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Math worksheet with word problems on calculating area and perimeter of rectangles.

A math worksheet titled "Area and Perimeter of Rectangle - Word Problems" from Math Monks, featuring six word problems involving calculations of area and perimeter for rectangles, with spaces for answers.

A math worksheet titled "Area and Perimeter of Rectangle - Word Problems" from Math Monks, featuring six word problems involving calculations of area and perimeter for rectangles, with spaces for answers.

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Show Answer Key & Explanations Step-by-step solution for: Area and Perimeter of Rectangles Worksheets - Math Monks
Let’s solve each problem one by one, step by step. We’ll use the formulas for area and perimeter of a rectangle:

- Area = length × width
- Perimeter = 2 × (length + width)

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Problem 1:

Length = 16 ft
Width = 12 ft

Area = 16 × 12 = 192 ft²
Perimeter = 2 × (16 + 12) = 2 × 28 = 56 ft

Answer: Area = 192 ft², Perimeter = 56 ft

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Problem 2:

Width = 30 cm
Length = 40 cm

Area = 40 × 30 = 1200 cm²
Perimeter = 2 × (40 + 30) = 2 × 70 = 140 cm

Answer: Area = 1200 cm², Perimeter = 140 cm

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Problem 3:

Length = 8 cm
Width = 6 cm

Area = 8 × 6 = 48 cm²
Perimeter = 2 × (8 + 6) = 2 × 14 = 28 cm

Answer: Area = 48 cm², Perimeter = 28 cm

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Problem 4:

Width = 250 m
Length = 500 m

We only need perimeter here (for the fence).

Perimeter = 2 × (500 + 250) = 2 × 750 = 1500 m

Answer: Perimeter = 1500 m

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Problem 5:

Area = 150 m²
Length = 25 m

First, find width:
Width = Area ÷ Length = 150 ÷ 25 = 6 m

Now find perimeter:
Perimeter = 2 × (25 + 6) = 2 × 31 = 62 m

Answer: Width = 6 m, Perimeter = 62 m

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Problem 6:

Area = 5200 ft²
Width = 75 ft

Find length:
Length = Area ÷ Width = 5200 ÷ 75

Let’s calculate that:

75 × 69 = 5175 → too low
75 × 70 = 5250 → too high
So try 5200 ÷ 75:

Divide: 5200 ÷ 75 = 69.333...? Wait — let’s do it properly.

Actually, 75 × 69 = 5175
5200 - 5175 = 25 → so 69 + 25/75 = 69 + 1/3 ≈ 69.333… but we should check if it divides evenly.

Wait — maybe I made a mistake. Let me recalculate:

5200 ÷ 75

Divide numerator and denominator by 25:
5200 ÷ 25 = 208
75 ÷ 25 = 3
→ So 208 ÷ 3 = 69.333…? That can’t be right for a real orchard dimension? But mathematically, it’s correct.

But wait — let me double-check: 75 × 69.333… = 75 × (208/3) = (75/3) × 208 = 25 × 208 = 5200

So length = 208/3 ft or 69⅓ ft. But since the problem doesn’t specify to round, we can leave as fraction or decimal.

However, in word problems like this, sometimes they expect exact values. Let’s write it as a mixed number or improper fraction.

But actually — let me check again: Is 5200 divisible by 75?

75 = 25 × 3
5200 ÷ 25 = 208 → yes
208 ÷ 3 = 69.333… → not whole number.

But the problem says “find the length”, so we must give the exact value.

So:

Length = 5200 ÷ 75 = 208 ÷ 3 = 69⅓ ft

But perhaps we should write it as a decimal rounded? The problem doesn’t say. Since other answers are whole numbers, maybe I misread?

Wait — let me re-read Problem 6:

“The area of an apple orchard is 5200 ft². Find the length of the rectangular orchard, if it's width is 75 ft.”

No mention of rounding. So we must give exact answer.

But 5200 ÷ 75 simplifies:

Divide numerator and denominator by 25:
5200 ÷ 25 = 208
75 ÷ 25 = 3
→ 208/3 ft = 69 1/3 ft

Alternatively, as decimal: 69.333... ft

But in school math, often they prefer fractions unless specified.

However, looking back at all other problems — they all resulted in whole numbers. Maybe there’s a typo? Or maybe I should just compute it correctly.

Wait — let me calculate 75 × 69.333... = 75 × 69 + 75 × 1/3 = 5175 + 25 = 5200 Correct.

So length is 208/3 ft or 69 1/3 ft.

But perhaps the problem expects us to write it as a decimal? Or maybe I should check if 5200 ÷ 75 reduces.

Actually, 5200 ÷ 75 = 1040 ÷ 15 = 208 ÷ 3 → same thing.

I think for accuracy, we'll write it as a fraction.

But let me see — maybe the problem meant 5250? No, it says 5200.

Okay, we’ll go with exact value.

So:

Length = 5200 ÷ 75 = 208/3 ft = 69 1/3 ft

But since the question only asks for length (not perimeter), we stop here.

Answer: Length = 208/3 ft or 69 1/3 ft

But to match format of other answers, perhaps write as decimal? However, in math class, fractions are preferred when exact.

Alternatively, maybe I made a calculation error earlier? Let me verify once more:

75 × 69 = 5175
5200 - 5175 = 25
25 / 75 = 1/3 → so 69 + 1/3 = 69 1/3 → correct.

So final answer for #6 is 69 1/3 ft.

But let’s write it as an improper fraction or mixed number? Mixed number is clearer.

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Final Answers:

1. Area = 192 ft², Perimeter = 56 ft
2. Area = 1200 cm², Perimeter = 140 cm
3. Area = 48 cm², Perimeter = 28 cm
4. Perimeter = 1500 m
5. Width = 6 m, Perimeter = 62 m
6. Length = 69 1/3 ft (or 208/3 ft)

But for consistency, since others are whole numbers, and this is a word problem, perhaps they expect decimal? But no instruction.

Actually, let me check online or standard practice — in such worksheets, if division isn't exact, they usually accept fraction or decimal. But since 1/3 is repeating, better to write as fraction.

Alternatively, maybe I should write it as 69.33 ft? But that’s approximate.

The problem says "find the length", so exact value is best.

I’ll go with 69 1/3 ft.

But to make it neat, let’s write all answers clearly.

──────────────────────────────────────

Final Answer:
1. Area = 192 ft², Perimeter = 56 ft
2. Area = 1200 cm², Perimeter = 140 cm
3. Area = 48 cm², Perimeter = 28 cm
4. Perimeter = 1500 m
5. Width = 6 m, Perimeter = 62 m
6. Length = 69 1/3 ft
Parent Tip: Review the logic above to help your child master the concept of area and perimeter word problems worksheet.
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