + q) \); use \( m = 2 \), \( p = 6 \), and \( q = 6 \)
Substitute \( m = 2 \), \( p = 6 \), and \( q = 6 \):
\[
p(m + q) = 6(2 + 6)
\]
Calculate \( 2 + 6 \):
\[
2 + 6 = 8
\]
Multiply by 6:
\[
6 \times 8 = 48
\]
Answer: \( 48 \)
---
#### 11. \( 4 - (x - y) \); use \( x = 5 \), and \( y = 2 \)
Substitute \( x = 5 \) and \( y = 2 \):
\[
4 - (x - y) = 4 - (5 - 2)
\]
Calculate \( 5 - 2 \):
\[
5 - 2 = 3
\]
Subtract from 4:
\[
4 - 3 = 1
\]
Answer: \( 1 \)
---
#### 12. \( p + q + p \); use \( p = 1 \), and \( q = 2 \)
Substitute \( p = 1 \) and \( q = 2 \):
\[
p + q + p = 1 + 2 + 1
\]
Add the terms:
\[
1 + 2 + 1 = 4
\]
Answer: \( 4 \)
---
#### 13. \( xy - x \); use \( x = 4 \), and \( y = 4 \)
Substitute \( x = 4 \) and \( y = 4 \):
\[
xy - x = 4 \cdot 4 - 4
\]
Calculate \( 4 \cdot 4 \):
\[
4 \cdot 4 = 16
\]
Subtract 4:
\[
16 - 4 = 12
\]
Answer: \( 12 \)
---
#### 14. \( y(y - x) \); use \( x = 1 \), and \( y = 4 \)
Substitute \( x = 1 \) and \( y = 4 \):
\[
y(y - x) = 4(4 - 1)
\]
Calculate \( 4 - 1 \):
\[
4 - 1 = 3
\]
Multiply by 4:
\[
4 \times 3 = 12
\]
Answer: \( 12 \)
---
#### 15. \( j + k - 5 \); use \( j = 1 \), and \( k = 5 \)
Substitute \( j = 1 \) and \( k = 5 \):
\[
j + k - 5 = 1 + 5 - 5
\]
Calculate \( 1 + 5 \):
\[
1 + 5 = 6
\]
Subtract 5:
\[
6 - 5 = 1
\]
Answer: \( 1 \)
---
#### 16. \( j + hk \); use \( h = 6 \), \( j = 3 \), and \( k = 3 \)
Substitute \( h = 6 \), \( j = 3 \), and \( k = 3 \):
\[
j + hk = 3 + 6 \cdot 3
\]
Calculate \( 6 \cdot 3 \):
\[
6 \cdot 3 = 18
\]
Add 3:
\[
3 + 18 = 21
\]
Answer: \( 21 \)
---
#### 17. \( 5(x + y) \); use \( x = 1 \), and \( y = 1 \)
Substitute \( x = 1 \) and \( y = 1 \):
\[
5(x + y) = 5(1 + 1)
\]
Calculate \( 1 + 1 \):
\[
1 + 1 = 2
\]
Multiply by 5:
\[
5 \times 2 = 10
\]
Answer: \( 10 \)
---
#### 18. \( n + m - 6 \); use \( m = 2 \), and \( n = 5 \)
Substitute \( m = 2 \) and \( n = 5 \):
\[
n + m - 6 = 5 + 2 - 6
\]
Calculate \( 5 + 2 \):
\[
5 + 2 = 7
\]
Subtract 6:
\[
7 - 6 = 1
\]
Answer: \( 1 \)
---
#### 19. \( x - y + z \); use \( x = 6 \), \( y = 3 \), and \( z = 6 \)
Substitute \( x = 6 \), \( y = 3 \), and \( z = 6 \):
\[
x - y + z = 6 - 3 + 6
\]
Calculate \( 6 - 3 \):
\[
6 - 3 = 3
\]
Add 6:
\[
3 + 6 = 9
\]
Answer: \( 9 \)
---
#### 20. \( pm - 5 \); use \( m = 5 \), and \( p = 6 \)
Substitute \( m = 5 \) and \( p = 6 \):
\[
pm - 5 = 6 \cdot 5 - 5
\]
Calculate \( 6 \cdot 5 \):
\[
6 \cdot 5 = 30
\]
Subtract 5:
\[
30 - 5 = 25
\]
Answer: \( 25 \)
---
#### 21. \( xy + y \); use \( x = 5 \), and \( y = 8 \)
Substitute \( x = 5 \) and \( y = 8 \):
\[
xy + y = 5 \cdot 8 + 8
\]
Calculate \( 5 \cdot 8 \):
\[
5 \cdot 8 = 40
\]
Add 8:
\[
40 + 8 = 48
\]
Answer: \( 48 \)
---
#### 22. \( pq \div 4 \); use \( p = 14 \), and \( q = 14 \)
Substitute \( p = 14 \) and \( q = 14 \):
\[
pq \div 4 = 14 \cdot 14 \div 4
\]
Calculate \( 14 \cdot 14 \):
\[
14 \cdot 14 = 196
\]
Divide by 4:
\[
196 \div 4 = 49
\]
Answer: \( 49 \)
---
Final Answers:
\[
\boxed{
\begin{array}{ll}
1. & 9 \\
2. & 1 \\
3. & 2 \\
4. & 25 \\
5. & 24 \\
6. & 6 \\
7. & 3 \\
8. & 30 \\
9. & 8 \\
10. & 48 \\
11. & 1 \\
12. & 4 \\
13. & 12 \\
14. & 12 \\
15. & 1 \\
16. & 21 \\
17. & 10 \\
18. & 1 \\
19. & 9 \\
20. & 25 \\
21. & 48 \\
22. & 49 \\
\end{array}
}
\]
Parent Tip: Review the logic above to help your child master the concept of algebraic expressions 7th grade.