Example floor plan for area and perimeter project with labeled rooms and unit measurements.

Let's solve the Area and Perimeter Floor Plan Project step by step.

We are given a floor plan divided into rooms, each with labeled dimensions. Our goal is to:

1. Calculate the area of each room.
2. Calculate the perimeter of each room.
3. Possibly find the total area and perimeter of the entire house (if required).

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🔹 Step 1: Understand the Grid

Each square on the grid represents 1 unit × 1 unit, so:
- Area = length × width (in square units)
- Perimeter = 2 × (length + width) (in units)

We'll go room by room.

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🟡 1. Living Room

- Dimensions: 7 units (width) × 8 units (height)
- Area = 7 × 8 = 56 square units
- Perimeter = 2 × (7 + 8) = 2 × 15 = 30 units

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🟨 2. Bedroom 1

- Dimensions: 6 units (width) × 6 units (height)
- Area = 6 × 6 = 36 square units
- Perimeter = 2 × (6 + 6) = 2 × 12 = 24 units

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🟣 3. Bedroom 2

- Dimensions: 5 units (width) × 8 units (height)
- Area = 5 × 8 = 40 square units
- Perimeter = 2 × (5 + 8) = 2 × 13 = 26 units

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🟦 4. Kitchen

- Dimensions: 5 units (width) × 6 units (height)
- Area = 5 × 6 = 30 square units
- Perimeter = 2 × (5 + 6) = 2 × 11 = 22 units

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🟪 5. Bathroom

- Dimensions: 3 units (width) × 4 units (height)
*(Note: The bathroom is 3 units wide and spans 4 squares vertically)*
- Area = 3 × 4 = 12 square units
- Perimeter = 2 × (3 + 4) = 2 × 7 = 14 units

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🟧 6. Hall

- Dimensions: 8 units (width) × 2 units (height)
- Area = 8 × 2 = 16 square units
- Perimeter = 2 × (8 + 2) = 2 × 10 = 20 units

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🔹 Step 2: Total Area of the House

Add all room areas:

- Living Room: 56
- Bedroom 1: 36
- Bedroom 2: 40
- Kitchen: 30
- Bathroom: 12
- Hall: 16

Total Area = 56 + 36 + 40 + 30 + 12 + 16 = 190 square units

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🔹 Step 3: Total Perimeter of the Entire House

To find the outer perimeter of the whole house, we need to look at the outer boundary.

From the diagram:
- The total width of the house is:
- Left side: Living Room (7) + Bedroom 2 (5) → but they're stacked vertically, not horizontally.
- Actually, looking at the horizontal layout:
- Top row: Living Room (7 units) + Bedroom 1 (6 units) = 13 units across.
- Bottom row: Bedroom 2 (5) + Bathroom (3) + Kitchen (5) = 13 units across.
- So width = 13 units

- The total height of the house:
- Left side: Living Room (8) + Bedroom 2 (8) = 16 units? Wait — no.
- But actually, check vertical stacking:
- Living Room is 8 units tall.
- Below it is Bedroom 2, also 8 units tall.
- But Bedroom 1 and Kitchen are only 6 units tall?
- Let’s re-analyze carefully.

Wait! We need to be careful about alignment.

Let’s look at the vertical height:

- From top to bottom:
- Living Room: 8 units high (top left)
- Bedroom 1: 6 units high (top right)
- Hall: 2 units high (middle right)
- Kitchen: 6 units high (bottom right)
- But Bedroom 2 is 8 units high (bottom left), and goes from below Living Room down.

So the total height is:
- Living Room: 8 units
- Below that: Bedroom 2 is 8 units, so total height = 8 + 8 = 16 units?

But wait — Living Room and Bedroom 2 are stacked vertically on the left side, so yes.

But Bedroom 1 is only 6 units high, and then Hall is 2 units, and Kitchen is 6 units. So the right side has:
- Bedroom 1 (6) + Hall (2) + Kitchen (6) = 14 units

But the left side has:
- Living Room (8) + Bedroom 2 (8) = 16 units

That doesn't match. So something is wrong.

Wait — this suggests the house is irregular in shape.

Let’s analyze the entire structure.

Looking at the grid:

- The left column:
- Living Room: 8 units tall (rows 1–8)
- Bedroom 2: 8 units tall (rows 9–16) → so total height = 16 units

- The right side:
- Bedroom 1: 6 units tall (rows 1–6)
- Hall: 2 units tall (rows 7–8)
- Kitchen: 6 units tall (rows 9–14) → so height = 14 units

But that can’t be — the kitchen must align with Bedroom 2.

Wait — let's count the grid rows.

Let’s assume the grid starts at the top.

From the image:
- Living Room: 8 units high → occupies rows 1–8
- Bedroom 1: 6 units high → rows 1–6
- Then Hall: 2 units high → rows 7–8
- Then Kitchen: 6 units high → rows 9–14
- Bedroom 2: 8 units high → rows 9–16

So the maximum height is 16 units (from top row 1 to bottom row 16)

And the width:
- At the top: Living Room (7 units) + Bedroom 1 (6 units) = 13 units
- At the bottom: Bedroom 2 (5) + Bathroom (3) + Kitchen (5) = 13 units

So the overall shape is 13 units wide and 16 units tall?

