Math worksheet with word problems on calculating area and perimeter of rectangles.
A math worksheet titled "Area and Perimeter of Rectangle - Word Problems" from Math Monks, featuring six word problems involving calculations of area and perimeter for rectangles, with spaces for answers.
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Step-by-step solution for: Area and Perimeter of Rectangles Worksheets - Math Monks
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Show Answer Key & Explanations
Step-by-step solution for: Area and Perimeter of Rectangles Worksheets - Math Monks
Let’s solve each problem one by one, step by step. We’ll use the formulas for area and perimeter of a rectangle:
- Area = length × width
- Perimeter = 2 × (length + width)
---
Problem 1:
Length = 16 ft
Width = 12 ft
Area = 16 × 12 = 192 ft²
Perimeter = 2 × (16 + 12) = 2 × 28 = 56 ft
✔ Answer: Area = 192 ft², Perimeter = 56 ft
---
Problem 2:
Width = 30 cm
Length = 40 cm
Area = 40 × 30 = 1200 cm²
Perimeter = 2 × (40 + 30) = 2 × 70 = 140 cm
✔ Answer: Area = 1200 cm², Perimeter = 140 cm
---
Problem 3:
Length = 8 cm
Width = 6 cm
Area = 8 × 6 = 48 cm²
Perimeter = 2 × (8 + 6) = 2 × 14 = 28 cm
✔ Answer: Area = 48 cm², Perimeter = 28 cm
---
Problem 4:
Width = 250 m
Length = 500 m
We only need perimeter here (for the fence).
Perimeter = 2 × (500 + 250) = 2 × 750 = 1500 m
✔ Answer: Perimeter = 1500 m
---
Problem 5:
Area = 150 m²
Length = 25 m
First, find width:
Width = Area ÷ Length = 150 ÷ 25 = 6 m
Now find perimeter:
Perimeter = 2 × (25 + 6) = 2 × 31 = 62 m
✔ Answer: Width = 6 m, Perimeter = 62 m
---
Problem 6:
Area = 5200 ft²
Width = 75 ft
Find length:
Length = Area ÷ Width = 5200 ÷ 75
Let’s calculate that:
75 × 69 = 5175 → too low
75 × 70 = 5250 → too high
So try 5200 ÷ 75:
Divide: 5200 ÷ 75 = 69.333...? Wait — let’s do it properly.
Actually, 75 × 69 = 5175
5200 - 5175 = 25 → so 69 + 25/75 = 69 + 1/3 ≈ 69.333… but we should check if it divides evenly.
Wait — maybe I made a mistake. Let me recalculate:
5200 ÷ 75
Divide numerator and denominator by 25:
5200 ÷ 25 = 208
75 ÷ 25 = 3
→ So 208 ÷ 3 = 69.333…? That can’t be right for a real orchard dimension? But mathematically, it’s correct.
But wait — let me double-check: 75 × 69.333… = 75 × (208/3) = (75/3) × 208 = 25 × 208 = 5200 ✔
So length = 208/3 ft or 69⅓ ft. But since the problem doesn’t specify to round, we can leave as fraction or decimal.
However, in word problems like this, sometimes they expect exact values. Let’s write it as a mixed number or improper fraction.
But actually — let me check again: Is 5200 divisible by 75?
75 = 25 × 3
5200 ÷ 25 = 208 → yes
208 ÷ 3 = 69.333… → not whole number.
But the problem says “find the length”, so we must give the exact value.
So:
Length = 5200 ÷ 75 = 208 ÷ 3 = 69⅓ ft
But perhaps we should write it as a decimal rounded? The problem doesn’t say. Since other answers are whole numbers, maybe I misread?
Wait — let me re-read Problem 6:
“The area of an apple orchard is 5200 ft². Find the length of the rectangular orchard, if it's width is 75 ft.”
No mention of rounding. So we must give exact answer.
But 5200 ÷ 75 simplifies:
Divide numerator and denominator by 25:
5200 ÷ 25 = 208
75 ÷ 25 = 3
→ 208/3 ft = 69 1/3 ft
Alternatively, as decimal: 69.333... ft
But in school math, often they prefer fractions unless specified.
However, looking back at all other problems — they all resulted in whole numbers. Maybe there’s a typo? Or maybe I should just compute it correctly.
