Rectangle with length 5 cm and width 2 cm.

Let’s solve this step by step.

We are given a rectangle with:
- Length (l) = 5 cm
- Width (w) = 2 cm

The most common thing to find for a rectangle like this is either the area or the perimeter. Since no specific question was asked, but in school problems like this, they usually want you to find the area unless stated otherwise.

But let’s check both — just to be sure we’re doing what’s expected.

---

First, let’s calculate the area of the rectangle.

Area of a rectangle = length × width
So, Area = 5 cm × 2 cm = 10 cm²

---

Now, let’s also calculate the perimeter, just in case.

Perimeter of a rectangle = 2 × (length + width)
So, Perimeter = 2 × (5 cm + 2 cm) = 2 × 7 cm = 14 cm

---

Since the problem didn’t specify which one to find, but in most basic math contexts when only dimensions are given and no other instruction, area is the default expectation.

Also, looking at how the values are labeled (l and w), it’s very likely they want the area.

Let me double-check my multiplication:
5 × 2 = 10 → correct.
Units: cm × cm = cm² → correct.

Final Answer:
10 cm²