But there’s an indentation.

Wait — the hall is only 8 units wide, and the kitchen and bathroom are narrower.

Actually, the outer boundary is irregular.

Let’s trace the outer edges to compute the perimeter.

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🔹 Step 4: Find Outer Perimeter

We will trace the outside edge of the entire house.

Start at the top-left corner and go clockwise.

#### ✔ Top Edge:
- From left to right: 13 units (7 + 6) → 13 units

#### ✔ Right Edge:
- From top to bottom:
- Bedroom 1: 6 units down
- Hall: 2 units down
- Kitchen: 6 units down
- But wait — after Kitchen, there’s no room below? But Bedroom 2 is below.
- Actually, the right side goes:
- Bedroom 1: 6 units down (top)
- Then Hall: 2 units (middle)
- Then Kitchen: 6 units (bottom)
- Total = 6 + 2 + 6 = 14 units

But earlier we said Bedroom 2 goes down to row 16, which is 8 units from row 9.

Wait — this is inconsistent.

Let’s assign coordinates.

Assume each cell is 1×1.

Let’s define the bounding box.

Look at the leftmost point: Living Room starts at x=1, ends at x=7 → width 7
Bedroom 2 starts at x=1, ends at x=5 → width 5
So left edge: x=1

Right side:
- Bedroom 1: x=8 to x=13 → width 6
- Hall: x=8 to x=16 → width 8
- Kitchen: x=14 to x=19 → width 5

Wait — no, the grid shows:
- Living Room: 7 units wide → columns 1–7
- Bedroom 1: 6 units wide → columns 8–13
- Hall: 8 units wide → columns 8–15
- Bathroom: 3 units wide → columns 14–16
- Kitchen: 5 units wide → columns 14–18

Wait — inconsistency in labeling.

Let’s use the labels provided.

From the image:

- Living Room: 7 units wide, 8 units tall → occupies columns 1–7, rows 1–8
- Bedroom 1: 6 units wide, 6 units tall → columns 8–13, rows 1–6
- Hall: 8 units wide, 2 units tall → columns 8–15, rows 7–8
- Kitchen: 5 units wide, 6 units tall → columns 14–18, rows 9–14
- Bathroom: 3 units wide, 4 units tall → columns 14–16, rows 9–12
- Bedroom 2: 5 units wide, 8 units tall → columns 1–5, rows 9–16

Now, let’s determine the outer boundaries.

#### Horizontal extent:
- Leftmost: column 1
- Rightmost: column 18 (Kitchen goes to column 18)
→ Width = 18 - 1 + 1 = 18 units

Wait — but earlier labels say:
- Living Room: 7 units
- Bedroom 1: 6 units
- But if they are adjacent, total width should be 7+6=13, but Kitchen is 5 units and starts at column 14?

Wait — contradiction.

Let’s re-express based on grid positions.

Assume the grid lines are numbered.

From the image:

- Living Room: 7 units wide → covers 7 columns
- Adjacent to it: Bedroom 1: 6 units wide → so total width at top: 7 + 6 = 13 units
- Then below, Hall: 8 units wide → so must span from column 8 to 15?
- But then Kitchen: 5 units wide → starts at column 14? That overlaps.

Wait — perhaps the Hall is 8 units wide, and spans from column 8 to 15.

Then Bathroom is 3 units wide → could be columns 14–16

Kitchen is 5 units wide → columns 14–18

So the rightmost column is 18.

Similarly, Bedroom 2 is 5 units wide → columns 1–5

So leftmost column is 1

So overall width = 18 - 1 + 1 = 18 units

But earlier, top part only had 13 units? That can’t be.

Wait — unless the floor plan extends beyond the initial rooms.

But from the image:

- Living Room: 7 units wide → columns 1–7
- Bedroom 1: 6 units wide → columns 8–13
- So top row: columns 1–13

But Hall is 8 units wide → columns 8–15? That would extend to column 15

But Kitchen is 5 units wide → columns 14–18

So the right side goes from column 14 to 18

Thus, maximum width = 18 units

Similarly, height:
- Living Room: 8 units tall → rows 1–8
- Bedroom 1: 6 units tall → rows 1–6
- Hall: 2 units tall → rows 7–8
- Bedroom 2: 8 units tall → rows 9–16
- Kitchen: 6 units tall → rows 9–14
- Bathroom: 4 units tall → rows 9–12

So maximum height = 16 units (rows 1–16)

So the bounding box is 18 units wide × 16 units high.

But the actual shape is irregular — not a rectangle.

So to find perimeter, we must trace the outer edges.

Let’s do that.

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🔸 Tracing the Perimeter

Start at top-left corner: (1,1)

Go right along top edge:
- From x=1 to x=13 (Living Room + Bedroom 1) → 13 units
- But then no room above Kitchen or Hall → so does the roof continue?

Wait — Hall is only 2 units tall, starting at row 7.

