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Evaluating Algebraic Expression Worksheets (printable, online ... - Free Printable

Evaluating Algebraic Expression Worksheets (printable, online ...

Educational worksheet: Evaluating Algebraic Expression Worksheets (printable, online .... Download and print for classroom or home learning activities.

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Show Answer Key & Explanations Step-by-step solution for: Evaluating Algebraic Expression Worksheets (printable, online ...
To solve the given problem, we need to evaluate each algebraic expression by substituting the given values for the variables. Let's go through each expression step by step.

Expression 1: $-4 - 8f$, if $f = -6$


\[
-4 - 8f = -4 - 8(-6)
\]
First, calculate $-8 \times -6$:
\[
-8 \times -6 = 48
\]
Now substitute back:
\[
-4 + 48 = 44
\]
So, the value is:
\[
\boxed{44}
\]

Expression 2: $7n - 2$, if $n = -8$


\[
7n - 2 = 7(-8) - 2
\]
First, calculate $7 \times -8$:
\[
7 \times -8 = -56
\]
Now substitute back:
\[
-56 - 2 = -58
\]
So, the value is:
\[
\boxed{-58}
\]

Expression 3: $-4 + 4r$, if $r = -5$


\[
-4 + 4r = -4 + 4(-5)
\]
First, calculate $4 \times -5$:
\[
4 \times -5 = -20
\]
Now substitute back:
\[
-4 - 20 = -24
\]
So, the value is:
\[
\boxed{-24}
\]

Expression 4: $-4r + 9$, if $r = 3$


\[
-4r + 9 = -4(3) + 9
\]
First, calculate $-4 \times 3$:
\[
-4 \times 3 = -12
\]
Now substitute back:
\[
-12 + 9 = -3
\]
So, the value is:
\[
\boxed{-3}
\]

Expression 5: $8 + 3z$, if $z = -2$


\[
8 + 3z = 8 + 3(-2)
\]
First, calculate $3 \times -2$:
\[
3 \times -2 = -6
\]
Now substitute back:
\[
8 - 6 = 2
\]
So, the value is:
\[
\boxed{2}
\]

Expression 6: $\frac{15}{d} - 2$, if $d = -5$


\[
\frac{15}{d} - 2 = \frac{15}{-5} - 2
\]
First, calculate $\frac{15}{-5}$:
\[
\frac{15}{-5} = -3
\]
Now substitute back:
\[
-3 - 2 = -5
\]
So, the value is:
\[
\boxed{-5}
\]

Expression 7: $-8c + 6$, if $c = 3$


\[
-8c + 6 = -8(3) + 6
\]
First, calculate $-8 \times 3$:
\[
-8 \times 3 = -24
\]
Now substitute back:
\[
-24 + 6 = -18
\]
So, the value is:
\[
\boxed{-18}
\]

Expression 8: $-7 + 3s$, if $s = -4$


\[
-7 + 3s = -7 + 3(-4)
\]
First, calculate $3 \times -4$:
\[
3 \times -4 = -12
\]
Now substitute back:
\[
-7 - 12 = -19
\]
So, the value is:
\[
\boxed{-19}
\]

Expression 9: $9 - 2h$, if $h = -4$


\[
9 - 2h = 9 - 2(-4)
\]
First, calculate $-2 \times -4$:
\[
-2 \times -4 = 8
\]
Now substitute back:
\[
9 + 8 = 17
\]
So, the value is:
\[
\boxed{17}
\]

Expression 10: $19 - \frac{21}{h}$, if $h = -3$


\[
19 - \frac{21}{h} = 19 - \frac{21}{-3}
\]
First, calculate $\frac{21}{-3}$:
\[
\frac{21}{-3} = -7
\]
Now substitute back:
\[
19 - (-7) = 19 + 7 = 26
\]
So, the value is:
\[
\boxed{26}
\]

Final Answer:


\[
\boxed{44, -58, -24, -3, 2, -5, -18, -19, 17, 26}
\]
Parent Tip: Review the logic above to help your child master the concept of algebraic expressions 7th grade.
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