Wait — let me calculate 75 × 69.333... = 75 × 69 + 75 × 1/3 = 5175 + 25 = 5200 ✔ Correct.
So length is 208/3 ft or 69 1/3 ft.
But perhaps the problem expects us to write it as a decimal? Or maybe I should check if 5200 ÷ 75 reduces.
Actually, 5200 ÷ 75 = 1040 ÷ 15 = 208 ÷ 3 → same thing.
I think for accuracy, we'll write it as a fraction.
But let me see — maybe the problem meant 5250? No, it says 5200.
Okay, we’ll go with exact value.
So:
Length = 5200 ÷ 75 = 208/3 ft = 69 1/3 ft
But since the question only asks for length (not perimeter), we stop here.
✔ Answer: Length = 208/3 ft or 69 1/3 ft
But to match format of other answers, perhaps write as decimal? However, in math class, fractions are preferred when exact.
Alternatively, maybe I made a calculation error earlier? Let me verify once more:
75 × 69 = 5175
5200 - 5175 = 25
25 / 75 = 1/3 → so 69 + 1/3 = 69 1/3 → correct.
So final answer for #6 is 69 1/3 ft.
But let’s write it as an improper fraction or mixed number? Mixed number is clearer.
---
Final Answers:
1. Area = 192 ft², Perimeter = 56 ft
2. Area = 1200 cm², Perimeter = 140 cm
3. Area = 48 cm², Perimeter = 28 cm
4. Perimeter = 1500 m
5. Width = 6 m, Perimeter = 62 m
6. Length = 69 1/3 ft (or 208/3 ft)
But for consistency, since others are whole numbers, and this is a word problem, perhaps they expect decimal? But no instruction.
Actually, let me check online or standard practice — in such worksheets, if division isn't exact, they usually accept fraction or decimal. But since 1/3 is repeating, better to write as fraction.
Alternatively, maybe I should write it as 69.33 ft? But that’s approximate.
The problem says "find the length", so exact value is best.
I’ll go with 69 1/3 ft.
But to make it neat, let’s write all answers clearly.
──────────────────────────────────────
Final Answer:
1. Area = 192 ft², Perimeter = 56 ft
2. Area = 1200 cm², Perimeter = 140 cm
3. Area = 48 cm², Perimeter = 28 cm
4. Perimeter = 1500 m
5. Width = 6 m, Perimeter = 62 m
6. Length = 69 1/3 ft
- Area = length × width
- Perimeter = 2 × (length + width)
---
Problem 1:
Length = 16 ft
Width = 12 ft
Area = 16 × 12 = 192 ft²
Perimeter = 2 × (16 + 12) = 2 × 28 = 56 ft
✔ Answer: Area = 192 ft², Perimeter = 56 ft
---
Problem 2:
Width = 30 cm
Length = 40 cm
Area = 40 × 30 = 1200 cm²
Perimeter = 2 × (40 + 30) = 2 × 70 = 140 cm
✔ Answer: Area = 1200 cm², Perimeter = 140 cm
---
Problem 3:
Length = 8 cm
Width = 6 cm
Area = 8 × 6 = 48 cm²
Perimeter = 2 × (8 + 6) = 2 × 14 = 28 cm
✔ Answer: Area = 48 cm², Perimeter = 28 cm
---
Problem 4:
Width = 250 m
Length = 500 m
We only need perimeter here (for the fence).
Perimeter = 2 × (500 + 250) = 2 × 750 = 1500 m
✔ Answer: Perimeter = 1500 m
---
Problem 5:
Area = 150 m²
Length = 25 m
First, find width:
Width = Area ÷ Length = 150 ÷ 25 = 6 m
Now find perimeter:
Perimeter = 2 × (25 + 6) = 2 × 31 = 62 m
✔ Answer: Width = 6 m, Perimeter = 62 m
---
Problem 6:
Area = 5200 ft²
Width = 75 ft
Find length:
Length = Area ÷ Width = 5200 ÷ 75
Let’s calculate that:
75 × 69 = 5175 → too low
75 × 70 = 5250 → too high
So try 5200 ÷ 75:
Divide: 5200 ÷ 75 = 69.333...? Wait — let’s do it properly.
Actually, 75 × 69 = 5175
5200 - 5175 = 25 → so 69 + 25/75 = 69 + 1/3 ≈ 69.333… but we should check if it divides evenly.
