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Practice worksheet for solving angle relationships using geometric diagrams and algebraic expressions.

Worksheet titled "Angle Relationships" with 12 diagrams and equations to find missing angle measures.

Worksheet titled "Angle Relationships" with 12 diagrams and equations to find missing angle measures.

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Show Answer Key & Explanations Step-by-step solution for: angle relationships worksheet | Angle relationships, Relationship ...
To solve the problems involving angle relationships, we need to use basic geometric principles such as:

1. Complementary Angles: Two angles are complementary if their measures add up to 90°.
2. Supplementary Angles: Two angles are supplementary if their measures add up to 180°.
3. Vertical Angles: Vertical angles are congruent (equal in measure).
4. Adjacent Angles: Adjacent angles share a common vertex and a common side but do not overlap.

Let's solve each problem step by step.

---

Problem 1:


Given:
- \( m\angle CPM = \)
- \( m\angle QTM = 62^\circ \)

Since \( \angle CPM \) and \( \angle QTM \) are vertical angles, they are congruent:
\[ m\angle CPM = m\angle QTM = 62^\circ \]

Answer:
\[ \boxed{62^\circ} \]

---

Problem 2:


Given:
- \( m\angle XFY = \)
- \( m\angle TFY = 24^\circ \)

Since \( \angle XFY \) and \( \angle TFY \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle XFY + m\angle TFY = 180^\circ \]
\[ m\angle XFY + 24^\circ = 180^\circ \]
\[ m\angle XFY = 180^\circ - 24^\circ \]
\[ m\angle XFY = 156^\circ \]

Answer:
\[ \boxed{156^\circ} \]

---

Problem 3:


Given:
- \( m\angle CXZ = \)
- \( m\angle BXZ = 52^\circ \)

Since \( \angle CXZ \) and \( \angle BXZ \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle CXZ + m\angle BXZ = 180^\circ \]
\[ m\angle CXZ + 52^\circ = 180^\circ \]
\[ m\angle CXZ = 180^\circ - 52^\circ \]
\[ m\angle CXZ = 128^\circ \]

Answer:
\[ \boxed{128^\circ} \]

---

Problem 4:


Given:
- \( m\angle ZMP = \)
- \( m\angle ZMQ = 82^\circ \)

Since \( \angle ZMP \) and \( \angle ZMQ \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle ZMP + m\angle ZMQ = 180^\circ \]
\[ m\angle ZMP + 82^\circ = 180^\circ \]
\[ m\angle ZMP = 180^\circ - 82^\circ \]
\[ m\angle ZMP = 98^\circ \]

Answer:
\[ \boxed{98^\circ} \]

---

Problem 5:


Given:
- \( m\angle XFD = \)
- \( m\angle EFD = 53^\circ \)

Since \( \angle XFD \) and \( \angle EFD \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle XFD + m\angle EFD = 180^\circ \]
\[ m\angle XFD + 53^\circ = 180^\circ \]
\[ m\angle XFD = 180^\circ - 53^\circ \]
\[ m\angle XFD = 127^\circ \]

Answer:
\[ \boxed{127^\circ} \]

---

Problem 6:


Given:
- \( m\angle CRU = \)
- \( m\angle BRU = 69^\circ \)

Since \( \angle CRU \) and \( \angle BRU \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle CRU + m\angle BRU = 180^\circ \]
\[ m\angle CRU + 69^\circ = 180^\circ \]
\[ m\angle CRU = 180^\circ - 69^\circ \]
\[ m\angle CRU = 111^\circ \]

Answer:
\[ \boxed{111^\circ} \]

---

Problem 7:


Given:
- \( m\angle USM = \)
- \( m\angle KSM = 92^\circ \)

Since \( \angle USM \) and \( \angle KSM \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle USM + m\angle KSM = 180^\circ \]
\[ m\angle USM + 92^\circ = 180^\circ \]
\[ m\angle USM = 180^\circ - 92^\circ \]
\[ m\angle USM = 88^\circ \]

Answer:
\[ \boxed{88^\circ} \]

---

Problem 8:


Given:
- \( m\angle KMR = \)
- \( m\angle QMR = 133^\circ \)

Since \( \angle KMR \) and \( \angle QMR \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle KMR + m\angle QMR = 180^\circ \]
\[ m\angle KMR + 133^\circ = 180^\circ \]
\[ m\angle KMR = 180^\circ - 133^\circ \]
\[ m\angle KMR = 47^\circ \]

Answer:
\[ \boxed{47^\circ} \]

---

Problem 9:


Given:
- \( m\angle HMR = \)
- \( m\angle ZMR = 115^\circ \)

Since \( \angle HMR \) and \( \angle ZMR \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle HMR + m\angle ZMR = 180^\circ \]
\[ m\angle HMR + 115^\circ = 180^\circ \]
\[ m\angle HMR = 180^\circ - 115^\circ \]
\[ m\angle HMR = 65^\circ \]

Answer:
\[ \boxed{65^\circ} \]

---

Problem 10:


Given:
- \( m\angle EXP = \)
- \( m\angle GXP = 74^\circ \)

Since \( \angle EXP \) and \( \angle GXP \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle EXP + m\angle GXP = 180^\circ \]
\[ m\angle EXP + 74^\circ = 180^\circ \]
\[ m\angle EXP = 180^\circ - 74^\circ \]
\[ m\angle EXP = 106^\circ \]

Answer:
\[ \boxed{106^\circ} \]

---

Problem 11:


Given:
- \( m\angle CZQ = \)
- \( m\angle GZQ = 11^\circ \)

Since \( \angle CZQ \) and \( \angle GZQ \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle CZQ + m\angle GZQ = 180^\circ \]
\[ m\angle CZQ + 11^\circ = 180^\circ \]
\[ m\angle CZQ = 180^\circ - 11^\circ \]
\[ m\angle CZQ = 169^\circ \]

Answer:
\[ \boxed{169^\circ} \]

---

Problem 12:


Given:
- \( m\angle FTR = \)
- \( m\angle VTR = 129^\circ \)

Since \( \angle FTR \) and \( \angle VTR \) are adjacent angles forming a straight line, they are supplementary:
\[ m\angle FTR + m\angle VTR = 180^\circ \]
\[ m\angle FTR + 129^\circ = 180^\circ \]
\[ m\angle FTR = 180^\circ - 129^\circ \]
\[ m\angle FTR = 51^\circ \]

Answer:
\[ \boxed{51^\circ} \]

---

Final Answers:


\[
\boxed{
62^\circ, 156^\circ, 128^\circ, 98^\circ, 127^\circ, 111^\circ, 88^\circ, 47^\circ, 65^\circ, 106^\circ, 169^\circ, 51^\circ
}
\]
Parent Tip: Review the logic above to help your child master the concept of angle relationships worksheet pdf.
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