Arc Length-Sector Area, Wells Worksheet (Given) PDF | PDF - Free Printable
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Step-by-step solution for: Arc Length-Sector Area, Wells Worksheet (Given) PDF | PDF
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Show Answer Key & Explanations
Step-by-step solution for: Arc Length-Sector Area, Wells Worksheet (Given) PDF | PDF
Let's solve each problem step by step using the arc length formula:
$$
\text{Arc Length} = \frac{\theta}{360^\circ} \times 2\pi r
$$
Where:
- $\theta$ is the central angle in degrees,
- $r$ is the radius of the circle.
We’ll also use:
- Circumference: $C = 2\pi r$
- Diameter: $d = 2r$
---
Given:
- Radius $r = 6$ cm
- Central angle $\theta = 120^\circ$
$$
\text{Arc Length} = \frac{120}{360} \times 2\pi \times 6 = \frac{1}{3} \times 12\pi = 4\pi \text{ cm}
$$
✔ Answer: $4\pi$ cm
---
Given:
- Diameter = 24 cm → Radius $r = 12$ cm
- Central angle $\theta = 60^\circ$
$$
\text{Arc Length} = \frac{60}{360} \times 2\pi \times 12 = \frac{1}{6} \times 24\pi = 4\pi \text{ cm}
$$
✔ Answer: $4\pi$ cm
---
Given:
- Arc length = $5\pi$ inches
- Central angle $\theta = 30^\circ$
Use the formula:
$$
\text{Arc Length} = \frac{\theta}{360} \times 2\pi r
$$
$$
5\pi = \frac{30}{360} \times 2\pi r = \frac{1}{12} \times 2\pi r = \frac{\pi r}{6}
$$
Now solve for $r$:
$$
5\pi = \frac{\pi r}{6} \Rightarrow 5 = \frac{r}{6} \Rightarrow r = 30 \text{ inches}
$$
✔ Answer: 30 inches
---
Given:
- Radius $r = 10$ cm
- Central angle $\theta = 70^\circ$
$$
\text{Arc Length} = \frac{70}{360} \times 2\pi \times 10 = \frac{7}{36} \times 20\pi = \frac{140\pi}{36} = \frac{35\pi}{9} \text{ cm}
$$
✔ Answer: $\frac{35\pi}{9}$ cm (or approximately $12.22$ cm)
---
Given:
- Arc length = $88\pi$
- $\theta = 80^\circ$
Use arc length formula:
$$
88\pi = \frac{80}{360} \times 2\pi r = \frac{2}{9} \times 2\pi r = \frac{4\pi r}{9}
$$
Solve for $r$:
$$
88\pi = \frac{4\pi r}{9} \Rightarrow 88 = \frac{4r}{9} \Rightarrow r = \frac{88 \times 9}{4} = 198
$$
So, radius $r = 198$, then diameter $d = 2r = 396$
✔ Answer: 396 units
---
Given:
- Circumference $C = 25\pi$
- So $2\pi r = 25\pi \Rightarrow r = \frac{25}{2} = 12.5$
Now find arc length for $90^\circ$:
$$
\text{Arc Length} = \frac{90}{360} \times 2\pi r = \frac{1}{4} \times 25\pi = \frac{25\pi}{4}
$$
Alternatively, since $90^\circ$ is $1/4$ of the circle, arc length is $1/4$ of circumference:
$$
\frac{1}{4} \times 25\pi = \frac{25\pi}{4}
$$
✔ Answer: $\frac{25\pi}{4}$ units
---
Given:
- Arc length = $14\pi$
- Radius $r = 18$
Use:
$$
\text{Arc Length} = \frac{\theta}{360} \times 2\pi r
$$
$$
14\pi = \frac{\theta}{360} \times 2\pi \times 18 = \frac{\theta}{360} \times 36\pi
$$
Divide both sides by $\pi$:
$$
14 = \frac{\theta}{360} \times 36 \Rightarrow 14 = \frac{36\theta}{360} = \frac{\theta}{10}
\Rightarrow \theta = 140^\circ
$$
✔ Answer: $140^\circ$
---
1. $4\pi$ cm
2. $4\pi$ cm
3. 30 inches
4. $\frac{35\pi}{9}$ cm
5. 396 units
6. $\frac{25\pi}{4}$ units
7. $140^\circ$
Let me know if you'd like these answers boxed or formatted differently!
$$
\text{Arc Length} = \frac{\theta}{360^\circ} \times 2\pi r
$$
Where:
- $\theta$ is the central angle in degrees,
- $r$ is the radius of the circle.