Wait — maybe I made a mistake. Let me recalculate:
5200 ÷ 75
Divide numerator and denominator by 25:
5200 ÷ 25 = 208
75 ÷ 25 = 3
→ So 208 ÷ 3 = 69.333…? That can’t be right for a real orchard dimension? But mathematically, it’s correct.
But wait — let me double-check: 75 × 69.333… = 75 × (208/3) = (75/3) × 208 = 25 × 208 = 5200 ✔
So length = 208/3 ft or 69⅓ ft. But since the problem doesn’t specify to round, we can leave as fraction or decimal.
However, in word problems like this, sometimes they expect exact values. Let’s write it as a mixed number or improper fraction.
But actually — let me check again: Is 5200 divisible by 75?
75 = 25 × 3
5200 ÷ 25 = 208 → yes
208 ÷ 3 = 69.333… → not whole number.
But the problem says “find the length”, so we must give the exact value.
So:
Length = 5200 ÷ 75 = 208 ÷ 3 = 69⅓ ft
But perhaps we should write it as a decimal rounded? The problem doesn’t say. Since other answers are whole numbers, maybe I misread?
Wait — let me re-read Problem 6:
“The area of an apple orchard is 5200 ft². Find the length of the rectangular orchard, if it's width is 75 ft.”
No mention of rounding. So we must give exact answer.
But 5200 ÷ 75 simplifies:
Divide numerator and denominator by 25:
5200 ÷ 25 = 208
75 ÷ 25 = 3
→ 208/3 ft = 69 1/3 ft
Alternatively, as decimal: 69.333... ft
But in school math, often they prefer fractions unless specified.
However, looking back at all other problems — they all resulted in whole numbers. Maybe there’s a typo? Or maybe I should just compute it correctly.
Wait — let me calculate 75 × 69.333... = 75 × 69 + 75 × 1/3 = 5175 + 25 = 5200 ✔ Correct.
So length is 208/3 ft or 69 1/3 ft.
But perhaps the problem expects us to write it as a decimal? Or maybe I should check if 5200 ÷ 75 reduces.
Actually, 5200 ÷ 75 = 1040 ÷ 15 = 208 ÷ 3 → same thing.
I think for accuracy, we'll write it as a fraction.
But let me see — maybe the problem meant 5250? No, it says 5200.
Okay, we’ll go with exact value.
So:
Length = 5200 ÷ 75 = 208/3 ft = 69 1/3 ft
But since the question only asks for length (not perimeter), we stop here.
✔ Answer: Length = 208/3 ft or 69 1/3 ft
But to match format of other answers, perhaps write as decimal? However, in math class, fractions are preferred when exact.
Alternatively, maybe I made a calculation error earlier? Let me verify once more:
75 × 69 = 5175
5200 - 5175 = 25
25 / 75 = 1/3 → so 69 + 1/3 = 69 1/3 → correct.
So final answer for #6 is 69 1/3 ft.
But let’s write it as an improper fraction or mixed number? Mixed number is clearer.
---
Final Answers:
1. Area = 192 ft², Perimeter = 56 ft
2. Area = 1200 cm², Perimeter = 140 cm
3. Area = 48 cm², Perimeter = 28 cm
4. Perimeter = 1500 m
5. Width = 6 m, Perimeter = 62 m
6. Length = 69 1/3 ft (or 208/3 ft)
But for consistency, since others are whole numbers, and this is a word problem, perhaps they expect decimal? But no instruction.
Actually, let me check online or standard practice — in such worksheets, if division isn't exact, they usually accept fraction or decimal. But since 1/3 is repeating, better to write as fraction.
Alternatively, maybe I should write it as 69.33 ft? But that’s approximate.
The problem says "find the length", so exact value is best.
I’ll go with 69 1/3 ft.
But to make it neat, let’s write all answers clearly.
──────────────────────────────────────
Final Answer:
1. Area = 192 ft², Perimeter = 56 ft
2. Area = 1200 cm², Perimeter = 140 cm
3. Area = 48 cm², Perimeter = 28 cm
4. Perimeter = 1500 m
5. Width = 6 m, Perimeter = 62 m
6. Length = 69 1/3 ft
Parent Tip: Review the logic above to help your child master the concept of area and perimeter word problems worksheet.