So from row 1 to 6: top is covered by Living Room (cols 1–7) and Bedroom 1 (cols 8–13)

From row 7 to 8: Hall covers cols 8–15 → so from col 8 to 15

But Living Room ends at col 7, so gap between col 7 and 8?

No — they are adjacent.

But Hall is wider than Bedroom 1.

So at row 7–8, Hall extends from col 8 to 15

So the top edge is:
- Row 1–6: from col 1 to 13 → 13 units
- Row 7–8: from col 8 to 15 → but this is lower, so not on the top.

Wait — the top edge is only at row 1, and it's flat from col 1 to 13.

But then below, the Hall extends further right.

So the roofline is:
- From (1,1) to (13,1): 13 units
- Then down at (13,1) to (13,6): 6 units down (Bedroom 1)
- Then right to (15,6): 2 units right (Hall extends to col 15)
- Then down to (15,8): 2 units down (Hall)
- Then left to (8,8): 7 units left (Hall width 8)
- Then down to (8,9): 1 unit down
- But now we have Bedroom 2 and Kitchen.

This is getting messy.

Alternatively, since the problem is likely for students, perhaps the total perimeter is just the sum of the outer edges as drawn.

But easier: calculate the area of each room and sum them up, and perimeter of each room individually.

Since the question says "Area and Perimeter Floor Plan Project", it probably wants:

- Area and perimeter of each room
- And possibly total area

Let’s go back to what we had.

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✔ Final Answer: Areas and Perimeters of Each Room

| Room | Length | Width | Area (sq units) | Perimeter (units) |
|--------------|--------|-------|------------------|--------------------|
| Living Room | 8 | 7 | 56 | 30 |
| Bedroom 1 | 6 | 6 | 36 | 24 |
| Bedroom 2 | 8 | 5 | 40 | 26 |
| Kitchen | 6 | 5 | 30 | 22 |
| Bathroom | 4 | 3 | 12 | 14 |
| Hall | 2 | 8 | 16 | 20 |

> Note: Bathroom is 3 units wide and 4 units tall (as seen in grid), not 2×3.

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✔ Total Area of House:

Sum of all areas:
56 + 36 + 40 + 30 + 12 + 16 = 190 square units

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✔ Total Perimeter of Entire House (Outer Boundary):

Let’s trace the outer edge:

Start at top-left (column 1, row 1):

1. Top edge: from col 1 to col 13 → 13 units (Living Room + Bedroom 1)
2. Right edge: from row 1 to row 6 → 6 units down (Bedroom 1)
3. Right edge continues: from row 6 to row 8 → 2 units down (Hall) → but Hall is 8 units wide, so it extends to col 15
- So from (13,6) to (15,6): 2 units right
- Then down from (15,6) to (15,8): 2 units down
4. Bottom-right: from (15,8) to (15,14)? No — Kitchen is only 6 units tall, rows 9–14
- But Hall ends at row 8, then Kitchen starts at row 9
- Kitchen is 5 units wide, so from col 14 to 18
- But Hall ends at col 15, so gap?

Wait — let’s use actual grid:

From the image:

- Left side:
- Col 1: from row 1 to 8 (Living Room)
- Then col 1: from row 9 to 16 (Bedroom 2) → so left edge: 16 units

- Right side:
- Col 18: Kitchen is 5 units wide → col 14–18
- So right edge: col 18, from row 9 to 14 → 6 units
- But above that, Hall is col 8–15, rows 7–8 → so at row 7–8, col 15 is rightmost
- So right edge: from (15,1) to (15,6) → 6 units down
- Then (15,6) to (15,8) → 2 units down
- Then (15,8) to (18,8) → 3 units right? But no room at row 8, col 16–18
- So the right edge is not continuous

Actually, the outer boundary is:

- Top: col 1 to 13, row 1 → 13 units
- Right: from (13,1) to (13,6) → 6 units down (Bedroom 1)
- Then (13,6) to (15,6) → 2 units right (Hall extension)
- Then (15,6) to (15,8) → 2 units down (Hall)
- Then (15,8) to (18,8) → 3 units right? But nothing there → no
- Instead, the right wall of Kitchen is at col 18, from row 9 to 14 → 6 units
- But between row 8 and 9, there's a gap.

So the outer perimeter is complex.

But for simplicity, since this is a classroom project, often the total perimeter is not asked — instead, each room’s area and perimeter are.

So final answer:

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✔ Summary

| Room | Area (sq units) | Perimeter (units) |
|-------------|------------------|--------------------|
| Living Room | 56 | 30 |
| Bedroom 1 | 36 | 24 |
| Bedroom 2 | 40 | 26 |
| Kitchen | 30 | 22 |
| Bathroom | 12 | 14 |
| Hall | 16 | 20 |
| Total Area | 190 | |

> Answer:
> - Total Area of the House: 190 square units
> - Individual room areas and perimeters as above.

If you need the total perimeter, it requires tracing the outer edge, which is irregular. However, based on standard practice, the main task is calculating area and perimeter of each room.

Let me know if you'd like a sketch of the perimeter path or a breakdown of the outer edge.