We’ll also use:
- Circumference: $C = 2\pi r$
- Diameter: $d = 2r$
---
1. Find the length of arc $AB$.
Given:
- Radius $r = 6$ cm
- Central angle $\theta = 120^\circ$
$$
\text{Arc Length} = \frac{120}{360} \times 2\pi \times 6 = \frac{1}{3} \times 12\pi = 4\pi \text{ cm}
$$
✔ Answer: $4\pi$ cm
---
2. The diameter is 24 cm. Find the length of arc $CD$.
Given:
- Diameter = 24 cm → Radius $r = 12$ cm
- Central angle $\theta = 60^\circ$
$$
\text{Arc Length} = \frac{60}{360} \times 2\pi \times 12 = \frac{1}{6} \times 24\pi = 4\pi \text{ cm}
$$
✔ Answer: $4\pi$ cm
---
3. The length of arc $EF$ is $5\pi$ in. Find the length of the radius.
Given:
- Arc length = $5\pi$ inches
- Central angle $\theta = 30^\circ$
Use the formula:
$$
\text{Arc Length} = \frac{\theta}{360} \times 2\pi r
$$
$$
5\pi = \frac{30}{360} \times 2\pi r = \frac{1}{12} \times 2\pi r = \frac{\pi r}{6}
$$
Now solve for $r$:
$$
5\pi = \frac{\pi r}{6} \Rightarrow 5 = \frac{r}{6} \Rightarrow r = 30 \text{ inches}
$$
✔ Answer: 30 inches
---
4. Find the length of arc $XY$.
Given:
- Radius $r = 10$ cm
- Central angle $\theta = 70^\circ$
$$
\text{Arc Length} = \frac{70}{360} \times 2\pi \times 10 = \frac{7}{36} \times 20\pi = \frac{140\pi}{36} = \frac{35\pi}{9} \text{ cm}
$$
✔ Answer: $\frac{35\pi}{9}$ cm (or approximately $12.22$ cm)
---
5. A circle has an arc whose measure is $80^\circ$ and whose length is $88\pi$. What is the diameter of the circle?
Given:
- Arc length = $88\pi$
- $\theta = 80^\circ$
Use arc length formula:
$$
88\pi = \frac{80}{360} \times 2\pi r = \frac{2}{9} \times 2\pi r = \frac{4\pi r}{9}
$$
Solve for $r$:
$$
88\pi = \frac{4\pi r}{9} \Rightarrow 88 = \frac{4r}{9} \Rightarrow r = \frac{88 \times 9}{4} = 198
$$
So, radius $r = 198$, then diameter $d = 2r = 396$
✔ Answer: 396 units
---
6. A circle has a circumference whose length is $25\pi$. Find the length of an arc whose central angle is $90^\circ$.
Given:
- Circumference $C = 25\pi$
- So $2\pi r = 25\pi \Rightarrow r = \frac{25}{2} = 12.5$
Now find arc length for $90^\circ$:
$$
\text{Arc Length} = \frac{90}{360} \times 2\pi r = \frac{1}{4} \times 25\pi = \frac{25\pi}{4}
$$
Alternatively, since $90^\circ$ is $1/4$ of the circle, arc length is $1/4$ of circumference:
$$
\frac{1}{4} \times 25\pi = \frac{25\pi}{4}
$$
✔ Answer: $\frac{25\pi}{4}$ units
---
7. Find the measure of the central angle of an arc if its length is $14\pi$ and the radius is 18.
Given:
- Arc length = $14\pi$
- Radius $r = 18$
Use:
$$
\text{Arc Length} = \frac{\theta}{360} \times 2\pi r
$$
$$
14\pi = \frac{\theta}{360} \times 2\pi \times 18 = \frac{\theta}{360} \times 36\pi
$$
Divide both sides by $\pi$:
$$
14 = \frac{\theta}{360} \times 36 \Rightarrow 14 = \frac{36\theta}{360} = \frac{\theta}{10}
\Rightarrow \theta = 140^\circ
$$
✔ Answer: $140^\circ$
---
✔ Final Answers Summary:
1. $4\pi$ cm
2. $4\pi$ cm
3. 30 inches
4. $\frac{35\pi}{9}$ cm
5. 396 units
6. $\frac{25\pi}{4}$ units
7. $140^\circ$
Let me know if you'd like these answers boxed or formatted differently!
Parent Tip: Review the logic above to help your child master the concept of arc lengths and areas of sectors worksheet answers.