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Class 6 Maths Worksheet: Algebra Word Problems - Practice solving real-world problems using algebraic expressions and equations.

Class 6 Maths Worksheet on Algebra Word Problems from Kaboodle, featuring ten word problems involving basic algebraic expressions and equations.

Class 6 Maths Worksheet on Algebra Word Problems from Kaboodle, featuring ten word problems involving basic algebraic expressions and equations.

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Show Answer Key & Explanations Step-by-step solution for: Algebra (Word Problems) worksheet
Let's solve each problem step by step with clear explanations.

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1. Think of a number, add 2 to it and then multiply the sum by 6, the result is 42. Number = ?

Let the number be x.

According to the problem:
> (x + 2) × 6 = 42

Divide both sides by 6:
> x + 2 = 7

Subtract 2 from both sides:
> x = 5

Answer: 5

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2. The side of a regular hexagon is s cm. Find its perimeter.

A regular hexagon has 6 equal sides.

Perimeter = sum of all sides = 6 × s = 6s cm

Answer: 6s cm

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3. The number of bacteria in a culture is x now. It becomes square of itself after one week. What will be its number after two weeks?

- Now: x
- After 1 week: x²
- After 2 weeks: (x²)² = x⁴

Answer: x⁴

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4. If there are x rows of chairs and each row contains x² chairs. Determine the total number of chairs.

Total chairs = number of rows × chairs per row
= x × x² =

Answer: x³

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5. The length of a rectangle is y times its breadth x. The area of the rectangle is

Breadth = x
Length = y × x = xy

Area = length × breadth = xy × x = x²y

Answer: x²y

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6. The length and breadth of a room are 3x²y³ and 6x³y². Find its area.

Area = length × breadth
= (3x²y³) × (6x³y²)

Multiply coefficients: 3 × 6 = 18
Add exponents of like bases:
x² × x³ = x⁵
y³ × y² = y⁵

So, Area = 18x⁵y⁵

Answer: 18x⁵y⁵

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7. What is the value of x + x + x + ... (y times) =

Adding x, y times means: x × y = xy

Answer: xy

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8. A chair costs ₹x. The cost of x²y chairs is =

Cost of 1 chair = ₹x
Cost of x²y chairs = x × x²y = x³y

Answer: ₹ x³y

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9. A man spends ₹x per week. The total money spent by him in xy² weeks is =

Money per week = ₹x
Number of weeks = xy²
Total spent = x × xy² = x²y²

Answer: ₹ x²y²

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10. There are 47 boys in the class. This is three more than four times the number of girls. How many girls are there in the class?

Let number of girls = g

According to problem:
> 4g + 3 = 47

Subtract 3 from both sides:
> 4g = 44

Divide by 4:
> g = 11

Answer: 11 girls

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Final Answers:



1. 5
2. 6s cm
3. x⁴
4.
5. x²y
6. 18x⁵y⁵
7. xy
8. ₹ x³y
9. ₹ x²y²
10. 11

You can fill these into the boxes on your worksheet! Let me know if you need help writing them out neatly. 😊
Parent Tip: Review the logic above to help your child master the concept of algebraic word problems worksheet.
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